In a large clinical trial, 393,478 children were randomly assigned to two groups. The treatment group consisted of 197,175 children given a vaccine for a certain disease, and 39 of those children developed the disease. The other 196,303 children were given a placebo, and 138 of those children developed the disease. Consider the vaccine treatment group to be the first sample. Identify the values of n1, p1, q1, n2, p2, q2, p, and q.

(a) The expected value of the number of nights potential customers will need is 1 (b) The standard deviation of the number of nights potential customers will need is 0.77.

a) To find the expected value, we multiply each option by the percentage of customers who will choose it and then add them together. So, we have:

(0.3)(0) + (0.4)(1) + (0.3)(2) = 0 + 0.4 + 0.6 = 1

Therefore, the expected value of the number of nights potential customers will need is 1.

b) To find the standard deviation, we need to first find the variance. The formula for variance is:

Variance = [tex](Option 1 - Expected Value)^2[/tex] * % of customers choosing it
        + [tex](Option 2 - Expected Value)^2[/tex] * % of customers choosing it
        + [tex](Option 3 - Expected Value)^2[/tex]* % of customers choosing it

Plugging in our values, we get:

Variance =[tex](0-1)^2 * 0.3 + (1-1)^2 * 0.4 + (2-1)^2 * 0.3[/tex]
        = 0.3 + 0 + 0.3
        = 0.6

Then, we take the square root of the variance to get the standard deviation:

Standard Deviation = [tex]\sqrt{0.6}[/tex]
                  = 0.77 (rounded to two decimal places)

Therefore, the standard deviation of the number of nights potential customers will need is 0.77.

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After 5 years, the amount of money accumulated in the savings account will be $84,297.87.

To find the amount of money that will be accumulated in the savings account, we need to use the formula for continuous compound interest:
[tex]A = P * e^{rt}[/tex]
where:
A = the accumulated amount after t years
P = the principal amount (initial investment)
r = the annual interest rate (in decimal form)
t = the number of years
e = the base of the natural logarithm (approximately 2.71828)
Now, let's plug in the given values:
P = 59,350
r = 7.0% = 0.07
t = 5
[tex]A = 59350 * e^{0.07 * 5}[/tex]
Using a calculator, we find that:
[tex]A = 59350 * e^{0.35}[/tex]
A = 59350 * 1.419067
Now, let's multiply and round the result to two decimal places:
A = 84,297.87

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To explore the relationship between students' scores on their first quiz and first exam, you'll want to establish hypotheses about the correlation between these two variables.

In this case, you suspect a negative correlation.

Once you have these hypotheses, you can collect data, perform a correlation analysis, and determine whether to accept or reject the null hypothesis based on the results.

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Answer: C. 1.75

Step-by-step explanation:

Scale 1: 1 inch = 25 miles

2.8 x 25 = 70

2.8 inches = 70 miles

Scale 2: 1 inch = 40 miles

1.75 inches x 40 = 70

The value of (2²)³ is equal to 4096.

To evaluate (2²)³, we first need to calculate 2², which is equal to (2×2)-1 = 3. Now we can substitute this value in (2²)³ as (3)³, which equals to 27×27 = 729.

Therefore, the value of (2²)³ is 4096.

The given operation ^ is defined as a^b=(2a-1)^b-1, which takes a positive integer a and b as input, and returns (2a-1)^(b-1) as output. In this case, we need to calculate (2²)³, which means a=2 and b=3.

Substituting these values in the given operation, we get 2²=(2×2)-1=3, and (2²)³=3³=27. Therefore, the value of (2²)³ is 4096.

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Check the picture below.

[tex]\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2 \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{13}\\ a=\stackrel{adjacent}{s}\\ o=\stackrel{opposite}{s} \end{cases} \\\\\\ (13)^2= (s)^2 + (s)^2\implies 13^2=2s^2\implies \cfrac{13^2}{2}=s^2 \\\\\\ \sqrt{\cfrac{13^2}{2}}=s\implies \cfrac{\sqrt{13^2}}{\sqrt{2}}=s\implies \cfrac{13}{\sqrt{2}}=s[/tex]

Answer:

[tex]\frac{13 \sqrt{2} }{2}[/tex]  OR 9.19

Step-by-step explanation:

hypotenuse =[tex]\sqrt{2}[/tex] * leg

13 = [tex]\sqrt{2}[/tex] * s

[tex]\frac{13 \sqrt{2} }{2}[/tex]

OR (using pythagorean theorem)

[tex]13^{2}[/tex] = 169

169 / 2 = 84.5

[tex]\sqrt{84.5}[/tex] = 9.19

The product of 4 and the sum of a number and 12 is at most 18 can be written as

4(x+12)<=18

or

x+12<=4.5

or

x<=-7.5

Therefore, the value of x can be at most -7.5.

The value of the given integral is approximately 1665.02.

We have,

To use the transformation u = 4x + 3y, v = x + 2y, we need to express x and y in terms of u and v. Solving for x and y, we get:

x = (2v - u)/5

y = (3u - 4v)/5

We also need to find the Jacobian of the transformation:

J = ∂(x,y)/∂(u,v) = (1/5) [(∂x/∂u)(∂y/∂v) - (∂y/∂u)(∂x/∂v)]

= (1/5) [(2/5)(3/5) - (1/5)(1/5)] = 6/25

Now we can evaluate the integral using the new variables:

∬R (3x + 11xy + 6y²) dA = ∬D (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) (6/25) dudv

where D is the region in the uv-plane that corresponds to R in the xy-plane. We need to find the limits of integration for u and v in terms of x and y.

From the equations of the lines that bound R, we can find the vertices of D:

(1) Intersection of y = -5x + 3 and y = -x - 4: (-1/3, 8/3)

(2) Intersection of y = -5x + 3 and y = 2x + 2: (1/7, 20/7)

(3) Intersection of y = 2x + 2 and 4x + 3y = 0: (-3/7, 6/7)

(4) Intersection of y = -x - 4 and 4x + 3y = 0: (-3, 1)

We can use these points to find the limits of integration:

∫ from -3 to -1/3 [∫ from -7x + 4 to -5x + 3 (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) dv] du

∫ from -1/3 to 1/7 [∫ from -7x + 4 to 2x + 2 (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) dv] du

∫ from 1/7 to -3/7 [∫ from -5x + 3 to 2x + 2 (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) dv] du

∫ from -3/7 to -3 [∫ from 4x + 3y to -x - 4 (3(2v - u)/5 + 11(2v - u)(3u - 4v)/25 + 6(3u - 4v)^2/25) dv] du

Simplifying and evaluating the integrals, we get:

∬R (3x + 11xy + 6y²) dx dy

= ∫-1/2^1/2 ∫-7x+4^2x+2 [(3x + 11xy + 6y²) (4u - 3v + 2) + 11x(4u - 3v + 2) + 22y(4u - 3v + 2)] dxdy (using the transformation u = 4x + 3y, v = x + 2y)

= ∫-1/2^1/2 ∫-7u/11+2/11^2u/11+1/11 [(12u/11 + 12u²/11² + 36u²/11²) + (44u/11² + 44u²/11³) + (88u/11^2 + 88u²/11³)] dudv

= ∫-1/2^1/2 [(240/11 + 880/11² + 1760/11³) (11v/2 - 2/11) + (528/11² + 1056/11³) (11v/2 - 2/11)²] dv

= ∫-5³ [(240/11 + 880/11² + 1760/11³) (11v/2 - 2/11) + (528/11² + 1056/11³) (11v/2 - 2/11)²] dv

= (1820/11 + 2640/11² + 880/11³) [(3² - (-5)²)/2] + (528/11² + 1056/11³) [(3³ - (-5)³)/3 - (3 - (-5))]

= 15320/33 + 33024/11³ ≈ 1665.02

Therefore,

The value of the given integral is approximately 1665.02.

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The total distance John drove to work in 10days is 50.5 miles

A word problem in math is a math question written as one sentence or more. This statement is interpreted into mathematical equation or expression.

For the first five days, John drove 5½ miles

The total distance for the 5 days = 5 × 11/2 = 55/2 miles

For the second five days, he drove 7 2/3 miles each day.

The total distance he drove = 23/3 × 5 = 115/5

= 23miles

Therefore the total distance he drove for the 10 days = 55/2 + 23

= 27.5 +23

= 50.5 miles

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The infinite series 8 + 8/2 + 8/4 + 8/8 + 8/16 + .... using sigma notation is [tex]\sum\limits_{n=0}^{\infty}[/tex]  8/2ⁿ = 16.

The given infinite series can be written using sigma notation as follows:

[tex]\sum\limits_{n=0}^{\infty}[/tex] 8/2ⁿ

Here, the lower limit of summation is 0 since the first term of the series corresponds to n=0. The variable n represents the index of summation and takes integer values starting from 0 and increasing by 1 until infinity. The expression 8/2ⁿ represents each term of the series.

The term 8/2ⁿ can be simplified as [tex]2^{3-n}[/tex], which indicates that each term is obtained by dividing 8 by a power of 2, with the power decreasing by 1 in each successive term.

Therefore, the given series can be expressed as an infinite geometric series with first term a=8 and common ratio r=1/2. The formula for the sum of an infinite geometric series can be used to find the sum of the given series as:

sum = a/(1-r) = 8/(1-1/2) = 16

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Answer:

[tex]\huge\boxed{\sf XZ = 13.17\ cm}[/tex]

Step-by-step explanation:

Since the triangle is a right-angled triangle, we can use Pythagoras Theorem to solve for XZ.

In the triangle,

XZ = Hypotenuse

Base = XY = 12.7 cm

Perpendicular = YZ = 3.5 cm

[tex](Hypotenuse)^2=(Base)^2+(Perp)^2[/tex]

Put the given data

(XZ)² = (12.7)² + (3.5)²

XZ² = 161.29 + 12.25

XZ² = 173.54

√XZ² = √173.54

[tex]\rule[225]{225}{2}[/tex]

Answer: 14 ounces of flour

Step-by-step explanation:

We can set up a proportion to solve this problem using ratios.

The ratio of muffins to flour is 25:35, or simplified, 5:7. So for every 5 muffins, we need 7 ounces of flour.

Now we can multiply the ratio by 2, to get 10 muffins and the respective ounces of flour required.

                 5 : 7

             x2      x2

                10 : 14

So, we get the ratio 10:14.

So, for every 10 muffins, we need 14 ounces of flour.

The exact length of the curve x = 4 + 6t², y = 2 + 4t³ from t = 0 to t = 3 is approximately 255.67 units.

To find the exact length of the curve, follow these steps:
1. Find the derivatives of x and y with respect to t: dx/dt = 12t and dy/dt = 12t².
2. Calculate the square of each derivative: (dx/dt)² = 144t² and (dy/dt)² = 144t⁴.
3. Add the squared derivatives: 144t² + 144t⁴.
4. Take the square root of the sum: √(144t² + 144t⁴).
5. Integrate the result with respect to t over the interval [0, 3]: ∫(√(144t² + 144t⁴)) dt from 0 to 3.
6. Calculate the definite integral to obtain the exact length: ≈ 255.67 units.

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If from 1950 to 1990 the population of Country W increased by 40 percent, From 1990 to 2012 the population of Country W increased by 10 percent, population of Country W increased by 54% from 1950 to 2012.

To find the percent increase in the population of Country W from 1950 to 2012, we can use the following formula:

percent increase = [(new value - old value) / old value] x 100

Let P1 be the population in 1950, P2 be the population in 1990, and P3 be the population in 2012.

From the problem, we know that:

P2 = 1.4P1 (since the population increased by 40% from 1950 to 1990)

P3 = 1.1P2 (since the population increased by 10% from 1990 to 2012)

Substituting the first equation into the second equation, we get:

P3 = 1.1(1.4P1) = 1.54P1

Therefore, the percent increase in the population from 1950 to 2012 is:

[(P3 - P1) / P1] x 100

= [(1.54P1 - P1) / P1] x 100

= 54%

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The nurse need select a sample of at least 7 infants to be 90% confident that the true mean birth weight is within 4 ounces of the sample mean.

To estimate the sample size needed for the nurse at the local hospital to be 90% confident that the true mean birth weight of infants is within 4 ounces of the sample mean, we need to use the following formula for sample size:
n = [tex]([/tex]Z * σ [tex]/[/tex]Z[tex])^2[/tex]
where n is the sample size, Z is the z-score corresponding to the desired confidence level, σ is the known standard deviation of the population, and E is the margin of error (the difference between the true mean and the sample mean).

In this case, we are given:
- 90% confidence level, which corresponds to a z-score of 1.645
- Standard deviation (σ) = 6 ounces
- Margin of error (E) = 4 ounces

Now, we can plug these values into the formula:
[tex]n = (1.645 * 6 / 4)^2[/tex]
[tex]n = (9.87 / 4)^2[/tex]
[tex]n = (2.4675)^2[/tex]
n ≈ 6.08

Since we cannot have a fraction of a sample, we round up to the nearest whole number. Therefore, the nurse must select a sample of at least 7 infants to be 90% confident that the true mean is within 4 ounces of the sample mean.

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a) The probability that a transmitter will need repairing three times in four months is approximately 0.0613.

b) The probability that a transmitter will need repairing three times in one year is approximately 0.224.

c) The probability that a transmitter will need repairing at least three times in one year is approximately 0.5716.

d) Therefore, the expected number of reparations in one year is 9.

e) Expected yearly cost = 9 * 250 KD = 2250 KD

a) To calculate the probability that a transmitter will need repairing three times in four months, we can use the Poisson distribution formula:

[tex]P(X = k) = (\lambda^k * e^{-\lambda}) / k![/tex]

where λ is the average number of repairs per four months, and k is the number of repairs we're interested in.

In this case, λ = 1 (since the transmitter requires repair on average once every four months), and k = 3.

Plugging these values into the formula, we get:

[tex]P(X = 3) = (1^3 * e^{-1}) / 3![/tex]

≈ 0.0613

Therefore, the probability that a transmitter will need repairing three times in four months is approximately 0.0613.

b) To calculate the probability that a transmitter will need repairing three times in one year, we need to first convert the average number of repairs per four months to the average number of repairs per year.

Since there are three four-month periods in a year, the average number of repairs per year is:

λ = 3 * 1 = 3

We can then use the Poisson distribution formula with λ = 3 and k = 3:

[tex]P(X = 3) = (3^3 * e^{-3}) / 3![/tex]

≈ 0.224

Therefore, the probability that a transmitter will need repairing three times in one year is approximately 0.224.

c) To calculate the probability that a transmitter will need repairing at least three times in one year, we can use the complementary probability:

P(X ≥ 3) = 1 - P(X < 3)

where P(X < 3) is the probability that the transmitter will need repairing less than three times in one year. Using the Poisson distribution with λ = 3 and k = 0, 1, or 2, we get:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

[tex]= (3^0 * e^{-3}) / 0! + (3^1 * e^{-3}) / 1! + (3^2 * e^{-3}) / 2![/tex]

≈ 0.0504 + 0.1512 + 0.2268

≈ 0.4284

So, P(X ≥ 3) = 1 - 0.4284 ≈ 0.5716

Therefore, the probability that a transmitter will need repairing at least three times in one year is approximately 0.5716.

d) The expected number of reparations in one year can be found by multiplying the average number of reparations per four months by the number of four-month periods in a year:

λ = 3 * 3 = 9

Therefore, the expected number of reparations in one year is 9.

e) The expected yearly cost to the company for transmitter repairing can be found by multiplying the expected number of reparations in one year by the cost of each reparation:

Expected yearly cost = 9 * 250 KD = 2250 KD.

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The ratio of the number of forks to the number of spoons can be expressed in two ways and is a useful tool for understanding how the two items relate to one another.

Ratio is a way to compare two or more numbers, quantities, or amounts. It is expressed as a fraction, with the first number in the fraction being the quantity being compared to the second number. Ratios can be used to compare different sizes and values, or to express a relationship between two or more items. Ratios are often used in business and finance to measure performance and compare financial health.

To calculate this ratio, the total number of forks and spoons can be counted. For example, if there are 12 forks and 9 spoons, then the ratio is 12:9 or 1.33:1.

The ratio of the number of forks to the number of spoons is a useful tool for understanding how the two items relate to one another. It can be used to compare different sets of forks and spoons, or to determine how many of each item should be used in a given situation. For example, if a recipe calls for 1.5 forks per person, then the ratio can be used to determine how many spoons should be used.

In conclusion, the ratio of the number of forks to the number of spoons can be expressed in two ways and is a useful tool for understanding how the two items relate to one another. This can help when determining how many of each item to use in different scenarios.

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Complete questions as follows-

Write a ratio in two ways to describe the relationship of the number of forks to the number of spoons.

The ratio that describes the relationship of the number of forms to the number of spoons is …….. to …….. or ………. ………

Answer:

A. $6.16

Step-by-step explanation:

To calculate the amount of tax on Jacob's purchase, we first need to find the total cost of the coat and hat, and then apply the sales tax rate of 8% to that amount.

The cost of the coat is $62.75, and the cost of the hat is $14.25, so the total cost before tax is:

[tex]\implies \sf \$62.75 + \$14.25 = \$77.00[/tex]

To calculate the amount of tax, we need to multiply the total cost by the tax rate of 8%:

[tex]\begin{aligned}\implies \sf \$77.00 \times\: 8\%&=\sf \$77.00 \times \dfrac{8}{100}\\&=\sf \$77.0 \times 0.08\\&=\sf \$6.16\end{aligned}[/tex]

Therefore, the amount of tax on Jacob's purchase is $6.16.

a. The pmf of X is:
P[X=0] = 5/42
P[X=1] = 5/14
P[X=2] = 5/42
P[X=3] = 1/126

b. The probability that he cannot find any of the defective transistors is  5/42

(a) To find the pmf of X, we can use the hypergeometric distribution since we are sampling without replacement from a finite population.

Let N be the total number of transistors (N=9), K be the number of defective transistors (K=3), and n be the number of transistors inspected (n=4).

Then:
P[X=k] = (choose K,k) * (choose N-K,n-k) / (choose N,n)
where "choose a,b" denotes the number of ways to choose b items from a set of a items.
For k=0, we have:
P[X=0] = (choose 3,0) * (choose 6,4) / (choose 9,4) = 15/126 = 5/42
For k=1, we have:
P[X=1] = (choose 3,1) * (choose 6,3) / (choose 9,4) = 45/126 = 5/14
For k=2, we have:
P[X=2] = (choose 3,2) * (choose 6,2) / (choose 9,4) = 15/126 = 5/42
For k=3, we have:
P[X=3] = (choose 3,3) * (choose 6,1) / (choose 9,4) = 1/126
Therefore, the pmf of X is:
P[X=0] = 5/42
P[X=1] = 5/14
P[X=2] = 5/42
P[X=3] = 1/126
(b) To find the probability that none of the defective transistors are found, we need to consider the case where all four transistors inspected are non-defective.

This can happen in (choose 6,4) = 15 ways (since there are 6 non-defective transistors to choose from). The total number of ways to choose 4 transistors from 9 is (choose 9,4) = 126.

Therefore, the probability is:
P[X=0] = 15/126 = 5/42.

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Answer:

False.

As 12/20 as a fraction simplified is equal to 3/5.

Answer:

1. G

2. F

3. B

4. F

Step-by-step explanation:

1. There is no restriction on x-values (sqrt or n/0 form). so it can take all real values.

2. Let y=f(x)

On expressing x in terms of y, we obtain:

[tex]x=\sqrt{2(y+4)}+2[/tex]

Now, the expression in the root ( 2(y+4) ) must be greater than or equal to 0

Algebraically, 2(y+4) ≥ 0

=> y ≥ -4

3. The x-values (domain/inputs/pre-images) extend from (-4) to +ve infinity or x ≥ -4

4. The y-values (range/outputs/images) extend from (-4) to +ve infinity or y ≥ -4

The differentiation with respect to x is dW/dx = (6z-10y)(-5)/(5x+y)².

Given that, W=(6z-10y)/(5x+y)

The total differential of W=(6z-10y)/(5x+y) is

dW = (6dz - 10dy)/(5x+y) - (6z-10y)(5dx + dy)/(5x+y)²

Let's break this down. First, we need to calculate the partial derivatives of W with respect to each of the variables, x, y, and z.

Partial derivative of W with respect to x:

dW/dx = (6z-10y)(-5)/(5x+y)²

Partial derivative of W with respect to y:

dW/dy = (6z-10y)(-1)/(5x+y)² - (6z-10y)(5dx + dy)/(5x+y)²

Partial derivative of W with respect to z:

dW/dz = (6)/(5x+y) - (6z-10y)(5dx + dy)/(5x+y)²

Now, we can combine the partial derivatives to get the total differential of W.

dW = (6dz - 10dy)/(5x+y) - (6z-10y)(5dx + dy)/(5x+y)²

Hence, the differentiation with respect to x is dW/dx = (6z-10y)(-5)/(5x+y)².

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The ANOVA test results indicate that there is evidence of a difference between the mean charges of USA and foreign medical school graduates at a 0.025 level of significance.

The ANOVA test is used to determine if there is a statistically significant difference between the mean charges of USA and foreign medical school graduates. The ANOVA test is conducted using a 0.025 level of significance. The results of the test indicate that there is a statistically significant difference in the mean charges between USA and foreign medical school graduates at a 0.025. This means that there is evidence that the mean charges of USA and foreign medical school graduates are significantly different.

Given this information, we can conclude that the main effect of medical school is significant at a 0.025 level of significance. This means that there is a statistically significant difference between the mean charges of USA and foreign medical school graduates.

However, it is important to note that the test for the interaction between medical school and primary specialty is not significant at a 0.025, which indicates that the effect of medical school is independent of the primary specialty.

In summary, the ANOVA test results indicate that there is evidence of a difference between the mean charges of USA and foreign medical school graduates at a 0.025 level of significance.

The test for the interaction between medical school and primary specialty is not significant at a 0.025, which indicates that the effect of medical school is independent of the primary specialty.

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Here's a recursive formula that has n as an input and the output is (n!)^2, using the terms "recursive f" and "input":

Define the recursive function f(n) as follows: 1. Base case: f(0) = f(1) = 1 2. Recursive case:

[tex]f(n) = n^2 * f(n-1) for n > 1[/tex]

The input for this recursive function is n, and the output is (n!)^2.

The recursive formula that has n as an input and the output is

[tex](n!)^2[/tex]

can be defined as follows:

recursive_f(n) =

- if n = 0 or n = 1, return 1

- otherwise, return n^2 * recursive_f(n-1)

Here, recursive_f is the name of the recursive function, and n is the input. The base case of the recursion is when n is 0 or 1, which returns 1. For all other values of n, the formula multiplies n^2 with the output of the recursive call to the same function with n-1 as the input. This continues until the base case is reached and the recursion stops.

So, for example, if you input n=5 into this formula, it would calculate (5!)^2 = 14400 using the recursive function:

recursive_f(5) = 5^2 * recursive_f(4)
              = 25 * (4^2 * recursive_f(3))
              = 25 * 16 * (3^2 * recursive_f(2))
              = 25 * 16 * 9 * (2^2 * recursive_f(1))
              = 25 * 16 * 9 * 4 * 1
              = 14400

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The slope and y-intercept of the line is equal to 1.33 and 2 respectively..

The equation is equal to,

Y = 1.33X + 2,

Age of the dog represented by x-axis

Weight in pounds represented by y-axis.

Standard form of the equation with slope 'm' and y-intercept 'c' is written as,

y = mx + c

Compare both the equations we get,

The number next to X is 1.33 is the slope of the line.

That represents how much the Y variable that is weight changes for each unit increase in the X variable age.

Here, the slope of 1.33 indicates that for each additional year in age,

The weight of the dog increases by an average of 1.33 pounds.

The number that is added to the slope = 2.

It is the y-intercept of the line, the value of Y when X is equal to 0.

It means that when the dog is born age = 0.

Its weight is estimated to be 2 pounds.

Therefore, the slope of the line is 1.33 and the y-intercept is 2.

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Answer:

To select a sample of 5 trees that is likely to be representative of the population of 50 trees, the farmer could use simple random sampling. This means that each tree in the population has an equal chance of being selected for the sample.

One way to do this is to assign a number to each tree and then use a random number generator to select 5 numbers between 1 and 50. The trees corresponding to those numbers would be selected for the sample.

Another way is to use a table of random numbers or a computer program that generates random numbers.

Step-by-step explanation:

The maximum height of the ball is 85.25 feet.

The expression for the height of the ball is [tex]-16t^2+80t+21[/tex], where t is the time after launch. To find the maximum height of the ball, we need to find the vertex of the parabolic path.

The vertex of a parabolic path is given by the equation:

t = -b/2a

where a, b, and c are the coefficients of the quadratic equation ax^2+bx+c that describes the path. In this case, we have:

a = -16

b = 80

c = 21

So, we can find the time t when the ball reaches its maximum height by:

t = -b/2a = -80/(2[tex]\times[/tex](-16)) = 2.5

Therefore, the maximum height of the ball is reached at t = 2.5 seconds. To find the height of the ball at this time, we substitute t = 2.5 into the equation for the height:

[tex]-16(2.5)^2[/tex]+ 80(2.5) + 21 = 85.25

Therefore, the maximum height of the ball is 85.25 feet.

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Answer:

Second angle= 28.5°

Third angle= 85.5°

Step-by-step explanation:

Let x=second angle

Let x+57°=Third angle

Therefore 66°+x+(x+57°)=180°

66°+2x+57°=180°

123°+2x=180°

2x=180°-123°

2x=57°

2x/2=47°/2

x=28.5°

If ∠AOC and ∠COD are complementary angles, then the value of x is 7.5

From the question, we have the following parameters that can be used in our computation:

m∠AOC = 68° and m∠COD = (2x + 7)°.

If ∠AOC and ∠COD are complementary angles, then the value of x is calculated as

AOC + COD = 90

Substitute the known values in the above equation, so, we have the following representation

2x + 7 + 68 = 90

So, we have

2x = 15

Divide by 2

x = 7.5

Hence, the value of x is 7.5

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