In circle with m EFG = 58 and EF = 6 units, find the length of arc EG. Round to the nearest hundredth.

The dimensions of the box are x =  8.93 cm and h = 5.95 cm

The volume of the box is:

V = x²*h          

where, x is the side of the square base and h the height

Then    

h  =  V/ x²

h = 475 / x²

The total cost of box C is 30

C  = C₁  +  4C₂      

Where C₁  and C₂  are the costs of the base and one lateral side respectevily

Then cost C =  8x² + 24hx

The cost C as a function of x is

C(x)  =  8x²  + (24* 475 /x² )*x

C(x)  =  8x²  +  11400/x

Tacking derivatives on both sides of the equation;

C´(x)  =  16*x -  11400/x²

C´(x)  =  30    

 16*x  -  11400/x²  = 0

x³ =  712,5

x  =  8,93  cm

h   =  475 / (8,93)²  

h  =  5,95  cm

C(min)  =  8*79,77  +  4* ( 8,93)*5,95

C(min)  =  638,16  +  212,53

C(min)  =  850,69 cents

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The sum of this convergent geometric series is 225/14.The given series is a geometric series with first term a = 15 and common ratio r = 1/7. To determine whether the series is convergent or divergent, we use the formula for the sum of a geometric series:

S = a/(1-r)

Substituting a = 15 and r = 1/7, we get:

S = 15/(1-1/7) = 15/(6/7) = 17.5

Since the sum S is a finite number, the geometric series is convergent. Therefore, the sum of the given series is 17.5.
Hello! Let's first identify the given geometric series and the relevant terms. From your input, it appears that the series is:

15 + 1 + 49/343

To determine if a geometric series is convergent or divergent, we need to identify the common ratio (r). We can find this by dividing the second term by the first term, and then checking if the ratio is consistent throughout the series.

(1/15) = (49/343) / 1

The common ratio (r) is 1/15.

Now, let's see if this series is convergent or divergent. A geometric series is convergent if the absolute value of the common ratio (|r|) is less than 1, and divergent otherwise.

In our case, |r| = |1/15| = 1/15, which is less than 1. Therefore, this geometric series is convergent.

To find the sum of this convergent geometric series, we can use the formula:

Sum = a / (1 - r)

where a is the first term and r is the common ratio.

Sum = 15 / (1 - 1/15)

Now, let's calculate the sum:

Sum = 15 / (14/15)

Sum = (15 * 15) / 14

Sum = 225 / 14

So, the sum of this convergent geometric series is 225/14.

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The height of the box is 2 inches.

Given: A package of gift cards has a length of 8 inches, a width of 4 inches, and a volume of 64 inches cubed.

To Find: The height of the box.

Solution: We can use the volume of a rectangular prism formula to compute the height of the box.

V = l x w x h.

Where V denotes volume,

l denotes length,

w denotes width,

and h denotes height.

It is given that the volume is 64 inches cubed and the length and breadth of the box are 8 and 4 inches, respectively.

Now, the formula becomes h = Volume / (length x width)height

Here, we get,

64 / (8 x 4)h

Now, after solving the above equation with the given formula we get the height of the box = 2 inches.  As a result, the box's height is 2 inches.

Thus, the height of the box is 2 inches.

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The value of the probability of picking a 5 and then picking a 4 is 1/3

From the question, we have the following parameters that can be used in our computation:

Rolling a fair, six-sided number cube

The sample space of a number cube is

S = {1, 2, 3, 4, 5, 6}

Where the outcome is 4, we have

P(4) = 1/6

Where the outcome is 5, we have

P(5) = 1/6

Using the above as a guide, we have the following:

P(4 or 5) = P(4) + P(5)

So, we have

P(4 or 5) = 1/6 + 1/6

Evaluate

P(4 or 5) = 1/3

Hence, the value of P(4 or 5) is 1/3

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The probability of getting a five or higher on the first roll and getting a total of 7 on the two dice is 1/18.

Step 1: Calculate the probability of getting a five or higher on the first roll.
There are two favorable outcomes (rolling a 5 or a 6), and there are six possible outcomes (rolling 1, 2, 3, 4, 5, or 6) on the first dice. So, the probability of getting a five or higher is:

P(5 or higher) = Favorable Outcomes / Total Outcomes = 2/6 = 1/3

Step 2: Calculate the probability of getting a total of 7 on the two dice.
There are six possible outcomes on each dice, making 6 x 6 = 36 possible outcomes in total. There are six favorable outcomes that result in a total of 7: (1,6), (2,5), (3,4), (4,3), (5,2), and (6,1). So, the probability of getting a total of 7 is:

P(total of 7) = Favorable Outcomes / Total Outcomes = 6/36 = 1/6

Step 3: Calculate the probability of both events occurring.
Since the two events are independent, you can multiply their probabilities to find the probability of both events occurring:

P(5 or higher on first roll and total of 7) = P(5 or higher) × P(total of 7) = (1/3) × (1/6) = 1/18

So, the probability of getting a five or higher on the first roll and getting a total of 7 on the two dice is 1/18.

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The sticker price for the cake pans should be $5.00 to achieve a 60% gross margin.

To achieve a 60% gross margin, the store wants to mark up the cost of the cake pans by 60% of the cost. So, if the store purchases the cake pans for $3 each, it wants to mark up the price by:

60% of $3 = 0.6 x $3 = $1.80

The sticker price for the cake pans would be the cost of the pans plus the markup:

Sticker price = Cost + Markup

Sticker price = $3 + $1.80

Sticker price = $4.80

Therefore, the sticker price for the cake pans should be $5.00 to achieve a 60% gross margin.

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The length of leg CB is approximately 150.3

Basics of Trigonometry deals with measuring angles and problems related to angles. There are six basic trigonometric ratios: sine, cosine, tangent, cosecant, secant, and cotangent. All important trigonometric concepts are based on these trigonometric relationships or functions.

To find the length of leg CB, we can use the tangent function that connects the opposite side angle of  a right triangle to the side adjacent to the same angle. In particular, we have:

tan(A) = opposite/adjacent

If A is the measure of an angle, then the opposite is the side opposite  the angle and the adjacent is the side next to the angle.

In our case, ∠A = 27°, AB = 300 and we want to find CB.

So we can define the equation:

tan(27°) = CB/300

To solve for CB, we can multiply both sides by 300:

CB = 300 * tan (27°)

while calculating the value of tan (27°) = 0.50952544949

after multiply by this value to 300 we get,

CB = 150.3

Therefore, the length of leg CB is approximately 150.3 (rounded to the nearest tenth).

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1)Taking the first derivative of the function and setting it to zero, we get:

f'(x) = 3x^2 - 12x = 3x(x-4) = 0

This has two roots: x = 0 and x = 4.

Taking the second derivative of the function, we get:

f''(x) = 6x - 12

At x = 0, f''(0) = -12, which is negative. So, we have a relative maximum at x = 0.

At x = 4, f''(4) = 12, which is positive. So, we have a relative minimum at x = 4.

Therefore, the relative maximum is (0,3) and the relative minimum is (4,-29).

2)To find the relative extrema of the function, we need to find its critical points by setting its derivative equal to zero and solving for x:

f(x) = x^3 - 6x^2 + 3

f'(x) = 3x^2 - 12x

0 = 3x(x - 4)

So the critical points are x = 0 and x = 4. To determine whether they correspond to a relative maximum or minimum, we need to use the second-derivative test. We calculate the second derivative of f(x):

f''(x) = 6x - 12

At x = 0, we have f''(0) = -12, which is less than zero, so the function has a relative maximum at x = 0. At x = 4, we have f''(4) = 12, which is greater than zero, so the function has a relative minimum at x = 4.

Therefore, the relative maximum is at (0, 3) and the relative minimum is at (4, -29).

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a) The average velocity of the silver dollar on the interval( 1, 4) is 683 ft/s.b) The immediate velocity when t = 1 is-32 ft/ s and the immediate velocity when t = 4 is-128ft/s.c) It'll take the silver dollar about 5.39 seconds to hit the ground.d) The haste of the tableware bone when it hits the ground is roughly-172.48 ft/s.

a) To find the average velocity of the tableware bone on the interval( 1, 4), we need to calculate the difference quotient:

average haste = ( s( 4)- s( 1))( 4- 1)

= (-( 16)*4*4 + 525 - ( 16)( 1)+ 525)/ 3

= ( 2560- 509)/ 3

= 683 ft/ s

thus, the average velocity of the tableware bone on the interval( 1, 4) is 683 ft/s.

b) To find the immediate rapidity when t = 1 and t = 4, we need to take the derivative of the function s( t)

s'( t) = -32 t

also, we can find the immediate rapidity

s'( 1) = -32( 1) = -32 ft/ s

s'( 4) = -32( 4) = -128 ft/ s

thus, the immediate haste when t = 1 is-32 ft/ s and the immediate haste when t = 4 is-128 ft/s.

c) To find the time it takes the dollar to hit the ground, we need to set s( t) = 0 and break for t

= -16[tex]t^{2}[/tex] +525

16[tex]t^{2}[/tex]= 525

[tex]t^{2}[/tex]= 525/16

t ≈5.39 seconds( rounded to two decimal places)

thus, it'll take the tableware bone about 5.39 seconds to hit the ground.

d) To find the haste of the bone when it hits the ground, we can use the immediate haste at time t = 5.39 seconds. Using the outgrowth we set up before

s'(5.39) = -32(5.39) ≈-172.48 ft/ s

thus, the velocity of the dollar when it hits the ground is roughly-172.48 ft/s.

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The total number of boxes that fit into this crate is 23040

From the question, we have the following parameters that can be used in our computation:

Width = 24 boxes

Height = 16 boxes

Length = 60 boxes

using the above as a guide, we have the following:

Boxes = Width * Height * Length

Substitute the known values in the above equation, so, we have the following representation

Boxes = 24 * 16 * 60

Evaluate

Boxes = 23040

Hence, the number of boxes is 23040

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The expression of sine function of sinâ1(â3/2) is undefined. The value of cosâ1(1/2) = π/3 radians.

The expression sinâ1(â3/2), since the sine function is only defined for angles between -π/2 and π/2, we cannot find an angle with a sine of -â3/2. Therefore, the expression is undefined.

The expression cosâ1(1/2), Since the cosine function is positive for angles between 0 and π, we know that the angle we are looking for is in the first or fourth quadrant.

To find the angle, we can use the inverse cosine function, which gives us the angle whose cosine is equal to the given value. Therefore, we have

cosθ = 1/2

Taking the inverse cosine of both sides, we get

θ = cos⁻¹(1/2)

Using the unit circle or trigonometric identities, we can find that cos⁻¹(1/2) = π/3 or 2π/3. Since the cosine function is positive in the first quadrant and negative in the fourth quadrant, we choose the solution in the first quadrant, which is θ = π/3.

Therefore, cosâ1(1/2) = π/3 radians.

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The test statistic, based on the given information, is 4.67.

To calculate the test statistic for the given situation, we will use the sample proportion (p'), population proportion (p), sample size (n), and the standard error of the proportion (SE).

1. Determine the sample proportion (p'):

p' = number of passengers with carry-on luggage / total number of passengers

p' = 148 / 300 = 0.4933

2. Identify the population proportion (p):

p = 36% = 0.36

3. Calculate the sample size (n):

n = 300

4. Determine the standard error of the proportion (SE):

SE = sqrt[(p * (1 - p)) / n]

SE = sqrt[(0.36 * (1 - 0.36)) / 300] = 0.0286

5. Calculate the test statistic (z):

z = (p' - p) / SE

z = (0.4933 - 0.36) / 0.0286 = 4.67

So, the test statistic is 4.67 when rounded to two decimal places.

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To find the derivative of 8(x) = x7, we need to use the power rule. The power rule states that the derivative of x^n is n*x^(n-1). Applying this rule, we get:
g'(x) = 7x^6
Therefore, the derivative of the function 8(x) = x7 is g'(x) = 7x^6.
To find f'(1), we need to take the derivative of the function f(x) = x^2 + 19 and evaluate it at x=1. Using the power rule again, we get:
f'(x) = 2x
Evaluating at x=1, we get:
f'(1) = 2(1) = 2
Therefore, f'(1) = 2.

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True, if S generates the vector space V, then every vector in V can be written as a linear combination of vectors in S in only one way.

In a vector space V, a set of vectors S is said to generate V if every vector in V can be expressed as a linear combination of vectors in S. This means that for any vector v in V, there exist unique coefficients (scalars) such that v can be written as a linear combination of vectors in S.

To prove this, we can consider two cases:

Every vector in V can be written as a linear combination of vectors in S:

In this case, for any vector v in V, we can write v as a linear combination of vectors in S using unique coefficients. This means that there is only one way to express v as a linear combination of vectors in S, and the coefficients are unique for each vector in V.

There exists a vector in V that can be written as a linear combination of vectors in S in more than one way:

This case contradicts the assumption that S generates V, because if there exists a vector in V that can be expressed as a linear combination of vectors in S in more than one way, then the coefficients are not unique. This implies that S does not generate V, which contradicts the premise of the question.

Therefore, if S generates the vector space V, then every vector in V can be written as a linear combination of vectors in S in only one way.

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To be "95% confident" in an inference means that there is a 95% probability that the true value of the population parameter (in this case, the mean denoted by μ) falls within the calculated confidence interval, which is (1000, 1900).

A confidence interval is a range of values that is calculated from a sample of data and is used to estimate an unknown population parameter, such as the mean. The confidence level, expressed as a percentage (in this case, 95%), indicates the level of confidence we have in the interval capturing the true population parameter.

In this context, the confidence interval (1000, 1900) means that we are 95% confident that the true population mean (μ) falls within this range. This does not mean that there is a 95% probability that the true population mean falls within the specific interval (1000, 1900), as the true population mean is a fixed value and not subject to probability. Instead, it means that if we were to repeat the sampling process and construct 100 different confidence intervals, about 95 of those intervals would contain the true population mean.

Therefore, being "95% confident" in an inference means that there is a high degree of confidence that the true population parameter falls within the calculated confidence interval, based on the sample data and the chosen level of confidence.

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To find the difference between the numbers of saplings with a height of 27 1/4 inches or less and those with a height greater than 27 1/4 inches, we need to calculate the values of n1 and n2.

Height is the measure of an object's distance from the ground or base to its highest point. It is measured in units of length, such as inches, feet, or centimeters. Height is an important factor that influences an individual's physical appearance, health, and lifestyle. It can also be used to compare the size of different objects or people. Height is a key factor in many sports and activities, as taller people tend to have an advantage.

To answer this question, we need to calculate the difference in the numbers of saplings with a height of 27 1/4 inches or less and those with a height greater than 27 1/4 inches. Let us call the number of saplings with a height of 27 1/4 inches or less as n1 and the number of saplings with a height greater than 27 1/4 inches as n2.

We can calculate the difference between n1 and n2 by subtracting n2 from n1. This difference, which is the number of saplings with a height of 27 1/4 inches or less that were more than saplings with a height greater than 27 1/4 inches, can be expressed as:

Difference = n1 - n2

Therefore, to find the difference between the numbers of saplings with a height of 27 1/4 inches or less and those with a height greater than 27 1/4 inches, we need to calculate the values of n1 and n2.

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Complete questions as follows-
how many more saplings with a height of 27 1/4 inches or less were than saplings with a height greater than 27 1/4 inches?

The equivalent expression of the expression are as follows:

2(m + 3) + m - 2 = 3m + 4

5(m + 1) - 1 = 5m + 4

m + m + m + 1 + 3 = 3m + 4

Two expressions are said to be equivalent if they have the same value irrespective of the value of the variable(s) in them.

Two algebraic expressions are equivalent if they have the same value when any number is substituted for the variable.

Therefore, let's simplify the expression to find the equivalent expression.

2(m + 3) + m - 2

2m + 6 + m - 2

2m + m + 6 - 2

3m + 4

5(m + 1) - 1

5m + 5 - 1

5m + 4

m + m + m + 1 + 3

3m + 4

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Answer:

(x, y) ≈ (-2.17, ±sqrt(95)) or (x, y) ≈ (-1.03, ±sqrt(21))

Step-by-step explanation:

To solve this system of equations, we can use the method of substitution. We can start by isolating one of the variables in one of the equations and substituting it into the other equation. Let's solve for x in the first equation:

5y² + 24x - 77 = 0

24x = 77 - 5y²

x = (77 - 5y²)/24

Now we can substitute this expression for x into the second equation:

14x² + 5y² + 150x + 119 = 0

14((77-5y²)/24)² + 5y² + 150((77-5y²)/24) + 119 = 0

Simplifying this expression gives:

49y^4 - 5390y² - 108090y - 404271 = 0

We can solve for y using the quadratic formula:

y² = (5390 ± sqrt(5390² - 4(49)(-404271)))/(2(49))

y² = (5390 ± sqrt(16946804))/98

y² = (5390 ± 4118)/98

y² = 95 or y² = 21

Substituting each value of y into the expression we found for x earlier gives:

x = (77 - 5(±sqrt(95))²)/24 ≈ -2.17 or x = (77 - 5(±sqrt(21))²)/24 ≈ -1.03

Therefore, the solution to the system of equations is:

(x, y) ≈ (-2.17, ±sqrt(95)) or (x, y) ≈ (-1.03, ±sqrt(21))

The recursive sequence that produces the sequence 4, -6, 4 is:

a(1) = 4

a(n+1) = -a(n) + 8, for n ≥ 1

In mathematics, a recursive sequence or function is one where each term or value is defined in terms of the previous one or ones. The term "recursive" comes from the word "recursion," which means to repeat or iterate.

A recursive sequence is often defined by a recursive formula or rule, which gives a formula for each term in terms of the previous ones. For example, the Fibonacci sequence is a b sequence where each term is the sum of the two previous terms.

To generate the sequence 4, -6, 4 using a recursive formula, we need to determine the pattern or rule that relates each term to the previous ones. We can see that the first and third terms are the same, and the second term is negative.

One possible recursive formula that generates this sequence is:

a(1) = 4

a(n+1) = -a(n) + 8, for n ≥ 1

Using this formula, we can find each term of the sequence by applying the rule to the previous term:

a(2) = -a(1) + 8 = -4 + 8 = 4

a(3) = -a(2) + 8 = -4 + 8 = 4

Therefore, the recursive sequence that produces the sequence 4, -6, 4 is:

a(1) = 4

a(n+1) = -a(n) + 8, for n ≥ 1

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The formula for the sum in Exercise 40 is: Σ(k² + k + 1) for k=1 to n. To calculate the sum for n=100, n=500, and n=1000, follow these steps:

1. Identify the given formula: Σ(k² + k + 1) for k=1 to n.
2. Calculate the sum for each n value separately:
  a. For n=100, calculate the sum of (k² + k + 1) for k=1 to 100.
  b. For n=500, calculate the sum of (k² + k + 1) for k=1 to 500.
  c. For n=1000, calculate the sum of (k² + k + 1) for k=1 to 1000.

After performing these calculations, you'll get the sums for n=100, n=500, and n=1000.

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1. m∠5 = 75° (corresponding angles theorem)

2. 180°

3. m∠3 = 55° (triangle sum theorem).

4. A straight angle = 180°

5. m∠2 = 50° (angles on a straight line)

What is the triangle sum theorem?

A mathematical statement about a triangle's three inner angles is known as the triangle sum theorem, triangle angle sum theorem, or angle sum theorem. According to the theory, any triangle's three internal angles will always add up to 180 degrees.

Here, we have

1. m∠5 = m∠1 = 75° (corresponding angles are congruent)

2. Measure of the sum of all angles in a triangle = 180°

3. To find ∠3, we would have the following equation:

m∠3 = 180 - m∠4 - m∠5 (triangle sum theorem).

Substitute and solve

m∠3 = 180 - 50 - 75

m∠3 = 55°

4. A straight angle = 180°

5. m∠2 = 180 - m∠3 - m∠1 (angles on a straight line)

Substitute and solve

m∠2 = 180 - 55 - 75

m∠2 = 50°

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All initial value problems for second-order linear homogeneous ODEs with constant coefficients are solvable and have a unique solution. The given statement is true.

The statement is true, and it is a consequence of the fact that second-order linear homogeneous ODEs with constant coefficients have a general solution of the form:

y(t) = c1e^(r1t) + c2e^(r2t)

where r1 and r2 are the roots of the characteristic equation:

ar^2 + br + c = 0

where a, b, and c are constants, and c1 and c2 are arbitrary constants determined by the initial conditions.

Since the characteristic equation has two roots, it is always possible to find the general solution for any initial value problem of the form:

ay'' + by' + cy = 0

y(0) = y0, y'(0) = y1

by plugging the initial conditions into the general solution and solving for c1 and c2.

Moreover, the solution is unique because the general solution is a linear combination of two functions, and the coefficients c1 and c2 are uniquely determined by the initial conditions.

Therefore, all initial value problems for second-order linear homogeneous ODEs with constant coefficients are solvable and have a unique solution.

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If the population is known to be exponential, or the sample size is less than 10, the t distribution should not be used.

The t distribution can be used when the population is not normal, as long as certain assumptions are met. Let's examine each of the conditions you mentioned to see whether they meet these assumptions:

"The population distribution is not badly skewed": The t distribution assumes that the population is approximately normally distributed. If the population is not normal, but is not badly skewed, then the t distribution may still be used. However, the more the population deviates from normality, the less reliable the t distribution becomes.

"The sample size is less than 10": If the sample size is less than 10, the t distribution is generally not recommended. Instead, a small sample size can be better analyzed using non-parametric tests or exact tests, which do not assume any particular population distribution.

"The population distribution is known to be exponential": If the population distribution is known to be exponential, then the t distribution should not be used, as it assumes normality. Instead, an appropriate distribution, such as the exponential distribution, should be used to analyze the data.

"The sample size is not too small": The t distribution can be used when the sample size is not too small. Typically, a sample size of at least 30 is recommended for the t distribution to be reliable. However, if the population is not normal or if the sample is highly skewed, a larger sample size may be required.

In summary, using the t distribution requires certain assumptions to be met. If the population is not normal, but is not badly skewed, and the sample size is not too small, the t distribution can be used. However, if the population is known to be exponential, or the sample size is less than 10, the t distribution should not be used.

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Answer:

Step-by-step explanation:

To convert square meters to square centimeters, we need to multiply by the conversion factor (100 cm / 1 m)^2.

So,

3.9 m² = 3.9 × (100 cm / 1 m)²

3.9 m² = 3.9 × 10,000 cm²

3.9 m² = 39,000 cm²

Therefore, 3.9 square meters is equal to 39,000 square centimeters.

The student is tasked with a Mathematics exercise, in which they need to correctly position given values on a figure. The student needs to use mathematical reasoning to identify and place the correct values.

This seems to be a task in a drag-and-drop interactive exercise related to Mathematics. Your job is to place the given values in their correct positions in the given figure. Not all values will be used, so you should be able to identify which values are needed and which are not. It's important to carefully examine the requirements of the exercise and use your mathematical reasoning skills to determine where each value should be placed.

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Decision about null hypothesis: Based on our analysis or insert statistical test and calculated test statistic, The result is with a p-value,

Sentence: Our hypothesis test, APA style: independent-samples t-test.

i. Decision about null hypothesis: Based on our analysis (insert statistical test and calculated test statistic, e.g., t-value or Z-score), we (choose one: "reject" or "fail to reject") the null hypothesis (state null hypothesis, e.g., "there is no significant difference between the means of Group A and Group B").

ii. Is it significant? The result is (choose one: "statistically significant" or "not statistically significant") with a p-value of (insert p-value, e.g., 0.03).

iii. Sentence: Our hypothesis test shows that (restate the conclusion, e.g., "there is a significant difference between the means of Group A and Group B").

iv. APA style: When citing the results of your hypothesis test in APA style, it would look like this: "A (insert statistical test, e.g., independent-samples t-test) revealed a (choose one: "significant" or "non-significant") difference between Group A and Group B, t(df) = (insert test statistic), p = (insert p-value, e.g., .03)." Replace the placeholders with the specific details of your test.

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The 95% confidence interval for the population mean is between 16.696 hours and 20.504 hours.

To find the 95% confidence interval for the population mean, you'll need to use the following formula:

Confidence Interval = Mean ± (Critical Value × Standard Deviation / √Sample Size)

In this case, the mean is 18.6, the population standard deviation is 6.8, and the sample size is 49 eighth graders. For a 95% confidence interval, the critical value is 1.96 (which is the Z-score for a 95% confidence interval).

Now, plug the values into the formula:

Confidence Interval = 18.6 ± (1.96 × 6.8 / √49)

Calculating the values:

Confidence Interval = 18.6 ± (1.96 × 6.8 / 7)

Confidence Interval = 18.6 ± (1.96 × 0.9714)

Confidence Interval = 18.6 ± 1.904

Now, find the lower and upper limits of the confidence interval:

Lower Limit = 18.6 - 1.904 = 16.696
Upper Limit = 18.6 + 1.904 = 20.504

So, the 95% confidence interval for the population mean is between 16.696 hours and 20.504 hours.

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Answer

x=4

Explanation

-4 = x -8

add 8 to both sides

-4+8 = x

x=4

Answer: 1.845 x 10^10.