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What expression shows 3 less than a number?
A. n + 3
B. n - 3
C. 3 - n
D. 3n

Answer:

2x2x2x2x2x2, 4x16, and 8x8

Step-by-step explanation:

Marissa should expect approximately 118 shark attacks over the next 3 summers while working as a beach lifeguard in Florida. Keep in mind that this is just an estimation based on the provided data.

To estimate the number of shark attacks Marissa should expect over the next 3 summers, we will need to find the average number of attacks per year and then multiply it by 3. Let's ignore the irrelevant terms ("NW" and "Marissa") in the data set and calculate the average.

1. Add the given number of attacks:
34 + 40 + 47 + 32 + 28 + 29 + 53 + 48 + 43 = 354

2. Count the number of years in the data set:
There are 9 years.

3. Calculate the average number of attacks per year:
Average = Total attacks / Number of years = 354 / 9 = 39.33 (rounded to two decimal places)

4. Estimate the number of attacks over the next 3 summers:
Expected attacks = Average attacks per year × 3 = 39.33 × 3 = 118 (rounded to the nearest whole number)

Marissa should expect approximately 118 shark attacks over the next 3 summers while working as a beach lifeguard in Florida. Keep in mind that this is just an estimation based on the provided data. Marissa should expect about 118 shark attacks over the next 3 summers.

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The general solution of dy/dx = sin2x is -1/2 cosx + c and dy/dx = sinx is

-cos x + c

Given that, we need to find the general solution of the derivatives, dy/dx = sin2x and dy/dx = sinx

1) dy/dx = sin2x

y = ∫sin2x dx

y = -1/2 cos 2x + c

2) dy/dx = sinx

y = ∫sinx

y = -cosx + c

Hence, the general solution of dy/dx = sin2x is -1/2 cosx + c and dy/dx = sinx is -cos x + c

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i. The value of k that results in a valid probability distribution is 0.25.

ii. The expected value of X is 1.9.

iii. The variance of X is 0.9025 and the standard deviation of X is 0.95.

iv. The probability that X is greater than or equal to 1 is 0.85.

v.  The CDF of X is:

F(x) = 0 for x<0

F(x) = 0.15 for 0<=x<1

F(x) = 0.4 for 1<=x<2

F(x) = 0.65 for 2<=x<3

F(x) = 1 for x>=3.

i. To find the value of k that results in a valid probability distribution, we need to use the fact that the sum of the probabilities for all possible values of X must equal 1.

Thus, we have:

0.15 + 0.25 + k + 0.35 = 1

Simplifying this equation, we get:

k = 0.25

Therefore, the value of k that results in a valid probability distribution is 0.25.

ii. The expected value of X, denoted by E(X), can be calculated using the formula:

E(X) = Σ[x*P(X=x)]

where the sum is taken over all possible values of X.

Thus, we have:

E(X) = (00.15) + (10.25) + (20.25) + (30.35)

E(X) = 1.9

Therefore, the expected value of X is 1.9.

iii. The variance of X, denoted by Var(X), can be calculated using the formula:

Var(X) = Σ[(x-E(X))^2*P(X=x)]

where the sum is taken over all possible values of X.

Thus, we have:

[tex]Var(X) = (0-1.9)^20.15 + (1-1.9)^20.25 + (2-1.9)^20.25 + (3-1.9)^20.35[/tex]

Var(X) = 0.9025

The standard deviation of X, denoted by σ(X), is the square root of the variance, i.e., σ(X) = [tex]\sqrt{(Var(X)}[/tex].

Therefore:

σ(X) = sqrt(0.9025) = 0.95

Therefore, the variance of X is 0.9025 and the standard deviation of X is 0.95.

iv. The probability that X is greater than or equal to 1 can be calculated by adding the probabilities of X=1, X=2, and X=3.

Thus, we have:

P(X>=1) = P(X=1) + P(X=2) + P(X=3)

= 0.25 + 0.25 + 0.35

= 0.85

Therefore, the probability that X is greater than or equal to 1 is 0.85.

v. The CDF of X, denoted by F(x), is defined as:

F(x) = P(X<=x)

for all possible values of x.

Thus, we have:

F(0) = P(X<=0) = 0.15

F(1) = P(X<=1) = 0.15 + 0.25 = 0.4

F(2) = P(X<=2) = 0.4 + k = 0.65

F(3) = P(X<=3) = 0.65 + 0.35 = 1

Therefore, the CDF of X is:

F(x) = 0 for x<0

F(x) = 0.15 for 0<=x<1

F(x) = 0.4 for 1<=x<2

F(x) = 0.65 for 2<=x<3

F(x) = 1 for x>=3.

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The credibility factor, Z, for Year 2 is 1.2875.

To determine the credibility factor, Z, for Year 2, we can use the

Buhlmann-Straub model, which assumes that the number of claims for

each policyholder follows a negative binomial distribution with mean θ

and dispersion parameter β. The credibility formula is given by:

Z = (k + nβ)/(n + β),

where k is the number of claims observed in Year 1, n is the number of

policyholders in Year 1, and β is the dispersion parameter.

From the data provided, we can calculate the values of k and n for Year 1

as follows:

k = 1400 + 2300 + 380 + 420 = 820

n = 2200 + 400 + 300 + 80 + 20 = 3000

To determine the dispersion parameter β, we can use the method of

moments. For a negative binomial distribution, the mean and variance

are given by:

mean = θ

variance = θ(1 + βθ)

Solving for θ and β, we get:

θ = variance/mean

β = (variance/mean) - 1

Using the data from Year 1, we can estimate the mean and variance of the number of claims as follows:

mean = k/n = 820/3000 = 0.2733

[tex]variance = \sum (x - mean)^2 / n = 02200 + 1400 + 2300 + 380 + 4\times 20 / 3000 = 0.6313[/tex]

Substituting these values into the equations above, we get:

θ = 0.6313/0.2733 = 2.3104

β = (0.6313/0.2733) - 1 = 1.3088

Finally, we can use the credibility formula to calculate the credibility factor, Z, for Year 2:

Z = (k + nβ)/(n + β) = (0 + 3000*1.3088)/(3000 + 1.3088) = 1.2875

Therefore, the credibility factor, Z, for Year 2 is 1.2875. This means that we should give more weight to the expected number of claims for Year 2 based on the data from Year 1, rather than the expected number of claims based on the conditional negative binomial distribution with β=0.5.

The higher the credibility factor, the more weight we should give to the observed data from Year 1, and the less weight we should give to the prior distribution.

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Answer:

The correct set of data is D.

The unknown sides and angles of the pyramid can be found as follows:

The diagram is a square based pyramid. ABCD is the square based side. Hence, M is the mid point of BC.

Let's find the required sides as follows:

Let's find the length of XM.

XM = 10 / 2 = 5 cm

Let's find the length VM using Pythagoras's theorem.

c²= a² + b²

where

Therefore,

VM = √8² - 5²

VM = √64 - 25

VM = √39 cm

Therefore, let's find the angle between VM and ABCD

Using trigonometric ratios,

tan M = opposite / adjacent

tan M = 8 / 5

M = tan⁻¹ 1.6

M = 57.9946167919

M = 58 degrees

Therefore, the angle is 58 degrees.

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The probability of at most three successes (P(X ≤ 3)) in 7 independent Bernoulli trials is 0.7106.

To calculate the probability of at most three successes (P(X ≤ 3)) in 7 independent Bernoulli trials with p = 0.4 and q = 0.6, you can use the binomial probability formula. The formula is:

P(X = k) = C(n, k) * p^k * q^(n-k)

where n is the number of trials, k is the number of successes, p is the probability of success, q is the probability of failure, and C(n, k) is the number of combinations of n items taken k at a time.

For P(X ≤ 3), you'll need to calculate the probabilities for 0, 1, 2, and 3 successes and add them together:

P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

For each value of k (0, 1, 2, and 3), compute the probability using the binomial formula:

1. P(X = 0) = C(7, 0) * (0.4)^0 * (0.6)^7
2. P(X = 1) = C(7, 1) * (0.4)^1 * (0.6)^6
3. P(X = 2) = C(7, 2) * (0.4)^2 * (0.6)^5
4. P(X = 3) = C(7, 3) * (0.4)^3 * (0.6)^4

Calculate the probabilities and add them together:

P(X ≤ 3) ≈ 0.02799 + 0.13043 + 0.26186 + 0.29030 ≈ 0.71058

So, the probability of at most three successes (P(X ≤ 3)) in 7 independent Bernoulli trials with p = 0.4 and q = 0.6 is approximately 0.7106 (rounded to four decimal places). You can check this answer using a calculator or software that supports binomial probability calculations.

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The dimension of the matrix space Mm×n(F) is not m + n. The correct answer is false.

The dimension of a matrix space is determined by the number of linearly independent vectors or rows/columns it contains. For Mm×n(F), which represents matrices with m rows and n columns over the field F, the dimension is given by m × n, not m + n. This is because each matrix in Mm×n(F) has m × n entries, and the number of linearly independent entries determines the dimension of the matrix space.

Therefore, the correct answer is false.

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The value of the given function is f(t) = (t²/2) - (1/2t²) + 6 under the given condition that  f'(t) = t + 1/t³, t>0, f(1) = 6.

The given function f(t) can be solved using the principles of  integrating f'(t) concerning t

f'(t) = t + 1/t³

Applying integration on both sides concerning t is

f(t) = (t²/2) - (1/2t²) + C

here C = constant of integration.

Now, placing f(1) = 6, we can evaluate C

6 = (1/2) - (1/2) + C

C = 6

The value of the given function is f(t) = (t²/2) - (1/2t²) + 6 under the given condition that  f'(t) = t + 1/t³, t>0, f(1) = 6.

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The average temperature Tave during the period from 9 AM to 9 PM is 51°F.

The period from 9 AM to 9 PM is 12 hours, so we need to find the average temperature of the function T(t) over that interval. We can do this by finding the definite integral of T(t) over the interval [0, 12] and then dividing by 12.

∫[0,12] T(t) dt = ∫[0,12] (50 + 19 sin πt/12) dt

Using the integral formula ∫ sin ax dx = -1/a cos ax, we can evaluate the integral:

= [50t - 19/π cos πt/12] [0,12]

= [600 - 19/π cos π - (-19/π cos 0)]

= [600 + 19/π (cos 0 - cos π)]

= [600 + 38/π] ≈ 611.93

Therefore, the average temperature Tave is:

Tave = [∫[0,12] T(t) dt] / 12 ≈ 611.93 / 12 ≈ 51.00°F

Rounding to the nearest degree, we get Tave ≈ 51°F.

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State whether S is bounded or unbounded.

However, you have not provided the set "S" for which this information is needed. Please provide the set "S" so I can assist you with the question.

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The probability that a student who received college credit scored a 3 on the exam is 0.034 or about 3.4%.

Let A be the event that the student scored 4 or 5, B be the event that the student scored 3, and C be the event that the student scored 1 or 2. We are given that P(A) = 0.60, P(B) = 0.25, and P(C) = 1 - P(A) - P(B) = 0.15.

We are also given the conditional probabilities P(Credit|A) = 0.95, P(Credit|B) = 0.50, and P(Credit|C) = 0.04, where Credit is the event that the student received college credit.

Using Bayes' theorem, we can calculate the probability that a student who received college credit scored a 3:

P(B|Credit) = P(Credit|B) * P(B) / [P(Credit|A) * P(A) + P(Credit|B) * P(B) + P(Credit|C) * P(C)]

= 0.50 * 0.25 / [0.95 * 0.60 + 0.50 * 0.25 + 0.04 * 0.15]

= 0.034

This result shows that even though 25% of the students scored 3 on the exam, they have a much lower probability of receiving college credit compared to those who scored 4 or 5.

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Complete question is:

Suppose that 60% of the students who take the ap statistics exam score 4 or 5, 25% score 3, and the rest score 1 or 2. suppose further that 95% of those scoring 4 or 5 receive college credit, 50% of those scoring 3 receive such credit, and 4% of those scoring 1 or 2 receive credit. if a student who is chosen at random from among those taking the exam receives college credit, what is the probability that she received a 3 on the exam?

If two triangles are similar, then their corresponding sides are proportional and their corresponding angles are congruent 1. Therefore, we can set up a proportion of the corresponding sides of the two triangles and solve for x.

For example, if we have two similar triangles ABC and EDC with sides AB = 6, BC = 8, AC = 10 and ED = 9, DC = 12, EC = 15 respectively as shown below:

    A

    /\

   /  \

  /____\

 B      C

    E

    /\

   /  \

  /____\

 D      C

We can set up a proportion of the corresponding sides as follows:

AB/ED = BC/DC = AC/EC

6/9 = 8/12 = 10/15

Simplifying this proportion gives us:

2/3 = 2/3 = 2/3

Therefore, x is equal to:

x = EC - DC

x = 15 - 12

x = 3

So in this case, x is equal to 3.

I hope that helps!

Estimating the square root of the number √232 gives 15

From the question, we have the following parameters that can be used in our computation:

√232

To estimate the number is to approximate the number

The number closest to 232 whose square root can be calculated is 225

This means that

√232 ≈ √225

Evaluate the square root

√232 ≈ 15

Hence, the estimate is 15

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The mean decreases and the median remains the same.

option D.

The mean and median of the distribution is calculated as follows;

Initial mean =  $40 + $83 + $37 + $40 + $31 + $68

= 299 / 6

= $49.8

Final mean;

Total = $40 + $83 + $37 + $40 + $31 + $68 + $23

Total = $322

mean = $322 / 7 = $46

To find the median, we first need to put the earnings in order from smallest to largest.

median = $23, $31, $37, $40, $40, $68, $83

the median is the fourth number =  $40.

The initial median and final median will be the same.

Thus, mean decreases and the median remains the same.

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The given claim by the company that a cereal packet   weighs around 14 oz is considered as a Type I error because it rejects an accurate null hypothesis. Type I error refers to a statistical concept that describes  the incorrect rejection of an accurate null hypothesis.

In short, it is a false positive observation. For the given case, the cereal company positively projects that the mean weight of cereal present in  packets is at least 14 oz and gets rejected, this claim even though it is accurate and should not be rejected, but it wents and is labelled as a Type I error.

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Answer:

Step-by-step explanation:

To determine the answer, we need to calculate the number of boxes that can fit along the width of the crate, which is 8 feet or 96 inches.

To do this, we need to find out how many boxes can fit in one row along the width of the crate. We know that each box is 4 inches wide, so we can divide the width of the crate by the width of one box:

96 inches / 4 inches = 24 boxes

Therefore, the answer is A. 24 boxes will fit along the width of the crate.

Answer:

24 boxes

Step-by-step explanation:

The number of boxes that can fit along the width of the crate, which is 8 feet or 96 inches, must be calculated in order to find the solution.

To do this, we must ascertain the number of boxes that can be arranged in a row across the width of the crate. We can divide the width of the crate by the width of one box because we know that each box is 4 inches wide:

96 inches / 4 inches equals 24 boxes.

As a result, the response is A. Along the width of the crate, 24 boxes can fit.

The direction angles of the vector v = 2i + 6j - 3k are α = 73°, β = 31°, and γ = 115°

To find the direction angles of the vector v = 2i + 6j - 3k, we need to calculate the angles α, β, and γ between the vector and the x, y, and z axes, respectively.

1. Calculate the magnitude of the vector:

|v| = [tex]√(2^2 + 6^2 + (-3)^2)[/tex]

= √(4 + 36 + 9)

= √49 = 7

2. Find the cosine of each direction angle:
  cos(α) = (2) / |v| = 2/7
  cos(β) = (6) / |v| = 6/7
  cos(γ) = (-3) / |v| = -3/7

3. Calculate the direction angles by finding the inverse cosine of each cosine value:
  α = [tex]cos^(-1)(2/7)[/tex] ≈ 73°
  β = [tex]cos^(-1)(6/7)[/tex] ≈ 31°
  γ = [tex]cos^(-1)(-3/7)[/tex]≈ 115°

Thus, the direction angles of the vector v = 2i + 6j - 3k are α = 73°, β = 31°, and γ = 115°.

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The cost of installing a typical septic system without any special features can vary depending on various factors, such as the size of the property, soil type, and location. On average, a septic system installation can cost anywhere from $3,000 to $7,000.

The cost of installing a septic system can depend on various factors, such as the size of the property, soil type, location, and regulations in the area. The installation process typically involves excavating the area, installing the septic tank and leach field, and connecting the plumbing to the septic system. The cost of the septic tank itself can range from $500 to $2,000, and the leach field can cost around $2,000 to $4,000. In addition, there may be additional costs associated with obtaining permits and hiring contractors.

Therefore, the cost of installing a typical septic system without any special features can range from $3,000 to $7,000, depending on various factors.

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The standard deviation of the average drying times is 2.5 minutes.

To find the standard deviation of the average drying times for a sample of 36 paint drying times, we'll use the formula: Standard deviation of the sample mean = Population standard deviation / √(sample size).

In this case, the paint drying times are normally distributed with a mean of 120 minutes and a standard deviation of 15 minutes.

The sample size is 36. Standard deviation of the sample mean = 15 / √(36) = 15 / 6 = 2.5 minutes. So, the standard deviation of the average drying times for the sample is 2.5 minutes.

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The behavior of this solution is oscillating with decreasing amplitude, as the exponential factor e^(-8t) causes the amplitude of the cosine and sine functions to decrease over time .

[tex]y(t) = e^(-8t)(2 cos(9t) + (4/3) sin(9t))[/tex]

To solve the differential equation [tex]y' + 8y + 177 = 0[/tex], we first find the characteristic equation by assuming that the solution is of the form y = e^(rt), where r is a constant:

[tex]r e^(rt) + 8 e^(rt) + 177 = 0[/tex]

Factor out e^(rt):

e^(rt) (r + 8) + 177 = 0

Solve for r:

[tex]r = -8 ± sqrt((-8)^2 - 4(1)(177)) / 2(1) = -4 ± 9i[/tex]

Thus, the general solution to the differential equation is:

[tex]y(t) = e^(-8t)(c1 cos(9t) + c2 sin(9t))[/tex]

To find the values of c1 and c2, we use the initial conditions given:

y(0) = 2, y'(0) = -12

Plugging in t = 0 and y(0) = 2, we get:

2 = c1

Plugging in t = 0 and y'(0) = -12, we get:

[tex]y'(t) = -8 e^(-8t) (c1 cos(9t) + c2 sin(9t)) + 9 e^(-8t) (-c1 sin(9t) + c2 cos(9t))[/tex]

-12 = -8(c1) + 9(c2)

Substituting c1 = 2 into the second equation, we get:

-12 = -16 + 9(c2)

c2 = 4/3

Therefore, the solution to the differential equation y' + 8y + 177 = 0 with initial conditions y(0) = 2 and y'(0) = -12 is:

[tex]y(t) = e^(-8t)(2 cos(9t) + (4/3) sin(9t))[/tex]

The behavior of this solution is oscillating with decreasing amplitude, as the exponential factor e^(-8t) causes the amplitude of the cosine and sine functions to decrease over time.

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Consecutive interior angles are formed when a pair of parallel lines is intersected by a transversal line. False, two consecutive interior angles are not always supplementary angles.

Consecutive interior angles are formed when a pair of parallel lines is intersected by a transversal line. These angles are located on the same side of the transversal and on the interior of the parallel lines. While it is true that consecutive interior angles can be supplementary in some cases, they are not always supplementary.

To understand why, let's consider an example. Suppose we have two parallel lines intersected by a transversal, and one pair of consecutive interior angles measures 90 degrees each. In this case, the other pair of consecutive interior angles will also measure 90 degrees each, making them supplementary angles (since the sum of their measures is 180 degrees). However, if one pair of consecutive interior angles measures 120 degrees and the other pair measures 60 degrees, then they are not supplementary angles.

In general, consecutive interior angles are only supplementary when the parallel lines are intersected by a transversal at a right angle (90 degrees). If the lines are intersected at any other angle, the consecutive interior angles will not be supplementary.

Therefore, the statement "Two consecutive interior angles are always supplementary angles" is false.

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For the given sequences, 11) a_n = {4/n²} is monotonic decreasing and bounded, 12) a_n = {(3n²)/(n²+1)} is monotonic increasing and unbounded, and 13) a_n = {2(-1)ⁿ⁺¹} is neither monotonic nor bounded.


11) a_n = {4/n²}: As n increases, the terms in the sequence decrease, since the denominator (n²) grows larger, making the fraction smaller. This makes the sequence monotonic decreasing. Additionally, the sequence is bounded below by 0, as the terms are always positive, and it approaches 0 as n approaches infinity.

12) a_n = {(3n²)/(n²+1)}: As n increases, the terms in the sequence also increase, since the numerator (3n²) grows larger and the denominator (n²+1) also grows larger, but at a slower rate.

This makes the sequence monotonic increasing. However, there is no upper limit for the terms, as the sequence does not approach a specific value when n approaches infinity, making it unbounded.

13) a_n = {2(-1)ⁿ⁺¹}: This sequence alternates between positive and negative values for each consecutive term, making it neither monotonic nor bounded.

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(a)The most likely value for the number of burgers in a sample of 50 that contain more than 1,000 calories is 31.

(b) There is an approximately 62% chance that a batch of 50 ZeroCal patties contains 31 or more patties with more than 1,000 calories.

To compute the probability distribution for n = 50 Bernoulli trials with a known success rate of 61%, we can use the binomial distribution. Let X be the number of ZeroCal hamburger patties that contain more than 1,000 calories in a sample of 50. Then X follows a binomial distribution with parameters n = 50 and p = 0.61.

(a) The most likely value for the number of burgers in a sample of 50 that contain more than 1,000 calories is the expected value of X, which is np = 50 x 0.61 = 30.5.

Since we cannot have a fractional number of burgers, we round this to the nearest whole number, which is 31 burgers.

(b) To find the probability that a batch of 50 ZeroCal patties contains k or more patties with more than 1,000 calories, we can use the cumulative distribution function (CDF) of the binomial distribution. P(X >= k) = 1 - P(X < k) = 1 - F(k-1), where F(k-1) is the CDF evaluated at k-1.

Using a calculator or software, we can find that P(X >= 31) is approximately 0.616, or 61.6%. Therefore, the completed sentence is: "There is an approximately 62% chance that a batch of 50 ZeroCal patties contains 31 or more patties with more than 1,000 calories."

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The Prime factors of 18 are (2²) * 3 or 2 * 2 * 3. Thus, option B is the correct answer.

Prime numbers are numbers that are not divisible by any other number other than 1 and the number itself.

Composite numbers are numbers that have more than 2 factors that are except 1 and the number itself.

Prime factors are the prime numbers that when multiplied get the original number.

To calculate the prime factor, we use the division method.

In this method, firstly we divide the number by the smallest prime number it is when divided it leaves no remainder. In this case, we divide 18 by 2 and get 9.

Again, divide the number we get that, in this case, is 9, in the previous step by the prime number it is divisible by. So, 9 is again divided by 3 and we get 3.

We have to perform the previous step until we get 1. And 3 ÷ 3 = 3. Since we get 1, we stop here.

Finally, Prime factorization of 18 is expressed as 2 × 2 × 3  or we can write it as (2²) * 3

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A financial register is a good reference for tracking spending patterns.

A financial register is tool used for managing personal finances because it allows to record and track spending patterns in a systematic way. It typically includes fields for recording transaction details such as date, description, category and amount.

By updating the financial register with all expenses, one can gain insights into spending habits, identify areas where you may be overspending and make informed decisions about budgeting and saving.

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Answer:

checkbook

Step-by-step explanation:

A checkbook register is a good reference for tracking spending patterns.

The the parametric form of the circle x^2 + y^2 = 64 is x= 8cosθ,y= 8sinθ.

Given that,

x^2 + y^2 = 64

or, x^2 + y^2 = 8^2

r=8, center=(0,0)

Parametric equations are x= 8cosθ

y= 8sinθ

∴x= 8cosθ,y= 8sinθ

Explanation:

we know that,

The polar form of the equation is expressed in terms of r and theta,

The conversion of Cartesian co-ordinate to Polar co-ordinate is given by,

x^2 + y^2 = r^2

Parametric equations shows the relation between a group of quantities by expressing the coordinates of points of a curve and function as one or more independent variables.

1) For a given value of the independent variable the parametric equation is used exactly one point on the graph

2) the parametric equations  have a finite domain

3) the parametric equation is easier to enter into a calculator for graphic

we can represent the circle in a parametric form as:

x= 8cosθ,y= 8sinθ.

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1. No, the two triangles are not identical.

2. Yes, the two triangles are identical.

How can two triangles be the same?

If two triangles satisfy one of the following conditions, they are congruent: The three corresponding side pairings are all equal. The comparable angles between two pairs of corresponding sides are equal. The corresponding sides between two pairs of corresponding angles are equal.

This is demonstrated by noticing that a triangle's three angles must sum to 180 degrees.

For the first triangle, the angles are 95°, 70°, and 40°, which add up to 205°.

For the second triangle, the angles are 70°, 40°, and 70°, which add up to 180°.

Since the two triangles' angles differ, the triangles themselves must also be unique.

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The solution to the given differential equation with the given initial conditions is y(t) = 5/2 [tex]e^{-13/40 t}[/tex] [cos(√249/40 t) + (5/√249)sin(√249/40 t)]

The given differential equation is a second-order linear homogeneous differential equation with constant coefficients. We can use the characteristic equation method to solve it.

The characteristic equation is:

20r² + 13r + 1 = 0

We can solve for r using the quadratic formula:

r = (-13 ± √(13² - 4201)) / (2*20)

= (-13 ± √249) / 40

The roots are real and distinct, so the general solution to the differential equation is:

y(t) = c₁[tex]e^{(rt) }[/tex] + c₂[tex]e^{(rt) }[/tex]

where c₁ and c₂ are constants determined by the initial conditions.

Using the initial condition y(0) = 5, we have:

y(0) = c₁ + c₂ = 5

Using the initial condition y'(0) = 3, we have:

y'(t) = c₁r₁[tex]e^{(rt) }[/tex] + c₂r₂[tex]e^{(rt) }[/tex]

y'(0) = c₁r₁ + c₂r₂ = 3

Solving these two equations for c₁ and c₂, we get:

c₁ = (5r₂ - 3) / (r₂ - r₁)

c₂ = (3 - 5r₁) / (r₂ - r₁)

Substituting these values into the general solution, we get:

y(t) = [(5r₂ - 3) / (r₂ - r₁)][tex]e^{(rt) }[/tex]+ [(3 - 5r₁) / (r₂ - r₁)][tex]e^{(rt) }[/tex]

Substituting the values of r₁ and r₂, we get:

y(t) = [(-13 + √249)/40 - 5/4][tex]e^{((-13 - √249)/40 t)[/tex] + [(5/4 - (-13 - √249)/40)[tex]e^{((-13 + \sqrt249)/40 t)}][/tex]

Simplifying and rearranging, we get:

y(t) = 5/2 [tex]e^{-13/40 t}[/tex] [cos(√249/40 t) + (5/√249)sin(√249/40 t)]

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