Find the area inside one leaf of the rose:r = 6 sin (4theta)Previous Problem Problem List Next Problem (5 points) Find the area inside one leaf of the rose: r = 6 sin(40) The area is

The p-value (0.1334) is greater than the significance level (α = 0.01), we fail to reject the null hypothesis (H0). There isn't enough evidence to support the alternative hypothesis (Ha) that μ < 45 at the 0.01 significance level.

To find the value of the test statistic, we can use the formula:

t = (x - μ) / (s / √n)

where x is the sample mean, μ is the hypothesized population mean (from H0), s is the sample standard deviation, and n is the sample size.

Plugging in the values given, we get:

t = (44 - 45) / (5.3 / √36) = -1.70

To find the p-value, we need to find the area under the t-distribution curve to the left of -1.70. We can use a t-table or a calculator to find this probability. For α = 0.01 with 35 degrees of freedom (df = n - 1), the t-critical value is -2.718.

Since -1.70 > -2.718, the test statistic is not in the rejection region and we fail to reject the null hypothesis.

The p-value for this test is the probability of getting a t-value less than -1.70, which we can find using a t-table or a calculator. For 35 degrees of freedom, the p-value is approximately 0.0491 (or 0.049 in four decimal places). Since the p-value is greater than α, we fail to reject the null hypothesis.

Therefore, we can conclude that there is not enough evidence to support the claim that the population mean is less than 45 at a significance level of 0.01.

To answer your question, we'll use the appropriate technology to find the test statistic and p-value. Given the information:

H0: μ ≥ 45
Ha: μ < 45
Sample size (n) = 36
Sample mean (x) = 44
Sample standard deviation (s) = 5.3
Significance level (α) = 0.01

First, we'll find the test statistic using the formula:

t = (x - μ) / (s / √n)

t = (44 - 45) / (5.3 / √36) = -1 / (5.3 / 6) ≈ -1.135 (rounded to three decimal places)

Now, we'll find the p-value. Since we have a left-tailed test (μ < 45), we'll look for the area to the left of the test statistic in the t-distribution table. Using appropriate technology or software, we get:

p-value ≈ 0.1334 (rounded to four decimal places)

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The probability that the number of sales is 2 or 3 is 0.50" is TRUE.

Sales (x) --> Probability (P(x))
0 --> 0.10
1 --> 0.15
2 --> 0.20
3 --> 0.30
4 --> 0.20
5 --> 0.05

To determine if the probability of making 2 or 3 sales is 0.50, we need to add the probabilities for 2 and 3 sales:

P(2 or 3) = P(2) + P(3) = 0.20 + 0.30 = 0.50

Since the sum of the probabilities for 2 and 3 sales is 0.50, the statement "Given this distribution,

the probability that the number of sales is 2 or 3 is 0.50" is TRUE.

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The equation for the line that is perpendicular to y = 2x + 3 and passes through the point (-6/5, -7/5) is y = (-1/2)x - 3/5.

Suppose we have an equation for a straight line represented by y = mx + b. To find the slope of a line that is perpendicular to this line, we must first understand the relationship between the slopes of perpendicular lines.

So, the equation for a line perpendicular to y = 2x + 3 will have a slope of -1/2. Let's call this slope "m₂". The equation for the new line can be represented as y = m₂x + b₂, where b₂ represents the y-intercept of the new line. To determine the value of b₂, we need to know a point that lies on the new line.

One way to find a point on the new line is to use the point of intersection between the two lines. To find this point, we can solve the two equations simultaneously. Let's suppose the equation for the new line is y = (-1/2)x + b2. We can set this equation equal to the original equation y = 2x + 3 and solve for x and y:

(-1/2)x + b₂ = 2x + 3

(-5/2)x = 3 - b₂

x = (-2/5)(3 - b₂)

x = (-6/5) + (2/5)b₂

Now we can substitute this value of x into either equation and solve for y:

y = 2x + 3

y = 2((-6/5) + (2/5)b₂) + 3

y = (-12/5) + (4/5)b₂ + 3

y = (-7/5) + (4/5)b₂

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Complete Question:

What slope is required for a second equation if it produces a straight line that is perpendicular to the line from the original equation (y = 2x + 3)?

The prism below is made of cubes whose total volume is 9/16 ft²

A prism made of cubes is a three-dimensional shape that consists of multiple cubes arranged in a specific way. Prisms made of cubes are often used in mathematics to teach geometric concepts, such as volume and surface area.

We know that the volume of a cube = Side³

Prism is made up of 36 cubes.   (from the below figure)

Each cube has a side length of 1/4 ft.

The volume of each cube = Side³

The volume of each cube =  (1/4)³

The volume of each cube =  1/64

The volume of the prism = 36 x 1/64

The volume of the prism = 36/64

The volume of the prism = 9/16 ft²

Therefore, The volume of the prism is 9/16 ft².

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Answer: [tex]3{x^{2} } -3x-18[/tex]

Step-by-step explanation:  

distribute:

)(−3)(3+6)

)(3+6)−3(3+6)

+6)(3+6)−3(3+6)

+6x−3(3x+6)32+6−3(3+6)

3x2+6x−3(3x+6)32+6−3(3+6)

3x2+6x−3(3x+6)32+6−3(3+6)

3x2+6x−9x−1832+6−9−18

combine like terms:

x2+6x−9x−1832+6−9−18

3x2−3x−1832−3−18

solution:

3{x^{2} } -3x-18

The 95% confidence interval for the population mean (μ) is approximately ($3228.76, $3671.24).

To construct a 95% confidence interval for the population mean (μ) with a sample size of 28 teachers, a sample mean of $3450, and a standard deviation of $600, we will use the following formula:

Confidence Interval = Sample Mean ± (Critical Value × (Standard Deviation / √Sample Size))

First, we need to find the critical value for a 95% confidence interval. For a normal distribution, the critical value (Z-score) is approximately 1.96.

Next, we can plug the given values into the formula:

Confidence Interval = $3450 ± (1.96 × ($600 / √28))

Now, we can calculate the margin of error:

Margin of Error = 1.96 × ($600 / √28) ≈ $221.24

Finally, we can construct the confidence interval:

Lower Bound = $3450 - $221.24 ≈ $3228.76
Upper Bound = $3450 + $221.24 ≈ $3671.24

So, the 95% confidence interval for the population mean (μ) is approximately ($3228.76, $3671.24).

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The down payment going to be $60

A down payment is the amount of cash you put toward the sale price of a home. It reduces the amount of money you will have to borrow and is usually shown as a percentage of the purchase price.

The given parameters are

Cost of the car = $7,400

Tax to be paid = 7%

The percent of down payment is 15%

The amount traded in a vehicle worth $1,050.00,

This implies that

0.07*7400 = $518

Down payment = 0.15 * 7400 = $1110

Therefore The amount of down payment is $(1110-1050)

= $60

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The general solution for g(x) is g(x) =[tex]2x^(5/2) + 8/3x^(3/2)[/tex] + 10√x + C, where C is an arbitrary constant. This is the family of functions that satisfy g'(x) = [tex]5x²+4x+5/√x.[/tex]

To find all functions g such that g'(x) = 5x²+4x+5/√x, we need to integrate both sides of the equation with respect to x.

First, we can rewrite the right-hand side of the equation using the power rule for integration of [tex]x^n[/tex], which states that[tex]∫x^n dx = x^(n+1)/(n+1) + C,[/tex]where C is the constant of integration. Applying this rule, we get:

g'(x) = [tex]∫(5x²+4x+5)/√x dx[/tex]

g'(x) = [tex]5∫x^(3/2) dx + 4∫x^(1/2) dx + 5∫1/√x dx[/tex]

g(x) = [tex]5(2/5)x^(5/2) + 4(2/3)x^(3/2) + 5(2√x) + C[/tex]

g(x) = [tex]2x^(5/2) + 8/3x^(3/2) + 10√x + C[/tex]

Therefore, the general solution for g(x) is[tex]g(x) = 2x^(5/2) + 8/3x^(3/2) + 10√x + C[/tex], where C is an arbitrary constant. This is the family of functions that satisfy g'(x) = [tex]5x²+4x+5/√x.[/tex]

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The HALF column contains the rank of NONCONF, where values greater than 30 are ranked as 1 and values less than or equal to 30 are ranked as 0.

Based on the input and output datasets provided, it is likely that the following PROC RANK statement was used:

proc rank data=LEAGUES out=LEAGRANK groups=2 ties=low;

 var NONCONF;

 ranks HALF;

 where NONCONF > 30;

 ranks HALF / display=(noties);

run;

This statement performs the following actions:

The data option specifies the input dataset LEAGUES, and the out option specifies the output dataset LEAGRANK.

The groups option specifies the number of groups that the data will be divided into.

In this case, groups = 2 indicates that the data will be split into two groups based on the variable NONCONF.

The ties option specifies how to handle ties. ties=low means that if there is a tie, the lowest rank will be assigned.

The var statement specifies the variable to rank, which is NONCONF.

The ranks statement specifies the variable to store the ranks, which is HALF.

The where statement is used to exclude any observations where NONCONF is less than or equal to 30.

The display option is used to specify that tied values should not be displayed.

The resulting output dataset LEAGRANK contains the LEAGUE, NONCONF, and HALF columns.

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Correlation is a statistical measure that describes the strength and direction of a relationship between two variables. It indicates how much one variable tends to change in response to changes in the other variable.

To compute the correlation coefficient between two variables, we can use the following formula: r = [nΣxy - (Σx)(Σy)] / [√(nΣx^2 - (Σx)^2) √(nΣy^2 - (Σy)^2)]

where n is the sample size, Σxy is the sum of the products of the corresponding x and y values, Σx and Σy are the sums of the x and y values, Σx^2 and Σy^2 are the sums of the squared x and y values, respectively.

n = 4 (since we have 5 trees)

Σx = 12

Σy = 260

Σx^2 = 42

Σy^2 = 13200

Σxy = (2)(30) + (2)(40) + (3)(90) + (5)(100) = 830

r = [nΣxy - (Σx)(Σy)] / [√(nΣx^2 - (Σx)^2) √(nΣy^2 - (Σy)^2)]

r = [4(830) - (12)(260)] / [√(4(42) - (12)^2) √(4(13200) - (260)^2)]

r = 0.98

Therefore, the correlation coefficient between the height and base diameter of the five trees is 0.98, indicating a strong positive linear relationship between the two variables.

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The probability that the mean length of 8 randomly chosen items is less than 8.7 inches is approximately 0.8106 or 81.06%.

To solve this problem, we need to use the central limit theorem, which states that the distribution of sample means is approximately normal, regardless of the underlying distribution, as long as the sample size is large enough. In this case, we are given that the population is normally distributed, so we can apply the theorem directly.

First, we need to find the standard error of the mean, which is the standard deviation of the sample means, and is given by the formula:

SE = σ / √n

where σ is the standard deviation of the population, and n is the sample size. Plugging in the values given, we get:

SE = 1.6 / √8 = 0.566

Next, we need to standardize the sample mean using the z-score formula:

z = (x - μ) / SE

where x is the sample mean, μ is the population mean, and SE is the standard error of the mean. We want to find the probability that the sample mean is less than 8.7 inches, so we plug in the values given:

z = (8.7 - 8.2) / 0.566 = 0.884

Finally, we look up the probability corresponding to a z-score of 0.884 in the standard normal distribution table or calculator, and find:

P(z < 0.884) = 0.8106

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Constraints limit systems. Explicit constraints are defined, while implicit constraints are assumed. Dimensional and geometric constraints differ in their definitions.

Imperatives are constraints or limitations put on an article or framework to guarantee it capabilities as planned or meets specific prerequisites. Express limitations are those that are explicitly characterized and recorded, while certain requirements are those that are expected or seen yet not really archived.

Layered limitations determine the size, shape, and area of items or parts inside a framework, while mathematical imperatives characterize the connections between various parts or articles, like parallelism or oppositeness. The two kinds of requirements are significant in designing and plan, as they assist with guaranteeing that a framework or item is utilitarian, safe, and meets the ideal details.

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The equation for the nth term of the arithmetic sequence -8, -6, -4, -2, 0,... is A(n) = 2n - 10, where n is the index of the term.

The arithmetic sequence given is -8, -6, -4, -2, 0,.... The common difference between consecutive terms in the sequence is 2.

To find the equation for the nth term of an arithmetic sequence, we can use the formula

a_n = a_1 + (n-1)*d

where a_n is the nth term, a_1 is the first term, n is the index of the term, and d is the common difference.

In this sequence, a_1 = -8 and d = 2. Substituting these values into the formula, we get

a_n = -8 + (n-1)*2

= -8 + 2n - 2

= 2n - 10

Therefore, the equation for the nth term of the sequence is 2n - 10.

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Answer: it is most likely d

Step-by-step explanation: it is d because the highest dot is on 7.5 as the y-axes and 1 as the x-axes

The total number of pieces of mails delivered by max in time period of 2 months is equal to 1420 pieces of mails .

Number of pieces of mails delivered by Max in a year = 8520

let us consider the 'n' be the number of mails Max delivered in a month.

Convert year into month.

1 year is equal to 12 months

This implies ,

12 × n = 8520 pieces of mails

Divide both the side of the equation by 12 we get,

⇒ ( 12 × n ) / 12 = 8520 / 12

⇒ n = 710 pieces of mails in one month

Number of pieces of mails in 2 months

= 2 × 710

= 1420 pieces of mails

Therefore, Max delivers 1420 pieces of mails in 2 months.

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The given question is incomplete, I answer the question in general according to my knowledge:

Max delivers 8520 pieces of mail in one year. how many pieces of mail are delivered in 2 months?

On solving the provided query we have Therefore, assuming that order equation counts, there are 20,736 different ways to arrange 12 different books on four shelves.

A mathematical equation is a formula that connects two claims and uses the equals symbol (=) to denote equivalence. An equation in algebra is a mathematical statement that establishes the equivalence of two mathematical expressions. For instance, in the equation 3x + 5 = 14, the equal sign places a space between the variables 3x + 5 and 14. The relationship between the two sentences that are written on each side of a letter may be understood using a mathematical formula. The symbol and the single variable are frequently the same. as in, 2x - 4 equals 2, for instance.

Using the permutation formula with repetition, we can determine how many different ways there are to arrange 12 books on 4 shelves.

[tex]n^r[/tex]

where r is the number of empty spaces to be filled (in this example, 4 shelves) and n is the number of options to select from (12 distinct books in this case).

[tex]12^4 = 20,736[/tex]

Therefore, assuming that order counts, there are 20,736 different ways to arrange 12 different books on four shelves.

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We find  f such that f'(x) = 2x² + 9x -2 and f(0) = 1 as f(x) = (2/3)x³ + (9/2)x² - 2x + 1.

To find f(x), we need to integrate f'(x):
∫(2x² + 9x - 2) dx = (2/3)x³ + (9/2)x² - 2x + C
where C is the constant of integration.
Since we have the initial condition f(0) = 1, we can solve for C:

Substituting this value into the formula for f(x), we get:

f(0) = (2/3)(0)³ + (9/2)(0)² - 2(0) + C = 1
C = 1
Therefore, the function f(x) is:
f(x) = (2/3)x³ + (9/2)x² - 2x + 1

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The sampling distribution of the mean for samples of size 39 has a mean of 64 inches and a standard deviation of approximately 0.496 inches.

We are required to determine the sampling distribution of the mean for samples of size 39, given that the heights of people in a certain population are normally distributed with a mean of 64 inches and a standard deviation of 3.1 inches.

The sampling distribution of the mean is also normally distributed. To find the mean and standard deviation of the sampling distribution, you'll use the following formulas:

1. Mean of the sampling distribution (μx) = Mean of the population (μ)

2. Standard deviation of the sampling distribution (σx) = Standard deviation of the population (σ) divided by the square root of the sample size (n)

Applying these formulas:

1. μx = μ = 64 inches

2. σx = σ / √n = 3.1 inches / √39 ≈ 0.496

So, the mean is 64 inches and a standard deviation is approximately 0.496 inches.

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Probability is the likelihood or chance of an event occurring.

Based on the normal distribution curve, the most likely probability of the number of customers buying the product from the first 2 years would be around 68%. This is because in a normal distribution, approximately 68% of the data falls within one standard deviation of the mean.

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Based on the Pew Research poll, we can say with 95% confidence that the true percentage of people around the world who believe that racial and ethnic discrimination is a serious problem in the US falls between 85.5% and 92.5%, given the margin of error of 3.5%.

A correct statement based on the given situation is: "According to a recent Pew Research poll, it is estimated that between 85.5% and 92.5% of people sampled from the top 16 countries around the world believe that racial and ethnic discrimination is a serious problem in the US, with a 95% confidence level."

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1) A recent Pew Research poll showed that 89% of people sampled around the world believe that racial and ethnic discrimination is a serious problem in the US. Their sample included 1600 people from the top 16 countries around the world. Their report said that this estimate comes with a margin of error of 3.5% with a 95% confidence level. Which of the following is a correct statement, based on this situation?______________________

The given class boundaries are reasonable and provide a clear and informative summary of the savings account balances at the bank.

In statistics, a frequency distribution is a way of organizing data into intervals, or classes, and counting the number of observations that fall within each interval. The purpose of constructing a frequency distribution is to summarize large amounts of data and identify patterns and trends in the data.

When constructing a frequency distribution for savings account balances at a bank, it is important to choose appropriate class boundaries that are meaningful and representative of the data.

The class boundaries given in the question are $0.00-$5,000, $5,000-$10,000, $10,000-$15,000, and $15,000-$20,000, with the minimum balance of $5.00 and the maximum balance of $18,700.

These class boundaries are reasonable and appropriate for representing the savings account balances at the bank. The first class includes balances from $0.00 to $5,000, which is the minimum balance that the bank allows. The remaining classes are each $5,000 in width, which provides a consistent and easy-to-follow pattern.

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Complete question is:

In constructing a frequency distribution for the savings account balances for customers at a bank, the following class boundaries might be acceptable if the minimum balance is $5.00 and the maximum balance is $18,700:

$0.00-$5,000

$5,000-10,000

$10,000-$15,000

$15,000-$20,000

Are these class boundaries reasonable.

Answer:

D

Step-by-step explanation:

To solve the problem, we can create a proportion based on the information given:

30 broken bars = 250 bars produced

x broken bars = 1500 bars produced

Cross-multiplying, we get:

30 * 1500 = 250 * x

Simplifying, we get:

x = (30 * 1500) / 250 = 180

Therefore, the factory can expect approximately 180 chocolate bars to be broken by the end of the day. The answer is D.

Another way to solve this problem is to use the ratio of broken bars to total bars produced.

In one hour, the factory produced 250 chocolate bars, and 30 of them were broken. So the ratio of broken bars to total bars produced in one hour is:

30/250 = 0.12

This means that 12% of the chocolate bars produced in one hour were broken.

To find out how many bars the factory can expect to be broken in a day when 1500 bars are produced, we can multiply the ratio of broken bars by the total number of bars produced in a day:

0.12 * 1500 = 180

So the factory can expect approximately 180 chocolate bars to be broken by the end of the day. This method uses the same approach as the proportion method, but it expresses the ratio of broken bars as a percentage.

Answer:

1

Step-by-step explanation:

Only 1 dot is plotted above 0, therefore only 1 student had zero siblings.

(a)21 students were surveyed.

(b)52.38% of students are taller than or equal to 50 inches but less than 60 inches.

Based on the information provided, the histogram shows the frequency (number of students) at each height interval:

Height (inches) | Frequency
---------------------------
50 - 54         |    6
55 - 59         |    5
60 - 64         |    4
65 - 69         |    3
70 - 74         |    2
75 - 79         |    1

(a) To find the total number of students surveyed, you simply need to add up the frequency of each height interval:

6 + 5 + 4 + 3 + 2 + 1 = 21 students

So, 21 students were surveyed.

(b) To find the percentage of students who are taller than or equal to 50 inches but less than 60 inches, you need to look at the height intervals from 50-54 inches and 55-59 inches. The total number of students in these intervals is 6 + 5 = 11.

Now, to find the percentage, divide the number of students in these intervals (11) by the total number of students surveyed (21), then multiply by 100:

(11 / 21) * 100 = 52.38%

Therefore, 52.38% of students are taller than or equal to 50 inches but less than 60 inches.

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The velocity of the flow in the channel is 1.2fps

The optimum velocity in sewers is approximately 2 feet per second at peak flow, because this velocity normally prevents solids from settling from the lines; however, when the flow reaches the grit channel, the velocity should decrease to about 1 foot per second to permit the heavy inorganic solids to settle.

It takes a float 30 seconds to travel 37 feet in a grit channel.

To find the velocity of the flow in the channel.

We know the formula of velocity of the flow in the channel.

[tex]Velocity(fps) = \frac{distance traveled(ft)}{time required(seconds)}[/tex]

[tex]Velocity(fps) = \frac{37 ft}{30 sec}=1.2 fps[/tex]

The calculation below can be used for a single channel or tank or for multiple channels or tanks with the same dimensions and equal flow. If the flow through each unit of the unit dimensions is unequal, the velocity for each channel or tank must be computed individually.

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The given question is incomplete, complete question is:

It takes a float 30 seconds to travel 37 feet in a grit channel. What is the velocity of the flow in the channel?

A card player declares that there is a one in thirteen chance that the next card pulled from a well-shuffled, full deck will be a queen. The given scenario is an example of theoretical probability.

Theoretical probability refers to the probability calculated based on the possible outcomes and their likelihood, without conducting experiments or observing actual results.

In this case, there are 4 queens in a standard 52-card deck, so the probability of drawing a queen is 4/52 or 1/13. This is a theoretical probability because it is based on the known composition of the deck and not on the actual outcomes of drawing cards.

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The value of functions are,

f(- 2) = 28

f(6) = 84

f(-6) = 11

f(8) = 322

Given that;

The value of function is,

f(x) = -2x - 1, if x < -2,

And, f(x) = 4x² - 9x -6 if x ≥ -2

Hence, The value of f (- 2) is,

f(x) = 4x² - 9x -6

Put x = - 2;

f(- 2) = 4(- 2)² - 9(- 2) -6

f (- 2) = 16 + 18 - 6

f (- 2) = 28

The value of f (6) is,

f(x) = 4x² - 9x -6

Put x = 6;

f(6) = 4(6)² - 9(6) -6

f (6) = 144 - 54 - 6

f (6) = 84

The value of f (- 6) is,

f(x) = - 2x - 1

Put x = - 6;

f(- 6) = - 2 (- 6) - 1

f (- 6) = 12 - 1

f (- 6) = 11

The value of f (8) is,

f(x) = 4x² - 9x -6

Put x = -8;

f(- 8) = 4(- 8)² - 9(- 8) - 6

f (- 8) = 256 + 72 - 6

f (- 8) = 322

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Rounded to 3 decimal places, the probability that X is between 4 and 1 is 0.119.

If X follows a normal distribution with a mean of -3 (µ = -3) and a standard deviation of 4 (σ = 4), denoted as X ~ N(-3, 4), we want to find the probability that X is between 4 and 1.

To do this, we will first calculate the Z-scores for both values:

Z1 = (1 - (-3)) / 4 = 4 / 4 = 1
Z2 = (4 - (-3)) / 4 = 7 / 4 = 1.75

Now, we need to find the area between these Z-scores using the standard normal distribution table. The area to the left of Z1 = 1 is 0.8413, and the area to the left of Z2 = 1.75 is 0.9599.

To find the probability that X is between 4 and 1, we subtract the area of Z1 from the area of Z2:

P(1 ≤ X ≤ 4) = P(Z2) - P(Z1) = 0.9599 - 0.8413 = 0.1186

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The probability of a roll having 3 or more defects is approximately 0.6611 or 66.11%.

In this scenario, we are given that the average number of defects in a sheet of rolled steel is 3.2. Therefore, λ = 3.2. We want to find the probability that a roll has 3 or more defects. Let X be the number of defects in a roll of steel. Then, X follows a Poisson distribution with parameter λ = 3.2.

The probability mass function (PMF) of a Poisson distribution is given by:

P(X=k) = [tex](e^{-\lambda} \times \lambda ^k) / k![/tex]

where k is a non-negative integer representing the number of events that occur in the interval, e is the mathematical constant approximately equal to 2.71828, and k! is the factorial of k.

Using this PMF, we can calculate the probability of a roll having 3 or more defects as follows:

P(X≥3) = 1 - P(X<3)

= 1 - P(X=0) - P(X=1) - P(X=2)

= 1 - [tex][(e^{-\lambda} \times \lambda^0) / 0!] - [(e^{-\lambda} \times \lambda^1) / 1!] - [(e^{-\lambda} \times \lambda^2) / 2!][/tex]

= 1 - [tex][(e^{-3.2} \times 3.2^0) / 0!] - [(e^{-3.2} \times 3.2^1) / 1!] - [(e^{-3.2} \times 3.2^2) / 2!][/tex]

= 1 -[tex][(e^{-3.2} \times 1) / 1] - [(e^{-3.2} \times 3.2) / 1] - [(e^{-3.2} \times 10.24) / 2][/tex]

= 1 - 0.0408 - 0.1307 - 0.1680

= 0.6611 or 66.11%.

To know more about Poisson distribution here

https://brainly.com/question/17280826

#SPJ4

Answer:

4

Step-by-step explanation:

Recall that the mode of a set of data is the number that recurs the most.

Let's look at the data:

2, 2, 4, 4, 4, 14

2 appears twice. 4 appears thrice. 14 appears once.

Since 4 appears the most, it is the mode.