Based on your own knowledge and opinion, what do you believe will be the most common job in New York in 2030? In one paragraph, explain your rationale.

Answers

Answer 1

Answer:

According to research and current trends, some of the most in-demand jobs in New York by 2030 could be related to technology, healthcare, and sustainability. With the ongoing digital transformation, the demand for IT professionals, software developers, and data analysts is expected to increase. The healthcare industry is also growing due to the aging population and advances in medical technology. Moreover, with the growing concerns about climate change and sustainability, there could be a rise in jobs related to renewable energy, environmental science, and green technology.


Related Questions

Three-year-old boys in the United States have a mean height öf 38 inches and a standard deviation of 2 inches.
How tall is a three-year-old boy with a z-score of -1.0?
A boy with a z-score of -1.0 in this situation would be inches tall.

Answers

Answer:

To solve this problem, we'll use the formula: z = (x - μ) / σ

where z is the z-score, x is the height of the boy, μ is the mean height, and σ is the standard deviation.

We know that μ = 38 inches and σ = 2 inches. We also know that the z-score is -1.0.

Plugging in these values and solving for x, we get: -1.0 = (x - 38) / 2

Multiplying both sides by 2, we get: -2 = x - 38

Adding 38 to both sides, we get: x = 38 - 2

x = 36

Therefore, a three-year-old boy with a z-score of -1.0 would be 36 inches tall

The graph to the right is the uniform probability density function for a friend who is x minutes late.
​(a) Find the probability that the friend is between 10 and 25 minutes late.
​(b) It is 10 A.M. There is a 30​% probability the friend will arrive within how many​ minutes?

Answers

Answer:

To find the probability that the friend is between 10 and 25 minutes late, we need to find the area under the curve between 10 and 25 on the x-axis.

The area under a uniform probability density function is given by: Area = base x height

where the base is the width of the interval (25-10 = 15 minutes) and the height is the value of the density function (1/30).

Therefore, the probability that the friend is between 10 and 25 minutes late is: Area = 15 x 1/30 = 0.5

Rounding to three decimal places, the probability is 0.500

So the answer is 0.500

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