a researcher divided subjects into groups according to gender and then selected memebrs from each group for her sample. what sampling method was the researcher using?

The point- slope form of the line is y-5 = -0.25(x+6).

What is line?

A line is an one-dimensional figure. It has length but no width. A line can be made of a set of points which is extended in opposite directions to infinity. There are straight line, horizontal, vertical lines or may be parallel lines perpendicular lines etc.

A line with a slope of –1/4 passes through the point (–6,5)

Any line in point - slope form can be written as

y - y₁= m(x -x₁) -------(1)

where,

y= y coordinate of second point

y₁ = y coordinate of first point

m= slope of the line

x= x coordinate of second point

x₁ = x coordinate of first point

In the given problem (x₁ , y₁) = (-6,5) and m= -1/4

Putting all these values in equation (1) we get,

y-5= (-1/4) (x- (-6))

⇒ y-5 = -0.25(x+6)

Hence, the point- slope form of the line is y-5 = -0.25(x+6).

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Answer:

12.4 ft

Step-by-step explanation:

a² + b² = c²

4² + h² = 13²

16 + h² = 169

h² = 169 - 16

h² = 153

h = 12.369316

Answer: 12.4 ft

Answer:

12.4 ft

Step-by-step explanation:

4² + h² = 13²

h² = 13² - 4² = 169 - 16 = 153

h = √153 ≈ 12.37 ft ≈ 12.4 ft

$ 27,255.25 would be the accumulated value at the interest rate of 4.73% compounded monthly.$ 25,334 would be the accumulated value at the interest rate of 4.73% compounded semi-annually. $1921.25 is the amount that much more interest if he chose the monthly compounding interest rate instead of the semi-annually.

Compound interest is calculated as follows:

A = P [tex](1+\frac{r}{n} )^{nt[/tex]

where A is the amount

P is the principal

r is the rate in decimal

n is the frequency of time interest is compounded

t is the time

a. P = $13,250

r = 4.73% or 0.0473

n = 12 since compounded monthly

t = 15 years

A = 13250  [tex](1+\frac{0.0473}{12})^{12*15[/tex]

= 13250 [tex](1.004)^{180[/tex]

= 13250 * 2.051

= $ 27,255.25

b. P = $13,250

r = 4.73% or 0.0473

n = 2 since compounded semi-annually

t = 15 years

A = 13250  [tex](1+\frac{0.0473}{2})^{2*15[/tex]

= 13250 [tex](1.02185)^{30[/tex]

= 13250 * 1.912

= $ 25,334

c. Difference between the interest in semi-annual and monthly compounded = 27,255.25 - 25,334

= $1921.25

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The marginal revenue at a quantity of 900 lbs is $50. The Skagway Coffee Company can sell 900 lbs of its premium blend coffee.

To determine the price at which the Skagway Coffee Company can sell 900 lbs of its premium blend coffee, we need to solve the demand equation for price when quantity is 900:

900 = 800 + 25√p

Simplifying this equation, we get:

100 = 25√p

Squaring both sides, we get:

10000 = 625p

Solving for p, we get:

p = 16

Therefore, the price at which the Skagway Coffee Company can sell 900 lbs of its premium blend coffee is $16.

To determine the revenue at this quantity, we can simply multiply the price by the quantity:

revenues = $16 x 900 = $14,400

To determine the marginal revenue at this quantity, we need to take the derivative of the demand equation with respect to quantity, and then evaluate it at the quantity of 900. The derivative of the demand equation is:

[tex]dq/dp[/tex] = 25/(2√p)

Substituting p = 16, we get:

[tex]dq/dp[/tex] = 25/(2√16) = 25/8

Multiplying this by the price of $16, we get:

marginal revenue = (25/8) x $16 = $50

Therefore, the marginal revenue at a quantity of 900 lbs is $50.

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The  correct choice is:

A(BC) =

-722 -164

-184 -72

We solve the matrix operation A(BC) as follows:

BC =

4(9) + (-2)(-2) + (-6)(-1) 4(8) + (-2)(-4) + (-6)(-2)

1(9) + 9(-2) + (-4)(-1) 1(8) + 9(-4) + (-4)(-2)

BC =

46 44

-15 -34

we then multiply A with BC as follows:

A(BC) =

-7 -8

-4 4

×

46 44

-15 -34

=

((-7)(46) + (-8)(-15)) ((-7)(44) + (-8)(-34))

((-4)(46) + (4)(-15)) ((-4)(44) + (4)(-34))

=

-722 -164

-184 -72

In a matrix multiplication, the number of columns in the first matrix must be equal to the number of rows in the second matrix.

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Substituting these values into the chain rule formula, we get:
[tex]h'(x) = 2g(e) * 9(2)cos(e) * We * a[/tex]
Without knowing the values of g(e) and a, we cannot find the value of h'(x).

a) To decide the function h(x), we need to know the values of g(e) and a. Unfortunately, those values are not given in the question. Without that information, we cannot determine the function h(x).

b) To derive h(x), we need to use the chain rule. Recall that the chain rule states that the derivative of a composition of functions is equal to the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function. In other words:

[tex]h'(x) = f'(g(e)) * g'(e) * e'(x) * a[/tex]
Now, we need to find the derivatives of each of the functions involved.

f'(x) = 2x (by the power rule)
g'(e) = 9(2)cos(e) (by the chain rule and the derivative of sin(x) = cos(x))
e'(x) = We (given in the question)

Substituting these values into the chain rule formula, we get:

[tex]h'(x) = 2g(e) * 9(2)cos(e) * We * a[/tex]

Without knowing the values of g(e) and a, we cannot find the value of h'(x).

The complete question is-

Given the function , h(x) = f(g(e))a) Decide the function h(x) if f (x) = x2 – 1 and 9(2) sin(x) + 1 b) Derive h(x) T We and decide the value for derivative of h(x).

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The number of baseball teams of nine members that can be chosen from among twelve boys, without regard to the position played by each member is 220.

To solve this problem, we need to use the combination formula. The formula is:
nCr = n / r(n-r)
where n is the total number of items, r is the number of items we want to choose,
In this case, we have 12 boys and we want to choose a team of 9. So we have:
n = 12
r = 9
Plugging these values into the formula, we get:

12C9 = 12 / 9(12-9)
         = (12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4) / (9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1)
         = 220
Therefore, there are 220 ways to choose a baseball team of nine members from among twelve boys, without regard to the position played by each member.

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The function f(x+4) = 3^(x+4) - 4 is shifted 4 units to the left compared to g(x) = 3^x. f(x) - 4 = 3^x - 8 is shifted 4 units down compared to g(x) = 3^x. f(x) + 4 = 3^x is the same as g(x) = 3^x, but shifted 4 units up. f(x-4) = 3^(x-4) - 4 is shifted 4 units to the right compared to g(x) = 3^x.

To compare the functions f(x) = 3^x - 4 and g(x) = 3^x, we need to evaluate the difference between the two functions for different values of x. To shift the function f(x) four units to the left, we substitute x + 4 for x in the function. Therefore, f(x+4) = 3^(x+4) - 4.

To shift the function f(x) four units down, we subtract 4 from the function. Therefore, f(x) - 4 = 3^x - 8. To shift the function f(x) four units up, we add 4 to the function. Therefore, f(x) + 4 = 3^x. To shift the function f(x) four units to the right, we substitute x - 4 for x in the function. Therefore, f(x-4) = 3^(x-4) - 4.

In general, shifting a function left or right involves replacing x with x + a or x - a, respectively, where a is the amount of the shift. Shifting a function up or down involves adding or subtracting a constant from the function, respectively.

In each case, we can see that the function f(x) is different from the basic function g(x) due to a shift and/or a vertical translation.

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The indefinite integral of S(3t²+t/4)dt is t³ + t²/8 + C, where C is the constant of integration. An antiderivative of a function is the function's indefinite integral.

In other words, if we take the derivative of the indefinite integral, we get back the original function (up to a constant of integration). We can utilise the integration rules to integrate each term individually in order to determine the indefinite integral of S(3t²+t/4)dt. Specifically, we can apply the power rule of integration and the constant multiple rule.

∫ 3t² + t/4 dt

= 3 ∫ t² dt + 1/4 ∫ t dt

= 3 (t³/3) + 1/4 (t²/2) + C

= t³ + t²/8 + C

Therefore, the indefinite integral of S(3t²+t/4)dt is t³ + t²/8 + C, where C is the constant of integration. Note that when we take the derivative of this function with respect to t, we get 3t² + t/4, which is the original function. The constant of integration represents a family of functions that differ by a constant, and is necessary because the derivative of a constant is zero.

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(a) The left-hand sum estimate for the integral is 1.214

(b) The right-hand sum estimate is 1.642, both rounded to three decimal places.

(a) To estimate the integral of eˣ using n=5 rectangles with left-hand sum and right-hand sum, we will first find the width of each rectangle (Δx) and then calculate the area of the rectangles using the function values.

Step 1: Calculate Δx
Δx = (b-a)/n = (1-0)/5 = 0.2

Step 2: Calculate the left-hand sum (LHS)
LHS = Δx * (f(x0) + f(x1) + f(x2) + f(x3) + f(x4))
LHS = 0.2 * ([tex]e^0+e^0^.^2+e^0^.^4+e^0^.^6+e^0^.^8[/tex])

LHS ≈ 1.214

(b) Step 3: Calculate the right-hand sum (RHS)
RHS = Δx * (f(x1) + f(x2) + f(x3) + f(x4) + f(x5))
RHS = 0.2 * ([tex]e^0+e^0^.^2+e^0^.^4+e^0^.^6+e^0^.^8[/tex])
RHS ≈ 1.642

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Answer:

the correct is D the graph is a decreasing function

Using logarithmic differentiation the derivative of the function [tex]y'(x) = (ln(x))cos(6x) * [(-6sin(6x) * ln(ln(x))) + (cos(6x) * (1/x) * (1/ln(x)))][/tex]

Here's the function and the terms we'll be using:

Function:[tex]y = (ln(x))cos(6x)[/tex]

Terms: logarithmic differentiation, derivative

Step 1: Apply logarithmic differentiation by taking the natural logarithm (ln) of both sides of the equation.
[tex]ln(y) = ln((ln(x))cos(6x))[/tex]

Step 2: Simplify the right side of the equation using the properties of logarithms.
[tex]ln(y) = cos(6x) * ln(ln(x))[/tex]

Step 3: Differentiate both sides of the equation with respect to x using implicit differentiation.
[tex](d/dx) ln(y) = (d/dx) [cos(6x) * ln(ln(x))][/tex]

Step 4: Use the product rule on the right side of the equation. The product rule states that (uv)' = u'v + uv'.
[tex]y' / y = (-6sin(6x) * ln(ln(x))) + (cos(6x) * (1/x) * (1/ln(x)))[/tex]

Step 5: Multiply both sides of the equation by y to isolate y'.
[tex]y'(x) = y * [(-6sin(6x) * ln(ln(x))) + (cos(6x) * (1/x) * (1/ln(x)))][/tex]

Step 6: Substitute the original function y = (ln(x))cos(6x) back into the equation.
[tex]y'(x) = (ln(x))cos(6x) * [(-6sin(6x) * ln(ln(x))) + (cos(6x) * (1/x) * (1/ln(x)))][/tex]

That's your final answer for the derivative of the given function using logarithmic differentiation.

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Our general solution is  y = c1e((-3 + √(13))/2)t + c2e((-3 - √(13))/2)t  where c1 and c2 are constants determined by initial or boundary conditions.

To find the general solution to this differential equation, we first need to find the characteristic equation by assuming that y = e(rt) and substituting it into the equation.

So we have y" + 3y' - y = 0
Substituting y = e(rt) we get
r² e(rt) + 3r e(rt) - e(rt) = 0

Dividing by e^(rt) we get
r² + 3r - 1 = 0

Now we solve for r by using the quadratic formula:
r = (-3 ± √(3² - 4(1)(-1))) / (2(1))
r = (-3 ± √(13)) / 2

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95% confidence that the average number of words typed by all graduates of the secretarial school is between 78.03 and 89.17 words per minute.

The 95% confidence interval for the average number of words typed by all graduates of the secretarial school, we can use the formula:

[tex]CI = \bar X \± t\alpha/2 \times (s/\sqrt n)[/tex]

[tex]\bar X[/tex]is the sample mean, s is the sample standard deviation, n is the sample size,[tex]t\alpha /2[/tex] is the t-score with (n-1) degrees of freedom and a probability of [tex](1-\alpha/2)[/tex] in the upper tail.

95% confidence interval, [tex]\alpha = 0.05[/tex], so [tex]\alpha/2 = 0.025[/tex]. We can look up the t-score with 10 degrees of freedom.

[tex](n-1 = 11-1 = 10)[/tex] and a probability of 0.025 in the upper tail in a t-table or calculator.

The value is approximately 2.228.

Plugging in the values from the problem, we get:

[tex]CI = 83.6 \± 2.228 \times (7.2/\sqrt {11})[/tex]

[tex]CI = 83.6 \± 5.57[/tex]

[tex]CI = (78.03, 89.17)[/tex]

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Using cylindrical coordinates,

(a) The volume of the region E is 96π/5 units.

(b) The centroid of E is (0, 0, 24/5) units.

For part (a), we first need to find the limits of integration. Since the paraboloid and the cone intersect at z = 16, we have the limits of integration for z as 2√(x² + y²) ≤ z ≤ 48 - x² - y². For ρ, we have 0 ≤ ρ ≤ 2z/√(2) = z√2, and for θ, we have 0 ≤ θ ≤ 2π. Thus, the integral to find the volume is:

V = ∫∫∫ E dV = ∫∫∫ zρ dz dρ dθ

where E is the region given in the problem. Evaluating this integral gives V = (256/15)π.

For part (b), we use the formulas for the centroid in cylindrical coordinates:

x = (1/M) ∫∫∫ E ρ cosθ z dV

y = (1/M) ∫∫∫ E ρ sinθ z dV

z = (1/2M) ∫∫∫ E (ρ² - z²) dV

where M is the mass of the solid. Since the density is constant, M is proportional to the volume, so we can find the centroid by evaluating the integrals without dividing by M. Evaluating these integrals gives (x, y, z) = (0, 0, 16/5).

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Use cylindrical coordinates.

(a) Find the volume of the region E that lies between the paraboloid z = 48 - x² - y² and the cone z = 2 √(x² + y²).

(b) Find the centroid of E (the center of mass in the case where the density is constant) (x, y, z) = ______.

The interval of convergence for the power series is (2-1/2, 2+1/2), or (3/2, 5/2).

Hence, the interval of convergence of the given power series is (3/2, 5/2).

To find the interval of convergence of the given power series:

We will first apply the Ratio Test:

[tex]|(-8)^{n+1} (x-2)^{3(n+1)} (n+1)^2 + 1| |(-8)^n (x-2)^{3n} (n^2 + 1)|[/tex]

___________________ = lim ____________________________________

[tex]|(-8)^n (x-2)^{3n} (n^2 + 1)| |(-8)^{n+1} (x-2)^{3(n+1)} (n+1)^2 + 1|[/tex]

Simplifying this expression, we get:

[tex]lim |(-8)(x-2)^3(n+1)^2 + 1|/(n^2+1)[/tex]

As n approaches infinity, the [tex](n+1)^2[/tex]  term in the numerator becomes dominant, so the limit simplifies to:

[tex]lim |-8(x-2)^3(n+1)^2|/n^2[/tex]

[tex]= 8|(x-2)|^3 lim (n+1)^2/n^2[/tex]

Using the limit properties, we can simplify the above limit to:

[tex]8|(x-2)|^3 lim (1 + 1/n)^2[/tex]

As n approaches infinity, the term [tex](1/n)^2[/tex] becomes negligible and the limit simplifies to:

[tex]8|(x-2)|^3 lim 1 = 8|(x-2)|^3[/tex]

Thus, the series converges absolutely if[tex]8|(x-2)|^3[/tex] < 1.

Solving the above inequality for x, we get:

[tex]|8(x-2)^3|[/tex] < 1

Taking the cube root of both sides, we get:

| x - 2 | < 1/2.

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The expression that would result in a rational number would be C ( 5  1/9 ) ( - 0. 3 bar ) .

The laws of maths state that when two rational numbers multiply themselves, the result would be a rational number. We can therefore check if these numbers are rational.

Convert the mixed fraction (5 1/9) to an improper fraction:

5 1/9 = (5 x 9 + 1) / 9 = 46 / 9

This is an improper fraction.

- 0. 3 bar in fraction form is :

= - 1 / 3

It is rational.

This therefore means that ( 5  1/9 ) ( - 0. 3 bar ) gives a rational number.

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The probability that the time until the first critical-part failure is less than 1 year is 0.2548. So the correct answer is (D) 0.254811.

Given that the time until the first critical part failure for a certain car is exponentially distributed with a mean of 3.4 years.

f(t) = λe^(-λt)

where λ is the rate parameter and is equal to 1/mean = 1/3.4 = 0.2941.

To find the probability that the time until the first critical-part failure is less than 1 year, we need to calculate the cumulative distribution function (CDF) of the exponential distribution up to 1 year:

F(1) = ∫[0,1] λe^(-λt)dt

Using integration by substitution, let u = λt, then du/dt = λ and dt = du/λ.

F(1) = ∫[0,λ] e^(-u)du

= [-e^(-u)]_[0,λ]

= -e^(-λ) + e^(-0)

= 1 - e^(-0.2941 * 1)

= 0.2548 (rounded to four decimal places)

Therefore, the likelihood that the period until the first critical-part failure is less than 1 year is 0.2548. So the correct answer is (D) 0.254811.

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The value of the integral is 512/15. To evaluate the integral S4 0 (4-t)√t dt, we can use integration by substitution. Let u = √t, then du/dt = 1/(2√t), which implies that dt = 2u du.

Substituting u = √t and dt = 2u du, the integral becomes:

S4 0 (4-t)√t dt = S4 0 (4-t) u * 2u du = 2 S2 0 (4-u²) u² du

Now, we can expand the integrand and integrate term by term:

2 S2 0 (4-u²) u² du = 2 [∫4 0 u² du - ∫4 0 u⁴ du]

= 2 [(u³/3) |4 0 - (u⁵/5) |4 0]

= 2 [(64/3 - 64/5) - (0 - 0)]

= 2 [(320/15) - (64/15)]

= 2 [(256/15)]

= 512/15

Therefore, the value of the integral is 512/15.

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The correct interpretation of the 95% confidence interval (-0.223, 0.988) for the mean yield difference between Silver Queen and Country Gentlemen corn varieties is that we can be 95% confident that the true mean difference in yield (Silver Queen - Country Gentlemen) falls within this range.

This means that, on average, Silver Queen could yield anywhere from 0.223 units less to 0.988 units more than Country Gentlemen with a 95% level of confidence.

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To find the total cost of producing 42 units, we will consider both the fixed costs and the variable costs. Since the marginal cost (MC) is given as $170.017 per unit, we can calculate the variable costs by multiplying MC by the number of units produced.

Variable costs = MC × Number of units = 170.017 × 42 = $7,140.714
Now, we'll add the fixed costs to the variable costs to get the total cost:
Total cost = Fixed costs + Variable costs = $3,350 + $7,140.714 = $10,490.714
Rounding to the nearest cent, the total cost of producing 42 units is $10,490.71.

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The difference between the linear and projectile motion is that "Linear-motion" refers to motion of object in a "straight-line", while "projectile-motion" refers to motion of an object that is thrown into air, in a curved path.

In linear motion, the object moves along a straight line, with its velocity and acceleration aligned in the same direction. The object's speed and direction may change, but its motion remains linear.

In projectile motion, the object moves along a curved path under the influence of gravity. The object is launched into the air with an initial velocity, and then gravity causes it to follow a parabolic path until it lands back on the ground. The motion of the object is influenced by both its initial velocity and the force of gravity.

In both linear and projectile motion, the "horizontal-component" of velocity will usually remain constant because there is no external force acting on the object in horizontal direction, and thus no acceleration.

Therefore, the object will continue to move at a constant velocity in the horizontal direction, as long as there is no external force acting on it.

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The first four terms of the sequence are 3, 10, 31, and 94.

To find the first four terms of the sequence defined by [tex]a_1 = 3[/tex] and [tex]a_n = 3a_{n-1} + 1[/tex] for all n > 1, follow these steps:

1. The first term is given: [tex]a_1 = 3.[/tex]
2. Use the formula to find the second term: [tex]a_2 = 3a_1 + 1 = 3(3) + 1 = 9 + 1 = 10.[/tex]
3. Use the formula to find the third term: [tex]a_3 = 3a_2 + 1 = 3(10) + 1 = 30 + 1 = 31.[/tex]
4. Use the formula to find the fourth term: [tex]a_4 = 3a_3 + 1 = 3(31) + 1 = 93 + 1 = 94.[/tex]

So, the first four terms of the sequence are 3, 10, 31, and 94.

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Assuming an interest rate of 5% per year, the deposit amount required today to provide the annuity is approximately $49,019.15.

To calculate the present value of the annuity, we can use the formula for the present value of an annuity:

PV = PMT x [1 - (1 + r)⁻ⁿ] / r

Where:

PV = Present value

PMT = Payment amount per period

r = Interest rate per period

n = Total number of periods

For the first two years, Piers will receive $1,000 at the end of each month, for a total of 24 payments. Using the formula above, we can calculate the present value of these payments:

PV1 = $1,000 x [1 - (1 + r)⁻²⁴] / r

For the next three years, Piers will receive $500 at the end of each month, for a total of 36 payments. Using the same formula, we can calculate the present value of these payments:

PV2 = $500 x [1 - (1 + r)⁻³⁶] / r

The total present value of the annuity is the sum of PV1 and PV2:

Total PV = PV1 + PV2

Total PV = 24,019+25,000.15 = $49,019.15.

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The given improper integral diverges.

We can use the integral test to determine if the improper integral converges or diverges.

Consider the function f(x) = x^2 ln(x).

Taking the derivative of f(x), we get:

f'(x) = 2x ln(x) + x

Setting f'(x) = 0 to find the critical points, we get:

2 ln(x) + 1 = 0

ln(x) = -1/2

x = e^(-1/2)

Note that f(x) is positive and decreasing for x > e^(-1/2). Therefore, we have:

∫1 [infinity] In(x) /x^2 dx = ∫e^(-1/2) [infinity] x^2 ln(x) /x^2 dx

= ∫e^(-1/2) [infinity] ln(x) dx

Since ln(x) is an increasing function, we know that:

∫e^(-1/2) [infinity] ln(x) dx is divergent by the integral test.

Therefore, the original improper integral:

∫1 [infinity] In(x) /x^2 dx

is also divergent by comparison to the divergent integral.

In conclusion, the given improper integral diverges.

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The series diverges and the nth term test is used to identify the divergence.

It looks like there is a typo in the series.

The series should have a common difference between terms.

Assuming that the series is:

31 + 61 + 91 + ... + (30n+1)

We can use the nth term test to determine the convergence of the

series.

The nth term of the series is given by:

an = 30n + 1

As n goes to infinity, the dominant term in the nth term expression is

30n.

Therefore, the series diverges since the nth term does not approach

zero.

Hence, the series diverges and the nth term test is used to identify the

divergence.

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Answer:

8i + 34j

Step-by-step explanation:

[tex]4v - 2w \\ 4(5i + 4j) - 2(6i - 9j) \\ 20i + 16j - 12i + 18j \\ 20i - 12i + 16j + 18j \\ 8i + 34j[/tex]

The differentiation value of F(1) by evaluating the function of definite integral denoted by F(x) for F(x) = d/dx(Sx⁴ 0 2t³dt) is 8.

To find F(x), we first integrate 2t³ with respect to t to get t⁴, and then substitute the limits of integration to obtain 2x⁴.

F(x) = d/dx(Sx⁴ 0 2t³dt)

F(x) = d/dx [[tex](2x^3)^4[/tex] - [tex](0)^4[/tex]] / 4

Next, we differentiate 2x⁴ with respect to x to obtain F(x) = 8x³.

F(x) = 8x³

To find F(1), we substitute x = 1 in F(x) to get F(1) = 8(1)³ = 8.

F(1) = 8(1)³

F(1) = 8

Therefore, the value of F(1) is 8.

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