When Positive charge is distributed uniformly throughout a large insulating cylinder of radius R=0.900 m. The charge per unit length in the cylindrical volume is λ = 3 ×10⁻⁹ C/m. then the magnitude of the electric field at a distance of 0.200 m from the axis of the cylinder is 33.88 N/C.
Electric field is field around electrically charged particle where columbic force of attraction or repulsion can be experienced by other charged particles. It is denoted by letter E and it's SI unit is V/m Volt per meter or N/C newton per coulomb. Electric field comes inward to the center of the negative charge and it is going outward for positive charge.
The electric field E at a point outside the charged cylinder at a distance r is given by,
E = [tex]\frac{\lambda r}{2\epsilon }[/tex]
where λ is charge density, r is distance, ε₀ = 8.854×10⁻¹² m⁻³ kg⁻¹ s⁴A²= permittivity of free space.
Given,
λ = 3 ×10⁻⁹ C/m
radius R = 0.900 m
r = 0.200 m
ε₀ = 8.854×10⁻¹² m⁻³ kg⁻¹ s⁴A².
[tex]E = \frac{\ 3 *10^{-9} *0.2}{2 * 8.854*10^{-12} }[/tex]
E = 33.88 N/C
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STT 6.3 A car is tolling over the top of a hill at constant speed V. At this instant, A N > WB N
A car is tolling over the top of a hill at constant speed V. At this instant, N=W. So, the correct option is C).
The normal force (N) is the force exerted by the surface on the car perpendicular to the surface. The weight force (W) is the force exerted by gravity on the car in the downward direction.
At the top of the hill, the car is momentarily at rest and therefore the net force on the car is zero. This means that the normal force must be equal in magnitude and opposite in direction to the weight force to balance the forces and prevent the car from accelerating in any direction.
Therefore, the correct answer is C). N=W.
The speed of the car (v) does not affect the normal force at the top of the hill as long as the car is not accelerating in any direction.
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--The given question is incomplete, the complete question is given
" A car is rolling over the top of a hill at speed v. At thisinstant,
A. N>W
B. N<W
C. N=W
D. We can't tell about N without knowing v."--
What colors of light does yellow paint absorb?
Entry field with correct answer
Blue.
Green.
Red.
Neither red, green, nor blue
Answer:Neither red, green, nor blue
Explanation: It is because it is light not paint that absorbs colour.
[Show student response to predict question] Explain why the latent period became longer as the load became heavier in the experiment. How well did the results compare with your prediction?
In the experiment, as the load became heavier, the latent period became longer. This can be explained by the fact that as the load increases, it takes more time for the muscle fibers to generate enough force to move the load.
Some additional information that could be helpful to understand the relationship between load and latent period:
The latent period is the time between the initiation of the muscle stimulation and the onset of the muscle contraction.The load is the amount of weight or force that is placed on the muscle during the experiment.As the load increases, the muscle fibers must generate more force to move the load, and this process takes more time, resulting in a longer latent period.The relationship between load and latent period is not always linear and can vary based on other factors such as muscle type and fatigue.In terms of the comparison between the results and the prediction, it would depend on the specific hypothesis and expectations of the experiment. If the hypothesis predicted a longer latent period with heavier loads, and the results supported this, then the prediction would be considered accurate. If the results did not align with the prediction, further analysis and investigation may be necessary to understand why.As a result, the time between the stimulation of the muscle and the initiation of the contraction (latent period) increases.
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Does the wave function let us make predictions about the outcome of measurements?
Yes, the wave function does allow us to make predictions about the outcome of measurements in quantum mechanics. The wave function describes the state of a quantum system, and it is used to calculate the probability of a particular outcome for a given measurement.
In other words, the wave function contains information about the possible outcomes of a measurement and the likelihood of each outcome.
For example, if we consider the measurement of the position of a particle, the wave function can be used to calculate the probability of finding the particle in a particular location. The wave function provides a probability density function that describes the likelihood of finding the particle in different regions of space. This information can then be used to make predictions about the outcome of the measurement.
Similarly, if we consider the measurement of a particle's energy, the wave function can be used to calculate the probability of finding the particle with a particular energy value. The wave function contains information about the possible energy levels of the particle, and their respective probabilities.
Overall, the wave function is a fundamental tool in quantum mechanics that allows us to make predictions about the outcomes of measurements. By analyzing the wave function, we can determine the probabilities of different measurement outcomes and gain insight into the behavior of quantum systems.
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a playground rides consist of a disk of mass and radius mounted on a low friction axle if the disk was initially at rest now how fast is it rotating
The angular velocity of the rotating disk can be found after finding the values of torque, a moment of inertia, and angular acceleration.
To determine how fast a playground ride consisting of a disk of mass and radius mounted on a low friction axle is rotating, we need to know the following terms:
torque, a moment of inertia, and angular acceleration.
Step 1: Calculate the moment of inertia (I) of the disk using the formula:
I = (1/2) * mass * radius².
Step 2: Determine the torque (τ) applied to the disk.
For this, we need information about the force applied and the distance from the axle. The formula is:
τ = force * distance.
Step 3: Calculate the angular acceleration (α) using the relationship between torque and moment of inertia:
τ = I * α.
Solve for α:
α = τ / I.
Step 4: Find the angular velocity (ω) after a given time (t) using the equation:
ω = α * t, where t is the time elapsed since the disk was initially at rest.
Without specific values for mass, radius, force, distance, and time, I cannot provide a numerical answer.
However, you can follow these steps to find the angular velocity of the rotating disk once you have the necessary information.
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A 415kg satellite orbiting the earth experiences 215N of gravitational force from the Earth. (RE=6.38x106m, ME=5.97x1024kg). What is the potential energy of the satellite relative to the Earth's surface?
The potential energy of the satellite relative to the Earth's surface is [tex]- 1.91 \times 10^{10}[/tex] J.
To calculate the potential energy of the satellite relative to the Earth's surface, we need to use the formula for gravitational potential energy:
PE = - G x M x m / r
Where PE is the potential energy, G is the gravitational constant, M is the mass of the Earth, m is the mass of the satellite, and r is the distance between the center of the Earth and the satellite.
First, we need to calculate the distance r using the information given in the problem. We know that the satellite is experiencing a gravitational force of 215 N from the Earth, so we can use the formula for gravitational force to solve for r:
F = G x M x m / [tex]r^2[/tex]
Rearranging the formula and plugging in the given values, we get:
r = [tex]\sqrt{(G \times M / F)[/tex]
r = [tex]\sqrt{(6.67 \times 10^{-11}\:m^3 / kg \:s^2 \times 5.97 \times 10^{24}\: kg / 215 \:N)[/tex]
r ≈ [tex]7.19 \times 10^6[/tex] m
Now we can plug in the values for G, M, m, and r into the formula for potential energy:
PE = - G x M x m / r
PE ≈ [tex]- (6.67 \times 10^{-11} \:m^3 / kg \:s^2) \times (5.97 \times 10^{24} \:kg) \times (415 \:kg) / (7.19 \times 10^6 \:m)[/tex]
PE ≈ [tex]- 1.91 \times 10^{10}[/tex] J
The negative sign indicates that the potential energy of the satellite is relative to the Earth's surface is negative, which means it is in a bound state and requires energy to escape the gravitational pull of the Earth.
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A 0.200kg ball is shot out of a toy gun from a height of 3.00m. The gun works by compressing a spring k=175N/m a distance of 0.400m. What is the force applied to the ball?
A 0.200kg ball is shot out of a toy gun from a height of 3.00m. The gun works by compressing a spring k=175N/m a distance of 0.400m. then the force applied to the ball is 70 N.
Simple harmonic motion is a specific kind of periodic motion of a body that arises from a dynamic equilibrium between an inertial force that is proportional to the body's acceleration away from the static equilibrium position and a restoring force on the moving object that is directly proportional to the magnitude of the object's displacement and acts towards the object's equilibrium position. Oscillating spring perform SHM.
Force applied on the spring is spring constant times distance.
F = kx
Given,
mass m = 0.2 kg
height h = 3 m
k = 175 N/m
x = 0.4 m
The force applied to the ball is,
F = kx
F = 175×0.4
F = 70 N
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A gas is adiabatically compressed. The work done on the gas is 1200 J. What is the change in the thermal energy due to this process.
Since the gas is adiabatically compressed, there is no heat transfer involved. Therefore, the change in thermal energy is equal to the work done on the gas. Thus, the change in thermal energy due to this process is also 1200 J.
When a gas is adiabatically compressed, the change in its thermal energy can be determined using the first law of thermodynamics. In an adiabatic process, there is no heat transfer (Q = 0), so the first law simplifies to:
ΔU = W
Here, ΔU represents the change in thermal energy, and W is the work done on the gas. Since the work done on the gas is 1200 J, the change in the thermal energy of the gas is also 1200 J.
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Suppose you wanted to get rid of 12C nuclei and in the process release energy. In principle, this could be done by
To get rid of 12C nuclei and release energy is through a process called nuclear fusion.
How would you get rid of 12C nuclei?One way to get rid of 12C nuclei and release energy is through a process called nuclear fusion. Nuclear fusion is the process in which two or more atomic nuclei come together to form a heavier nucleus, releasing a large amount of energy in the process.
In the case of 12C nuclei, one possible fusion reaction is the combination of two 12C nuclei to form a 24Mg nucleus:
12C + 12C → 24Mg + energy
This reaction can release a significant amount of energy, as predicted by Einstein's famous equation[tex]E=mc^2[/tex], which describes the conversion of mass into energy.
However, achieving nuclear fusion requires extremely high temperatures and pressures, as well as precise conditions to initiate and sustain the fusion reaction. This is why fusion is currently not a practical source of energy for most applications, although research is ongoing to develop viable fusion power technologies.
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if a incident light ray approachs a mirror at an angle of 37 degrees from the perpendicular. what will be the angle of the reflected ray?
When a light ray approaches a mirror at an angle of 37 degrees from the perpendicular, the angle of the reflected ray will also be 37 degrees from the perpendicular, as dictated by the law of reflection.
When an incident light ray approaches a mirror, the angle at which it is reflected can be determined using the law of reflection. This law states that the angle of incidence is equal to the angle of reflection. In this case, the incident light ray approaches the mirror at an angle of 37 degrees from the perpendicular.
Since the angle of incidence is measured with respect to the perpendicular (also known as the normal), we need to find the angle of reflection in relation to the normal as well. Since the law of reflection tells us that the angle of incidence is equal to the angle of reflection, the reflected ray will also be at an angle of 37 degrees from the perpendicular.
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a person wants to use a camera to take a picture (obtain a small real image on the film inside the camera). where should they place the object in relation to a converging lens to get the correct image?
To obtain a small real image on the film inside the camera, the object should be placed at a distance greater than the focal length of the converging lens.
Some additional information that could be helpful to understand how to obtain a small real image in a camera:
A converging lens is a lens that causes parallel rays of light to converge at a point after passing through it.The distance between the object and the lens is known as the object distance (u), while the distance between the lens and the image formed is known as the image distance (v).The point where the light rays converge after passing through the lens is known as the focal point, and the distance between the focal point and the lens is known as the focal length (f).When an object is placed at a distance greater than the focal length of the lens, a real image is formed on the other side of the lens.The size and orientation of the image formed depend on the distance between the object and the lens and the focal length of the lens.To obtain a small real image on the film inside the camera, the object should be placed at a distance greater than the focal length of the lens, and the lens should be adjusted to focus the image onto the film.Learn More About converging
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T/F A braking force is always negative and leads to a decrease in velocity>
The given statement "A braking force is always negative and leads to a decrease in velocity" is true.
What is braking force?The force that slows the car when the driver depresses the brake pedal is known as the braking force.
The given statement is True.
A braking force is a force that opposes the direction of motion and acts to slow down or stop an object. It is always negative in the direction of velocity, which means it acts opposite to the direction of motion. This negative force results in a decrease in velocity, as the force slows down the object or brings it to a stop. Therefore, a braking force always leads to a decrease in velocity.
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T/F in the vertical direction, the ground reaction force is the effective force
True , in the context of biomechanics, the ground reaction force is the force exerted by the ground on a body in contact with it. In the vertical direction, the ground reaction force is the effective force that opposes the body's weight and is responsible for maintaining its equilibrium. This force is created as a response to the force exerted by the object on the ground due to gravity.
When an object is in contact with the ground, the ground pushes back with an equal and opposite force, as described by Newton's third law of motion. This ground reaction force ensures that the object remains in equilibrium and does not accelerate in the vertical direction when no other forces are acting on it.\
This force is essential for activities such as walking, jumping, and running, as it allows the body to push off the ground and generate motion. Additionally, the magnitude and direction of the ground reaction force can provide valuable information about the body's movement patterns and the forces acting on it during various activities.
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The length of a simple pendulum with a period on Earth of 2.0 seconds is most nearly:
The length of a simple pendulum with a period on Earth of 2.0 seconds is most nearly 0.99 m.
A basic pendulum is a machine in which the point mass is hung from a fixed support by a light, inextensible string. The mean position of a simple pendulum is shown by a vertical line flowing through a fixed support. The length of the simple pendulum, abbreviated L, is the vertical distance between the point of suspension and the suspended body's centre of mass (when it is in mean position). The resonant mechanism supporting this type of pendulum has a single resonant frequency.
Period of the simple pendulum is given by,
T = 2π√L/g
Given,
T = 2 s
g = 9.8 m/s² ( acceleration due to gravity)
putting values in the equation,
2 = 2π√L/9.8
4=4π²L/9.8
L = 0.99 m
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Write 2 – 3 sentences explaining how quantum mechanics describes light and matter. How do the distinct lines in the emission spectra of elements support the idea that light can behave as a particle?
what occurs when the loop of a cell goes from the positive to negative terminals of a battery
If the positive charge moves from the positive terminal to the negative terminal then the force is attractive and the charge loses potential energy.
So in that sense the negative terminal means negative potential energy.
If you illuminate red paint with pure blue light, what color will that paint appear?
Entry field with correct answer
Red.
Blue.
White.
Black.
If you illuminate red paint with pure blue light, then Black color will that paint appear. Hence option D is correct.
Visible light spectrum is nothing but the range of wavelength of radiation from 4000 angstrom to 7000 angstrom(Violet to Red). light is a energy packet. Every Photon having different wavelength travels with same velocity c (velocity of light). When we focus numbers of colors from visible spectrum to a point, that point appears as a white light. hence white light is composed of numbers of Colors in it.
a red paint absorbs blue and green light therefore it is appear to be black.
Hence option D is correct.
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To take off from an aircraft carrier, a 21000 kg jet needs to accelerate at 36.9 m/s^2. How much force is required? (unit = N)
The force required for the jet to take off from an aircraft carrier is 773,490 N (Newton).
To calculate the force required for the jet to take off from the aircraft carrier, you can use Newton's second law of motion, which is:
Force (F) = Mass (m) × Acceleration
(a) Given the mass (m) of the jet as 21,000 kg and the acceleration
To calculate the force required for the 21000 kg jet to accelerate at 36.9 m/s^2, we need to use Newton's second law of motion which states that force (F) is equal to mass (m) multiplied by acceleration (a).
So,
F = m x a
F = 21000 kg x 36.9 m/s^2
F = 773,490 N
∴ force required = 773,490 N
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The steel used for piano wire has a tensile strength p_T of 3*10^9 N/m^2 and a density ⍴ of 7800 kg/m^3. What is the speed v of a wave traveling down such a wire if the wire is stretched to its breaking point?
express the speed in m/s to the nearest integer.
The speed of a wave traveling down a wire can be calculated using the formula. Therefore, the speed of a wave traveling down a piano wire stretched to its breaking point is approximately 620 m/s.
v = √(p_T/⍴)
where p_T is the tensile strength and ⍴ is the density of the wire.
Substituting the given values, we get:
v = √(3*10^9 N/m^2 / 7800 kg/m^3)
v = √384615.3846 m^2/s^2
v ≈ 620 m/s
Therefore, the speed of a wave traveling down a piano wire stretched to its breaking point is approximately 620 m/s.
You want to find the speed v of a wave traveling down a piano wire, given that the tensile strength p_T is 3*10^9 N/m^2 and the density ⍴ is 7800 kg/m^3 when the wire is stretched to its breaking point.
To calculate the wave speed v, we can use the formula:
v = sqrt(T/μ),
where T is the tension in the wire and μ is the linear mass density of the wire.
Since the wire is stretched to its breaking point, the tension T equals the tensile strength p_T:
T = p_T = 3*10^9 N/m^2.
To find the linear mass density μ, we need to know the cross-sectional area A and the length L of the wire. However, we can express μ in terms of the given density ⍴:
μ = (A * L * ⍴) / L = A * ⍴.
Now we can plug the values of T and ⍴ into the wave speed formula:
v = sqrt((3*10^9 N/m^2) / (A * 7800 kg/m^3)).
Since the cross-sectional area A does not affect the final answer, we can remove it from the formula:
v = sqrt((3*10^9 N/m^2) / (7800 kg/m^3)).
Now, compute the wave speed:
v ≈ sqrt(384615.38 m^2/s^2) ≈ 620 m/s.
So, the speed of a wave traveling down such a piano wire when stretched to its breaking point is approximately 620 m/s to the nearest integer.
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The flow rate of blood through the average human aorta, of radius 1.0 cm, is about 90 cm3/s. What is the speed of the blood flow through the aorta?
The speed of blood flow through the average human aorta is approximately 28.7 cm/s.
What is the speed of the blood flow through the aorta?The speed of blood flow through the average human aorta, which has a radius of 1.0 cm and a flow rate of about 90 cm³/s.
To find the speed, we'll use the formula: Flow rate = Cross-sectional area × Speed
Calculate the cross-sectional area (A) of the aorta using the formula A = πr², where r is the radius of the aorta (1.0 cm).
A = π(1.0 cm)² = π(1) = π cm²
Rearrange the formula to find the speed: Speed = Flow rate / Cross-sectional area
Plug in the values for the flow rate (90 cm³/s) and the cross-sectional area (π cm²) and solve for the speed:
Speed = (90 cm³/s) / (π cm²) ≈ (90 / 3.14) cm/s ≈ 28.7 cm/s
The average human aorta moves blood at a speed of around 28.7 cm/s.
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Question 2 of 25
You burn a log on a fire. You use the fire to warm yourself and to help you see
to read a book. What energy transformation is taking place?
A. Nuclear energy is transformed to light energy and heat energy.
OB. Chemical energy is transformed to nuclear energy and heat
energy.
C. Nuclear energy is transformed to light energy and chemical
energy.
OD. Chemical energy is transformed to light energy and heat energy.
Answer:
A
Explanation:
the answer is A because the energy is light and heat
Answer:
i think it's, Chemical energy is transformed to light energy and heat energy.
Explanation:
i used the last brain cells i had...lol...pls mark brainliest
Compute the wavelength for a 6.5eV photon (in nm).
A wavelength can be transformed into electronvolts (eV), a unit of energy: Make use of the Planck energy equation E = h c /. The photon's wavelength is 1240 nm with an energy of 6.5 eV, or 196 nm.
A wavelength example is what?Examples of waves. All visible light has a wavelength between 400 and 700 nanometers (nm). The wavelength of yellow light is approximately 570 nanometers. Infrared, or "redder than red," energy has a wavelength that is too long to be seen.
What exactly is a light wavelength?"The distance between both of the subsequent crests or troughs of both the light wave" is how the light's wavelength is described. The Greek letter omega () is used to represent it. Hence, the wavelength is defined as the separation between one wave's crest or trough and the following wave.
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A 1.5-kg object has a velocity of 5j m/s at t = 0. It is accelerated at a constant rate for five seconds after which it has a velocity of (6i + 12j) m/s. What is the direction of the resultant force acting on the object during this time interval?
1) 65°
2) 56°
3) 61°
4) 49°
5) 27°
The direction of the resultant force acting on the object during this time interval is 49° (option 4).
To find the direction of the resultant force acting on the object, we first need to determine the acceleration during this time interval. We can use the formula:
final_velocity = initial_velocity + acceleration * time
Let's rearrange this formula to find acceleration:
acceleration = (final_velocity - initial_velocity) / time
The initial velocity is given as 5j m/s, and the final velocity is (6i + 12j) m/s. The time interval is 5 seconds.
acceleration = ((6i + 12j) - 5j) / 5 = (6i + 7j) / 5 = (6/5)i + (7/5)j
Now we can find the resultant force acting on the object using Newton's second law:
force = mass * acceleration = 1.5 * ((6/5)i + (7/5)j) = (9i + 10.5j) N
To find the direction of the force, we can calculate the angle θ with respect to the positive x-axis using the arctangent function:
θ = arctan(opposite/adjacent) = arctan(10.5/9)
θ ≈ 49°
So, the direction of the resultant force acting on the object during this time interval is 49° (option 4).
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A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it rests is 0.24. What maximum distance can the truck travel (starting from rest and moving horizontally with constant acceleration) in 3.0 s without having the box slide?
1) 14 m
2) 11 m
3) 19 m
4) 24 m
5) 29 m
The maximum distance the truck can travel in 3.0 s without having the box slide is approximately 10.6 m, which is closest to option (2) 11 m.
To determine the maximum distance the truck can travel in 3.0 s without having the box slide, we need to consider the maximum acceleration that the truck can have without exceeding the maximum static frictional force that can act on the box. The maximum static frictional force that can act on the box is given by:
F_friction = friction coefficient * F_normal
where F_normal is the normal force acting on the box due to its weight. Since the box is not accelerating vertically, the normal force must be equal in magnitude to the weight of the box, which is given by:
F_weight = m*g
where m is the mass of the box and g is the acceleration due to gravity.
The maximum static frictional force that can act on the box is therefore:
F_friction = friction coefficient * F_weight = friction coefficient * m * g
Since the truck is starting from rest, we can use the following kinematic equation to find the maximum acceleration that the truck can have without having the box slide:
d = (1/2)at^2
where d is the distance traveled, t is the time, and a is the acceleration.
Solving for a, we get:
a = 2*d/(t^2)
The maximum acceleration that the truck can have without having the box slide is given by:
a_max = F_friction / m
Substituting the expressions for F_friction and a_max, and solving for d, we get:
d = (1/2)a_maxt^2 = (1/2)*(friction coefficient)gt^2
Substituting the given values, we get:
d = (1/2)(0.24)(9.81 m/s^2)*(3.0 s)^2 = 10.6 m
Therefore, the maximum distance the truck can travel in 3.0 s without having the box slide is approximately 10.6 m, which is closest to option (2) 11 m.
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(B) Since the capacitor is isolated, Q remains constant. Filling the place with oil (a dielectric) will
increase the capacitance, causing the potential (V = Q/C) to decrease.
An isolated capacitor with air between its plates has a potential difference Vo and a charge Qo. After the space
between the plates is filled with oil, the difference in potential is V and the charge is Q. Which of the following
pairs of relationships is correct?
(A) Q = Qâ and V > Vâ
(B) Q = Qâ and V < Vâ
(C) Q > Qâ and V = Vâ
(D) Q < Qâ and V < Vâ
(E) Q > Qâ and V > Vâ
Since the capacitor is isolated, the pair of relations that is correct Q > Q₀and V = V₀. Hence option C is correct.
Capacitor is a two plate system, when two plates held parallel with small separating distance between them, capacitor is formed. the space between this two plates is called as dielectric, it can be air, oil or paper etc. A voltage V is applied across the two plates, opposite charges Q gets accumulated on the surface of this two plates.
capacitance of the capacitor is directly related to the dielectric of capacitor by the relation,
C = ε₀k A/d , where ε₀ is permittivity of free space, k is dielectric constant. A is area of plate and d is distance between plate.
In this problem,
dielectric constant of oil is greater than air,
i.e. k > k₀ , C > C₀
Q = CV
Q > Q₀
for V=V₀
Hence option C is correct.
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An angle of 1 arcsecond is _________.
-about the width of your fist held at arm's length
-about the width of a finger held at arm's length
-slightly more than the width of a basketball held at arm's length
-less than the thickness of a human hair held at arm's length
An angle of 1 arcsecond is less than the thickness of a human hair held at arm's length.
Arcsecond is a unit of angular measurement, where one degree is divided into 60 minutes, and one minute is further divided into 60 seconds. This means that an angle of 1 arcsecond is a very small angle. It is often used in astronomy to measure the apparent size of celestial objects, as well as their separation.
To put it into perspective, imagine holding a strand of hair at arm's length. The thickness of the hair is likely to be greater than an angle of 1 arcsecond. This small angle is also why telescopes with high angular resolution are necessary to observe fine details of celestial objects.
In summary, an angle of 1 arcsecond is an incredibly small angle, less than the thickness of a human hair held at arm's length. Understanding this unit of measurement is crucial for astronomers to accurately observe and study celestial objects.
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1. a uniform pressure of 7.0 X 10^5 N/m^2 is applied to all six sides of a copper cube. what is the percentage change in volume of the cube? (for copper B= 14x 10^10 N/m^2
B) How large a force is necessary to stretch a 2.0mm diameter steel wire by 1%? ( Y= 2.0x10^11 N/m^2) Hint: the cross sectional area of a circular wire is pir^2
A. The percentage change in volume of the copper cube is 3%.
B. The force necessary to stretch a 2.0 mm diameter steel wire by 1% is approximately 25.1 N.
A.
To find the percentage change in volume of the copper cube, we can use the formula:
ΔV/V = 3BΔP/Β
Where ΔV/V is the fractional change in volume,
B is the bulk modulus of the material (given as [tex]14\times10^{10}\: N/m^2[/tex] for copper), and ΔP is the change in pressure.
Since the pressure is the same on all six sides of the cube,
ΔP = [tex]7.0\times10^5 \:N/m^2.[/tex]
Substituting the values into the formula, we get:
ΔV/V = [tex]3(14\times10^{10}\: N/m^2)(7.0\times10^5 N/m^2)/(14\times10^{10}\: N/m^2)[/tex]
ΔV/V = 0.03 or 3%
B.
To find the force necessary to stretch a 2.0 mm diameter steel wire by 1%, we can use the formula:
F = AΔL Y/L
Where F is the force required,
A is the cross-sectional area of the wire (given as πr^2, where r = 1.0 mm = 0.001 m),
ΔL is the change in length (given as 1% of the original length, or 0.01 x 2.0 mm = 0.02 mm = 0.00002 m),
Y is the Young's modulus of the material (given as 2.0x10^11 N/m^2), and L is the original length of the wire (which we will assume to be 1 meter for simplicity).
Substituting the values into the formula, we get:
F = [tex]\pi(0.001 m)^2 (0.00002 \:m) (2.0\times10^{11}\: N/m^2) / 1 m[/tex]
F ≈ 25.1 N
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explain what happens to the light when the laser is moved downward between the 60 angle and the surface of the less dense medium below
When the laser is moved downward between the 60 angle and the surface of the less dense medium below, the light undergoes refraction.
Refraction is the bending of light as it passes from one medium to another, such as from air to water or from air to glass. The amount of bending that occurs depends on the angle at which the light hits the surface and the difference in density between the two mediums.
In this case, the laser is passing from a more dense medium (air) to a less dense medium (the surface below), so the light will bend away from the normal (a line perpendicular to the surface) as it enters the less dense medium.
The amount of bending will be determined by the angle of incidence (the angle at which the light hits the surface) and the refractive index of the less dense medium.
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Calculate the equivalent resistance. All resistors are identical, R=3Ω:
The equivalent resistance of three identical 3 Ω resistors in parallel is 3 Ω.
To calculate the equivalent resistance of identical resistors in parallel, we can use the formula:
1/Req = 1/R1 + 1/R2 + 1/R3 + ...
where Req is the equivalent resistance and R1, R2, R3, etc. are the individual resistances.
In this case, we have three identical resistors in parallel, so we can simplify the formula to:
1/Req = 1/R + 1/R + 1/R = 3/R
Multiplying both sides by R/3, we get:
R/3 = 1/Req
Therefore:
Req = 3/1 = 3 Ω
So the equivalent resistance of three identical 3 Ω resistors in parallel is 3 Ω.
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2. What type of color and light did Turner use in your painting? (Please refer to the formal powerpoint for more information:
3. What is the subject of your painting? How does the subject reflect the turbulence of the times?
The subject of the painting is a seascape, with a storm raging in the background. The turbulent waves and dark clouds reflect the turbulence of the time.
What is waves ?Waves are a type of energy that moves in a periodic pattern and is created when a force is applied to a medium. Waves are characterized by their amplitude, frequency, and wavelength. They can propagate through different mediums such as air, water, and solids. Examples of waves include sound, light, and seismic. Waves are used in various scientific fields, such as physics and engineering, as well as in everyday life. For example, sound waves are used to communicate, and light waves are used for vision. Waves can also be used to measure distances, such as in radar and sonar.
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