an entrepreneur is considering the purchase of a coin-operated laundry. the current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75. a sample of 30 days reveals daily revenue of $625.if you were to test the null hypothesis that the daily average revenue was $675, which test woulduse?

If from 1950 to 1990 the population of Country W increased by 40 percent, From 1990 to 2012 the population of Country W increased by 10 percent, population of Country W increased by 54% from 1950 to 2012.

To find the percent increase in the population of Country W from 1950 to 2012, we can use the following formula:

percent increase = [(new value - old value) / old value] x 100

Let P1 be the population in 1950, P2 be the population in 1990, and P3 be the population in 2012.

From the problem, we know that:

P2 = 1.4P1 (since the population increased by 40% from 1950 to 1990)

P3 = 1.1P2 (since the population increased by 10% from 1990 to 2012)

Substituting the first equation into the second equation, we get:

P3 = 1.1(1.4P1) = 1.54P1

Therefore, the percent increase in the population from 1950 to 2012 is:

[(P3 - P1) / P1] x 100

= [(1.54P1 - P1) / P1] x 100

= 54%

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Check the picture below.

[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2 \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{13}\\ a=\stackrel{adjacent}{s}\\ o=\stackrel{opposite}{s} \end{cases} \\\\\\ (13)^2= (s)^2 + (s)^2\implies 13^2=2s^2\implies \cfrac{13^2}{2}=s^2 \\\\\\ \sqrt{\cfrac{13^2}{2}}=s\implies \cfrac{\sqrt{13^2}}{\sqrt{2}}=s\implies \cfrac{13}{\sqrt{2}}=s[/tex]

Answer:

[tex]\frac{13 \sqrt{2} }{2}[/tex]  OR 9.19

Step-by-step explanation:

hypotenuse =[tex]\sqrt{2}[/tex] * leg

13 = [tex]\sqrt{2}[/tex] * s

[tex]\frac{13 \sqrt{2} }{2}[/tex]

OR (using pythagorean theorem)

[tex]13^{2}[/tex] = 169

169 / 2 = 84.5

[tex]\sqrt{84.5}[/tex] = 9.19

The product of 4 and the sum of a number and 12 is at most 18 can be written as

4(x+12)<=18

or

x+12<=4.5

or

x<=-7.5

Therefore, the value of x can be at most -7.5.

The slope and y-intercept of the line is equal to 1.33 and 2 respectively..

The equation is equal to,

Y = 1.33X + 2,

Age of the dog represented by x-axis

Weight in pounds represented by y-axis.

Standard form of the equation with slope 'm' and y-intercept 'c' is written as,

y = mx + c

Compare both the equations we get,

The number next to X is 1.33 is the slope of the line.

That represents how much the Y variable that is weight changes for each unit increase in the X variable age.

Here, the slope of 1.33 indicates that for each additional year in age,

The weight of the dog increases by an average of 1.33 pounds.

The number that is added to the slope = 2.

It is the y-intercept of the line, the value of Y when X is equal to 0.

It means that when the dog is born age = 0.

Its weight is estimated to be 2 pounds.

Therefore, the slope of the line is 1.33 and the y-intercept is 2.

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The value of the given integral is approximately 1665.02.

We have,

To use the transformation u = 4x + 3y, v = x + 2y, we need to express x and y in terms of u and v. Solving for x and y, we get:

x = (2v - u)/5

y = (3u - 4v)/5

We also need to find the Jacobian of the transformation:

J = ∂(x,y)/∂(u,v) = (1/5) [(∂x/∂u)(∂y/∂v) - (∂y/∂u)(∂x/∂v)]

= (1/5) [(2/5)(3/5) - (1/5)(1/5)] = 6/25

Now we can evaluate the integral using the new variables:

∬R (3x + 11xy + 6y²) dA = ∬D (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) (6/25) dudv

where D is the region in the uv-plane that corresponds to R in the xy-plane. We need to find the limits of integration for u and v in terms of x and y.

From the equations of the lines that bound R, we can find the vertices of D:

(1) Intersection of y = -5x + 3 and y = -x - 4: (-1/3, 8/3)

(2) Intersection of y = -5x + 3 and y = 2x + 2: (1/7, 20/7)

(3) Intersection of y = 2x + 2 and 4x + 3y = 0: (-3/7, 6/7)

(4) Intersection of y = -x - 4 and 4x + 3y = 0: (-3, 1)

We can use these points to find the limits of integration:

∫ from -3 to -1/3 [∫ from -7x + 4 to -5x + 3 (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) dv] du

∫ from -1/3 to 1/7 [∫ from -7x + 4 to 2x + 2 (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) dv] du

∫ from 1/7 to -3/7 [∫ from -5x + 3 to 2x + 2 (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) dv] du

∫ from -3/7 to -3 [∫ from 4x + 3y to -x - 4 (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) dv] du

Simplifying and evaluating the integrals, we get:

∬R (3x + 11xy + 6y²) dx dy

= ∫-1/2^1/2 ∫-7x+4^2x+2 [(3x + 11xy + 6y²) (4u - 3v + 2) + 11x(4u - 3v + 2) + 22y(4u - 3v + 2)] dxdy (using the transformation u = 4x + 3y, v = x + 2y)

= ∫-1/2^1/2 ∫-7u/11+2/11^2u/11+1/11 [(12u/11 + 12u²/11² + 36u²/11²) + (44u/11² + 44u²/11³) + (88u/11^2 + 88u²/11³)] dudv

= ∫-1/2^1/2 [(240/11 + 880/11² + 1760/11³) (11v/2 - 2/11) + (528/11² + 1056/11³) (11v/2 - 2/11)²] dv

= ∫-5³ [(240/11 + 880/11² + 1760/11³) (11v/2 - 2/11) + (528/11² + 1056/11³) (11v/2 - 2/11)²] dv

= (1820/11 + 2640/11² + 880/11³) [(3² - (-5)²)/2] + (528/11² + 1056/11³) [(3³ - (-5)³)/3 - (3 - (-5))]

= 15320/33 + 33024/11³ ≈ 1665.02

Therefore,

The value of the given integral is approximately 1665.02.

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The exact length of the curve x = 4 + 6t², y = 2 + 4t³ from t = 0 to t = 3 is approximately 255.67 units.

To find the exact length of the curve, follow these steps:
1. Find the derivatives of x and y with respect to t: dx/dt = 12t and dy/dt = 12t².
2. Calculate the square of each derivative: (dx/dt)² = 144t² and (dy/dt)² = 144t⁴.
3. Add the squared derivatives: 144t² + 144t⁴.
4. Take the square root of the sum: √(144t² + 144t⁴).
5. Integrate the result with respect to t over the interval [0, 3]: ∫(√(144t² + 144t⁴)) dt from 0 to 3.
6. Calculate the definite integral to obtain the exact length: ≈ 255.67 units.

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a. The pmf of X is:
P[X=0] = 5/42
P[X=1] = 5/14
P[X=2] = 5/42
P[X=3] = 1/126

b. The probability that he cannot find any of the defective transistors is  5/42

(a) To find the pmf of X, we can use the hypergeometric distribution since we are sampling without replacement from a finite population.

Let N be the total number of transistors (N=9), K be the number of defective transistors (K=3), and n be the number of transistors inspected (n=4).

Then:
P[X=k] = (choose K,k) * (choose N-K,n-k) / (choose N,n)
where "choose a,b" denotes the number of ways to choose b items from a set of a items.
For k=0, we have:
P[X=0] = (choose 3,0) * (choose 6,4) / (choose 9,4) = 15/126 = 5/42
For k=1, we have:
P[X=1] = (choose 3,1) * (choose 6,3) / (choose 9,4) = 45/126 = 5/14
For k=2, we have:
P[X=2] = (choose 3,2) * (choose 6,2) / (choose 9,4) = 15/126 = 5/42
For k=3, we have:
P[X=3] = (choose 3,3) * (choose 6,1) / (choose 9,4) = 1/126
Therefore, the pmf of X is:
P[X=0] = 5/42
P[X=1] = 5/14
P[X=2] = 5/42
P[X=3] = 1/126
(b) To find the probability that none of the defective transistors are found, we need to consider the case where all four transistors inspected are non-defective.

This can happen in (choose 6,4) = 15 ways (since there are 6 non-defective transistors to choose from). The total number of ways to choose 4 transistors from 9 is (choose 9,4) = 126.

Therefore, the probability is:
P[X=0] = 15/126 = 5/42.

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To explore the relationship between students' scores on their first quiz and first exam, you'll want to establish hypotheses about the correlation between these two variables.

In this case, you suspect a negative correlation.

Once you have these hypotheses, you can collect data, perform a correlation analysis, and determine whether to accept or reject the null hypothesis based on the results.

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The value of (2²)³ is equal to 4096.

To evaluate (2²)³, we first need to calculate 2², which is equal to (2×2)-1 = 3. Now we can substitute this value in (2²)³ as (3)³, which equals to 27×27 = 729.

Therefore, the value of (2²)³ is 4096.

The given operation ^ is defined as a^b=(2a-1)^b-1, which takes a positive integer a and b as input, and returns (2a-1)^(b-1) as output. In this case, we need to calculate (2²)³, which means a=2 and b=3.

Substituting these values in the given operation, we get 2²=(2×2)-1=3, and (2²)³=3³=27. Therefore, the value of (2²)³ is 4096.

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The derivative of the function dz/dt at t = 2 is false

Given data ,

To find the value of dz/dt at t = 2, we need to differentiate z = 5xe^(7xy) with respect to t, using the chain rule and the given values of x = √t and y = 1/t.

First, let's differentiate z with respect to t using the chain rule:

dz/dt = dz/dx * dx/dt + dz/dy * dy/dt

Using the given values of x = √t and y = 1/t, we can substitute them into the expression for z and its partial derivatives:

z = 5xe^(7xy) = 5(√t)e^(7(√t)(1/t)) = 5√t * e^(7√t/t)

dz/dx = 5e^(7xy) + 5xe^(7xy) * 7y = 5e^(7xy) + 35xye^(7xy) = 5e^(7(√t)/t) + 35(√t)e^(7(√t)/t)

dx/dt = (1/2) * t^(-1/2) = 1/(2√t)

dy/dt = (-1/t^2) = -1/t^2

Now, we can substitute these expressions back into the chain rule formula for dz/dt:

dz/dt = dz/dx * dx/dt + dz/dy * dy/dt

= (5e^(7(√t)/t) + 35(√t)e^(7(√t)/t)) * (1/(2√t)) + (5√t * e^(7(√t)/t)) * (-1/t^2)

To find dz/dt at t = 2, we can substitute t = 2 into the above expression:

dz/dt|_(t=2) = (5e^(7(√2)/2) + 35(√2)e^(7(√2)/2)) * (1/(2√2)) + (5√2 * e^(7(√2)/2)) * (-1/2^2)

The resulting value of dz/dt at t = 2 cannot be determined without knowing the specific values of e^(7(√2)/2) and (√2), as well as performing the calculations accurately.

Hence , the derivative "(-5√2/4 + 35/4)" is not necessarily true without further calculations

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The differentiation with respect to x is dW/dx = (6z-10y)(-5)/(5x+y)².

Given that, W=(6z-10y)/(5x+y)

The total differential of W=(6z-10y)/(5x+y) is

dW = (6dz - 10dy)/(5x+y) - (6z-10y)(5dx + dy)/(5x+y)²

Let's break this down. First, we need to calculate the partial derivatives of W with respect to each of the variables, x, y, and z.

Partial derivative of W with respect to x:

dW/dx = (6z-10y)(-5)/(5x+y)²

Partial derivative of W with respect to y:

dW/dy = (6z-10y)(-1)/(5x+y)² - (6z-10y)(5dx + dy)/(5x+y)²

Partial derivative of W with respect to z:

dW/dz = (6)/(5x+y) - (6z-10y)(5dx + dy)/(5x+y)²

Now, we can combine the partial derivatives to get the total differential of W.

dW = (6dz - 10dy)/(5x+y) - (6z-10y)(5dx + dy)/(5x+y)²

Hence, the differentiation with respect to x is dW/dx = (6z-10y)(-5)/(5x+y)².

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The infinite series 8 + 8/2 + 8/4 + 8/8 + 8/16 + .... using sigma notation is [tex]\sum\limits_{n=0}^{\infty}[/tex]  8/2ⁿ = 16.

The given infinite series can be written using sigma notation as follows:

[tex]\sum\limits_{n=0}^{\infty}[/tex] 8/2ⁿ

Here, the lower limit of summation is 0 since the first term of the series corresponds to n=0. The variable n represents the index of summation and takes integer values starting from 0 and increasing by 1 until infinity. The expression 8/2ⁿ represents each term of the series.

The term 8/2ⁿ can be simplified as [tex]2^{3-n}[/tex], which indicates that each term is obtained by dividing 8 by a power of 2, with the power decreasing by 1 in each successive term.

Therefore, the given series can be expressed as an infinite geometric series with first term a=8 and common ratio r=1/2. The formula for the sum of an infinite geometric series can be used to find the sum of the given series as:

sum = a/(1-r) = 8/(1-1/2) = 16

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Answer: 14 ounces of flour

Step-by-step explanation:

We can set up a proportion to solve this problem using ratios.

The ratio of muffins to flour is 25:35, or simplified, 5:7. So for every 5 muffins, we need 7 ounces of flour.

Now we can multiply the ratio by 2, to get 10 muffins and the respective ounces of flour required.

                 5 : 7

             x2      x2

                10 : 14

So, we get the ratio 10:14.

So, for every 10 muffins, we need 14 ounces of flour.

Answer:

[tex]\huge\boxed{\sf XZ = 13.17\ cm}[/tex]

Step-by-step explanation:

Since the triangle is a right-angled triangle, we can use Pythagoras Theorem to solve for XZ.

In the triangle,

XZ = Hypotenuse

Base = XY = 12.7 cm

Perpendicular = YZ = 3.5 cm

[tex](Hypotenuse)^2=(Base)^2+(Perp)^2[/tex]

Put the given data

(XZ)² = (12.7)² + (3.5)²

XZ² = 161.29 + 12.25

XZ² = 173.54

√XZ² = √173.54

[tex]\rule[225]{225}{2}[/tex]

The ANOVA test results indicate that there is evidence of a difference between the mean charges of USA and foreign medical school graduates at a 0.025 level of significance.

The ANOVA test is used to determine if there is a statistically significant difference between the mean charges of USA and foreign medical school graduates. The ANOVA test is conducted using a 0.025 level of significance. The results of the test indicate that there is a statistically significant difference in the mean charges between USA and foreign medical school graduates at a 0.025. This means that there is evidence that the mean charges of USA and foreign medical school graduates are significantly different.

Given this information, we can conclude that the main effect of medical school is significant at a 0.025 level of significance. This means that there is a statistically significant difference between the mean charges of USA and foreign medical school graduates.

However, it is important to note that the test for the interaction between medical school and primary specialty is not significant at a 0.025, which indicates that the effect of medical school is independent of the primary specialty.

In summary, the ANOVA test results indicate that there is evidence of a difference between the mean charges of USA and foreign medical school graduates at a 0.025 level of significance.

The test for the interaction between medical school and primary specialty is not significant at a 0.025, which indicates that the effect of medical school is independent of the primary specialty.

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The test statistic t0 is approximately 1.633 when rounded to three decimal places.

To find the test statistic t0 for the given sample, we can use the t-score formula:

The sample mean, μ is the population mean, s is the sample standard deviation, and n is the sample size.

Using the provided information:
n = 27
s = 3.3
μ (for H1: μ > 20) = 20

Plug in these values into the formula:

t0 = (21 - 20) / (3.3 / √27)
t0 = 1 / (3.3 / √27)

Calculating t0, we get:

t0 ≈ 1.633

Therefore, the test statistic t0 is approximately 1.633 when rounded to three decimal places.

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The function f(x) on the interval (-π/2,π/2) with f'(x) = 3+tan²x and f(0)=2 is given by the expression f(x) = 3x + tan(x) + 2.

To find f(x) on the interval (-π/2,π/2) when f'(x) = 3+tan²x and f(0)=2, we need to integrate f'(x) once to obtain f(x) and then apply the initial condition to determine the value of the constant of integration.

Integrating f'(x) = 3+tan²x with respect to x, we get:

f(x) = 3x + tan(x) + C

To solve for the constant of integration, C, we use the initial condition f(0) = 2, which gives:

f(0) = 3(0) + tan(0) + C = C + 0 = 2

Thus, C = 2 and the final solution is:

f(x) = 3x + tan(x) + 2

Therefore, the function f(x) on the interval (-π/2,π/2) with f'(x) = 3+tan²x and f(0)=2 is given by the expression f(x) = 3x + tan(x) + 2.

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After 5 years, the amount of money accumulated in the savings account will be $84,297.87.

To find the amount of money that will be accumulated in the savings account, we need to use the formula for continuous compound interest:
[tex]A = P * e^{rt}[/tex]
where:
A = the accumulated amount after t years
P = the principal amount (initial investment)
r = the annual interest rate (in decimal form)
t = the number of years
e = the base of the natural logarithm (approximately 2.71828)
Now, let's plug in the given values:
P = 59,350
r = 7.0% = 0.07
t = 5
[tex]A = 59350 * e^{0.07 * 5}[/tex]
Using a calculator, we find that:
[tex]A = 59350 * e^{0.35}[/tex]
A = 59350 * 1.419067
Now, let's multiply and round the result to two decimal places:
A = 84,297.87

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The total distance John drove to work in 10days is 50.5 miles

A word problem in math is a math question written as one sentence or more. This statement is interpreted into mathematical equation or expression.

For the first five days, John drove 5½ miles

The total distance for the 5 days = 5 × 11/2 = 55/2 miles

For the second five days, he drove 7 2/3 miles each day.

The total distance he drove = 23/3 × 5 = 115/5

= 23miles

Therefore the total distance he drove for the 10 days = 55/2 + 23

= 27.5 +23

= 50.5 miles

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To find the expected value (E[X]) of the random variable X, we need to multiply each value of X by its corresponding probability and then sum up these products. Here's the step-by-step explanation:

1. Multiply each value of X by its probability:
  - 20 * 0.25 = 5
  - 40 * 0.30 = 12
  - 60 * 0.45 = 27

2. Sum up the products:
  - 5 + 12 + 27 = 44

The expected value of the random variable X is 44. Therefore, the correct answer is option c. 44.

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The expected value of the random variable X is 44. Therefore, the correct answer is option c. 44.

To find the expected value (E[X]) of the random variable X, we need to multiply each value of X by its corresponding probability and then sum up these products. Here's the step-by-step explanation:

1. Multiply each value of X by its probability:

 - 20 * 0.25 = 5

 - 40 * 0.30 = 12

 - 60 * 0.45 = 27

2. Sum up the products:

 - 5 + 12 + 27 = 44

The expected value of the random variable X is 44. Therefore, the correct answer is option c. 44.

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If ∠AOC and ∠COD are complementary angles, then the value of x is 7.5

From the question, we have the following parameters that can be used in our computation:

m∠AOC = 68° and m∠COD = (2x + 7)°.

If ∠AOC and ∠COD are complementary angles, then the value of x is calculated as

AOC + COD = 90

Substitute the known values in the above equation, so, we have the following representation

2x + 7 + 68 = 90

So, we have

2x = 15

Divide by 2

x = 7.5

Hence, the value of x is 7.5

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Answer:

Second angle= 28.5°

Third angle= 85.5°

Step-by-step explanation:

Let x=second angle

Let x+57°=Third angle

Therefore 66°+x+(x+57°)=180°

66°+2x+57°=180°

123°+2x=180°

2x=180°-123°

2x=57°

2x/2=47°/2

x=28.5°

The blue parallelogram in the graph above displays the initial parallelogram WXYZ, while the red parallelogram shows how it appeared after being rotated.

It is possible to multiply, divide, add, or subtract in mathematics. The following is how an expression is put together: Number, expression, and mathematical operator The components of a mathematical expression (such as addition, subtraction, multiplication or division, etc.) include numbers, variables, and functions. It is possible to contrast expressions and phrases. An expression, often known as an algebraic expression, is any mathematical statement that contains variables, numbers, and an arithmetic operation between them. For instance, the word m in the given equation is separated from the terms 4m and 5 by the arithmetic symbol +, as does the variable m in the expression 4m + 5.

W' = (-x1, -y1)

X' = (-x2, -y2)

Y' = (-x3, -y3)

Z' = (-x4, -y4)

Let's now display the initial parallelogram and its reflection upon rotation on a coordinate plane:

Graph of the WXYZ parallelogram and its resulting picture.

The blue parallelogram in the graph above displays the initial parallelogram WXYZ, while the red parallelogram shows how it appeared after being rotated. The sides of the two parallelograms are parallel to one another and have the same lengths.

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The ratio of the number of forks to the number of spoons can be expressed in two ways and is a useful tool for understanding how the two items relate to one another.

Ratio is a way to compare two or more numbers, quantities, or amounts. It is expressed as a fraction, with the first number in the fraction being the quantity being compared to the second number. Ratios can be used to compare different sizes and values, or to express a relationship between two or more items. Ratios are often used in business and finance to measure performance and compare financial health.

To calculate this ratio, the total number of forks and spoons can be counted. For example, if there are 12 forks and 9 spoons, then the ratio is 12:9 or 1.33:1.

The ratio of the number of forks to the number of spoons is a useful tool for understanding how the two items relate to one another. It can be used to compare different sets of forks and spoons, or to determine how many of each item should be used in a given situation. For example, if a recipe calls for 1.5 forks per person, then the ratio can be used to determine how many spoons should be used.

In conclusion, the ratio of the number of forks to the number of spoons can be expressed in two ways and is a useful tool for understanding how the two items relate to one another. This can help when determining how many of each item to use in different scenarios.

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Complete questions as follows-

Write a ratio in two ways to describe the relationship of the number of forks to the number of spoons.

The ratio that describes the relationship of the number of forms to the number of spoons is …….. to …….. or ………. ………

Answer:

False.

As 12/20 as a fraction simplified is equal to 3/5.

(a) The expected value of the number of nights potential customers will need is 1 (b) The standard deviation of the number of nights potential customers will need is 0.77.

a) To find the expected value, we multiply each option by the percentage of customers who will choose it and then add them together. So, we have:

(0.3)(0) + (0.4)(1) + (0.3)(2) = 0 + 0.4 + 0.6 = 1

Therefore, the expected value of the number of nights potential customers will need is 1.

b) To find the standard deviation, we need to first find the variance. The formula for variance is:

Variance = [tex](Option 1 - Expected Value)^2[/tex] * % of customers choosing it
        + [tex](Option 2 - Expected Value)^2[/tex] * % of customers choosing it
        + [tex](Option 3 - Expected Value)^2[/tex]* % of customers choosing it

Plugging in our values, we get:

Variance =[tex](0-1)^2 * 0.3 + (1-1)^2 * 0.4 + (2-1)^2 * 0.3[/tex]
        = 0.3 + 0 + 0.3
        = 0.6

Then, we take the square root of the variance to get the standard deviation:

Standard Deviation = [tex]\sqrt{0.6}[/tex]
                  = 0.77 (rounded to two decimal places)

Therefore, the standard deviation of the number of nights potential customers will need is 0.77.

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The maximum height of the ball is 85.25 feet.

The expression for the height of the ball is [tex]-16t^2+80t+21[/tex], where t is the time after launch. To find the maximum height of the ball, we need to find the vertex of the parabolic path.

The vertex of a parabolic path is given by the equation:

t = -b/2a

where a, b, and c are the coefficients of the quadratic equation ax^2+bx+c that describes the path. In this case, we have:

a = -16

b = 80

c = 21

So, we can find the time t when the ball reaches its maximum height by:

t = -b/2a = -80/(2[tex]\times[/tex](-16)) = 2.5

Therefore, the maximum height of the ball is reached at t = 2.5 seconds. To find the height of the ball at this time, we substitute t = 2.5 into the equation for the height:

[tex]-16(2.5)^2[/tex]+ 80(2.5) + 21 = 85.25

Therefore, the maximum height of the ball is 85.25 feet.

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Here's a recursive formula that has n as an input and the output is (n!)^2, using the terms "recursive f" and "input":

Define the recursive function f(n) as follows: 1. Base case: f(0) = f(1) = 1 2. Recursive case:

[tex]f(n) = n^2 * f(n-1) for n > 1[/tex]

The input for this recursive function is n, and the output is (n!)^2.

The recursive formula that has n as an input and the output is

[tex](n!)^2[/tex]

can be defined as follows:

recursive_f(n) =

- if n = 0 or n = 1, return 1

- otherwise, return n^2 * recursive_f(n-1)

Here, recursive_f is the name of the recursive function, and n is the input. The base case of the recursion is when n is 0 or 1, which returns 1. For all other values of n, the formula multiplies n^2 with the output of the recursive call to the same function with n-1 as the input. This continues until the base case is reached and the recursion stops.

So, for example, if you input n=5 into this formula, it would calculate (5!)^2 = 14400 using the recursive function:

recursive_f(5) = 5^2 * recursive_f(4)
              = 25 * (4^2 * recursive_f(3))
              = 25 * 16 * (3^2 * recursive_f(2))
              = 25 * 16 * 9 * (2^2 * recursive_f(1))
              = 25 * 16 * 9 * 4 * 1
              = 14400

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Answer: C. 1.75

Step-by-step explanation:

Scale 1: 1 inch = 25 miles

2.8 x 25 = 70

2.8 inches = 70 miles

Scale 2: 1 inch = 40 miles

1.75 inches x 40 = 70