grade 10 math. help for 20 points!!!

Answer:

The correct set of data is D.

If two triangles are similar, then their corresponding sides are proportional and their corresponding angles are congruent 1. Therefore, we can set up a proportion of the corresponding sides of the two triangles and solve for x.

For example, if we have two similar triangles ABC and EDC with sides AB = 6, BC = 8, AC = 10 and ED = 9, DC = 12, EC = 15 respectively as shown below:

    A

    /\

   /  \

  /____\

 B      C

    E

    /\

   /  \

  /____\

 D      C

We can set up a proportion of the corresponding sides as follows:

AB/ED = BC/DC = AC/EC

6/9 = 8/12 = 10/15

Simplifying this proportion gives us:

2/3 = 2/3 = 2/3

Therefore, x is equal to:

x = EC - DC

x = 15 - 12

x = 3

So in this case, x is equal to 3.

I hope that helps!

A baseball player hit 59 home runs in a season. Of the 59 home runs, 24 went to right field, 15 went to right centre field, 8 went to centre field, 10 went to left-centre field, and 2 went to left field.

(a) The probability that a randomly selected home run was hit to the right field is 0.407.

To find the probability that a randomly selected home run was hit to right field, you can follow these steps:
Step 1: Identify the total number of home runs and the number of home runs hit to the right field.
Total home runs = 59
Home runs to right field = 24
Step 2: Calculate the probability by dividing the number of home runs hit to the right field by the total number of home runs.
Probability = (Home runs to right field) / (Total home runs) = 24/59
The probability that a randomly selected home run was hit to the right field is 24/59, or approximately 0.407.

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The distance between the Pluto and the sun is about 5,905,800,000 kilometers.

Distance between Mercury  and the sun is = 57,900,000 kilometers.

The distance of Pluto from the sun

=  Pluto is about 1.02 x 10^2 times farther away from the sun than Mercury.

⇒Distance of Pluto from the sun

= Distance of Mercury from the sun x 1.02 x 10^2

⇒Distance of Pluto from the sun = 57,900,000 km x 1.02 x 10^2

⇒Distance of Pluto from the sun = 57,900,000 km x 102

⇒ Distance of Pluto from the sun = 5,905,800,000 kilometers

Therefore, the distance of Pluto is about 5,905,800,000 kilometers away from the sun.

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The probability of at most three successes (P(X ≤ 3)) in 7 independent Bernoulli trials is 0.7106.

To calculate the probability of at most three successes (P(X ≤ 3)) in 7 independent Bernoulli trials with p = 0.4 and q = 0.6, you can use the binomial probability formula. The formula is:

P(X = k) = C(n, k) * p^k * q^(n-k)

where n is the number of trials, k is the number of successes, p is the probability of success, q is the probability of failure, and C(n, k) is the number of combinations of n items taken k at a time.

For P(X ≤ 3), you'll need to calculate the probabilities for 0, 1, 2, and 3 successes and add them together:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

For each value of k (0, 1, 2, and 3), compute the probability using the binomial formula:

1. P(X = 0) = C(7, 0) * (0.4)^0 * (0.6)^7
2. P(X = 1) = C(7, 1) * (0.4)^1 * (0.6)^6
3. P(X = 2) = C(7, 2) * (0.4)^2 * (0.6)^5
4. P(X = 3) = C(7, 3) * (0.4)^3 * (0.6)^4

Calculate the probabilities and add them together:

P(X ≤ 3) ≈ 0.02799 + 0.13043 + 0.26186 + 0.29030 ≈ 0.71058

So, the probability of at most three successes (P(X ≤ 3)) in 7 independent Bernoulli trials with p = 0.4 and q = 0.6 is approximately 0.7106 (rounded to four decimal places). You can check this answer using a calculator or software that supports binomial probability calculations.

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We can use the double angle formula for cosine, which is: cos(2x) = 1 - 2*sin^2(x) First, we square sin(x): sin^2(x) = (3/4)^2 = 9/16 Now, substitute this value into the double angle formula: cos(2x) = 1 - 2*(9/16) = 1 - 18/16 = -2/16 So, cos(2x) = -1/8.

To compute Cos(2x), we can use the double angle formula which states that Cos(2x) = 2Cos^2(x) - 1.

Now, we are given that sin(x) = 3/4. Using the Pythagorean identity sin^2(x) + Cos^2(x) = 1, we can solve for Cos(x):

sin^2(x) + Cos^2(x) = 1

3/4^2 + Cos^2(x) = 1

9/16 + Cos^2(x) = 1

Cos^2(x) = 7/16

Cos(x) = ±√(7/16)

Since we know that x is in the first quadrant (sin is positive and Cos is positive), we can take the positive square root:

Cos(x) = √(7/16) = √7/4

Now we can plug this value of Cos(x) into the double angle formula:

Cos(2x) = 2Cos^2(x) - 1

Cos(2x) = 2(√7/4)^2 - 1

Cos(2x) = 2(7/16) - 1

Cos(2x) = 7/8 - 1

Cos(2x) = -1/8

Therefore, Cos(2x) = -1/8.

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the vector projection of v onto w is -1i + 3j.To get the vector projection of v onto w, you'll need to use the following formula:

proj_w(v) = (v • w / ||w||^2) * w
Where v = 2i + 4j, w = -2i + 6j, "•" represents the dot product, and ||w|| is the magnitude of w.
Step 1: Find the dot product (v • w)
v • w = (2 * -2) + (4 * 6) = -4 + 24 = 20
Step 2: Find the magnitude of w (||w||)
||w|| = √((-2)^2 + (6)^2) = √(4 + 36) = √40
Step 3: Square the magnitude of w (||w||^2)
||w||^2 = (40)
Step 4: Calculate the scalar value (v • w / ||w||^2)
Scalar value = (20) / (40) = 0.5
Step 5: Multiply the scalar value by w to get the vector projection of v onto w
proj_w(v) = 0.5 * (-2i + 6j) = -1i + 3j

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The standard deviation of the average drying times is 2.5 minutes.

To find the standard deviation of the average drying times for a sample of 36 paint drying times, we'll use the formula: Standard deviation of the sample mean = Population standard deviation / √(sample size).

In this case, the paint drying times are normally distributed with a mean of 120 minutes and a standard deviation of 15 minutes.

The sample size is 36. Standard deviation of the sample mean = 15 / √(36) = 15 / 6 = 2.5 minutes. So, the standard deviation of the average drying times for the sample is 2.5 minutes.

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The the parametric form of the circle x^2 + y^2 = 64 is x= 8cosθ,y= 8sinθ.

Given that,

x^2 + y^2 = 64

or, x^2 + y^2 = 8^2

r=8, center=(0,0)

Parametric equations are x= 8cosθ

y= 8sinθ

∴x= 8cosθ,y= 8sinθ

Explanation:

we know that,

The polar form of the equation is expressed in terms of r and theta,

The conversion of Cartesian co-ordinate to Polar co-ordinate is given by,

x^2 + y^2 = r^2

Parametric equations shows the relation between a group of quantities by expressing the coordinates of points of a curve and function as one or more independent variables.

1) For a given value of the independent variable the parametric equation is used exactly one point on the graph

2) the parametric equations  have a finite domain

3) the parametric equation is easier to enter into a calculator for graphic

we can represent the circle in a parametric form as:

x= 8cosθ,y= 8sinθ.

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Answer:

2x2x2x2x2x2, 4x16, and 8x8

Step-by-step explanation:

The credibility factor, Z, for Year 2 is 1.2875.

To determine the credibility factor, Z, for Year 2, we can use the

Buhlmann-Straub model, which assumes that the number of claims for

each policyholder follows a negative binomial distribution with mean θ

and dispersion parameter β. The credibility formula is given by:

Z = (k + nβ)/(n + β),

where k is the number of claims observed in Year 1, n is the number of

policyholders in Year 1, and β is the dispersion parameter.

From the data provided, we can calculate the values of k and n for Year 1

as follows:

k = 1400 + 2300 + 380 + 420 = 820

n = 2200 + 400 + 300 + 80 + 20 = 3000

To determine the dispersion parameter β, we can use the method of

moments. For a negative binomial distribution, the mean and variance

are given by:

mean = θ

variance = θ(1 + βθ)

Solving for θ and β, we get:

θ = variance/mean

β = (variance/mean) - 1

Using the data from Year 1, we can estimate the mean and variance of the number of claims as follows:

mean = k/n = 820/3000 = 0.2733

[tex]variance = \sum (x - mean)^2 / n = 02200 + 1400 + 2300 + 380 + 4\times 20 / 3000 = 0.6313[/tex]

Substituting these values into the equations above, we get:

θ = 0.6313/0.2733 = 2.3104

β = (0.6313/0.2733) - 1 = 1.3088

Finally, we can use the credibility formula to calculate the credibility factor, Z, for Year 2:

Z = (k + nβ)/(n + β) = (0 + 3000*1.3088)/(3000 + 1.3088) = 1.2875

Therefore, the credibility factor, Z, for Year 2 is 1.2875. This means that we should give more weight to the expected number of claims for Year 2 based on the data from Year 1, rather than the expected number of claims based on the conditional negative binomial distribution with β=0.5.

The higher the credibility factor, the more weight we should give to the observed data from Year 1, and the less weight we should give to the prior distribution.

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In experimental studies, the researcher manipulates the exposure, that is he or she allocates subjects to the intervention or exposure group.

In experimental studies, the researcher manipulates the exposure or intervention by allocating subjects to the intervention or exposure group. This allows for the comparison of outcomes between the intervention/exposure group and the control group, which did not receive the intervention/exposure.

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The absolute maximum value of f(x) over the interval [-3, 2] is approximately 5.24 and it occurs at x = 2, and the absolute minimum value is 1/8 and it occurs at x = 1/2.

To find the absolute maximum and minimum values of the function:

[tex]f(x) = (x^2-x)^{(2/3)}[/tex] over the interval [-3, 2], we need to follow these steps:

Find the critical points of the function by solving f'(x) = 0:

[tex]f'(x) = (2x - 1)\times{2/3}\times (x^2 - x)^{(-1/3)} = 0[/tex]

Solving for 2x - 1 = 0, we get x = 1/2. This is the only critical point in the interval [-3, 2].

Evaluate the function at the endpoints and the critical point:

f(-3) = ∛36 ≈ 3.301

f(2) = ∛12² ≈ 5.24

f(1/2) = 1/8

Determine which value is the absolute maximum and which is the absolute minimum:

The absolute maximum value is f(2) ≈ 5.24, and it occurs at x = 2.

The absolute minimum value is f(1/2) = 1/8, and it occurs at x = 1/2.

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The general solution of dy/dx = sin2x is -1/2 cosx + c and dy/dx = sinx is

-cos x + c

Given that, we need to find the general solution of the derivatives, dy/dx = sin2x and dy/dx = sinx

1) dy/dx = sin2x

y = ∫sin2x dx

y = -1/2 cos 2x + c

2) dy/dx = sinx

y = ∫sinx

y = -cosx + c

Hence, the general solution of dy/dx = sin2x is -1/2 cosx + c and dy/dx = sinx is -cos x + c

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The correct expression to find the volume of a rectangular prism is D. (3 × 6) × 15 = 270 in.3.

Expression is a word, phrase, or gesture that conveys an idea, thought, or feeling. It is an outward representation of an emotion, attitude, or opinion. Expressions can be verbal, physical, or written. They can also take the form of art, music, or dance. Expression is used to communicate and express emotions, thoughts, and ideas. It can be a powerful tool to create a connection with others and build relationships.

The correct expression to find the volume of a rectangular prism is D. (3 × 6) × 15 = 270 in.3. This expression involves multiplying the length, width, and height of the rectangular prism in order to calculate the total volume. In this case, the length is 3, the width is 6, and the height is 15. If these values are multiplied together, the result is 270 in.3, which is the total volume of the rectangular prism.

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The cost of installing a typical septic system without any special features can vary depending on various factors, such as the size of the property, soil type, and location. On average, a septic system installation can cost anywhere from $3,000 to $7,000.

The cost of installing a septic system can depend on various factors, such as the size of the property, soil type, location, and regulations in the area. The installation process typically involves excavating the area, installing the septic tank and leach field, and connecting the plumbing to the septic system. The cost of the septic tank itself can range from $500 to $2,000, and the leach field can cost around $2,000 to $4,000. In addition, there may be additional costs associated with obtaining permits and hiring contractors.

Therefore, the cost of installing a typical septic system without any special features can range from $3,000 to $7,000, depending on various factors.

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The solution to the difference equation Yt+1 + 3y = 16; Yo = 100,t 20.

Hence, the correct option is A.

To solve the difference equation Yt+1 + 3Yt = 16, with initial condition Y0 = 100 and t ≥ 0, we can first find the homogeneous solution, which is

Yh(t) = [tex]A(-1/3)^t[/tex]

Where A is a constant determined by the initial condition. Put in the initial condition Y0 = 100, we get

Yh(0) = A = 100

Therefore, the homogeneous solution is

Yh(t) = [tex]100(-1/3)^t[/tex]

Next, we find the particular solution by assuming a constant value for Yt+1 and Yt, which gives us

Yp(t) = 4

This is because we have

Yt+1 + 3Yt = 16

Yp(t+1) + 3Yp(t) = 16

4 + 3Yp(t) = 16

Yp(t) = 4

So the particular solution is

Yp(t) = 4

Finally, the general solution is the sum of the homogeneous and particular solution

Y(t) = Yh(t) + Yp(t) = [tex]100(-1/3)^t[/tex] + 4

Using the initial condition Y20 = 100, we can solve for the constant A

Y20 = [tex]100(-1/3)^20 + 4 = A(-1/3)^20 + 4[/tex]

100 = [tex]A(-1/3)^20 + 4[/tex]

A = 96

Therefore, the solution to the difference equation Yt+1 + 3Yt = 16 with initial condition Y0 = 100 and t ≥ 0 is

Y(t) = [tex]96(-1/3)^t + 4[/tex]

Yt = [tex]96(-3)^t + 4[/tex]

Hence, the correct option is A.

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The probability that a student who received college credit scored a 3 on the exam is 0.034 or about 3.4%.

Let A be the event that the student scored 4 or 5, B be the event that the student scored 3, and C be the event that the student scored 1 or 2. We are given that P(A) = 0.60, P(B) = 0.25, and P(C) = 1 - P(A) - P(B) = 0.15.

We are also given the conditional probabilities P(Credit|A) = 0.95, P(Credit|B) = 0.50, and P(Credit|C) = 0.04, where Credit is the event that the student received college credit.

Using Bayes' theorem, we can calculate the probability that a student who received college credit scored a 3:

P(B|Credit) = P(Credit|B) * P(B) / [P(Credit|A) * P(A) + P(Credit|B) * P(B) + P(Credit|C) * P(C)]

= 0.50 * 0.25 / [0.95 * 0.60 + 0.50 * 0.25 + 0.04 * 0.15]

= 0.034

This result shows that even though 25% of the students scored 3 on the exam, they have a much lower probability of receiving college credit compared to those who scored 4 or 5.

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Complete question is:

Suppose that 60% of the students who take the ap statistics exam score 4 or 5, 25% score 3, and the rest score 1 or 2. suppose further that 95% of those scoring 4 or 5 receive college credit, 50% of those scoring 3 receive such credit, and 4% of those scoring 1 or 2 receive credit. if a student who is chosen at random from among those taking the exam receives college credit, what is the probability that she received a 3 on the exam?

When a₁ = 4, d = 3.5, and n = 14 are given.The value of A(14) is 49.5, the correct answer is option C. The issue appears to be related to number juggling arrangements, where A(n) speaks to the nth term of the arrangement and a₁ speaks to the primary term of the sequence.

Ready to utilize the equation for the nth term of a math grouping:

A(n) = a₁ + (n-1)d

where d is the common contrast between sequential terms.

A(14) = 4 + (14-1)3.5

Streamlining this condition, we get:

A(14) = 4 + 13*3.5

A(14) = 4 + 45.5

A(14) = 49.5

Hence, the esteem of A(14) is 49.5, which is choice C. 

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For the given sequences, 11) a_n = {4/n²} is monotonic decreasing and bounded, 12) a_n = {(3n²)/(n²+1)} is monotonic increasing and unbounded, and 13) a_n = {2(-1)ⁿ⁺¹} is neither monotonic nor bounded.


11) a_n = {4/n²}: As n increases, the terms in the sequence decrease, since the denominator (n²) grows larger, making the fraction smaller. This makes the sequence monotonic decreasing. Additionally, the sequence is bounded below by 0, as the terms are always positive, and it approaches 0 as n approaches infinity.

12) a_n = {(3n²)/(n²+1)}: As n increases, the terms in the sequence also increase, since the numerator (3n²) grows larger and the denominator (n²+1) also grows larger, but at a slower rate.

This makes the sequence monotonic increasing. However, there is no upper limit for the terms, as the sequence does not approach a specific value when n approaches infinity, making it unbounded.

13) a_n = {2(-1)ⁿ⁺¹}: This sequence alternates between positive and negative values for each consecutive term, making it neither monotonic nor bounded.

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The direction angles of the vector v = 2i + 6j - 3k are α = 73°, β = 31°, and γ = 115°

To find the direction angles of the vector v = 2i + 6j - 3k, we need to calculate the angles α, β, and γ between the vector and the x, y, and z axes, respectively.

1. Calculate the magnitude of the vector:

|v| = [tex]√(2^2 + 6^2 + (-3)^2)[/tex]

= √(4 + 36 + 9)

= √49 = 7

2. Find the cosine of each direction angle:
  cos(α) = (2) / |v| = 2/7
  cos(β) = (6) / |v| = 6/7
  cos(γ) = (-3) / |v| = -3/7

3. Calculate the direction angles by finding the inverse cosine of each cosine value:
  α = [tex]cos^(-1)(2/7)[/tex] ≈ 73°
  β = [tex]cos^(-1)(6/7)[/tex] ≈ 31°
  γ = [tex]cos^(-1)(-3/7)[/tex]≈ 115°

Thus, the direction angles of the vector v = 2i + 6j - 3k are α = 73°, β = 31°, and γ = 115°.

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The Prime factors of 18 are (2²) * 3 or 2 * 2 * 3. Thus, option B is the correct answer.

Prime numbers are numbers that are not divisible by any other number other than 1 and the number itself.

Composite numbers are numbers that have more than 2 factors that are except 1 and the number itself.

Prime factors are the prime numbers that when multiplied get the original number.

To calculate the prime factor, we use the division method.

In this method, firstly we divide the number by the smallest prime number it is when divided it leaves no remainder. In this case, we divide 18 by 2 and get 9.

Again, divide the number we get that, in this case, is 9, in the previous step by the prime number it is divisible by. So, 9 is again divided by 3 and we get 3.

We have to perform the previous step until we get 1. And 3 ÷ 3 = 3. Since we get 1, we stop here.

Finally, Prime factorization of 18 is expressed as 2 × 2 × 3  or we can write it as (2²) * 3

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The unknown sides and angles of the pyramid can be found as follows:

The diagram is a square based pyramid. ABCD is the square based side. Hence, M is the mid point of BC.

Let's find the required sides as follows:

Let's find the length of XM.

XM = 10 / 2 = 5 cm

Let's find the length VM using Pythagoras's theorem.

c²= a² + b²

where

Therefore,

VM = √8² - 5²

VM = √64 - 25

VM = √39 cm

Therefore, let's find the angle between VM and ABCD

Using trigonometric ratios,

tan M = opposite / adjacent

tan M = 8 / 5

M = tan⁻¹ 1.6

M = 57.9946167919

M = 58 degrees

Therefore, the angle is 58 degrees.

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The mean decreases and the median remains the same.

option D.

The mean and median of the distribution is calculated as follows;

Initial mean =  $40 + $83 + $37 + $40 + $31 + $68

= 299 / 6

= $49.8

Final mean;

Total = $40 + $83 + $37 + $40 + $31 + $68 + $23

Total = $322

mean = $322 / 7 = $46

To find the median, we first need to put the earnings in order from smallest to largest.

median = $23, $31, $37, $40, $40, $68, $83

the median is the fourth number =  $40.

The initial median and final median will be the same.

Thus, mean decreases and the median remains the same.

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By using the L'Hospital's Rule, we have shown that the limit of x^(3/x) as x approaches infinity is equal to 1.

To find the limit of the function [tex]x^{3/x}[/tex] as x approaches infinity, we can use L'Hopital's Rule, which states that if we have an indeterminate form of a fraction such as 0/0 or infinity/infinity, we can take the derivative of the numerator and the denominator separately until we no longer have an indeterminate form.

First, we can rewrite the function as e^(ln([tex]x^{3/x}[/tex])). Then, we can use the properties of logarithms to simplify it further as e^((3ln(x))/x). Now, we have an indeterminate form of infinity/infinity, and we can apply L'Hopital's Rule.

Taking the derivative of the numerator and denominator, we get:

lim x→∞ [tex]x^{3/x}[/tex] = lim x→∞ e^((3ln(x))/x)

= e^(lim x→∞ (3ln(x))/x)

Using L'Hopital's Rule on the exponent, we get:

= e^(lim x→∞ (3/x²))

Since the denominator is approaching infinity faster than the numerator, the limit of 3/x² as x approaches infinity is zero, and we are left with:

= e^(0)

= 1

Therefore, the limit of [tex]x^{3/x}[/tex] as x approaches infinity is 1.

Alternatively, we can use some algebraic manipulation and the squeeze theorem to find the limit without using L'Hopital's Rule. We can rewrite the function as [tex]x^{3/x}[/tex] = (x^(1/x))³, and notice that as x approaches infinity, 1/x approaches zero, and so x^(1/x) approaches 1 (as the exponential function with base e^(1/x) approaches 1). Therefore, we have:

lim x→∞ [tex]x^{3/x}[/tex]= lim x→∞ (x^(1/x))³

= 1³

= 1

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Complete Question:

Find the limit. Use L'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.

lim x→∞ [tex]x^{3/x}[/tex]

The given claim by the company that a cereal packet   weighs around 14 oz is considered as a Type I error because it rejects an accurate null hypothesis. Type I error refers to a statistical concept that describes  the incorrect rejection of an accurate null hypothesis.

In short, it is a false positive observation. For the given case, the cereal company positively projects that the mean weight of cereal present in  packets is at least 14 oz and gets rejected, this claim even though it is accurate and should not be rejected, but it wents and is labelled as a Type I error.

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To show that the amount of glucose A(t) in the bloodstream at any time t is governed by the given differential equation, we need to consider the rates of glucose infusion and removal.

1. Glucose is infused into the bloodstream at a constant rate of C g/min. This means the rate of glucose infusion is simply C.

2. The glucose is converted and removed from the bloodstream at a rate proportional to the amount of glucose present. We can represent this by the equation: removal rate = kA, where k is a constant and A is the amount of glucose at time t.

Now, we can write the differential equation for A(t) by considering the net rate of change of glucose in the bloodstream. The net rate is the difference between the infusion rate and the removal rate:

A'(t) = infusion rate - removal rate

Substitute the values for the infusion rate and removal rate from the steps above:

A'(t) = C - kA

The amount of glucose A(t) in the bloodstream at any time t is governed by the differential equation A'(t) = C - kA, where C is the constant rate of glucose infusion, and k is the constant proportionality factor for glucose removal. This equation represents the net rate of change of glucose in the bloodstream, considering both infusion and removal rates.

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The algebraic expression with fractional exponents that is equivalent to the given radical expression is [tex]x^{\frac{3}{5} }[/tex].

Variables, constants, and mathematical operations (such as addition, subtraction, multiplication, division, and exponentiation) can all be found in an algebraic equation.

In algebra and other areas of mathematics, algebraic expressions are used to depict connections between quantities and to resolve equations and issues. A radical expression is any mathematical formula that uses the radical (also known as the square root symbol) sign.

To convert the radical expression [tex]\sqrt[5]{x^{3} }[/tex] into an algebraic expression with fractional exponents, we use the following rule:

[tex]a^{1/n}[/tex] = (n-th root of a)

In this case, we have:

[tex]\sqrt[5]{x^{3} }[/tex] = [tex](x^{3})^{\frac{1}{5} }[/tex]

= [tex]x^{\frac{3}{5}}[/tex]

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The limit of the given sequence is 7.

From the first three terms, we can see that the sequence is alternating between adding 5 and dividing by 6.

As we continue down the sequence, we can see that the terms approach 7.

To prove this, we can use the formula for the sum of an infinite geometric series, which is:
S = a / (1 - r)
Where S is the sum of the series, a is the first term, and r is the common ratio. In this case, a = 1 and r = 5/6. Plugging in these values, we get:
S = 1 / (1 - 5/6)
S = 1 / (1/6)
S = 6

Hence, we need to add the last term, which is 6, to get the actual sum of the sequence. Therefore, the limit of the sequence is 7.

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1. No, the two triangles are not identical.

2. Yes, the two triangles are identical.

How can two triangles be the same?

If two triangles satisfy one of the following conditions, they are congruent: The three corresponding side pairings are all equal. The comparable angles between two pairs of corresponding sides are equal. The corresponding sides between two pairs of corresponding angles are equal.

This is demonstrated by noticing that a triangle's three angles must sum to 180 degrees.

For the first triangle, the angles are 95°, 70°, and 40°, which add up to 205°.

For the second triangle, the angles are 70°, 40°, and 70°, which add up to 180°.

Since the two triangles' angles differ, the triangles themselves must also be unique.

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