By Rolle's theorem, there are at least two points on the interval [0,5] where the derivative of f(x) is equal to zero, namely x = 5/3 and x = 5/2.
Now, let's apply this theorem to the given function f(x) = x(x-5)^2 on the interval [0,5]. First, we need to check if the function satisfies the conditions of Rolle's theorem.
The function f(x) is a polynomial, and we know that polynomials are continuous and differentiable everywhere. Therefore, f(x) is continuous on the interval [0,5] and differentiable on the open interval (0,5).
Next, we need to check if f(0) = f(5). Evaluating the function at the endpoints of the interval, we get:
f(0) = 0(0-5)² = 0
f(5) = 5(5-5)² = 0
Since f(0) = f(5) = 0, we can conclude that Rolle's theorem applies to the function f(x) on the interval [0,5].
Finally, we need to find the point(s) that are guaranteed to exist by Rolle's theorem. According to the theorem, there must be at least one point c in (0,5) such that f'(c) = 0.
To find the derivative of f(x), we need to use the product rule and the chain rule:
f'(x) = (x-5)² + x(2(x-5)) = 3x² - 20x + 25
Now, we need to find the value(s) of x in (0,5) that make f'(x) = 0:
3x² - 20x + 25 = 0
Using the quadratic formula, we get:
x = (20 ± √(20² - 4(3)(25))) / (2(3)) = (20 ± 5) / 6
x = 5/3 or x = 5/2
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Using the margin of error formula from Chapter 8, construct a confidence interval for the following problem. A survey of 500 randomly selected students at a university found that 435 students felt that there is not enough parking on campus. Find the 90% confidence interval for the proportion of all students at this university who think that there isn’t enough parking. What general statement does this interval all you to make about the parking situation?
90% confidence interval is (0.833, 0.907). The general statement is given below.
The sample proportion of students who felt that there is not enough parking on campus is:
p = 435/500 = 0.87
The margin of error for a 90% confidence interval can be calculated using the formula:
ME = z*sqrt(p(1-p)/n)
where z is the critical value from the standard normal distribution corresponding to a 90% confidence level, which is 1.645 for a two-tailed test.
Substituting the values, we get:
ME = 1.645sqrt(0.87(1-0.87)/500) ≈ 0.037
The 90% confidence interval for the proportion of all students who think that there isn’t enough parking is:
p ± ME = 0.87 ± 0.037
= (0.833, 0.907)
We can be 90% confident that the true proportion of all students who think that there isn’t enough parking lies between 0.833 and 0.907.
Since the confidence interval does not contain 0.5, we can conclude that more than half of the students at the university feel that there is not enough parking on campus. This interval allows us to make a general statement that a large proportion of the students at the university think that there is not enough parking.
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By squaring the deviations, you make them positive numbers, and the sum will also be ____.
By squaring the deviations from the mean, we make them positive numbers, and the sum of the squared deviations will also be a positive number.
What is deviation?In mathematics and statistics, deviation refers to the difference between a value and a reference value or an expected value. More specifically, deviation is a measure of how far a set of numbers is spread out from their average value or the central point.
According to given information:By squaring the deviations from the mean, we make them positive numbers, and the sum of the squared deviations will also be a positive number. This is because squaring any number makes it positive, regardless of whether the original number was positive or negative.
Additionally, squaring the deviations before summing them up allows us to give more weight to larger deviations from the mean. This is because squaring a larger deviation will result in a much larger value than squaring a smaller deviation, which helps to highlight the effect of outliers or extreme values in the data set.
The sum of the squared deviations is used in many statistical calculations, including calculating the variance and standard deviation of a data set, which are measures of the spread of the data.
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The Booster Club at Martin MS is selling spirit buttons for homecoming. The buttons cost $0.75 to make and will be sold for $2 each. How many buttons, b, must be sold to make a profit of $500? A. $500 = $2b - $0.75b B. $500 = $2b + $0.75b C. $500 + $2b = $0.75b D. $500 - $0.75b = $2b
There are 182 buttons that have to be sold to make a profit of $500. And, the equation that represents the given situation is [tex]\$500 = \$2b + \$0.75b[/tex] or [tex]\$500 - \$0.75b = \$2b[/tex] . Therefore, options B and D are true.
Using the idea behind the equation that says,
A set of numerical variables and functions coupled via the use of operations like addition, subtraction, multiplication, and division make form an equation.
Given that,
For homecoming, the Booster Club at Martin Middle School is selling pride buttons.
And, The buttons cost $0.75 to make and will be sold for $2 each.
Let us assume that,
Number of buttons = b
Since we have to calculate the number of buttons to make a profit of $500.
Hence the equation can be written as,
[tex]\$500 = \$2b + \$0.75b[/tex]
Simplify the equation for b,
[tex]\$500 = \$2.75b[/tex]
Divide both sides by 2.75,
[tex]b = \dfrac{500}{2.75}[/tex]
[tex]b = 182[/tex]
Therefore, the correct option is B and D.
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The rate of change in any speed of the average students ds/dx = 3 (x+4) ^1/2 , where x is the number lessons the student has had and s is in entries per minutes.(a) Find the data entry speed as a function of the number or lessons if the average student can complete 12 entries per minute with no lessons (x = 0). (b) How many entries per minute can the average student complete after 12 lessons ?
a) The data entry speed as a function of the number of lessons x is given by s(x) = 2[tex](x+4)^{\frac{\frac{3}{2}}{3}[/tex] + 10.
b) The average student can complete 26 entries per minute after 12 lessons.
(a) To find the data entry speed as a function of the number of lessons x, we need to integrate the given rate of change function ds/dx = 3(x+4)^1/2 with respect to x:
s(x) = ∫ 3[tex](x+4)^{\frac{1}{2}}[/tex] dx
Using the power rule of integration, we get:
s(x) = 2[tex](x+4)^{\frac{\frac{3}{2}}{3}[/tex] + C
where C is the constant of integration. Since the average student can complete 12 entries per minute with no lessons (x = 0), we can find the value of C as follows:
12 = 2[tex](0+4)^{\frac{\frac{3}{2}}{3}[/tex] + C
C = 10
Substituting C back into the equation for s(x), we get:
s(x) = 2[tex](x+4)^{\frac{\frac{3}{2}}{3}[/tex] + 10
(b) To find how many entries per minute the average student can complete after 12 lessons (x = 12), we simply substitute x = 12 into the equation for s(x) that we found in part (a):
s(12) = 2[tex](12+4)^{\frac{\frac{3}{2}}{3}[/tex] + 10
s(12) = 26
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This is due like right now so someone please help me :,(
Answer:
Step-by-step explanation:
Complementary Angles add up to 90°
90°-46°=44°
∠m = 44°
t test for two independent samples - two-tailed example:True or FalseWhen finding the critical t-scores that forms the boundaries of the critical region for α = 0.05 you divide the α 0.05 by 2 and use 0.0250 to find the t-scores
It is true that when conducting a t-test for two independent samples with a two-tailed example and α = 0.05, you divide the α by 2 (0.05/2 = 0.025) to find the critical t-scores that form the boundaries of the critical region. This is because you are considering both tails of the distribution.
True. When conducting a t test for two independent samples with a two-tailed example, we need to find the critical t-scores that form the boundaries of the critical region for α = 0.05. To do this, we divide the α value of 0.05 by 2 to get 0.0250, and then use this value to find the t-scores using a t-distribution table or calculator. This is necessary because we are looking at the possibility of a significant difference in either direction, hence the two-tailed example.
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Determine the choice that illustrates the commutative property for (a + b) + c = A. a + (b + c) B. c + (a + b) C. a + b + c D. c (a + b)
The answer of the given question based on the commutative property is , choice B: c + (a + b).
What is commutative property?The commutative property is a fundamental property of some mathematical operations, which states that the order of the operands (inputs) can be changed without affecting the result. In other words, the commutative property means that the operation is independent of the order in which the operands are presented.
The commutative property of addition states that the order of the addends can be changed without changing the sum. In other words, a + b = b + a.
Using this property, we can rearrange the terms in the equation (a + b) + c = A to get:
c + (a + b) = A
This is the same as choice B: c + (a + b). Therefore, the choice that illustrates the commutative property for (a + b) + c is B.
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A rectangular page is to contain 29 square inches of print. The margins on each side are 1 inch. Find the dimensions of the page such that the least amount of paper is used.
______in (smaller value)
________in (larger value)
Find the point on the graph of the function that is closest to the given point. f(x) = x2 (21) (x, y) -
1. The dimensions of the printed area are approximately:
4.22 in (smaller value)
6.89 in (larger value).
2. An approximation for t, we can use it to find the point on the graph of f(x) that is closest to (x, y):
t = approximate solution from Newton's method
x-coordinate: t
y-coordinate: [tex]t^2 (21).[/tex]
Let the width of the printed area be x and the length of the printed area be y.
Then the total area of the page, including margins, is:
A = (x + 2)(y + 2)
The area of the printed portion is:
xy = 29
We want to minimize the total area, subject to the constraint that the printed area has an area of 29 square inches.
Using the constraint, we can solve for y in terms of x:
y = 29/x
Substituting this into the equation for A, we get:
A = (x + 2)(29/x + 2)
Expanding this expression, we get:
A = 29 + 2x + 58/x + 4
A = 2x + 58/x + 33.
To find the minimum value of A, we take the derivative with respect to x and set it equal to zero:
[tex]dA/dx = 2 - 58/x^2 = 0[/tex]
Solving for x, we get:
[tex]x = \sqrt{(58)}[/tex]
Substituting this back into the equation for y, we get:
[tex]y = 29/\sqrt{(58) }[/tex]
Therefore, the dimensions of the printed area are approximately:
4.22 in (smaller value)
6.89 in (larger value)
To find the point on the graph of the function [tex]f(x) = x^2 (21)[/tex]that is closest to the point (x, y), we can use the distance formula:
[tex]d = \sqrt{((x - t)^2 + (y - f(t))^2) }[/tex]
where t is the value of x that corresponds to the closest point on the graph, and[tex]f(t) = t^2 (21)[/tex]
We want to minimize d, so we take the derivative of d with respect to t and set it equal to zero:
[tex]dd/dt = (x - t) - 2t(21)(y - f(t)) = 0[/tex]
Expanding f(t), we get:
f(t) = 21t^2
Substituting this into the equation for dd/dt, we get:
[tex]dd/dt = (x - t) - 42ty + 42t^3 = 0[/tex]
Solving for t is difficult, but we can use an iterative numerical method, such as Newton's method, to approximate the solution.
We can start with an initial guess, [tex]t_0[/tex] , and use the iteration:
[tex]t_{n+1} = t_n - dd/dt(t_n) / d^2d/dt^2(t_n)[/tex]
where [tex]dd/dt(t_n)[/tex] is the value of dd/dt at [tex]t_n[/tex], and [tex]d^2d/dt^2(t_n)[/tex] is the second derivative of d with respect to t evaluated at[tex]t_n.[/tex]
We can continue this iteration until the value of [tex]t_n[/tex] stops changing or until we reach a desired level of accuracy.
Once we have an approximation for t, we can use it to find the point on the graph of f(x) that is closest to (x, y):
t = approximate solution from Newton's method.
x-coordinate: t
y-coordinate: [tex]t^2 (21).[/tex]
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If 10 tulips cost $7.80 how much would 1 tulip cost
Answer:
$0.78
Step-by-step explanation:
You divide the $7.80 by 10 to get the cost of one tulip.
The economic impact of fishing for nearly all great lakes states should fall within what range (in millions of dollars)?
The economic impact of fishing for nearly all great lakes states varies, but according to a report by the U.S. Fish and Wildlife Service, it falls within the range of $1 to $8 billion (in millions of dollars).
This impact includes the economic contributions of recreational fishing, commercial fishing, and related industries such as tourism and boat manufacturing. The exact amount varies from state to state and from year to year depending on factors such as weather, fish populations, and fishing regulations.
The Great Lakes region of the United States is home to some of the largest freshwater bodies in the world and boasts a rich variety of fish species. Fishing is an important economic activity in the region, contributing billions of dollars to the local and national economy. The economic impact of fishing in the Great Lakes region includes not only the direct revenue generated by commercial and recreational fishing, but also the indirect and induced effects of fishing-related industries such as tourism and boat manufacturing.
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Five thousand dollars is deposited into a savings account at 7.5% interest compounded continuously. (a) What is the formula for A(t), the balance after t years? (b) What differential equation is satisfied by A(t), the balance after t years? (c) How much money will be in the account after 2 years? (d) When will the balance reach $7000 ? (e) How fast is the balance growing when it reaches $7000 ? (a) A(t)= (b) A
′
(t)= (c) $ (Round to the nearest cent as needed.) (d) After years the balance will reach $7000. (Round to one decimal place as needed.) (e) The investment is growing at the rate of $ per year. (Type an integer or decimal rounded to two decimal places as needed.)
a) The Formula for A(t) is A(t) = 5000 [tex]e^{0.075t[/tex]
b) The differential equation is satisfied by A(t) is
dA/ dt = 375 [tex]e^{0.075t[/tex]
c) Amount after 2 year is $5, 809.
d) t= 4.48 years
We have,
R= 7.5%
P= $5000
a) The Formula for A(t) is
A(t) = P[tex]e^{rt[/tex]
Where P is Principal , t is time.
So, A(t) = 5000 [tex]e^{0.075t[/tex]
b) The differential equation is satisfied by A(t) is
dA/ dt = 375 [tex]e^{0.075t[/tex]
c) Amount after 2 year
A(2) = 5000 (2.71828[tex])^{0.15[/tex]
A(2) = 5000 x 1.1618
A(2)= $5, 809.
d) 7000 = 5000 [tex]e^{0.075t[/tex]
[tex]e^{0.075t[/tex]= 1.4
Taking log on both side
0.075t log e= log 1.4
0.075t= 0.14612803567/0.4342944819
0.075t= 0.3364
t= 4.48 years
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The ratio of the measures of the sides of a triangle is 9:12:5. If the perimeter of the triangle is 130 feet, find the measures of the sides.
The sides of the triangle are 45 feet, 60 feet and 25 feet.
The Perimeter of Triangle
The perimeter of the triangle is the sum of all the side lengths of the triangle.
Where a, b and c are three sides of a triangle.
Given that the sides of a triangle are in a ratio of 9:12:5 and its perimeter is 130 feet.
Let us consider that x is the basic measurement of a side of the triangle, then the ratio of the triangle is given as,
Ratio = 9x : 12x : 5x
In this case, the perimeter is,
The side of the triangle is given below.
Hence the sides of the triangle are 45 feet, 60 feet and 25 feet.
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The functions in this problem are exponential. Please use 4 or more decimals. a. Use the information about (a) to find the following g(0) = 20 q(1) = 22.2 9(2) = 24.642 (3) = 27.35262 i. Initial value: ii. 1-unit growth/decay factor: iti. 1-unit percent change iv. Function:
The initial value is 20, the 1-unit growth/decay factor is 1.11, the 1-unit per cent change is 11%, and the function is g(x) = 20(1.11)^x, where x is the input.
Based on the given information, we can determine that the functions in this problem are exponential. To find the initial value, we can simply plug in 0 for the input of the function g(x) and solve for g(0) = 20.
To find the 1-unit growth/decay factor, we can subtract the output of the function at x=0 from the output of the function at x=1 and divide by the output at x=0. This gives us (g(1)-g(0))/g(0) = (22.2-20)/20 = 0.11.
To find the 1-unit percent change, we can multiply the 1-unit growth/decay factor by 100 to get 11%.
Using these calculations, we can write the function as g(x) = 20(1.11)^x. To find g(2) and g(3), we can simply plug in the respective values for x and round to 4 or more decimals.
g(2) = 20(1.11)^2 = 24.4421
g(3) = 20(1.11)^3 = 27.1213
Therefore, the initial value is 20, the 1-unit growth/decay factor is 1.11, the 1-unit percent change is 11%, and the function is g(x) = 20(1.11)^x, where x is the input.
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Question 5. Ann is making a bowl of Laksa. In her Laksa she likes to have a bit of a range of proteins (chicken c, fish f, and tofu t), a good amount of green vegetables g; and a good amount of noodles n. These preferences can be represented by the utility. a) For each of the following, determine whether Ann's preferences have this property. If they do, prove this. If not, provide a counter-example. i. Rational ii. Weakly Monotone iii. Strongly Monotone iv. Locally Non-satiated
In conclusion, Ann's preferences are likely to be rational, weakly.
In order to determine if Ann's preferences have certain properties, we need to first understand what those properties mean in terms of preferences.
i. Rational:
Rationality is the property of preferences that requires them to be transitive. In other words, if Ann prefers A to B, and B to C, then she must prefer A to C. This is a reasonable assumption for any rational person making choices.
ii. Weakly Monotone:
Weak monotonicity is the property of preferences that requires them to be non-decreasing. In other words, if Ann prefers A to B, then she must prefer any combination of A and B where there is more of A and less of B. For example, if she prefers a bowl of Laksa with 1 chicken breast and 1 fish fillet to a bowl with 1 chicken breast and 1 tofu slice, then she should also prefer a bowl with 2 chicken breasts and 1 fish fillet to a bowl with 1 chicken breast and 1 fish fillet.
iii. Strongly Monotone:
Strong monotonicity is a stronger version of weak monotonicity that requires preferences to be strictly increasing. In other words, if Ann prefers A to B, then she must strictly prefer any combination of A and B where there is more of A and less of B. For example, if she prefers a bowl of Laksa with 1 chicken breast and 1 fish fillet to a bowl with 1 chicken breast and 1 tofu slice, then she must strictly prefer a bowl with 2 chicken breasts and 1 fish fillet to a bowl with 1 chicken breast and 1 fish fillet.
iv. Locally Non-satiated:
Local nonsatiation is the property of preferences that requires them to never be satisfied with any amount of a good. In other words, if Ann prefers A to B, then she must always prefer a little bit more of A to the same amount of B. This is a reasonable assumption for any person making choices, since there is always some amount of a good that would be preferred to the current amount.
a) Now let's consider each property in turn and determine whether Ann's preferences have that property or not.
i. Rational:
Ann's preferences are assumed to be rational, since rationality is a basic requirement for any preferences.
ii. Weakly Monotone:
Ann's preferences for a range of proteins, green vegetables, and noodles in her Laksa are likely to be weakly monotone, since it is reasonable to assume that if she prefers some amount of a good to another, she would prefer any combination of the two where there is more of the preferred good.
iii. Strongly Monotone:
Ann's preferences are not likely to be strongly monotone, since it is possible that she may have some preferences for specific combinations of goods that are not strictly increasing or decreasing. For example, she may prefer a bowl of Laksa with 1 chicken breast and 1 fish fillet to a bowl with 2 chicken breasts and no fish fillet.
iv. Locally Non-satiated:
Ann's preferences are likely to be locally non-satiated, since it is reasonable to assume that she would always prefer a little bit more of a good to the same amount of that good. For example, if she likes a bowl of Laksa with 1 chicken breast, 1 fish fillet, and 1 tofu slice, she would likely prefer a bowl with 1.1 chicken breasts, 1.1 fish fillets, and 1.1 tofu slices to the same bowl with 1 chicken breast, 1 fish fillet, and 1 tofu slice.
In conclusion, Ann's preferences are likely to be rational, weakly
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The data in the scatterplot below are an individual's weight and the time it takes (in seconds) on a treadmill to raise his or her pulse rate to 140 beats per minute. The o's correspond to females and the +'s to males. Which of the following conclusions is most accurate?
Based on the information provided about the scatterplot, we can draw a conclusion by analyzing the data points and their correlation with individual's weight and time it takes to raise their pulse rate to 140 beats per minute.
Step 1: Observe the scatterplot and identify the patterns or trends in the data.
Step 2: Compare the o's (females) and the +'s (males) to see if there are noticeable differences or similarities in the data.
Step 3: Determine if there is a positive, negative, or no correlation between weight and time taken to reach 140 beats per minute.
Step 4: Based on the observations, draw a conclusion about the most accurate statement regarding the data. Unfortunately, I cannot see the scatterplot itself, so I am unable to provide you with the most accurate conclusion.
However, using these steps, you can analyze the scatterplot and determine the correct conclusion.
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WORTH 45!! What are two arithmetic means between 5 and 23?
Answer:
5+(-9)=14
Step-by-step explanation:
Answer:
14 and 23
Step-by-step explanation:
To find two arithmetic means between 5 and 23, we need to first find the common difference between consecutive terms.
The common difference (d) between consecutive terms in an arithmetic sequence can be found using the formula:
d = (an - a1) / (n - 1)
where a1 is the first term, an is the last term, and n is the number of terms.
In this case, a1 = 5, an = 23, and n = 3 (since we want to find two means, there will be a total of 4 terms in the sequence). Plugging these values into the formula, we get:
d = (23 - 5) / (3 - 1) = 9
So the common difference between consecutive terms is 9. To find the first mean, we add the common difference to the first term:
First mean = 5 + 9 = 14
To find the second mean, we add the common difference to the first mean:
Second mean = 14 + 9 = 23
Therefore, the two arithmetic means between 5 and 23 are 14 and 23.
6) A and B are independent events. P(A) = 0.8 and P(B) = 0.2. Calculate P(B | A).
The probability of event B occurring given that event A has occurred is 0.2, which is the same as the probability of event B occurring without considering event A.
Since events A and B are independent, the occurrence of event A does not affect the probability of event B occurring. Therefore, the conditional probability of B given A is equal to the probability of B, which is 0.2 in this case.
The conditional probability P(B | A) can be calculated using the formula:
P(B | A) = P(A ∩ B) / P(A)
Since A and B are independent events, their intersection (A ∩ B) is the product of their probabilities:
P(A ∩ B) = P(A) * P(B) = 0.8 * 0.2 = 0.16
Therefore, the conditional probability of B given A is:
P(B | A) = P(A ∩ B) / P(A) = 0.16 / 0.8 = 0.2
In other words, the occurrence of event A does not provide any additional information about the probability of event B occurring.
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The varsity soccer team has 20 players. Three of the players are trained to be goalies while the remaining 17 can play any position. Only 11 of the players can be on the field at once. If 11 of the 20 players are randomly selected, what is the probability that exactly one goalie will be selected?
The probability that one goalie will select [tex]58344[/tex] approx.
What do you mean by probability?Probability is a measure of the likelihood or chance of an event occurring.
It is expressed as a number between [tex]0[/tex] and [tex]1[/tex], where [tex]0[/tex] represents an impossible event (i.e., an event that cannot occur), and [tex]1[/tex] represents a certain event (i.e., an event that is guaranteed to occur).
For events that are neither impossible nor certain, the probability is somewhere between [tex]0[/tex] and [tex]1[/tex] with higher probabilities indicating that the event is more likely to occur.
According to the problem,
[tex]17C10 = 19448[/tex]
To calculate by hand: divide the number of possible arrangements for [tex]10[/tex] players, which is [tex]10[/tex],
By the sum of the choices for the first player, the second player, and each subsequent player, in order: [tex]16[/tex] for the second player, [tex]15[/tex] for the third, [tex]12[/tex] for the fourth, [tex]10[/tex] for the eighth, [tex]9[/tex] for the ninth, and [tex]8[/tex] for the tenth. [tex](17 16 15 14 13 12 11 10 9[/tex] × [tex]8[/tex][tex])/10![/tex]
[tex]17C7 = 19448[/tex]
[tex]10[/tex] row to calculate by hand: [tex]17[/tex] choices for the first nonplayer multiplied by [tex]16[/tex] for the second, [tex]15[/tex] for the third, [tex]14[/tex] for the fourth, [tex]13[/tex] for the fifth, [tex]12[/tex] for the sixth, and [tex]11[/tex] for the seventh, divided by [tex]7[/tex], the total number of possible arrangements for [tex]7[/tex] nonplayers. [tex](7,17,16,15,14,13,,12,11,6)![/tex]
Therefore the final answer is [tex]3[/tex]×[tex]19448 = 58344[/tex]
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Using the formula for combinations, we can calculate the probability that exactly one goalie is selected when 11 players are randomly chosen from a group of 20 where 3 are goalies. We calculate the number of ways to pick 1 goalie from 3, and 10 players from the remaining 17, these are our favorable outcomes. The total number of outcomes is the number of ways to pick 11 players from 20. Finally, the ratio of favorable to total outcomes is our answer.
Explanation:This question is one of combinatorics, a topic in mathematics. We want to find the probability that exactly one goalie is included when 11 players are randomly selected from a group of 20, where 3 are goalies and 17 are not.
Step 1: We need to determine the number of ways to choose 1 goalie out of 3, which we denote as C(3,1). Using the formula for combinations, C(3,1) is equal to 3.
Step 2: We need to determine the number of ways to choose 10 players from the remaining 17 players (as we already chose 1 goalie), which we denote as C(17,10). This can be found using the combination formula as well.
Step 3: The number of favorable outcomes is the product of the outcomes from Step 1 and Step 2 which represent choosing 1 goalie and the rest of the players respectively.
Step 4: The total number of outcomes is the number of ways to choose 11 players from all 20, denoted as C(20,11).
Step 5: The probability we seek is the ratio of the number of favorable outcomes to the total number of outcomes. So we divide the product from Step 3 by the result from Step 4.
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7. Cars used to be built as rigid as possible to withstand collisions. Today, though, cars are designed to have "crumple zones" that collapse upon impact. What is the advantage of this new design?
Answer:
Step-by-step explanation:
The advantage of designing cars with crumple zones that collapse upon impact is that it helps to absorb the energy of a collision, which can reduce the amount of force that is transferred to the occupants of the vehicle. When a car collides with another object, the kinetic energy of the car is converted into other forms of energy, such as deformation of the car's structure and heat. By designing the car to crumple in certain areas upon impact, the energy of the collision can be dissipated over a longer period of time, reducing the peak force experienced by the occupants of the car. This can help to reduce the risk of injury or death in a collision. Additionally, the deformation of the car's structure can help to redirect the car's momentum, which can reduce the severity of the collision or prevent the car from spinning out of control. Overall, the use of crumple zones in car design is a significant safety improvement that can help to protect drivers and passengers in the event of a collision.
There were fifteen people who participated in the class between the ages of 25 and 45. Use the histogram to answer the question.How many participants had a heart rate between 120 and 130 bpm?
According to the histogram, a total of five participants had a heart rate between 120 and 130 bpm.
Review the histogram: Look at the histogram and locate the section that represents heart rates between 120 and 130 bpm.
Count the bars: Count the number of bars within that section.
Interpret the bars: Each bar represents one participant, so the total number of bars counted in the previous step represents the number of participants with heart rates between 120 and 130 bpm.
Identify the answer: The total number of bars counted is the answer to the question, which is five.
Therefore, according to the histogram, five participants had a heart rate between 120 and 130 bpm.
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Help Please! What are the measures of ∠1 and ∠2?
Measures of m∠1 = 67.4°, m∠2 = 104.5°
What are the measures of angle?
When two lines or rays intersect at a single point, an angle is created. The vertex is the term for the shared point. An angle measure in geometry is the length of the angle created by two rays or arms meeting at a common vertex.
Here, we have
The exterior angle 121.8° is the sum of the remote interior angles 17.3° and angle 2. Then ...
angle 2 = 121.8° -17.3° = 104.5° . . . . . . . matches the second choice
Angle 2 is the exterior angle of the top triangle. It, too, is the sum of the remote interior angles:
104.5° = angle 1 + 37.1°
angle 1 = 104.5° -37.1° = 67.4°
Hence, the measures of m∠1 = 67.4°, m∠2 = 104.5°.
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If the functionf(x) satisfies x→1lim x 2 −1f(x)−2 =π evaluate x→1lim f(x)
If the function f(x) satisfies x→1lim x 2 −1f(x)−2 =π Therefore,
x→1 lim f(x) = 2π / 2 = π.
To evaluate x→1 lim f(x),
we can use L'Hôpital's rule:
x→1 lim f(x) = x→1 lim [ ([tex]x^2[/tex] - 1) / 2 ] × f(x)
Using L'Hôpital's rule:
x→1 lim [ ([tex]x^2[/tex] - 1) / 2 ] × f(x) = x→1 lim [ 2x / 2 ] × f(x) = x→1 lim x × f(x)
So now we need to evaluate
x→1 lim x × f(x).
We can use the fact that x→1 lim [[tex]x^2[/tex] - 1 ] / (x - 1) = 2
(this is the derivative of [tex]x^2[/tex] with respect to x evaluated at x=1), so:
x→1 lim [ [tex]x^2[/tex] - 1 ] / (x - 1) × [ (x - 1) / x ] × f(x) = x→1 lim [ x + 1 ] × f(x) = 2π
Therefore, x→1 lim f(x) = 2π / 2 = π.
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Solve 15x⁴ + x³ - 52x² + 20x + 16 = 0 by Equations Reducible to Quadratic Equations. need this asap.
Therefore, the solutions of the equation 15x⁴ + x³ - 52x² + 20x + 16 = 0 Reducible to Quadratic Equations are:
x₁ = (±2/√5
x₂ = (±2/√3)
x₃ = 0
x₄ = (±1/20)
Quadratic equation calculation.
To solve 15x⁴ + x³ - 52x² + 20x + 16 = 0 by Equations Reducible to Quadratic Equations, we can use the substitution method. Let's first substitute x² = y and rewrite the equation as:
15y² + y - 52y + 20√y + 16 = 0
Now, let's group the terms:
(15y² - 52y + 16) + (y + 20√y) = 0
Let's solve the first quadratic equation:
15y² - 52y + 16 = 0
We can factor this quadratic equation as:
(3y - 4)(5y - 4) = 0
So, the solutions are:
y₁ = 4/5 and y₂ = 4/3
Now, let's solve the second quadratic equation:
y + 20√y = 0
We can factor out y:
y(1 + 20√y) = 0
So, the solutions are:
y₃ = 0 and y₄ = (-1/20)² = 1/400
Now, let's substitute back y = x²:
x₁ = √(y₁) = ±√(4/5) = ±(2/√5)
x₂ = √(y₂) = ±√(4/3) = ±(2/√3)
x₃ = √(y₃) = 0
x₄ = √(y₄) = ±(1/20)
Therefore, the solutions of the equation 15x⁴ + x³ - 52x² + 20x + 16 = 0 are:
x₁ = (±2/√5)
x₂ = (±2/√3)
x₃ = 0
x₄ = (±1/20)
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(1 point) Evaluate the indefinite integral. si sin(4x) cos(7x) dx = +C
The solution would be;
⇒ si sin(4x) cos(7x) dx = (1/2) [-cos(11x)/11 + cos(3x)/3] + C.
Now, For evaluate the indefinite integral of sin(4x) cos(7x) dx, we can use the trigonometric identity as;
⇒ sin(A)cos(B) = (1/2)[sin(A + B) + sin(A - B)]
Hence, Applying this identity as;
⇒ sin(4x) cos(7x) = (1/2)[sin(4x + 7x) + sin(4x - 7x)]
= (1/2)[sin(11x) + sin(-3x)]
= (1/2)[sin(11x) - sin(3x)]
Therefore, the indefinite integral of sin(4x) cos(7x) dx is given by:
∫ sin(4x) cos(7x) dx = (1/2) ∫ [sin(11x) - sin(3x)] dx
= (1/2) [-cos(11x)/11 + cos(3x)/3] + C
Hence, The solution would be;
⇒ si sin(4x) cos(7x) dx = (1/2) [-cos(11x)/11 + cos(3x)/3] + C.
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what is the measure of angle OAC
Answer:
60
Step-by-step explanation:
Find the difference. Write your answer in simplest form. 6 1/2 - 2 11/15
A. 3 3/5
B. 4 2/5
C. 4 5/6
D. 3 9/15
The difference between 6 1/2 and 2 11/15 is 4 2/5.
What is number?Number is a mathematical object used to count, measure, and label. It is an abstract concept that has been used since ancient times and is an important part of mathematics. Numbers are used to represent quantities, such as distance, time, and money. They can also be used to represent abstract ideas such as order in a sequence or the size of a set. Numbers can be represented in various ways, such as symbols, digits, and words. Numbers are also used in many everyday contexts, such as telephone numbers, dates, and scores.
To calculate the difference, we first need to convert 2 11/15 into an improper fraction. To do so, we multiply the denominator (15) by the whole number (2) and add the numerator (11) to get an improper fraction of 31/15.
Next, we subtract 31/15 from 6 1/2. To do so, we need to convert 6 1/2 into an improper fraction. We multiply the denominator (2) by the whole number (6) and add the numerator (1) to get an improper fraction of 13/2.
We then subtract 31/15 from 13/2 to get 4 2/5. This is the difference between 6 1/2 and 2 11/15, written in simplest form.
Therefore, the answer is 4 2/5.
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A basket contains four apples, four peaches, and four pears. You randomly select and eat three pieces of fruit. The first piece is an apple, the second piece is a peach, and the third is a pear.
Question: P(Apple,Peach,&Pear)= provide your answer as a percentage. Round to the nearest hundreth.
The probability of selecting apple, a peach and a pear in that order is [tex]4.85%[/tex]%.
What is the probability of selecting the fruit in order?In this basket, we have 4 apples, 4 peaches, and 4 pears and will select three pieces of fruit without replacement.
The probability of selecting an apple first is 4/12.
The probability of selecting a peach second is 4/11.
The probability of selecting a pear third is 4/10.
P(Apple, Peach, & Pear) = (4/12) * (4/11) * (4/10)
P(Apple, Peach, & Pear) = 64/1320
P(Apple, Peach, & Pear) = 8/165
P(Apple, Peach, & Pear) = 0.04848484848
P(Apple, Peach, & Pear) = 4.85%
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What is 57,309 rounded to the nearest ten
Answer:
57,310
Step-by-step explanation:
So you can either round up to 57,310 or round down to 57,300 and 57,309 is one away from 57,310 and 9 away from 57,300 so it’s closer to 57,310 therefore 57,310 is the answer
To round 57,309 to the nearest ten, we look at the ones place digit and round up if the digit is 5 or greater. In this case, since the ones place digit is 9, we round up the tens digit to 1.
Explanation:To round 57,309 to the nearest ten, we look at the digit in the ones place, which is 9. Since 9 is greater than or equal to 5, we round up the tens digit to the next number. Therefore, 57,309 rounded to the nearest ten is 57,310.
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James needs to attach a stabilizing wire to a tall tower. The wire is about 200 feet long and should be attached to the tower at a height of 100 feet. Assume that the ground around the tower is level and that the entire length of the wire is used. Find the distance from the tower to the point where the wire is attached to the ground
According to a CNN poll taken in February of 2008, 67% of respondents disapproved of the overall job that President Bush was doing. Based on this poll, for samples of size 140, what is the mean number of American adults who disapprove of the overall job that President Bush is doing?
The mean number of American adults who disapprove of the overall job that President Bush is doing, based on a sample size of 140, is approximately 93.8.
To calculate the mean, we need to first understand what it represents. The mean is a measure of central tendency, which represents the average value of a set of data. In this case, we want to find the average number of American adults who disapprove of President Bush's overall job.
Since we know that 67% of respondents disapproved of President Bush's overall job, we can assume that this percentage also applies to the entire population of American adults.
To find the mean number of American adults who disapprove, we can use the formula:
mean = total / sample size
In this case, the total number of American adults who disapprove can be calculated as:
total = sample size x percentage who disapprove
total = 140 x 0.67
total = 93.8
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