ch 13 the rate constant for a reaction at 25 C is .010s and its activation energy is 35.8 kJ. what is the rate constant at 50C?
a. .021
b. .010
c. .003
d. .031

So, the solubility of copper(II) sulfide at 25C is 1.1 x [tex]10^{-18[/tex] mol/L.

The Ksp expression for copper(II) sulfide is CuS(s) ⇌ [tex]Cu_2[/tex]+(aq) + [tex]S_2[/tex]-(aq). The Ksp value of 1.3 x [tex]10^{-18[/tex]  indicates that the concentration of [tex]Cu_2[/tex]+ and [tex]S_2[/tex]- ions in solution is very low.

The capacity of a material, the solute, to combine with another substance, the solvent, is known as solubility in chemistry. Insolubility, or the solute's inability to create such a solution, is the opposite attribute.

Let's assume that x is the solubility of CuS in moles/L at equilibrium. Then, the concentration of [tex]Cu_2[/tex]+ and [tex]S_2[/tex]- ions is also x. Substituting these values in the Ksp expression and solving for x gives:

Ksp = [[tex]Cu_2[/tex]+][S-] = x * x = [tex]x^2[/tex]

x = [tex]\sqrt{(Ksp) }[/tex]

=[tex]\sqrt{ (1.3 x 10^{_36)}[/tex]

= 1.1 x  [tex]10^{-18[/tex] mol/L

Therefore, the solubility of copper(II) sulfide at 25 oC is 1.1 x  [tex]10^{-18[/tex] mol/L.

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For the following reaction, you have 8 grams of hydrogen and 2 grams of oxygen. 2H2 + O2 → 2H2O. The limiting reagent is the oxygen is True.

1. Determine the molar mass of each reactant:
  H2 (hydrogen) = 2.02 g/mol
  O2 (oxygen) = 32.00 g/mol

2. Calculate the number of moles for each reactant:
  Moles of H2 = (8 grams) / (2.02 g/mol) = 3.96 moles
  Moles of O2 = (2 grams) / (32.00 g/mol) = 0.0625 moles

3. Determine the stoichiometric ratio of the reactants:
  For every 2 moles of H2, 1 mole of O2 is needed.

4. Calculate the amount of O2 needed for complete reaction with the given H2:
  Amount of O2 needed = (3.96 moles H2) * (1 mole O2 / 2 moles H2) = 1.98 moles

5. Compare the amount of O2 needed with the amount of O2 given:
  1.98 moles (needed) > 0.0625 moles (given)

Since there is less O2 than needed for a complete reaction, O2 is the limiting reagent.

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So, the balanced equation in a basic solution after all resulting species are combined and/or canceled correctly is:

H2O + 3TeO32- + 4Sb → 3Te + 4SbO2-.

To find the balanced equation in a basic solution for the given reaction: 2H+ + 3TeO32- + 4Sb → 3Te + 4SbO2- + H2O.

1. First, we need to neutralize the acidic solution. To do this, we'll add an equal amount of OH- ions to both sides of the equation to cancel out the H+ ions:

2H+ + 2OH- + 3TeO32- + 4Sb → 3Te + 4SbO2- + H2O + 2OH-

2. Now, we can combine the H+ and OH- ions to form water:

2H2O + 3TeO32- + 4Sb → 3Te + 4SbO2- + H2O

3. Finally, we'll cancel out any common species on both sides of the equation. In this case, we can cancel out one H2O molecule:

H2O + 3TeO32- + 4Sb → 3Te + 4SbO2-

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The new pH of the solution after adding 6.30 mL of 0.490 M HCl to a 200.0 mL acetate/acetic acid buffer solution with a total molarity of 0.100 M and a pH of 5.000.

To solve this problem, we need to use the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

Total Molarity = [A⁻] + [HA]

0.100 M = [A⁻] + [HA]

We also know that the pH of the buffer solution is 5.000. The pKa of acetic acid is 4.76, so we can use this information to find the ratio of [A⁻] to [HA]:

5.000 = 4.76 + log([A⁻]/[HA])

0.24 = log([A⁻]/[HA])

[HA]/[A⁻] = 10⁰.²⁴

We can use this ratio and the total molarity equation to find the initial concentrations:

[A⁻] = (10⁰.²⁴/[HA]) * (0.100 M - [HA])

- The HCl will react with the acetate to form acetic acid and chloride ions:

HCl + A⁻ → HA + Cl⁻

The amount of HCl added is:

0.490 M * 6.30 mL = 0.00309 moles HCl

The amount of acetate consumed and the amount of acetic acid formed will be 0.00309 moles.

The new concentration of acetic acid is:

[HA] = [HA]initial + 0.00309 moles / 0.2000 L = 0.0155 M

The new concentration of acetate is:

[A⁻] = [A⁻]initial - 0.00309 moles / 0.2000 L = 0.0485 M

We can now use the Henderson-Hasselbalch equation with the new concentrations to find the new pH:

pH = 4.76 + log(0.0485/0.0155) = 4.50

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Maltose is produced from starch under controlled conditions and is called maltodextrin, which is used in the manufacture of beet.

Maltodextrin is a type of carbohydrate that is commonly used as a food additive. It is produced by breaking down starch through a process called hydrolysis. In this process, starch molecules are broken down into smaller units, including maltose. Maltodextrin is often used as a thickener, filler, or sweetener in processed foods such as baked goods, snack foods, and sports drinks.

It is also used in the manufacture of beet sugar to improve the texture and stability of the sugar crystals. Maltodextrin is considered safe for consumption by the US Food and Drug Administration (FDA) and is widely used in the food industry.

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H₂ identifies the correct limiting reactant because it has the lower starting mass. The correct option is C.

In the described reaction, 2 moles of hydrogen and 1 mole of oxygen combine to form 2 moles of water. H₂ to H₂O has a stoichiometric ratio of 2:1 (or 1:1), whereas O₂ to H₂O has a stoichiometric ratio of 1:2.

We can determine the amount of moles of accessible H2 and O2 based on the facts given:

0.4g of H₂ corresponds to (0.4 g / 2.016 g/mol) = 0.198 mol of H₂.

1.8g of O₂ corresponds to (1.8 g / 32.00 g/mol) = 0.056 mol of O₂.

We determine that H₂ is the limiting reactant by comparing the moles of H₂ and O₂ that are accessible.

The amount of product (H₂O) that can be created is constrained because the reactant is fully consumed first. The stoichiometric ratio and the fact that there are less moles of H₂ than O₂ are the foundations for the reasoning.

Thus, the correct option is C.

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The three individual collagen chains are themselves polypeptides that differ from each other in their amino acid sequence. Collagen is a fibrous protein that provides strength and structure to various tissues in the body, including skin, bones, and tendons.

It is made up of three individual chains of amino acids that are coiled around each other to form a triple helix structure. These three chains are known as alpha chains, and there are different types of alpha chains that can combine to form various types of collagen.

The differences in the amino acid sequences of the alpha chains lead to differences in the properties of the collagen, such as its strength and flexibility.

Therefore, the specific combination of alpha chains that make up a particular collagen molecule determines its function and location in the body.

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When a large amount of pure water is consumed, a potential outcome is a fluid shift that can cause the volume of the intracellular fluid (ICF) to decrease.

The reason for this is that the concentration of solutes inside the ICF is higher than that of the extracellular fluid (ECF), and consuming a large amount of pure water can dilute the ECF. This results in the ECF becoming hypotonic, meaning it has a lower concentration of solutes compared to the ICF.

As a result, water moves from the ECF to the ICF to balance out the concentration gradient, causing a decrease in the volume of the ECF and an increase in the volume of the ICF.

This can have potential consequences, such as causing cells to swell and potentially leading to issues such as hyponatremia. It's important to maintain a balance of water and electrolytes in the body to avoid these potential outcomes.

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The structure of the isomerization product is similar to that of isopentenyl pyrophosphate, except that one of the double bonds has shifted to a different position in the molecule.

This is due to the acid-catalyzed process, which involves the transfer of a proton from the phosphate group to the carbon-carbon double bond, causing it to shift to a different position in the molecule. This results in the formation of dimethylallyl pyrophosphate, which is an important precursor in the biosynthesis of many essential compounds, including sterols, carotenoids, and tocopherols.

The isomerization process is a crucial step in the biosynthesis of these compounds, as it helps to ensure the correct formation of the carbon-carbon double bonds that are necessary for their biological activity.

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All of the following are characteristics of a Wittig  chemical reaction except it involves an SN² reaction between a carbanion and an aldehyde or ketone.

Chemical reactions are defined as changes which occur when a substance combines with another substance to form a new substance.Alternatively, when a substance breaks down or decomposes to give new substances it is also considered to be a chemical reaction.

There are several characteristics of chemical reactions like change in color, change in state , change in odor and change in composition . During chemical reaction there is also formation of precipitate an insoluble mass of substance or even evolution of gases.It involves SN¹ or SN²reactions.

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Answer:

To determine the empirical formula of the alcohol, we need to find the number of moles of each element in the sample. We can do this by using the mass of CO2 and H2O produced during combustion to calculate the mass of carbon and hydrogen in the sample.

The molar mass of CO2 is 44.01 g/mol, so 38.20 grams of CO2 is equivalent to 38.20 g / (44.01 g/mol) = 0.868 mol of CO2. Since each molecule of CO2 contains one atom of carbon, this means that there are 0.868 mol of carbon in the sample.

The molar mass of H2O is 18.02 g/mol, so 23.48 grams of H2O is equivalent to 23.48 g / (18.02 g/mol) = 1.303 mol of H2O. Since each molecule of H2O contains two atoms of hydrogen, this means that there are 1.303 mol * 2 = 2.606 mol of hydrogen in the sample.

Since the sample contains only carbon, hydrogen, and oxygen, we can calculate the number of moles of oxygen by subtracting the number of moles of carbon and hydrogen from the total number of moles in the sample. The molar mass of the alcohol is unknown, but we can assume that it is a whole number multiple of its empirical formula mass. Therefore, we can calculate the total number of moles in the sample by dividing its mass by an assumed empirical formula mass.

Let’s assume that the empirical formula mass is equal to the molar mass of CH4O (32.04 g/mol). This means that 20.00 grams of alcohol is equivalent to 20.00 g / (32.04 g/mol) = 0.624 mol of alcohol.

Since there are 0.868 mol of carbon and 2.606 mol of hydrogen in the sample, this means that there are 0.624 mol - 0.868 mol - 2.606 mol = -2.85 mol of oxygen in the sample.

Since it is not possible for there to be a negative number of moles of oxygen in the sample, our assumption that the empirical formula mass is equal to the molar mass of CH4O must be incorrect.

Let’s try assuming that the empirical formula mass is equal to twice the molar mass of CH4O (64.08 g/mol). This means that 20.00 grams of alcohol is equivalent to 20.00 g / (64.08 g/mol) = 0.312 mol of alcohol.

Since there are 0.868 mol of carbon and 2.606 mol of hydrogen in the sample, this means that there are 0.312 mol - 0.868 mol - 2.606 mol = -3.162 mol of oxygen in the sample.

Again, since it is not possible for there to be a negative number of moles of oxygen in the sample, our assumption that the empirical formula mass is equal to twice the molar mass of CH4O must also be incorrect.

We can continue trying different assumed values for the empirical formula mass until we find one that results in a non-negative number of moles for all elements in the sample.

After trying several different assumed values for the empirical formula mass, we find that assuming an empirical formula mass equal to four times the molar mass of CH4O (128.16 g/mol) results in a non-negative number

Explanation:

The functional groups that are present in a compound can be inferred from the IR spectra, but this information is not necessarily adequate to determine the complex's structure.

The IR spectrum can offer some helpful information in the case of a Diels-Alder reaction, but it cannot be used as proof that the structure of the product is a result of combining the two reactants.  In the Diels-Alder reaction, a diene and a dienophile combine to generate a cyclic molecule. Although the product's IR spectrum can display the distinctive peaks of both the diene and the dienophile, it cannot establish that the product is a mixture of the two reactants.

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The more information is needed to determine the pressure of nitrogen in the larger flask after the transfer.

Unfortunately, without additional information such as the volume of each flask, the initial pressure of the nitrogen gas, and the conditions under which the transfer occurs, it is not possible to determine the pressure of nitrogen in the larger flask.

The pressure of a gas is affected by several factors, including the volume of the container, the number of gas molecules present, and the temperature of the gas. Additionally, if the transfer occurs through a valve or some other type of opening, the pressure may change due to the change in volume and the escape of some gas molecules.

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Answer:

False.

Explanation:

The atomic radius tends to decrease as progression is made across a period from left to right.

The Henderson-Hasselbalch equation is: pH = pK + log (unprotonated/protonated). When the concentration of protonated and unprotonated molecules are equal, the equation becomes pH = pK.

The Henderson-Hasselbalch Equation is a mathematical formula that relates the pH of a solution to the pKa (the dissociation constant) of the weak acid and the ratio of the concentrations of the protonated (HA) and unprotonated (A-) forms of the acid. The equation is pH = pKa + log([A-]/[HA]). When the concentration of the protonated and unprotonated molecules are equal, the ratio [A-]/[HA] is 1, and the log term becomes zero, resulting in pH = pKa. Therefore, pH = pKa when the concentration of the protonated and unprotonated forms of the acid are equal.

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2.72 grams of Hydrochloric acid are required to react with the penny that has around 2.4375 grams of zinc present in it.

You will recognise the reaction between zinc and HCl as a displacement reaction:

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

The balanced chemical equation will give you the idea that 1 mole of Zn reacts with 2 moles of HCl. The molar mass of Zn is 65.38 g/mol. Therefore, the number of moles of Zn in a penny is:

2.4375 g Zn / 65.38 g/mol Zn = 0.0373 mol Zn

According to the stoichiometry of the reaction, you'll need 2 moles of HCl for every 1 mole of Zn. Therefore, the number of moles of HCl required to react with the Zn in the penny is:

0.0373 mol Zn × 2 mol HCl/1 mol Zn = 0.0746 mol HCl

Finally, you'll need to convert  the number of moles of HCl to grams using the molar mass of HCl, which is 36.46 g/mol:

0.0746 mol HCl × 36.46 g/mol HCl = 2.72 g HCl

Therefore, you will need 2.72 grams of HCl  to react with the zinc present  in a penny.

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The gas which have the largest Van der Waals constant a is ammonia, NH₃.

The Intermolecular forces in between the molecules are forces that are the  attractive forces which make them together or will be impart physical properties. The Stronger the forces and the closer the molecules of the substance.

The molecule that have the strongest forces and that will have the largest value of the Van der Waals constant a. The gas which have the largest Van der Waals constant a is ammonia, NH₃ as the ammonia has the strongest force because of the hydrogen bonding. Therefore, the NH₃  has the largest value of the a.

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This question is incomplete, the complete question is :

Real gases and vapors deviate from ideal behavior on account of intermolecular interactions. One equation of state for a real gas is the van der Waals equation, which is expressed in terms of two parameters, a and b. Which gas would you expect to have the largest Van der Waals constant a: F₂, Ne, NH₃.

The molar mass of [tex]Al(C_2H_3O_2)_3[/tex] is 204.13 g/mol. The correct option is B.

To calculate the molar mass of [tex]Al(C_2H_3O_2)_3[/tex], we need to determine the atomic masses of each element present in the compound and add them up, taking into account the number of each element in the formula.

26.98 g/mol is the atomic mass of Aluminum (Al).

12.01 g/mol is the atomic mass of Carbon (C).

1.01 g/mol is the atomic mass of Hydrogen (H).

16.00 g/mol is the atomic mass of Oxygen (O).

The compound contains one aluminum atom, three carbon atoms, nine hydrogen atoms, and six oxygen atoms.

Molar mass of [tex]Al(C_2H_3O_2)_3[/tex] = (1 × 26.98 g/mol) + (3 × 2 × 12.01 g/mol) + (9 × 1.01 g/mol) + (6 × 16.00 g/mol) = 204.13 g/mol

Therefore, the correct answer is (B) 204.13 g/mol.

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The best description of chromosomes by the end of anaphase II of meiosis is option D) The chromosomes reach opposite sides of the cell, incorporating into two haploid nuclei.

What happens to chromosomes by the end of anaphase II in meiosis?

During anaphase II of meiosis, the sister chromatids of each chromosome are separated and pulled towards opposite poles of the cell. At the end of anaphase II, the chromosomes reach opposite sides of the cell, where they become incorporated into two separate haploid nuclei. The other options mentioned describe the events that occur during earlier stages of meiosis or during mitosis.

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The most invasive type of nuclear radiation is typically thought to be gamma radiation.

The term "radiation" describes the release or transmission of electrical energy through area or matter in the form either particles or waves. Ionising radiation and non-ionizing radiation are the two basic categories into which it can be divided.Non-ionizing radiation has a lower energy and is generally thought to be less dangerous to human health. Examples include visible sunlight, radio waves, and microwaves. However, at high enough doses, such as those associated with coming into contact with intense infrared radiation, even radiation that is not ionising can harm tissue.

A tissue is a collection of cells with a common structure and function that work together to carry out a single duty or set of duties for the organism.

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The eutectic composition is mixture composition with lowest melting point when melting mixtures of compounds. At this composition, melting point is lower than that of individual components and any other mixture compositions. The correct answer is option: 4.

The eutectic point is a unique point on a phase diagram that represents the lowest possible melting point of a mixture of two or more substances. It occurs when the components of  mixture are present in a specific proportion, and any deviation from this proportion results in a higher melting point. The eutectic point is important in materials science, chemistry, and metallurgy, as it determines the optimal composition for alloy formation and helps to prevent unwanted solidification. Correct answer: 4.

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The addition of solute molecules can lead to a decrease in the rates of both evaporation and condensation.

How does the solute affect the rate of various reactions?

1. Evaporation: The addition of solute molecules to a solvent reduces the rate of evaporation. This is because solute molecules occupy spaces at the liquid surface and decrease the surface area available for solvent molecules to escape into the vapor phase. Additionally, solute-solvent interactions can lower the kinetic energy of the solvent molecules, making it harder for them to overcome the attractive forces and evaporate.

2. Condensation: The presence of solute molecules can also affect the rate of condensation. The solute molecules in the solution occupy space, reducing the amount of space available for vapor molecules to condense back into the liquid phase. As a result, the condensation rate might be reduced.

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The correct answer is E) 0.829 moles.

The given problem involves determining the number of moles of N2O4 in a given amount of the compound. To solve this problem, the molar mass of N2O4 is required, which is given as 92.02 g/mol.

To determine the number of moles of N2O4 in 76.3 g N2O4, you can use the molar mass of N2O4, which is 92.02 g/mol. Use the formula:

moles = mass (g) / molar mass (g/mol)

moles = 76.3 g / 92.02 g/mol

moles ≈ 0.829 moles

So the correct answer is E) 0.829 moles.

This means that there are approximately 0.829 moles of N2O4 in 76.3 grams of the compound.

The mole is a unit of measurement used in chemistry to express amounts of a chemical substance. It is defined as the amount of substance that contains as many elementary entities (such as atoms or molecules) as there are atoms in 12 grams of pure carbon-12.

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The crystal structure of NaCl (sodium chloride) consists of a repeating pattern of positively charged sodium ions and negatively charged chloride ions. This repeating pattern, known as a crystal lattice, forms a three-dimensional structure that extends throughout the entire sample of NaCl.

In the context of materials science, a phase is defined as a homogeneous and physically distinct portion of a material that has uniform physical and chemical properties. Therefore, the NaCl crystal structure is a single-phase material because it is a uniform and homogeneous arrangement of sodium and chloride ions throughout the crystal lattice.

However, it is important to note that NaCl can exist in different phases under different conditions of temperature and pressure. For example, at high temperatures and pressures, NaCl can exist in a cubic close-packed (ccp) structure rather than its usual face-centered cubic (fcc) structure.

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The process of a spot on a car where the paint was scratched starting to look brown/red is a chemical change. This is because the exposure of the metal beneath the paint to air and moisture causes a chemical reaction, which leads to rust formation. The process, called oxidation, involves a change in the chemical composition of the metal.

The formation of rust involves a change in the chemical composition of the metal, which is different from the original paint. Therefore, it is considered a chemical change.

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Answer:

394 grams initially in the rock

The activity of a radioactive isotope is measured by the isotope's half-life. Half-life is the time it takes for half of the nuclei in a radioactive sample to undergo radioactive decay. Radioisotopes can have half-lives from fractions of a second, to billions of years.

The formula for exponential decay, studied in mathematics, can be used to  describe the amount of undecayed radioisotopes present after a certain amount of time:

[tex]N_t = N_0\,e^{-\lambda t[/tex]

When one half-life (denoted by [tex]t_\frac{1}{2}[/tex] ) has elapsed, half the radioisotopes would have undergone radioactive decay. Hence after one half-life:

Nt = N₀/2, and we can write this equation as:

[tex]\frac{N_t}{2} = N_0\,e^{-\lambda t_\frac{1}{2}[/tex]. Isolating λ to one side, we are left with the formula for the decay constant:

[tex]\lambda = \frac{ln2}{t_\frac{1}{2} }[/tex]

Therefore, if potassium-40 decays with a half-life of 1.25 billion:

We can calculate decay constant:

[tex]\lambda = \frac{ln2}{t_\frac{1}{2} }\\\lambda = \frac{ln2}{1.25 }\\\\\lambda \approx 0.5545[/tex]

Hence:

[tex]98.4= N_0\,e^{-\frac{ln2}{1.25}\times2.50 }\\N_0 = 393.6\\N_0 \approx 394 \,\,grams[/tex]

TSL stands for Test and Set Lock. It is a synchronization primitive used in computer programming to prevent multiple threads from accessing a shared resource simultaneously.

The way TSL works is by first checking the value of a shared variable, and if it is not being used by another thread, the TSL operation sets the value to indicate that it is now in use by the current thread. This atomic operation ensures that no other thread can access the shared resource until the current thread has finished using it and releases the lock.

TSL is considered atomic because it happens without a switch in processes, meaning it is a single, indivisible operation that cannot be interrupted or modified by other threads. This property is essential for ensuring thread safety and preventing race conditions in concurrent programming.

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The octet rule states that second-row elements B and Be can have less than eight electrons in their valence shell because they have fewer available orbitals.

The octet rule is a guideline that suggests that atoms tend to gain, lose, or share electrons in order to have eight electrons in their outermost shell, or valence shell. This is because having eight valence electrons makes the atom more stable, due to a full outer shell.

However, second-row elements Beryllium (Be) and Boron (B) can have less than eight electrons in their valence shell because they have fewer available orbitals. Be has only four valence electrons and two available orbitals, while B has only three valence electrons and three available orbitals.

These elements may form compounds where they have fewer than eight electrons in their valence shell. For example, Be typically forms compounds where it has only four electrons in its valence shell, such as BeH₂, while B typically forms compounds where it has six electrons in its valence shell, such as BF₃.

Therefore, the octet rule is a useful guideline, but there are exceptions, such as second-row elements Be and B.

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The energy overlap and the s/p gap between S (sulfur) and H (hydrogen) are important factors that influence their chemical properties and reactivity.

The energy overlap refers to the extent to which the atomic orbitals of two atoms share the same region in space and have similar energy levels, allowing for the formation of molecular orbitals and, consequently, chemical bonds.

In the case of S (sulfur) and H (hydrogen), the energy overlap occurs primarily between the 3p orbital of sulfur and the 1s orbital of hydrogen. The 3p orbital of sulfur has a higher energy level compared to the 2s and 2p orbitals, while the 1s orbital of hydrogen is the only electron shell available for bonding.

The s/p gap, on the other hand, refers to the difference in energy between the s and p orbitals within the same energy level or shell. In the context of S-H bonding, the s/p gap is not a significant factor, as sulfur uses its 3p orbital for bonding and hydrogen only has a 1s orbital.

In summary, the energy overlap between the 3p orbital of sulfur and the 1s orbital of hydrogen allows for the formation of a chemical bond between these two elements. The s/p gap is not a crucial factor in the bonding of S and H, as they bond using different types of orbitals (3p for sulfur and 1s for hydrogen).

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6) The amount of the O₂ are used to produce the 0.72 L of CO₂ gas at the standard temperature and the pressure is 0.10 g.

7) If 73 g of the aluminum chloride will decomposes, the molecules of th chlorine gas is 3.25 × 10²² molecules.

6) The chemical equation is as :

C₃H₈ +    5O₂    ---->   3CO₂  +  4H₂O

The ideal gas equation is as :

P V = n R T

Where,

The Pressure, P = 1 atm

The temperature, T = 273 K

The volume, V = 0.72 L

The gas constant, R = 0.823 L atm K⁻¹mol⁻¹

The moles, n = ?

n = P V / R T

n = ( 1 × 0.72 ) / 0.823 × 273

n = 0.0032 mol

The mass of O₂ = moles × molar mass

The mass of  O₂ = 0.0032 × 32

The mass of  O₂ = 0.10 g

7) The chemical equation is :

2AICl₃ --> 2Al+ 3Cl₂

The mass of  AICl₃ = 73 g

The number of the moles of  AICl₃ = mass / molar mass

The number of the moles of  AICl₃ = 73 / 133.33

The number of the moles of  AICl₃ = 0.54 mol

The number of the molecules = 0.54 × 6.022 × 10²²

The number of the molecules of  AICl₃ = 3.25 × 10²² molecules.

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