How will bits of paper act near a charged rod even when they are uncharged?

Answers

Answer 1

When a charged rod is brought near bits of uncharged paper, the paper will become polarized. This means that the positive charges in the paper will be attracted to the negatively charged rod, and the negative charges in the paper will be repelled by the rod.

                                   This will cause the bits of paper to move towards the rod and potentially stick to it, even though they are themselves uncharged. This is because the polarized charges in the paper are attracted to the opposite charges on the rod.

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Related Questions

1. a television that is plugged into a wall socket has an electrical potential difference of 120 v. if a current of 1.25 a is flowing through the television, what is the resistance?

Answers

If a current of 1.25 a is flowing through the television plugged into a wall socket having electrical potential difference of 120 v, the resistance of the television is 96 ohms.

To find the resistance of the television, we will use Ohm's Law, which is defined as:

V = I * R

Where:
- V is the electrical potential difference (voltage) in volts (V)
- I is the current in amperes (A)
- R is the resistance in ohms (Ω)

Given the information in the question, we have:
- V = 120 V
- I = 1.25 A

We need to find the resistance (R). We can rearrange the formula to solve for R:

R = V / I

Now, plug in the given values:

R = 120 V / 1.25 A

Calculate the resistance:

R = 96 Ω

So, the resistance of the television is 96 ohms.

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A blimp is filled with 400 m3 of helium. How big a payload can the balloon lift? (The density of air is 1.29 kg/m3; the density of helium is 0.18 kg/m3.)

Answers

To find out how big a payload the blimp can lift, we need to calculate the weight of the helium in the blimp and subtract it from the maximum weight the blimp can support.

The weight of the helium can be calculated by multiplying its density (0.18 kg/m3) by the volume of the blimp (400 m3):

Weight of helium = Density x Volume
Weight of helium = 0.18 kg/m3 x 400 m3
Weight of helium = 72 kg

To find out the maximum weight the blimp can support, we need to use Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. In this case, the blimp is filled with helium, which is lighter than air, so it will float.

The buoyant force on the blimp is equal to the weight of the air it displaces, which can be calculated by multiplying the density of air (1.29 kg/m3) by the volume of the blimp:

Weight of air displaced = Density x Volume
Weight of air displaced = 1.29 kg/m3 x 400 m3
Weight of air displaced = 516 kg

Therefore, the maximum weight the blimp can support is 516 kg. To find out how big a payload the blimp can lift, we need to subtract the weight of the helium (72 kg) from the maximum weight:

Payload = Maximum weight - Weight of helium
Payload = 516 kg - 72 kg
Payload = 444 kg

Therefore, the blimp can lift a payload of up to 444 kg.

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A home uses ten 100-watt lightbulbs for five hours per day. Approximately how many kilowatt-hours of electrical energy are consumed in one year by using the lightbulbs?3651,8255,00010,500365,000

Answers

Approximately 1825 kilowatt-hours of electrical energy are consumed in one year by using ten 100-watt lightbulbs for five hours per day.

To calculate the kilowatt-hours of electrical energy consumed in one year by using ten 100-watt light bulbs for five hours per day, we need to first calculate the total watt-hours consumed in one day and then multiply it by 365 (days in a year).

Total wattage of ten 100-watt light bulbs = 10 x 100 = 1000 watts
Watt-hours consumed in one day = 1000 watts x 5 hours = 5000 watt-hours
Kilowatt-hours consumed in one day = 5000 watt-hours / 1000 = 5 kWh
Kilowatt-hours consumed in one year = 5 kWh x 365 = 1825 kWh

Therefore, approximately 1825 kilowatt-hours of electrical energy are consumed in one year by using ten 100-watt lightbulbs for five hours per day.

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You have 16 kg of a radioactive sample with a certain half-life of 15 years. How much is left after 60 years?A. 8 kgB. 4 kgC. 2kgD. 1kgE. nothing

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Given 16 kg of a radioactive sample with a certain half-life of 15 years:

To determine how much of the 16 kg radioactive sample is left after 60 years with a half-life of 15 years, we will use the following steps:

1. Calculate the number of half-lives that have passed: 60 years / 15 years per half-life = 4 half-lives
2. Calculate the remaining sample amount using the formula: remaining amount = initial amount * (1/2)^number of half-lives
3. Apply the formula: remaining amount = 16 kg * (1/2)^4 = 16 kg * 1/16 = 1 kg

After 60 years, 1 kg of the radioactive sample is left. The correct answer is D. 1kg.

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23.4 A clear plastic sandwich bag filled with water can act as a crude converging lens in air. if the bag is filled with air and placed under water, is the effective lens (a) converging or (b) diverging

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If a clear plastic sandwich bag filled with air is placed underwater, it will act as a 'diverging' lens. Option b is answer.

When light travels from one medium to another, its path is bent due to a change in the refractive index. In the case of the plastic sandwich bag filled with air, the light entering the bag from the air will be refracted away from the normal as it enters the water-filled bag. This will cause the rays to diverge after passing through the bag, resulting in a diverging lens effect. This is because water has a higher refractive index than air, causing the light to bend away from the normal as it enters the water.

Therefore, the effective lens created by the clear plastic sandwich bag filled with air and placed under water will be a diverging lens.

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Suppose that instead of being inclined to Earth's orbit around the Sun, the Moon's orbit was in the same plane as Earth's orbit around the Sun. (Click "Show Moon with flat orbit" to see this situation.) In this hypothetical situation, approximately how many solar eclipses would occur each year?
-0
-1
-2
-12
-24

Answers

This would result in approximately 12 solar eclipses per year, one for each new moon.

If the Moon's orbit was in the same plane as Earth's orbit around the Sun, it would mean that the Moon would be aligned with the Sun and Earth more often, leading to more frequent solar eclipses.

1) The Moon takes approximately 29.5 days to orbit around the Earth.

2) The Earth takes approximately 365.25 days to orbit around the Sun.

3) If the Moon's orbit was flat, there would be approximately 12 new moons per year, occurring once every 29.5 days (365.25/29.5 = 12).

4) Since a solar eclipse can only occur during a new moon, there would be approximately 12 solar eclipses per year if the Moon's orbit was flat.

In this hypothetical situation, the Moon would pass in front of the Sun once every lunar month, during the new moon phase.

Therefore, the answer is (4) -12.

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T/F The sign of momentum is always in the direction of travel

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The given statement is true .

The sign of momentum is indeed always in the direction of travel.
Momentum is defined as the product of an object's mass and its velocity. Mathematically, it can be expressed as:
Momentum (p) = mass (m) × velocity (v)

Since velocity is a vector quantity that has both magnitude and direction, the sign of momentum will also depend on the direction of the object's motion. If an object is moving in a positive direction (e.g., to the right or upward), its momentum will have a positive sign. Conversely, if an object is moving in a negative direction (e.g., to the left or downward), its momentum will have a negative sign.

In summary, the sign of momentum is always in the direction of travel because it is directly influenced by the object's velocity, which is a vector quantity with both magnitude and direction.

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a hot metal is immersed into a beaker of cold water. which statement is false? a. the heat will be absorbed by water and beaker. b. in the experiment described above the heat that leaves the system is considered to be a positive quantity. c. the temperature of water will be increasing. d. the heat given off by the metal and the heat absorbed by the surroundings will be equal but are given opposite signs by convention.

Answers

The statement is false when a hot metal is immersed into a beaker of cold water :

a. The heat will be absorbed by water and beaker.
This statement is true. When a hot metal is placed in cold water, heat will transfer from the metal to the water and the beaker, causing the water and beaker to increase in temperature.

b. In the experiment described above, the heat that leaves the system is considered to be a positive quantity.
This statement is false. In thermodynamics, heat leaving the system (the hot metal, in this case) is considered a negative quantity, while heat entering the system is considered a positive quantity.

c. The temperature of water will be increasing.
This statement is true. As the heat from the metal transfers to the water, the temperature of the water will increase.

d. The heat given off by the metal and the heat absorbed by the surroundings will be equal but are given opposite signs by convention.
This statement is true. According to the law of conservation of energy, the heat lost by the metal will be equal to the heat gained by the surroundings (water and beaker), but the signs will be opposite due to convention (negative for heat loss, positive for heat gain).


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Only two forces act on a 3.0-kg mass. One of the forces is 9.0 N east, and the other is 8.0 N in the direction of 62° north of west. What is the magnitude of the acceleration of the mass?
1) 2.0 m/s2
2) 2.4 m/s2
3) 3.3 m/s2
4) 2.9 m/s2
5) 5.7 m/s2

Answers

The closest answer to this value is 2.9 m/s², so the correct choice is:
4) 2.9 m/s²

To find the acceleration of the mass, we need to first find the net force acting on the mass and then use Newton's second law (F = ma).

First, let's break the 8.0 N force into its x (westward) and y (northward) components:
Fx = 8.0 N * cos(62°) = 3.8 N (west)
Fy = 8.0 N * sin(62°) = 7.1 N (north)

Now, we can find the net force in the x (east-west) direction:
Fnet_x = 9.0 N (east) - 3.8 N (west) = 5.2 N (east)

Since there's no force acting on the mass in the y (north-south) direction, Fnet_y = 7.1 N (north).

Next, we find the magnitude of the net force using the Pythagorean theorem:
Fnet = sqrt(Fnet_x^2 + Fnet_y^2) = sqrt(5.2^2 + 7.1^2) = 8.9 N

Now, we can find the acceleration using Newton's second law:
a = Fnet / m = 8.9 N / 3.0 kg = 2.97 m/s²

The closest answer to this value is 2.9 m/s², so the correct choice is:

4) 2.9 m/s²

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a cylinder with a 3 square inch piston and a 1 square inch rod is pushing a 1,450 lb load up an inclined plane at an angle of 22 degrees. the initial speed is 60 ft/min and the deceleration distance is 0.25 in. the coefficient of friction between the load and the surface is 0.3. what force (in lbs) is required to decelerate the load and bring it to a stop when it is traveling up the hill?

Answers

The force required to decelerate the load and bring it to a stop when it is traveling up the hill is approximately 959.3 lbs.

To calculate the force required to decelerate the load, we need to first calculate the acceleration due to gravity on the inclined plane.

The formula for calculating the acceleration due to gravity on an inclined plane is:

acceleration = g * sin(theta)

where g is the acceleration due to gravity (32.2 ft/s^2) and theta is the angle of the inclined plane (22 degrees).

So, acceleration = 32.2 * sin(22) = 11.7 ft/s^2

Next, we need to calculate the force required to decelerate the load using the equation:

force = mass * acceleration

To find the mass of the load, we can use the formula:

mass = weight / gravity

where weight is the weight of the load (1,450 lbs) and gravity is the acceleration due to gravity (32.2 ft/s^2).

So, mass = 1,450 / 32.2 = 45.03 slugs

Now, we can calculate the force required to decelerate the load:

force = mass * acceleration = 45.03 * 11.7 = 527.7 lbs

However, we also need to take into account the friction between the load and the surface. The formula for calculating friction is:

friction = coefficient of friction * normal force

where the normal force is the force perpendicular to the surface.

To find the normal force, we can use the formula:

normal force = weight * cos(theta)

where theta is the angle of the inclined plane (22 degrees).

So, normal force = 1,450 * cos(22) = 1,360.7 lbs

Now, we can calculate the frictional force:

friction = 0.3 * 1,360.7 = 408.2 lbs

The force required to decelerate the load, taking into account friction, is:

force = mass * acceleration + friction = 45.03 * 11.7 + 408.2 = 959.3 lbs

So, the force required to decelerate the load and bring it to a stop when it is traveling up the hill is approximately 959.3 lbs.

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A body of mass 1500g is dropped from 20m high tower. It will reach the ground in how many seconds? Step-by-Step explanation.

Answers


h = (1/2) * g * t^2


h = height of the tower (20m)

g = acceleration due to gravity (9.8 m/s^2)

t = time taken to reach the ground (unknown)

t = sqrt(2h/g)

Plugging in the values for h and g, we get:

t = sqrt(2(20)/9.8)

Evaluating this expression, we get:

t = 2.02 seconds

Therefore, the body will reach the ground in approximately 2.02 seconds ion i hope that helped lol

Answer: 2.02 seconds.

Explanation:  Let’s solve this problem step-by-step. When an object is dropped from a height, it falls freely under the influence of gravity. The distance fallen by a freely falling object is given by the equation of motion: s = 1/2 * g * t^2, where s is the distance fallen, g is the acceleration due to gravity (9.8 m/s^2 on Earth), and t is the time taken to fall that distance.

In this case, the body of mass 1500g (which is irrelevant to the problem) is dropped from a height of 20m. So we can plug s = 20m and g = 9.8 m/s^2 into the equation above to find the time taken for the body to reach the ground: 20 = 1/2 * 9.8 * t^2. Solving for t, we get t^2 = 20 / (1/2 * 9.8) = 4.08. Taking the square root of both sides, we get t = sqrt(4.08) ≈ 2.02 seconds.

So, a body of mass 1500g dropped from a 20m high tower will reach the ground in approximately 2.02 seconds.

If we move a negative charge towards a second negative charge, how does the potential energy of the charge change?

Answers

If we move a negative charge towards a second negative charge, the potential energy of the charge will increase.

This is because both negative charges repel each other due to the electrostatic force, which is a conservative force.

Work must be done to move the charges closer together against the force of repulsion.

As the charges get closer, the electrostatic potential energy stored in the system increases, which means that the potential energy of the charges increases.

The amount of potential energy stored in the system depends on the distance between the charges, as well as the magnitudes of the charges.

The closer the charges are, the higher the potential energy, and the greater the magnitude of the charges, the higher the potential energy.

The relationship between potential energy and separation distance for two point charges is given by Coulomb's law:

U = k(q1*q2)/r

where U is the potential energy,

k is Coulomb's constant,

q1 and q2 are the magnitudes of the charges, and

r is the separation distance between them.

As r decreases, U increases, which means that the potential energy of the charges increases as they are brought closer together.

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A cylinder (I = MR2/2) is rolling along the ground at 7.0 m/s. It comes to a hill and starts going up. Assuming no losses to friction, how high does it get before it stops?

Answers

In the absence of friction, the maximum height the cylinder can reach is 2.51 meters, after which it will stop.

How to find the hieght of cylinder?

The conservation of energy can be used to solve this problem. At the bottom of the hill, the total mechanical energy of the system is:

E = 1/2 I w² + 1/2 M v²

where I is the moment of inertia of the cylinder, M is its mass, w is its angular velocity, and v is its linear velocity.

Since the cylinder is rolling without slipping, we know that v = R w, where R is the radius of the cylinder. Substituting this into the above equation and simplifying, we get:

E = 1/2 M v² + 1/2 M v²

E = M v²

At the top of the hill, the cylinder comes to rest, so its final kinetic energy is zero. Therefore, the change in energy is:

ΔE = [tex]E_f_i_n_a_l[/tex] - [tex]E_i_n_i_t_i_a_l[/tex] = -M v²

This change in energy is equal to the work done by gravity in lifting the cylinder to a height h:

ΔE = -M g h

where g is the acceleration due to gravity.

Setting these two expressions for ΔE equal to each other and solving for h, we get:

h = v²/2g

Plugging in the given values, we get:

h = (7.0 m/s)² / (2 × 9.81 m/s²) ≈ 2.51 m

Therefore, the cylinder reaches a height of approximately 2.51 meters before it stops.

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Each of 138 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 138 N.What is the tension in the string connecting block 138 to block 137?

Answers

The tension in the string connecting block 138 to block 137 is 138 N, which is the same as the tension in the string connecting each block in the chain.

When a force is applied to the first block in the chain, it creates tension in the string connecting it to the second block. This tension is then transferred to the second block, which creates tension in the string connecting it to the third block, and so on. Therefore, as we move down the chain, the tension in the string between each block will remain constant.

In this case, the force applied to the first block is 138 N. Since the blocks are identical and there is no friction, each block will experience the same force. Therefore, the tension in the string between each block will also be 138 N.

To find the tension in the string connecting block 138 to block 137, we can simply look at the tension in the string connecting block 137 to block 136, which is also 138 N. This tension is then transferred to block 138, so the tension in the string between block 138 and block 137 is also 138 N.

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what is the amount of C¹² left in a sample after 40 s (given the half life of C¹² is 20 sec?)

Answers

The half-life of C¹² is 20 seconds, which means that every 20 seconds, half of the initial amount of C¹² will decay into other elements. After the first 20 seconds, half of the initial amount will be left, and after another 20 seconds, half of that amount will be left.

So, if we start with an initial amount of 100 units of C¹², after 20 seconds, 50 units will be left. After another 20 seconds (a total of 40 seconds), another half of the remaining 50 units will decay, leaving us with only 25 units of C¹².

Therefore, after 40 seconds, the amount of C¹² left in a sample with an initial amount of 100 units is 25 units.

It is important to note that the amount of C¹² left in a sample will always be half of the previous amount after every half-life with an initial amount of 100 units will be 25 units.

This information is crucial for radiocarbon dating and other applications of radioisotopes.

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In two or three sentences, explain the three tenants of Hinduism.

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Hinduism is based on three main beliefs: the idea of dharma (duty and righteousness), karma (the law of cause and effect), and moksha (the liberation from the cycle of rebirth).

What is effect?

Effect is a consequence or result of an action, event, or decision. It can also refer to the power to produce an outcome or result. Effects can be positive, negative, or neutral, depending on the context. Generally, when something has an effect, it changes the state or condition of something else. For example, a change in the weather can have an effect on the growth of crops, or a new law can have an effect on the way people interact with each other. Effects can be long-lasting or temporary, and they can even be cumulative, meaning that the effects of a single event can lead to several other effects. Effects can also be far-reaching, meaning that the effects can affect a large number of people in a variety of ways.

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A steel refrigerator door is not permanently magnetic because
Entry field with correct answer

There are no magnetic domains

The electrons are bound and can't move around much

The door is usually ground out and loses all its m agnetism.

All the magnetic domains are oriented randomly

Answers

A steel refrigerator door is not permanently magnetic because  "All the magnetic domains are oriented randomly." The correct answer is D.

Magnetism is a property of materials that arises from the motion of electrons within the atoms of the material. In magnetic materials, such as iron, nickel, and cobalt, the electrons are arranged in such a way that they create a magnetic field. These materials have magnetic domains, which are regions where the atoms are aligned in the same direction, creating a net magnetic field.

Steel is a magnetic material, but it is not usually permanently magnetic. This is because the magnetic domains in steel are oriented randomly, meaning that the net magnetic field of the material is zero. In order to make steel magnetic, an external magnetic field must be applied to align the magnetic domains. However, this alignment is not permanent, and the domains will eventually become randomized again.

Option A, "There are no magnetic domains," is not true because magnetic domains do exist in magnetic materials such as steel.

Option B, "The electrons are bound and can't move around much," is not true because the electrons in steel can move around freely and create a magnetic field.

Option C, "The door is usually ground out and loses all its magnetism," is not true because the loss of magnetism in steel is due to the random orientation of the magnetic domains, not due to external factors such as grinding.

Therefore, The correct answer is D. All the magnetic domains are oriented randomly.

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What is related to the difference in electric potential energy between two points?

Answers

The difference in electric potential energy between two points is related to the voltage, which is also known as the electric potential difference. Voltage is a measure of the electric potential energy per unit charge, and it represents the work that is done per unit charge to move a charge from one point to another in an electric field. The greater the difference in electric potential energy between two points, the higher the voltage and the greater the force that drives the flow of electric charge (current) between the two points.

A block sliding on ground where uk = 0.193 experiences a 14.7 N friction force. What is the mass of the block?

Answers

The mass of the block is approximately 7.76 kg for a block sliding on the ground where uk = 0.193 experiences a 14.7 N friction force.

The friction force of an object sliding on a surface is calculated using the formula Ff = μk x N, where μk is the coefficient of kinetic friction and N is the normal force.

In this problem, we are given the friction force of 14.7 N and the coefficient of kinetic friction of 0.193. We need to find the mass (m) of the block.

To find the mass, we first need to calculate the normal force acting on the block. The normal force is equal to the weight of the block, which can be calculated using the formula N = m x g, where g is the acceleration due to gravity (approximately 9.81 m/s²).

We substitute the formula for normal force in the frictional force formula to get 14.7 = 0.193 x m x 9.81.

We solve for m to get m = 7.76 kg. Therefore, the mass of the block is approximately 7.76 kg.

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In each variant, the substitution that took place changed the side chain at the affected position in which way?Variants:V86A M87A L209A I276A

Answers

The protein folds and interacts with other molecules, and could have implications for the protein's function.

In each of the variants V86A, M87A, L209A, and I276A, the substitution that took place changed the side chain of the amino acid at the affected position in the following way:

V86A: The amino acid at position 86 was valine (V), which has a branched side chain. The substitution changed it to alanine (A), which has a small, non-branched side chain.

M87A: The amino acid at position 87 was methionine (M), which has a sulfur-containing side chain. The substitution changed it to alanine (A), which has a small, non-sulfur-containing side chain.

L209A: The amino acid at position 209 was leucine (L), which has a branched side chain. The substitution changed it to alanine (A), which has a small, non-branched side chain.

I276A: The amino acid at position 276 was isoleucine (I), which has a branched side chain. The substitution changed it to alanine (A), which has a small, non-branched side chain.

In general, substitutions of amino acids in proteins can have a range of effects on the protein's structure and function, depending on the specific properties of the substituted amino acid and its location in the protein. In the case of the variants listed here, the substitutions are all changing bulky, branched amino acids to smaller, non-branched alanine residues. This can potentially affect the way the protein folds and interacts with other molecules, and could have implications for the protein's function.

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if the atmospheric carbon dioxide decreases by 1 ppm due to plants increasing their biomass, what is the order of magnitude of the increase in plant biomass (measured in kg) per unit of earth's surface area (measured in m2)? for this problem you will need to know that earth's atmospheric surface pressure is 105 n m-2

Answers

The order of magnitude of the increase in plant biomass per unit of Earth's surface area is approximately 0.1 kg/m².

To solve this problem, we need to use some information about the carbon cycle and the relationship between atmospheric CO₂and plant biomass.

According to the carbon cycle, plants absorb CO₂ from the atmosphere during photosynthesis and convert it into biomass. Therefore, if the atmospheric CO₂ decreases by 1 ppm, it suggests that plants have increased their biomass by absorbing that CO₂.

To estimate the increase in plant biomass per unit of Earth's surface area, we can use the following formula:

ΔB = ΔC / α

where ΔB is the increase in plant biomass, ΔC is the decrease in atmospheric CO₂(in parts per million, or ppm), and α is the carbon use efficiency, which represents the fraction of carbon that is incorporated into plant biomass during photosynthesis.

The value of α is typically between 0.3 and 0.5 for most plant species, so we can use an average value of 0.4.

To convert the decrease in atmospheric CO₂ from ppm to a mass per unit of Earth's surface area, we can use the following formula:

ΔC_mass = ΔC * M / A * P

where ΔC_mass is the decrease in CO₂mass per unit of Earth's surface area (in kg/m²), M is the molar mass of CO₂  (44 g/mol), A is Avogadro's number (6.022 x [tex]10^23[/tex]), and P is the atmospheric surface pressure (105 N/m²).

Plugging in the values, we get:

ΔC_mass = 1 ppm * (44 g/mol / 6.022 x[tex]10^23)[/tex] * (1 m² /[tex]10^6 mm²[/tex]) * (105 N/m²) ≈ 0.31 kg/m²

Therefore, the increase in plant biomass per unit of Earth's surface area can be estimated as:

ΔB = ΔC_mass / α ≈ 0.31 kg/m² / 0.4 ≈ 0.78 kg/m²

So the order of magnitude of the increase in plant biomass per unit of Earth's surface area is approximately 0.1 kg/m².

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A rope joins two toboggans. The first toboggan has a 65 kg crate on it and the second has a similar 25 kg crate. A 75 N force is applied to the first toboggan resulting in both moving forward. Calculate the acceleration and the tension in the rope joining the two toboggans. INCLUDE FBD!

Answers

The acceleration of the system is 3 m/s^2, and the tension in the rope is 245 N.

Let's start by finding total mass of the system:

m_total = m1 + m2 = 65 kg + 25 kg = 90 kg

Next, we can use Newton's second law of motion, F = ma, to find the acceleration of the system:

F_net = ma

F_net = F_applied - T

Substituting given values, we get:

75 N = (90 kg) a - T

We need to find the tension in the rope.

We can use the fact that two crates are connected by the same rope, so the tension in the rope is the same for both crates:

T = m2 g

Substituting the given values, we get:

[tex]T = (25 kg) (9.8 m/s^2) = 245 N[/tex]

[tex]75 N = (90 kg) a - 245 N[/tex]

Solving for the acceleration, we get:

[tex]a = (75 N + 245 N) / (90 kg) = 3 m/s^2[/tex]

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two noises have sound levels of 76.2 db and 79.6 db, respectively. what is the sound level when the two noises are combined?

Answers

Sound level when the two noises are combined is approximately 82.0 dB.

What is decibels?

Decibels (dB) is a unit used to measure the intensity or loudness of sound.

When two noises are combined, the resulting sound level can be calculated using the following equation:

L_total = 10 * log10 (I_total / I_ref)

L_total is total sound level in decibels (dB), I_total is total sound intensity, and I_ref is the reference intensity, which is set at 10⁻¹² W/m².

To calculate the total sound level when two noises with sound levels of 76.2 dB and 79.6 dB are combined, we need to convert the sound levels to sound intensities:

I_1 = 10^((76.2 dB - 10 * log10(I_ref))/10) = 1.0 x 10⁻⁷ W/m²

I_2 = 10^((79.6 dB - 10 * log10(I_ref))/10) = 3.98 x 10⁻⁷ W/m²

I_total = I_1 + I_2 = 4.98 x 10⁻⁷ W/m²

L_total = 10 * log10 (I_total / I_ref) = 82.0 dB

Therefore, the sound level when the two noises are combined is approximately 82.0 dB.

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why is a fan blade spinning at a constant speed constantly accelerating

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It moves at a constant linear speed around it. Yet, the linear velocity at any point on the blades is constantly varying and accelerating.

Does speeding up imply movement?

Acceleration typically indicates a change in speed, but not necessarily. An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.

Does accelerating only refer to increasing speed?

Most likely, you picture something racing up when you think about acceleration. But a moving thing accelerates as it slows down. A change in speed is what acceleration is, so keep that in mind. The speed of a car that is slowing down decreases.

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an electric field is produced by a1)a)either a constant or a changing magnetic field.b)constant magnetic field.c)changing magnetic field.d)none of the given answers

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An electric field is produced by either a constant or a changing magnetic field. The correct answer is option A.

Whenever there is a magnetic field that is either changing in strength or direction, it creates an electric field in the surrounding space. This phenomenon is known as electromagnetic induction and is the basis for many technological applications such as generators and transformers.

A coil and a magnet serve as a straightforward illustration to demonstrate the phenomenon of electromagnetic induction. A magnetic flux causes a relative motion to be created when a magnet is brought close to a coil. This generates an electromotive force, which causes the coil to conduct electricity.

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What is the intensity level of a sound with intensity of 5.0 ´ 10-10 W/m2? (I0 = 10-12 W/m2)

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The intensity level of a sound with an intensity of 5.0 × 10-10 W/m2 is 27 dB.

The intensity level of a sound can be calculated using the following formula:
Intensity level (dB) = 10 log (I/I0), where I is the intensity of the sound and I0 is the reference intensity, which is typically 10-12 W/m2.
Using this formula, we can calculate the intensity level of a sound with an intensity of 5.0 × 10-10 W/m2 as follows:
Intensity level (dB) = 10 log (5.0 × 10-10 / 10-12)
Intensity level (dB) = 10 log (5.0 × 102)
Intensity level (dB) = 10 × 2.7
Intensity level (dB) = 27 dB
Therefore, the intensity level of a sound with an intensity of 5.0 × 10-10 W/m2 is 27 dB. It's important to note that the intensity level is a measure of how loud a sound is perceived by the human ear, and is typically measured on a logarithmic scale. So, a sound with an intensity level of 27 dB is considered relatively quiet, while a sound with an intensity level of 120 dB (such as a jet engine or a rock concert) is considered very loud and can cause hearing damage if exposure is prolonged.

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a 10-cm -long thin glass rod uniformly charged to 12.0 nc and a 10-cm -long thin plastic rod uniformly charged to -12.0 nc are placed side by side, 3.90 cm apart. what are the electric field strengths e1 to e3 at distances 1.0 cm , 2.0 cm , and 3.0 cm , from the glass rod along the line connecting the midpoints of the two rods?

Answers

At x = 3.0 cm:

d1 = 3.9 cm / 2 + 3.0 cm = 3.85 cm

d2 = 3.9 cm / 2 - 3.0 cm = 0.05 cm

E1 =

To solve this problem, we can use Coulomb's law to find the electric field at each point along the line connecting the midpoints of the two rods. Coulomb's law states that the electric field created by a point charge is given by:

E = k * Q / r^2

where:

E is the electric field

k is the Coulomb constant, approximately equal to 9 x 10^9 N m^2 / C^2

Q is the charge of the point charge

r is the distance from the point charge

We can also use the principle of superposition to find the total electric field at each point due to both the glass and plastic rods.

First, we need to find the distance between each point on the line connecting the midpoints of the two rods and each rod. Let d1 be the distance between the glass rod and the point, and d2 be the distance between the plastic rod and the point. Since the rods are each 10 cm long and the point is on the line connecting their midpoints, we have:

d1 = 3.9 cm / 2 + x

d2 = 3.9 cm / 2 - x

where x is the distance from the midpoint of the line to the point.

Using Coulomb's law, the electric field due to the glass rod at each point is:

E1 = k * Q / d1^2

and the electric field due to the plastic rod at each point is:

E2 = k * (-Q) / d2^2

where the negative sign indicates that the plastic rod has the opposite charge to the glass rod.

Using the principle of superposition, the total electric field at each point is:

E = E1 + E2

Therefore, we have:

At x = 1.0 cm:

d1 = 3.9 cm / 2 + 1.0 cm = 2.95 cm

d2 = 3.9 cm / 2 - 1.0 cm = 1.95 cm

E1 = (9 x 10^9 N m^2 / C^2) * 12.0 nc / (2.95 cm)^2 = 1.037 x 10^5 N/C

E2 = (9 x 10^9 N m^2 / C^2) * (-12.0 nc) / (1.95 cm)^2 = -2.067 x 10^5 N/C

E = E1 + E2 = -1.030 x 10^5 N/C

At x = 2.0 cm:

d1 = 3.9 cm / 2 + 2.0 cm = 3.4 cm

d2 = 3.9 cm / 2 - 2.0 cm = 0.4 cm

E1 = (9 x 10^9 N m^2 / C^2) * 12.0 nc / (3.4 cm)^2 = 7.573 x 10^4 N/C

E2 = (9 x 10^9 N m^2 / C^2) * (-12.0 nc) / (0.4 cm)^2 = -4.3875 x 10^6 N/C

E = E1 + E2 = -4.311 x 10^6 N/C

At x = 3.0 cm:

d1 = 3.9 cm / 2 + 3.0 cm = 3.85 cm

d2 = 3.9 cm / 2 - 3.0 cm = 0.05 cm

E1 =

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A charged particle moves with a constant speed through a region where a uniform magnetic field is present. If the magnetic field points straight upward, the magnetic force acting on this particle will be maximum when the particle moves
A. upward at an angle of 45 degrees above the horizontal
B. Horizontally
C. Straight downward
D. Straight upward

Answers

A charged particle moves with a constant speed through a region where a uniform magnetic field is present. If the magnetic field points straight upward, the magnetic force acting on this particle will be maximum when the particle moves D. Straight upward

The magnetic force on a charged particle moving through a magnetic field is given by F = qvBsinθ, where q is the charge of the particle, v is its velocity, B is the magnetic field, and θ is the angle between the velocity vector and the magnetic field vector.

Since the speed of the particle is constant, the force is proportional to the sinθ. Therefore, the magnetic force acting on the particle will be maximum when θ is 90°, which means that the particle is moving perpendicular to the magnetic field. In this case, the correct answer is option D, which corresponds to the particle moving straight upward.

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What can be inferred about a material with an index of refraction of 0.9 and 1.5?

Answers

Will be bent at an angle when it enters or exits the material due to the difference in the speed of light in the material and in the air, resulting in phenomena like refraction, total internal reflection, and the creation of optical lenses.

The index of refraction of a material is a measure of how much it slows down light compared to its speed in a vacuum. A material with an index of refraction of 0.9 means that light travels faster in that material than in a vacuum, while a material with an index of refraction of 1.5 means that light is slowed down by a factor of 1.5 in that material compared to its speed in a vacuum.

Therefore, it can be inferred that the material with an index of refraction of 0.9 is a rare case and most likely does not exist in reality. This is because all materials known to us have a refractive index greater than 1, which means they all slow down light compared to its speed in a vacuum.

On the other hand, the material with an index of refraction of 1.5 is likely to be a transparent and dense material, such as glass or diamond, which are known for their high refractive indices. Light passing through such a material will be bent at an angle when it enters or exits the material due to the difference in the speed of light in the material and in the air, resulting in phenomena like refraction, total internal reflection, and the creation of optical lenses.

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a small circular hole 6.00 mm in diameter is cut in the side of a very large water tank 14.0 meters below the water level in the tank. the top of the tank is open to the air. find the volume of the water discharged in liters per second.

Answers

The volume of water discharged in liters per second is 4.04 L/s.

To find the volume of water discharged per second, we need to use Torricelli's law, which relates the velocity of fluid flowing out of a small hole at the bottom of a tank to the height of the fluid above the hole. Torricelli's law is given by:

v = sqrt(2gh)

where:

v = velocity of fluid flowing out of the hole

g = acceleration due to gravity (9.81 m/s^2)

h = height of fluid above the hole

We can use the law of conservation of energy to relate the potential energy of the water in the tank to the kinetic energy of the water flowing out of the hole. The potential energy of the water in the tank is given by:

PE = mgh

where:

m = mass of water

g = acceleration due to gravity

h = height of the water above the hole

The kinetic energy of the water flowing out of the hole is given by:

KE = (1/2)mv^2

where:

m = mass of water

v = velocity of water flowing out of the hole

Equating these two energies and solving for v, we get:

v = sqrt(2gh)

Now we need to find the height of the water above the hole. We know that the diameter of the hole is 6.00 mm, which gives us the radius of the hole, r = 3.00 mm = 0.003 m. The area of the hole is then:

A = πr^2 = π(0.003)^2 = 2.827e-5 m^2

The volume of water flowing out of the hole per second is given by:

Q = Av

where:

Q = volume of water flowing out per second

A = area of the hole

v = velocity of water flowing out of the hole

Substituting the values we have found, we get:

Q = (2.827e-5)(sqrt(2(9.81)(14.0))) = 0.00404 m^3/s

Finally, we convert this to liters per second:

Q = 0.00404 m^3/s * 1000 L/m^3 = 4.04 L/s

Therefore, the volume of water discharged in liters per second is 4.04 L/s.

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