The angular displacement of the merry-go-round during the 5.0 seconds is 47.5 radians.
We can use the formula:
θ = ω_i t + 1/2 α [tex]t^2[/tex]
where:
θ = angular displacement
ω_i = initial angular velocity
t = time
α = angular acceleration
Given:
ω_i = 2.0 rad/s
α = [tex]3.0 rad/s^2[/tex]
t = 5.0 s
Substituting the values, we get:
θ = (2.0 rad/s)(5.0 s) + 1/2 (3.0 rad/[tex]s^2[/tex])(5.0[tex]s)^2[/tex]
θ = 10.0 rad + 37.5 rad
θ = 47.5 rad
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a common source of wave motion is a wave pattern. harmonic object. region of variable high and low pressure. vibrating object. none of these
A common source of wave motion is a vibrating object, which creates a wave pattern that propagates through a region of variable high and low pressure.
This pattern can also be described as a harmonic pattern, as the vibrations are typically periodic and create a series of harmonics. Therefore, the correct answer is: vibrating object. When an object vibrates, it creates disturbances in the surrounding medium, which then propagate as waves. The wave pattern and regions of variable high and low pressure are a result of this vibrating object. Harmonic objects can also create wave motion, but they are not the only source.
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two packages at ups start sliding down the 20 degree ramp shown in the figure. package a has a mass of 4.00 and a coefficient of kinetic friction of 0.220. package b has a mass of 9.00 and a coefficient of kinetic friction of 0.170. how long does it take package a to reach the bottom?
It takes package a 2.16 seconds to reach the bottom of the ramp.
To solve this problem, we can use the following equation:
magsin(theta) - magcos(theta)mu = maa
where ma is the mass of package a, g is the acceleration due to gravity, theta is the angle of the ramp, mu is the coefficient of kinetic friction, and a is the acceleration of package a.
Plugging in the given values, we get:
4.009.81sin(20) - 4.009.81cos(20)0.220 = 4.00a
Solving for a, we get:
a = 1.24 m/[tex]s^2[/tex]
To find the time it takes package a to reach the bottom, we can use the following kinematic equation:
d = vit + (1/2)a[tex]t^2[/tex]
where d is the distance traveled, vi is the initial velocity (which is assumed to be zero), and t is the time.
The distance traveled by package a is the length of the ramp, which is:
d = Lsin(theta) = 10sin(20) = 3.42 m
Plugging in the values we have, we get:
3.42 = (1/2)(1.24)[tex]t^2[/tex]
Solving for t, we get:
t = 2.16 seconds
Therefore, it takes package a 2.16 seconds to reach the bottom of the ramp.
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You and your dog go for a walk to a nearby park. On the way, your dog takes many short side trips to chase squirrels, examine fire hydrants, and so on. When you arrive at the park, do you and your dog have the same displacement? Have you traveled the same distance?(Ch.2)
When you and your dog arrive at the park, you both have the same displacement, as displacement is the overall change in position from the starting point to the final point. However, you have not traveled the same distance. Your dog's side trips increased the total distance it traveled compared to your straighter path to the park.
Displacement is a vector quantity that represents the change in position of an object from its initial to final location, taking into account the direction of motion. The displacement of an object is the straight-line distance between its initial and final positions, measured in a specific direction. Therefore, if you and your dog started and ended your walk at the same location, the displacement will be same. On the other hand, distance is a scalar quantity that represents the total amount of ground covered by an object, without regard to the direction of motion. The distance traveled by an object is the sum of the magnitudes of the displacements along its path. Therefore, if you and your dog followed the same path to the park, you would have traveled less distance and your dog would have covered a greater distance than you.
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16 8O, 17 8O, and 18 8O are all stable oxygen isotopes. Which one likely has the largest binding energy per nucleon?A. 16 8O because it is doubly magic.B. 18 8O because it has the smallest proton to neutron ratio.C. 17 8O because it lies between two stable isotopes.D. They all have the same binding energy per nucleon.
In this case, 17 8O is likely the most stable because it lies between two stable isotopes, 16 8O and 18 8O. This means that it has a more balanced proton to neutron ratio, which results in a larger binding energy per nucleon compared to the other two isotopes. Therefore, option C is the correct answer. 17 8O because it lies between two stable isotopes.
Oxygen has three stable isotopes: 16 8O, 17 8O, and 18 8O. Binding energy per nucleon is the amount of energy required to disassemble a nucleus into its individual protons and neutrons. Generally, isotopes with a higher binding energy per nucleon are more stable.
17 8O likely has the largest binding energy per nucleon because it lies between two stable isotopes.
Isotopes are atoms of the same element that have different numbers of neutrons in their nucleus. Binding energy per nucleon refers to the amount of energy required to break apart the nucleus of an atom and is a measure of its stability.
The larger the binding energy per nucleon, the more stable the nucleus. The stability of a nucleus depends on the ratio of protons to neutrons in the nucleus. If the ratio is too high or too low, the nucleus becomes unstable and can decay.
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equation for kinetic energy. what is the SI unit for kinetic energy? What will happen if the speed doubles?
The equation for kinetic energy is 1/2 mv^2, where m is the mass of the object and v is its speed.
The SI unit for kinetic energy is Joules (J). If the speed doubles, the kinetic energy will quadruple because the kinetic energy is proportional to the square of the speed.Kinetic energy is a scalar quantity, meaning it has magnitude but no direction. It is typically measured in joules (J). Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: increasing either of these will increase the kinetic energy. It is also proportional to the square of the frequency of a wave.
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Which artifact is not related to the unexpected reflection of an acoustic wave ?
a. multipath
b. comet tail
c. reverberation
d. lateral resolution
The artifact that is not related to the unexpected reflection of an acoustic wave is: d. lateral resolution
Lateral resolution refers to the ability to distinguish two closely spaced objects as separate entities in an image, while artifacts a, b, and c (multipath, comet tail, and reverberation) are related to unexpected reflections of acoustic waves. Lateral resolution is the image generated when the two structures lying side by side are perpendicular to the beam. This is directly related to the width of the ultrasound beam. The narrower the beam better is the resolution. The width of the beam is inversely related to the frequency.
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If you calculated 108 ± 2 Ohms and the manufacturer says it is 100 Ohms with a 5% tolerance, do your data support the manufacturer's claims?
Yes, your data supports the manufacturer's claims. The manufacturer states the resistor has a value of 100 Ohms with a 5% tolerance. This means the actual resistance can vary between 95 Ohms (100 - 5) and 105 Ohms (100 + 5).
If the temperature and other physical parameters of the wire, such as stresses and strains, stay unchanged, the current flowing through the wire is precisely proportional to the potential difference applied across its ends.
In an electrical circuit with just passive components, the relationship between voltage, resistance, and current is described by Ohm's law as follows:
V=RI
where
V is the voltage that the battery provides.
R is the circuit's resistance.
Electrified heaters. Around the world, electric heaters are a typical wintertime device.
Irons and kettles with electricity. There are numerous resistors within the electric kettle and irons.
We can see from the equation that the voltage, V, and the circuit's current, I, are directly inversely proportional.
Your calculated value of 108 ± 2 Ohms falls within this range, as the lower limit is 106 Ohms (108 - 2) and the upper limit is 110 Ohms (108 + 2).
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What is meant by conservation of charge?
a) The amount of charge in every nucleus is the same.
b) Net charge cannot be created or destroyed.
c) All electrons have the same electric charge.
d) Whenever an electron is created, an equal and oppositely charged proton is also created.
What is meant by conservation of charge?
The correct answer is:
b) Net charge cannot be created or destroyed.
The conservation of charge principle states that the total charge within an isolated system remains constant over time. This means that in any physical or chemical process, the total amount of positive charge must be equal to the total amount of negative charge. The charge is the property of matter because of which the matter experiences the force of attraction or repulsion in an electric field. The coulomb is the unit of electric charges, whereas the current is measured in the amperes.
In other words, charges can be transferred between objects, but they cannot be created or destroyed. This principle is a fundamental law of physics and is applicable to both electric and magnetic interactions.
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If 2 springs are stretched different amounts by the same mass hung from them, which spring has the larger spring constant, the one that stretches most or the one that stretches the least? Explain.
If 2 springs are stretched by different amounts by the same mass hung from them, the one that stretches the least has the larger spring constant.
To determine which spring has the larger spring constant when 2 springs are stretched by different amounts by the same mass, we need to consider Hooke's Law.
Hooke's Law states that the force exerted by a spring is proportional to its displacement from the equilibrium position, represented by F = -kx, where F is the force, k is the spring constant, and x is the displacement.
Since the same mass is hung from both springs, the force exerted on each spring is the same (F = mg, where m is the mass and g is gravitational acceleration). The spring that stretches the least will have a larger spring constant because, according to Hooke's Law, a larger spring constant is needed to counteract the same force with a smaller displacement. So, the spring that stretches the least has the larger spring constant.
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what rms voltage is required to produce an rms current of 2.1 a in a 66 mh inductor at a frequency of 25 hz ?
An rms voltage of 21.79 V is required.
How to find the rms voltage?We can use the formula for the rms voltage in an AC circuit containing an inductor:
V = XL × I
where XL is the inductive reactance, I is the rms current, and V is the rms voltage.
The inductive reactance is given by the formula:
XL = 2πfL
where f is the frequency of the AC current and L is the inductance of the inductor.
Substituting the given values, we get:
XL = 2π × 25 Hz × 66 mH = 10.39 Ω
Now, we can use the formula for the rms voltage:
V = XL × I = 10.39 Ω × 2.1 A = 21.79 V
Therefore, an rms voltage of 21.79 V is required to produce an rms current of 2.1 A in a 66 mH inductor at a frequency of 25 Hz.
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an athlete runs with velocity 12 km/h for 5 minutes, 14 km/h for the next 4 minutes, and 18 km/h for other 6 minutes. compute the total distance traveled.
The athlete traveled a total distance of 3732.16 meters.
To find the total distance traveled, we need to calculate the distance traveled during each time interval and then add them up.
First, we need to convert the velocities from km/h to m/s, since distance is measured in meters and time is measured in seconds:
12 km/h = (12/3.6) m/s = 3.33 m/s
14 km/h = (14/3.6) m/s = 3.89 m/s
18 km/h = (18/3.6) m/s = 5.00 m/s
Now we can calculate the distances traveled during each time interval:
Distance traveled at 3.33 m/s for 5 minutes = (3.33 m/s)(5 min)(60 s/min) = 1000 m
Distance traveled at 3.89 m/s for 4 minutes = (3.89 m/s)(4 min)(60 s/min) = 932.16 m
Distance traveled at 5.00 m/s for 6 minutes = (5.00 m/s)(6 min)(60 s/min) = 1800 m
Finally, we can add up the distances to get the total distance traveled:
Total distance traveled = 1000 m + 932.16 m + 1800 m = 3732.16 m
Therefore, the athlete traveled a total distance of 3732.16 meters.
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Describe the perception of a pair of sinusoidal tones at 500 and 528 Hz sounded simultaneously.
For the perception of a pair of sinusoidal tones at 500 and 528 Hz sounded simultaneous, we can analyze the characteristics of the sinusoidal waves and how they interact with each other when perceived by our auditory system.
A sinusoidal tone is a type of continuous waveform that has a smooth, repetitive oscillation. When two sinusoidal tones with frequencies of 500 Hz and 528 Hz are sounded simultaneously, they will interfere with each other to create a phenomenon known as beat frequency.
The beat frequency is the difference between the two frequencies, which in this case is 528 Hz - 500 Hz = 28 Hz. This beat frequency can be perceived as a rhythmic fluctuation in the loudness of the combined sound. This occurs because the two sinusoidal waves periodically align and cancel each other out, resulting in an increase or decrease in amplitude.
In summary, when a pair of sinusoidal tones at 500 and 528 Hz are sounded simultaneously, the perception of these tones includes the experience of a beat frequency of 28 Hz, which manifests as a rhythmic fluctuation in loudness due to the interference of the two sinusoidal waves.
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Eight identical bulbs are connected in series across a 120-V line.
What is the voltage across each bulb?
The voltage across each identical bulb connected in series across a 120-V line is 15 volts.
To find the voltage across each bulb when eight identical bulbs are connected in series across a 120-V line, follow these steps:
1. Determine the total voltage across the series circuit. In this case, it's given as 120 volts.
2. Since the bulbs are identical and connected in series, the total voltage will be divided equally across each bulb.
3. Divide the total voltage by the number of bulbs to find the voltage across each bulb.
So, the voltage across each bulb is 120 V (total voltage) / 8 (number of bulbs) = 15 V.
The voltage across each identical bulb connected in series across a 120-V line is 15 volts.
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The unit for electric field, N/C, can be written equivalently as
The electric field is a physical quantity that describes the strength and direction of the force exerted by an electric charge on other charges. The unit for the electric field is newtons per coulomb (N/C), which can be written equivalently as volts per meter (V/m).
This is because the electric field is related to the potential difference between two points in an electric field by the formula E = V/d, where E is the electric field, V is the potential difference, and d is the distance between the two points.
The unit of potential difference is volts (V), and the unit of distance meters (m), so the unit of electric field can also be expressed in volts per meter.
In summary, the unit for the electric field, N/C, can be written equivalently as V/m and represents the strength of the electric field at a particular point.
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how is focal point and center of curvature related for a spherical mirror?
The focal point and center of curvature of a spherical mirror are related in that they both lie on the mirror's principal axis.
The center of curvature is the center of the sphere from which the mirror was cut. The focal point is the point on the principal axis at which parallel light rays incident on the mirror converge or appear to diverge from after reflection. For a concave mirror, the center of curvature is located in front of the mirror, while the focal point is located between the center of curvature and the mirror. For a convex mirror, the center of curvature is located behind the mirror, while the focal point is located behind the mirror as well.
The relationship between the focal point and center of curvature is important in understanding the behavior of light rays as they interact with spherical mirrors. It allows for the calculation of the mirror's focal length, which is a measure of the mirror's ability to converge or diverge light.
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If vertically polarized light encounters a perfect polarizer and no light is transmitted, what can you conclude?
If vertically polarized light encounters a perfect polarizer and no light is transmitted, you can conclude that the polarizer is oriented horizontally or at a 90-degree angle to the incoming vertically polarized light.
This means that the polarizer is blocking the vertically polarized light from passing through, resulting in no transmitted light.
When compared to other contrast-enhancing techniques like darkfield and brightfield illumination, differential interference contrast, phase contrast, Hoffman modulation contrast, and fluorescence, polarised light produces images of higher quality.
Humans can also sense the polarisation of light, though most of us are ignorant of this ability.
Whether in the air, on Earth's surface, or under the ocean, polarised light is prevalent in natural settings.
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A rigid two-blade wind turbine that is experiencing zero net torque
Entry field with correct answer
is motionless and may be horizontal or tilted.
has a constant angular velocity, which may be zero.
is motionless and horizontal.
has an angular velocity that is gradually decreasing toward zero.
A rigid two-blade wind turbine that is experiencing zero net torque means that the torque produced by the blades is equal to the torque acting on the turbine. In this scenario, the angular velocity of the turbine remains constant, which may be zero. This is because the turbine is not being affected by any external forces and is in a state of equilibrium.
However, if the turbine is left to spin on its own, its angular velocity will gradually decrease towards zero.
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Suppose it is full Moon. What phase of Earth would someone on the Moon see at this time?
-first quarter Earth
-Earth does not go through phases as seen from the Moon.
-full Earth
-new Earth
In a month it will be the next full moon
Explanation:
What is the deBroglie wavelength (in nm) of a neutron (m = 1.67*10-27 kg) moving with a speed of 24 m/s?
The deBroglie wavelength (in nm) of a neutron (m = 1.67*[tex]10^{-27[/tex] kg) moving with a speed of 24 m/s is 165 nm.
The de Broglie wavelength (λ) represents the wave-like behavior of particles and is particularly important in quantum mechanics. It can be calculated using the de Broglie equation:
λ = h / (m*v)
where λ is the de Broglie wavelength, h is the Planck constant (6.626 * [tex]10^{-34[/tex] Js), m is the mass of the particle, and v is its velocity.
In this case, we are given the mass of a neutron (m = 1.67 * [tex]10^{-27[/tex] kg) and its speed (v = 24 m/s). Plugging these values into the de Broglie equation, we get:
λ = (6.626 * [tex]10^{-34[/tex] Js) / ((1.67 * [tex]10^{-27[/tex] kg) * (24 m/s))
After performing the calculation, we find that the de Broglie wavelength is approximately 1.65 * [tex]10^{-10[/tex] meters. To convert this value to nanometers, we multiply by [tex]10^9[/tex] (since 1 meter equals [tex]10^9[/tex] nanometers):
λ ≈ 1.65 * [tex]10^{-10[/tex] meters * [tex]10^9[/tex] nm/meter = 165 nm
Thus, the de Broglie wavelength of a neutron moving at 24 m/s is approximately 165 nm. This demonstrates the wave-particle duality nature of subatomic particles, as the neutron exhibits both particle-like properties (mass and velocity) and wave-like properties (wavelength).
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Light passing from air into a denser transparent medium will
Entry field with correct answer
speed up.
slow down.
not change speed.
Not enough information is given to determine.
When light passing from air into a denser transparent medium will slow down. Hence option B is correct.
When a light is going from medium 1 to medium 2. The refractive index is defined as a ratio of velocity of light in medium 1 to velocity of light in medium 2. Refractive index is the factor which deals with the amount of bending of light. More refractive index means more it will bend in the medium 2. When it is 1 we can say that light has not been bent.
Refractive index is given by,
μ = velocity of the light in vacuum/ velocity of the light in medium.
If the refractive index is greater than one then velocity of light decreases when it goes from rarer medium to denser medium.
Hence option B is correct.
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the pulse strength (amplitude) should be rated on what scale
The pulse strength or amplitude can be rated on a scale of 0-10, with 0 being no pulse felt and 10 being the strongest possible pulse. This scale is commonly used in medical settings to assess the strength and regularity of a patient's pulse.
A weak pulse may indicate a problem with circulation or heart function, while a strong pulse may be a sign of hypertension or other cardiovascular issues. It is important to accurately rate the pulse strength to help diagnose and treat these conditions.
When assessing the pulse, it is important to take into account any factors that may affect the reading, such as the patient's age, physical activity level, or medication use. The pulse should also be evaluated at different points in the body, such as the wrist, neck, or ankle, to ensure an accurate assessment of overall cardiovascular health.
Overall, the pulse strength scale is a useful tool for healthcare providers to quickly and accurately assess a patient's cardiovascular function and detect any potential problems that may require further evaluation or treatment.
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T/F If a body starts with zero velocity and ends with zero velocity, then the total change in momentum is zero.
True, if a body starts with zero velocity and ends with zero velocity, then the total change in momentum is zero.
1. Momentum is the product of an object's mass (m) and its velocity (v). It can be represented by the equation: momentum = m * v.
2. If an object starts with zero velocity (v_initial = 0), its initial momentum will be: momentum_initial = m * 0 = 0.
3. Similarly, if an object ends with zero velocity (v_final = 0), its final momentum will be: momentum_final = m * 0 = 0.
4. Change in momentum is the difference between final momentum and initial momentum: Δmomentum = momentum_final - momentum_initial.
5. Since both initial and final momenta are zero, the total change in momentum is: Δmomentum = 0 - 0 = 0.
Therefore, it is true that if a body starts with zero velocity and ends with zero velocity, the total change in momentum is zero.
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a worker pushes a crate with a force of 46 n over a 5.0-m horizontal surface. if a frictional force of 9 n acts on the cart in a direction opposite to that of the worker, what is the net work done on the cart?
The net work done on the cart is 185 J.
To calculate the net work done on the cart, we need to first calculate the
work done by the worker and the work done by friction.
The work done by the worker is given by the formula:
W1 = F1 × d × cos(theta)
where F1 is the force applied by the worker, d is the distance over which
the force is applied, and theta is the angle between the force and the
displacement. In this case, the force and displacement are in the same
direction, so theta = 0, and we have:
W1 = F1 × d = 46 N × 5.0 m = 230 J
The work done by friction is given by the formula:
W2 = F2 × d × cos(theta)
where F2 is the force of friction, d is the distance over which the force is
applied, and theta is the angle between the force and the displacement.
In this case, the force of friction is in the opposite direction to the
displacement, so theta = 180 degrees, and we have:
W2 = F2 × d × cos(180 degrees) = -9 N × 5.0 m × cos(180 degrees) = -45 J
Note that the negative sign indicates that the work done by friction is in
the opposite direction to the displacement.
The net work done on the cart is the sum of the work done by the
worker and the work done by friction:
Wnet = W1 + W2 = 230 J - 45 J = 185 J
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for most materials, electrical conductivity only depends on the overall mobility of free electrons. question 2 options: true false
The statement "electrical conductivity only depends on the overall mobility of free electrons" is True because how rapidly and easily these electrons can travel through a material in response to an electric field determines the substance's electrical conductivity. .
Electrical conductivity in most materials is primarily determined by the mobility of free electrons, which refers to how easily and quickly these electrons can move through the material in response to an electric field.
Other factors such as the density of free electrons and the presence of impurities or defects can also affect conductivity, but mobility is a key factor.
Therefore, the statement electrical conductivity only depends on the overall mobility of free electrons is true.
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A proton is released at the origin in a constant electric field of 850 N/C acting in the positive x-direction. Find the change in the electric potential energy associated with the proton after it travels to x = 2.5 m. (a) 3.4 times 10^-16 (b) -3.4 times 10^-16 J (c) 2.5 times 10^-16 J (d) -2.5 times 10^-16 J (e) -1.6 times 10^-16 J
The change in electric potential energy (ΔPE) associated with the proton can be calculated using the equation ΔPE = qΔV, where q is the charge of the proton and ΔV is the change in electric potential.
Since the electric field is constant, the change in electric potential from the origin to x = 2.5 m is given by ΔV = Ed, where E is the electric field strength and d is the distance traveled by the proton. In this case, d = 2.5 m - 0 m = 2.5 m, and E = 850 N/C. Therefore, ΔV = (850 N/C)(2.5 m) = 2125 J/C.
The charge of a proton is q = +1.6 x 10^-19 C. Thus, ΔPE = (1.6 x 10^-19 C)(2125 J/C) = 3.4 x 10^-16 J.
Therefore, the answer is (a) 3.4 times 10^-16 J.
The change in electric potential energy (ΔU) can be calculated using the formula ΔU = -qEx, where q is the charge of the proton, E is the electric field, and x is the distance traveled in the field's direction.
For a proton, the charge q = 1.6 × 10^-19 C. Given E = 850 N/C and x = 2.5 m, we can find ΔU:
ΔU = - (1.6 × 10^-19 C) (850 N/C) (2.5 m) = -3.4 × 10^-16 J
The answer is (b) -3.4 times 10^-16 J.
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Your client does 10 repetitions of a front squat with 80kg (~785N) The distance from the top of the squat to the bottom of the squat is 1m. How much work did she perform?
To calculate the work performed by your client during the 10 repetitions of a front squat with 80kg (~785N), we need to use the formula for work:
Work = Force x Distance x cos(θ).
In this case, θ is the angle between the force and the distance, which is 0 degrees because the force is applied vertically, and the distance is also vertical.
Step 1: Convert the angle to radians.
θ = 0 degrees = 0 radians
Step 2: Calculate the cosine of the angle.
cos(θ) = cos(0 radians) = 1
Step 3: Calculate the work for one squat.
Work = Force x Distance x cos(θ) = 785N x 1m x 1 = 785 J (Joules)
Step 4: Calculate the work for 10 repetitions.
Total Work = Work per squat x Number of repetitions = 785 J x 10 = 7850 J
So, your client performed 7850 Joules of work during the 10 repetitions of a front squat with 80kg (~785N) and a 1m distance from the top to the bottom of the squat.
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A 3.1 kg object moving at 5.9 m/s in the positive direction of an x axis has a one-dimensional elastic collision with an object of mass M, initially at rest. After the collision the object of mass M has a velocity of 3.9 m/s in the positive direction of the x axis. What is mass M?
The mass of the second object is 6.2 kg.
The initial momentum of the system is:
[tex]p1 = m1 * v1 = (3.1 kg) * (5.9 m/s) = 18.29 kg m/s[/tex]
The final momentum of the system is:
[tex]p2 = m1 * v1' + m2 * v2'[/tex]
Since momentum is conserved, we can set p1 = p2:
[tex]m1 * v1 = m1 * v1' + m2 * v2'[/tex]
We can solve for v1' by isolating it on one side of the equation:
[tex]v1' = (m1 * v1 - m2 * v2') / m1[/tex]
Now we can use the conservation of kinetic energy to solve for m2. The initial kinetic energy of the system is:
[tex]KE1 = (1/2) * m1 * v1^2[/tex]
The final kinetic energy of the system is:
[tex]KE2 = (1/2) * m1 * v1'^2 + (1/2) * m2 * v2'^2[/tex]
Since the collision is elastic, the kinetic energy is conserved, so KE1 = KE2:
[tex](1/2) * m1 * v1^2 = (1/2) * m1 * v1'^2 + (1/2) * m2 * v2'^2[/tex]
Substituting in the expression for v1' that we found earlier, we get:
[tex](1/2) * m1 * v1^2 = (1/2) * m1 * [(m1 * v1 - m2 * v2') / m1]^2 + (1/2) * m2 * v2'^2[/tex]
Simplifying, we get:
[tex]m2 = (m1 * (v1 - v2')) / (v2' - v1)[/tex]
Plugging in the values we know, we get:
[tex]m2 = (3.1 kg * (5.9 m/s - 3.9 m/s)) / (3.9 m/s - 5.9 m/s) = 6.2 kg[/tex]
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In a simple DC circuit, the resistance is held constant while the applied voltage is halved. What will be the effect on the current flow as compared to the original current?A) doubleB) be divided by fourC) remain the sameD) be divided by two
In a simple DC circuit, the relationship between voltage, current, and resistance is given by Ohm's law:
V = IR
where V is the voltage, I is the current, and R is the resistance.
If the resistance is held constant while the applied voltage is halved, we can use Ohm's law to determine the effect on the current flow.
Let's assume the original voltage and current are V1 and I1, respectively, and the new voltage is V2 = V1/2.
Using Ohm's law, we can rewrite the original equation as:
I1 = V1/R
Similarly, for the new voltage, we can write:
I2 = V2/R
Substituting V2 = V1/2 into the second equation, we get:
I2 = (V1/2)/R
I2 = V1/(2R)
Therefore, the new current (I2) is half of the original current (I1). In other words, the current is divided by two when the applied voltage is halved while the resistance is held constant.
Hence, the correct answer is (D) the current will be divided by two.
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a neon sign, that requires an rms voltage of 11000v, is plugged into the wall outlet at 120 v rms. if there are 100 turns in the primary coils for the transformer, how many turns are in the secondary? the power output of the sign is 800 w.
If there are 100 turns in the primary coils for the transformer, there are approximately 9167 turns in the secondary coil.
To find the number of turns in the secondary coil, we can use the transformer equation:
Vp/Vs = Np/Ns
where Vp is the voltage in the primary coil, Vs is the voltage in the secondary coil, Np is the number of turns in the primary coil, and Ns is the number of turns in the secondary coil.
First, we need to find the voltage in the secondary coil. We can use the power output of the sign and the voltage in the primary coil to calculate the current:
P = IV
where P is the power output, I is the current, and V is the voltage. Rearranging the equation, we get:
I = P/Vp
Substituting the values given in the question, we get:
I = 800/120 = 6.67 A
Next, we can use the current and the voltage in the secondary coil to find the number of turns:
Vs = Vp(Ns/Np)
Ns = (Vs/Vp)Np
Substituting the values given in the question, we get:
11000 = 120(Ns/100)
Ns = (11000/120)100
Ns = 9166.67
Rounding to the nearest whole number, we get:
Ns = 9167
Therefore, there are approximately 9167 turns in the secondary coil.
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You are driving home from school steadily at 98 km/h for 160 km . It then begins to rain and you slow to 63 km/h instantly. You arrive home after driving 4.5 hours.a. How far is your hometown from school?b. What was your average speed?
a) The distance between school and home is 254.5 km.
b) The average speed for the entire trip is 56.6 km/h.
To answer this question, we need to use the formula: Distance = Speed x Time.
a. We know that the distance driven at a steady speed of 98 km/h is 160 km. We also know that the total time spent driving is 4.5 hours.
To find the distance between school and home, we can subtract the distance driven at 98 km/h from the total distance driven.
Distance driven at 63 km/h = (4.5 hours - time driven at 98 km/h) x 63 km/h
Distance driven at 63 km/h = 1.5 hours x 63 km/h
Distance driven at 63 km/h = 94.5 km
Total distance driven = Distance driven at 98 km/h + Distance driven at 63 km/h
Total distance driven = 160 km + 94.5 km
Total distance driven = 254.5 km
b. To find the average speed, we can use the formula: Average speed = Total distance / Total time
Average speed = 254.5 km / 4.5 hours
Average speed = 56.6 km/h (rounded to one decimal place)
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