Q? Find the percent of the total area under the standard normal curve between the following​ z-scores.
z = - 1.6 and z = - 0.65
percent of the total area between z = -1.6 and z = -0.65 ​%.

In a continuous distribution of random variables, P(x>2) is treated the same as P(x>-2) because both represent areas under the probability density function, rather than specific values of the variable.

The main difference between discrete random variables and continuous random variables is that discrete random variables can only take on specific values, while continuous random variables can take on any value within a range.

This leads to differences in how probabilities are calculated for different values of the variable. In a discrete distribution, the probability of an event such as P(x>2) can be calculated directly by adding up the probabilities of all possible values of x that are greater than 2.

However, in a continuous distribution, the probability of an event such as P(x>2) must be calculated using integration, because the variable can take on an infinite number of values within the range.

Additionally, because continuous random variables can take on any value within a range, probabilities for specific values are typically very small and are often expressed as the probability density function.

Therefore, in a continuous distribution, P(x>2) is treated the same as P(x>-2) because both represent areas under the probability density function, rather than specific values of the variable.

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When considering the area under the standard normal curve, the area between z = 3 and z = -3 is bigger than the area between z = 2.7 and z = 2.9.

The reason is that the area between z = 3 and z = -3 covers a wider range on the curve, including the values between z = 2.7 and z = 2.9.

The area under the standard normal curve between z = -3 and z = 3 includes the entire curve, since the standard normal distribution is symmetric around the mean of 0. Therefore, the area between z = -3 and z = 3 is equal to the total area under the curve, which is 1.

On the other hand, the area between z = 2.7 and z = 2.9 is a small portion of the total area under the curve, which is less than 1.

Therefore, the area between z = 3 and z = -3 is greater than the area between z = 2.7 and z = 2.9.

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Hence, she will be able to  go to Disneyland in 9 months if she saves $25 per month.

Savings is the amount of money left over after spending and other obligations are deducted from earnings. Savings represent money that is otherwise idle and not being put at risk with investments or spent on consumption. Savings accounts are very safe but tend to offer very low rates of return as a result. Saving is the portion of income not spent on current expenditures. In other words, it is the money set aside for future use and not spent immediately.

Subtract  your  spending from your  income to figure how much you are saving, then divide this number by your income. 

Susie needs to save money in her piggy bank,

So, $250 - $45 = $205  more to reach  her goal.

If she saves  $25  per month, the number of months she needs to reach her goal can be found by dividing the amount she needs to save by the  amount she saves per month:

$205 ÷ $25 per month = 8.2 months ≅  9 months.

Since she can't save a fraction of a month, we can  round up to the nearest whole number, which means that Susie will need to save for 9 months to reach her goal.

Therefore, she will be able to  go to Disneyland in 9 months if she saves $25 per month.

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The given scenario involves the use of consistent estimators and the concept of MVUE.

The given scenario involves independent samples from two populations, Xn and Y1, Y2...Yn, with means uy and uy and variances 012 and oz2, respectively. The estimator of u1 - u2 is I - Ỹ, which is a consistent estimator.

Further, the estimator of o2 is Σ(Xi - u1)2 + Σ(Yi - u2)2 / 2n-2. It is consistent, but it is not an MVUE of o2.

However, the estimator of o2 can be written as ô2 = Sy1 + Sy2, where Sy1 = Σ(Xi - u1)2 / n-1 and Sy2 = Σ(Yi - u2)2 / n-1. Both these estimators are the MVUE for o2.

It is important to note that the populations are normally distributed with variances 02 = 02. Overall, the given scenario involves the use of consistent estimators and the concept of MVUE (Minimum Variance Unbiased Estimator).

Based on your question, you're asking if the given estimator of σ² is a Minimum Variance Unbiased Estimator of σ².

Given that Xn and Yn are independent random samples from populations with means μx and μy and variances σx² and σy², respectively.

You have an estimator of the form: ô² = Sx² + Sy²
where Sx² = Σ (Xi - μx)² / (n - 1) and Sy² = Σ (Yi - μy)² / (n - 1).

The properties required for an MVUE are unbiasedness and minimum variance among all unbiased estimators.
Since both Sx² and Sy² are unbiased estimators of their respective variances (σx² and σy²), the sum ô² is also an unbiased estimator of σ² = σx² + σy².

To check if it has minimum variance, we need to consider the efficiency of the estimator. In this case, since the samples are independent and we have a linear combination of unbiased estimators, the estimator ô² is indeed an MVUE of σ².

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Solving the initial value problems, the function is f(x) = (x⁴ + x⁻⁴) / 4 + 17/16.

We have the initial value problem,

f'(x) = x³ - 1/x⁵

Let f(x) = y, then f'(x) = dy/dx.

dy/dx = x³ - 1/x⁵

dy = (x³ - 1/x⁵) dx

Integrating both sides,

∫dy = ∫(x³ - x⁻⁵) dx

y = [(x⁴/4) - (x⁻⁴/-4)] + C

y = (x⁴ + x⁻⁴) / 4 + C

We have y = 0 when x = √2/2 = 1/√2

((1/√2)⁴ + (1/√2)⁻⁴) / 4 + C = 0

Solving, C = 17/16

So the function is, f(x) = (x⁴ + x⁻⁴) / 4 + 17/16

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The y-intercept is found by setting x=0 on graph , which gives f(0) = (0+7)²(0-1) = -49. The roots are x = -7 and x = 1.

A graph is a visual representation of data, relationships or functions. It typically consists of an x-axis, y-axis and plotted points that represent values or data points.

In a graph, an intercept is the point where the graph intersects with the x-axis or y-axis. The x-intercept is where the graph crosses the x-axis, and the y-intercept is where it crosses the y-axis.

According to the given information:

The intercept is the point at which a function or graph intersects with one of the axes, either the x-axis or y-axis. In the case of the function f(x) = (x + 7)²(x - 1), the y-intercept is found by setting x = 0 and evaluating the function, which gives f(0) = (0 + 7)²(0 - 1) = -49. Therefore, the y-intercept is -49.

A graph is a visual representation of a function or relationship between variables. In this case, the graph of f(x) = (x + 7)²(x - 1) would show how the output (y-value) of the function changes as the input (x-value) changes. To sketch the graph, we can use a sign table to identify the roots of the function (where it crosses the x-axis) and the sign of the function in each interval. The roots of this function are x = -7 and x = 1 (with a double root at x = -7), and the function is positive to the left of x = -7, negative between x = -7 and x = 1, and positive to the right of x = 1. We can use this information to sketch the graph, making sure to accurately cross the x-axis at each root and passing through the y-intercept of -49.

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Answer: 48.6%

Step-by-step explanation:

Subtract all of 'em
1060-125-140-280= 515
Divide your answer with 1060
515/1060= 0.4858490566037736
Move the decimal to the right 2 times to make the percentage then round up
0.4858490566037736 = 48.6%

(I hope this helped!)

The lot size that will minimize inventory costs is 55 flat irons, and the number of orders per year would be 2.

To find the lot size and the number of orders per year that will minimize inventory costs, we need to consider the economic order quantity (EOQ) model.

The EOQ formula calculates the optimal order quantity that minimizes the total inventory costs.

EOQ = √((2× D× S) / H)

Where:

D = Annual demand (110 flat irons in this case)

S = Cost per order ($16.50 in this case)

H = Holding cost per unit per year ($1.20 in this case)

Let's calculate the EOQ and the number of orders per year:

Plug in the values in above formula:

EOQ = √((2×110 × 16.50) / 1.20)

EOQ = √(3630 / 1.20)

EOQ = 55

Now let us find the number of orders per year:

Number of orders = Annual demand / EOQ

Number of orders = 110 / 55

Number of orders = 2

Hence, the lot size that will minimize inventory costs is approximately 55 flat irons, and the number of orders per year would be 2.

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We would expect women with a waist measurement of 30.5 inches to have an average body fat percentage of 15.58% based on the correlation coefficient.

Using the equation y = 1.86 + 0.45x, where x is the waist measurement and y is the body fat percentage, and plugging in 30.5 inches for x, we get, based on correlation coefficient.

To evaluate the degree of relationships between data variables, correlation coefficients are utilised.

The most popular gauges the strength and direction of a linear link between two variables, known as a Pearson correlation coefficient.

Values usually fall between -1 and 1, with 1 denoting a perfectly positive correlation and -1 denoting a perfectly inverse relationship. Values at or near 0 suggest an extremely weak correlation or the absence of a linear relationship.

Depending on the application, different coefficient values are needed to convey a meaningful association. Assuming a normal population distribution, the correlation coefficient and sample size can be used to determine the statistical significance of a correlation.

y = 1.86 + 0.45(30.5)
y = 1.86 + 13.72
y = 15.58%

Therefore, we would expect women with a waist measurement of 30.5 inches to have an average body fat percentage of 15.58%.

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Answer:

54 3⁄10 = 543/10 in

Step-by-step explanation:

The maximum population in the next 75 years is 499.

We have,

population of a species of bird, P(t) = 450 + 200 cos(0.4πt)

So, the maximum population in the next 75 years

P(2075) = 450 + 200 cos (0.4π (2075))

P(2075)= 450 +200 cos (2,606.2)

P(2075)= 450 + 200 . 0.2463

P(2075)= 499.26

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A vector perpendicular to both u and v is the cross product of two vectors, u and v. The magnitude of the cross product is determined by multiplying the magnitudes of u and v by the sine of the angle between them. The right-hand rule determines the direction of the cross-product. So, u x v = (-18i + 27j - 30k), v x u = (-18i - 27j - 30k), v x v = 0.

(a) u x v:

The cross product of u and v can be found using the determinant method as follows:

u x v = | i  j  k |

           | 5  0  6 |

           | 2  6 -3 |

= (-18i + 27j - 30k)

Therefore, u x v = -18i + 27j - 30k.

(b) v x u:

The cross product of v and u can be found using the same determinant method:

v x u = | i  j  k |

           | 2  6 -3 |

           | 5  0  6 |

= (-18i - 27j - 30k)

Therefore, v x u = -18i - 27j - 30k.

(c) v x v:

The cross product of a vector with itself is always zero because the sine of the angle between the two vectors is zero. Therefore, v x v = 0.

In summary, u x v = -18i + 27j - 30k, v x u = -18i - 27j - 30k, and v x v = 0.

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Answer:

c mystify

Step-by-step explanation:

mystify means

utterly bewilder or perplex (someone).

"maladies that have mystified and alarmed researchers for over a decade"

#ofSTDEVs is often called a "Z-score"; we can use the symbol z, which can be used to calculate the confidence intervals in a data.

A z-score in statistics is the number of standard deviations a data point deviates from the population mean. The difference between a data point and the mean, divided by the standard deviation, is used to generate the z-score.  

#ofSTDEVs=(value−mean)/standard deviation

It is frequently applied when determining confidence intervals and evaluating hypotheses. A data point's z-score, for instance, is 1 if it deviates from the mean by one standard deviation. Its z-score is 2 if it deviates from the mean by two standard deviations.

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The decimal value of 1101 (base 2) is 13.

1. Identify the place values of each digit. In this case, from right to left, the place values are 2^0, 2^1, 2^2, and 2^3.

2. Multiply each digit by its corresponding place value.

1 * 2^3 = 1 * 8 = 8

1 * 2^2 = 1 * 4 = 4

0 * 2^1 = 0 * 2 = 0

1 * 2^0 = 1 * 1 = 1

3. Add the results of the previous step together: 8 + 4 + 0 + 1 = 13.

So, the decimal value is 13.

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Answer:

Step-by-step explanation:

The first four non-zero terms of the Taylor series for the function 24 about 0 are 24 + 0x + 0x^2 + 0x^3.

To find the Taylor series for the function f(x) = 24 about 0, we need to calculate its derivatives up to the fourth order at x = 0.

f(x) = 24
f'(x) = 0
f''(x) = 0
f'''(x) = 0
f''''(x) = 0

Since all the derivatives are zero, the Taylor series for f(x) at x = 0 is:

f(x) = f(0) = 24

So, the first four non-zero terms of the Taylor series for the function 24 about 0 are:

24 + 0x + 0x^2 + 0x^3

Note that all the coefficients of the higher-order terms are zero, as all the derivatives of the function are zero.

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The 99% confidence interval for the population proportion is (0.671, 0.769), using a z-score distribution table.

To find the 99% confidence interval for the population proportion, we can use the following formula:

CI = p ± z x√(p'(1-p')/n)

where CI is the confidence interval, p is the population proportion, p' is the sample proportion, n is the sample size, and z is the z-score associated with the desired confidence level.

In this case, we have p' = 360/500 = 0.72 and n = 500. To find the z-score, we can use a standard normal distribution table or calculator. For a 99% confidence level, the z-score is approximately 2.576.

Substituting these values into the formula, we get:

CI = 0.72 ± 2.576 x √(0.72(1-0.72)/500)

= 0.72 ± 0.049

Therefore, the 99% confidence interval for the population proportion is (0.671, 0.769).

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(i) The limit of 2/n goes to zero as n goes to infinity.

(ii) The sequence bn converges to 1.

(i) To determine if the sequence an = 2 + (-1)^n/n converges or diverges, we can use the limit test. We need to find the limit of the sequence as n approaches infinity.

lim n→∞ an = lim n→∞ (2 + (-1)ⁿ/n)

Since (-1)ⁿ oscillates between 1 and -1 as n goes to infinity, we can split the sequence into two parts:

lim n→∞ (2 + (-1)ⁿ/n) = lim n→∞ 2/n + lim n→∞ (-1)^n/n

The limit of (-1)ⁿ/n oscillates between 1/n and -1/n as n goes to infinity, and hence it does not converge to a specific value. Therefore, the sequence an diverges.

(ii) Let's determine if the sequence bn = n² / √10+n² converges or diverges. Again, we can use the limit test to find out.

lim n→∞ bn = lim n→∞ n² / √10+n²

To simplify this expression, we can multiply the numerator and denominator by 1/n²:

lim n→∞ bn = lim n→∞ (n²/n²) / (√10/n²+1)

Now, as n goes to infinity, the denominator goes to 1, and the numerator goes to 1 as well. Therefore, the limit of the sequence bn is 1.

lim n→∞ bn = 1

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The value of the given integral is -2cos(3) - e³ + 2.

To find the antiderivative of the given function, we need to use integration rules. The antiderivative of 2sin(x) is -2cos(x) and the antiderivative of eˣ is eˣ. Therefore, the antiderivative of the given function is:

∫(2sin(x) - eˣ) dx = -2cos(x) - eˣ + C

where C is the constant of integration.

Now we can evaluate the definite integral by substituting the limits of integration:

∫₃⁰ (2sin(x) - eˣ) dx = [-2cos(x) - eˣ] from 0 to 3

= (-2cos(3) - e³) - (-2cos(0) - e^0)

= -2cos(3) - e³ + 2

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Complete Question:

Evaluate the integral: integral from 0 to 3 (2insx-e^x)dx

The circumference of a donut is 10.99 inches.

There are 360 square inches in 2.5 square feet.

The circumference of a donut can be found using the formula C = πd, where C is the circumference and d is the diameter. Given that each donut has a diameter of 3.5 inches, the circumference of a donut is:

C = πd

C = π(3.5)

C ≈ 10.99 inches

Therefore, the circumference of a donut is approximately 10.99 inches.

In order to find the number of square inches in 2.5 square feet, we can multiply the number of square feet by the conversion factor of 144 square inches per square foot:

2.5 square feet × 144 square inches per square foot = 360 square inches

Therefore, there are 360 square inches in 2.5 square feet.

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The first and second derivatives of f(r) with respect to r. In this case, f'(r) = -22 and f"(r) = 0.

First, let's talk about what a derivative is. A derivative is a mathematical concept used to describe the rate at which a function changes. It tells us how quickly a function is changing at any given point. Now, let's move on to the given functions.

The first function is f(x) = e⁻ˣsin(2x). We're asked to prove that f"(x) + 2f'(x) + 2f(x) = 0.

To do this, we need to take the first and second derivatives of f(x). We'll start with the first derivative, or f'(x).

f'(x) = -e⁻ˣsin(2x) + 2e⁻ˣcos(2x)

Now, let's take the second derivative, or f"(x).

f"(x) = 2e⁻ˣsin(2x) - 4e⁻ˣcos(2x) - 2e⁻ˣcos(2x)

Now, we can plug these values back into the original equation:

f"(x) + 2f'(x) + 2f(x) = [2e⁻ˣsin(2x) - 4e⁻ˣcos(2x) - 2e⁻ˣcos(2x)] + 2[-e⁻ˣsin(2x) + 2e⁻ˣcos(2x)] + 2[e⁻ˣsin(2x)]

If we simplify this expression, we end up with:

f"(x) + 2f'(x) + 2f(x) = 0

Now, let's move on to the second function: f(x) = -22(1 + r). We're asked to find f'(x) and f"(x).

Well, there's a bit of a problem here. The function f(x) doesn't actually involve x at all - it only involves r. So it doesn't make sense to talk about its first or second derivative with respect to x.

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The value of k is 2 and the cumulative distribution function F(v) is given by F(v) = 1 - √(2/v).

To evaluate k, we need to use the fact that the total area under the density function must be equal to 1.

∫ f(y) dy = 1

Integrating the function over the given interval, we get:

∫ k/x^2 dy = ∫ kx^-2 dy from x=1 to x=2

= -kx^-1 from x=1 to x=2

= -k(1/2 - 1)

= k/2

So,

∫ f(y) dy = ∫ k/x^2 dy from x=1 to x=2 + ∫ 0 dy from y=2 to y=4

= k/2 + 0

= 1

Thus,

k/2 = 1

k = 2

So, the value of k is 2.

To find F(v), the cumulative distribution function, we need to integrate the density function over the interval (-∞,v]. Since the density function is zero for y less than or equal to zero, we have:

F(v) = ∫ f(y) dy from y = 0 to y = v

= ∫2/x^2 dy from x = √(2/v) to x = 2

= -2/x from x = √(2/v) to x = 2

= -2/2 + 2/√(2/v)

= 1 - √(2/v)

Thus, the cumulative distribution function F(v) is given by F(v) = 1 - √(2/v).

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The complete question is:
Consider the density function (10 points) f(y) ={k/x^2 < y < 4 0

d. Evaluate k.

e. Find F(v)

The derivative of a function of a real variable measures the sensitivity to change of the function value with respect to a change in its argument.

1. y = sin(3√x)

dy/dx = (3/2√x)cos(3√x) (Chain rule)

Final answer: dy/dx = (3cos(3√x))/(2√x)

2. y = tan^-1(1√x)

dy/dx = 1/(1+(1/x))(1/2x^(-1/2))

Final answer: dy/dx = 1/(2x(1+x))

3. y = cos^3 x

dy/dx = -3cos^2(x)sin(x) (Chain rule and Power rule)

Final answer: dy/dx = -3cos^2(x)sin(x)

4. y = csc ^-1(e^x)

dy/dx = -(1/(|x|√(e^(2x)-1)))e^x (Chain rule and inverse trigonometric derivative)

Final answer: dy/dx = -(e^x)/(|x|√(e^(2x)-1))

5. y = e^sin^-1x = exp(sin^-1 x)

dy/dx = (1/√(1-x^2))e^sin^-1x (Chain rule and inverse trigonometric derivative)

Final answer: dy/dx = (e^sin^-1x)/(√(1-x^2))

6. y = sec^-1 (log x)

dy/dx = (1/|x|)(1/(√(log^2x-1))) (Chain rule and inverse trigonometric derivative)

Final answer: dy/dx = (1/|x|)(1/(√(log^2x-1)))

7. y = ln(cot x)

dy/dx = -csc(x) (Chain rule and derivative of cotangent)

Final answer: dy/dx = -csc(x)

8. y = exp(x^2 +1)

dy/dx = 2xe^(x^2+1) (Chain rule and Power rule)

Final answer: dy/dx = 2xe^(x^2+1)

9. y = ln(1 + e^x)

dy/dx = (1/(1+e^x))e^x (Chain rule)

Final answer: dy/dx = (e^x)/(1+e^x)

10. y = cot^-1(xe^x)

dy/dx = -(1/(1+(xe^x)^2)))e^x + (1/(1+(xe^x)^2)))xe^x (Chain rule and inverse trigonometric derivative)

Final answer: dy/dx = [xe^x - e^x]/(x^2e^(2x)+1)

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(a) By solving we get, f(1) = cos(a), f'(x) = -a sin(atx), f'(1) = -a sin(a)

[tex]f''(x) = -a^2 cos(atx)[/tex], [tex]f''(1) = -a^2 cos(a)[/tex], [tex]f'''(x) = a^3 sin(atx)[/tex], [tex]f'''(1) = a^3 sin(a)[/tex][tex]f''''(x) = a^4 cos(atx)[/tex],  [tex]f''''(1) = a^4 cos(a)[/tex]

b. The Taylor series expansion of f(x) at x=1 is:

[tex]f(x) = cos(a) - a sin(a) (x-1) - (a^2/2) cos(a) (x-1)^2 + (a^3/6) sin(a) (x-1)^3 + (a^4/24) cos(a) (x-1)^4 - ....[/tex]

A Taylor series expansion is a mathematical tool used to represent a function as an infinite sum of its derivatives evaluated at a single point. The general formula for a Taylor series expansion of a function f(x) at the point x=a is given by:

f(x) = f(a) + f'(a)(x-a) + f''(a)(x-a)^2/2! + f'''(a)(x-a)^3/3! + ...

(a) We have:

f(x) = cos(atx)

So,

f(1) = cos(a)

f'(x) = -a sin(atx)

f'(1) = -a sin(a)

[tex]f''(x) = -a^2 cos(atx)[/tex]

[tex]f''(1) = -a^2 cos(a)[/tex]

[tex]f'''(x) = a^3 sin(atx)[/tex]

[tex]f'''(1) = a^3 sin(a)[/tex]

[tex]f''''(x) = a^4 cos(atx)[/tex]

[tex]f''''(1) = a^4 cos(a)[/tex]

(b)

To find the Taylor series expansion of f(x) at x=1, we need to find its derivatives at x=1:

f(x) = cos(atx)

f(1) = cos(a)

f'(x) = -a sin(atx)

f'(1) = -a sin(a)

[tex]f''(x) = -a^2 cos(atx)[/tex]

[tex]f''(1) = -a^2 cos(a)[/tex]

[tex]f'''(x) = a^3 sin(atx)[/tex]

[tex]f'''(1) = a^3 sin(a)[/tex]

[tex]f''''(x) = a^4 cos(atx)[/tex]

[tex]f''''(1) = a^4 cos(a)[/tex]

Then, the Taylor series expansion of f(x) at x=1 is:

[tex]f(x) = f(1) + f'(1)(x-1) + f''(1)(x-1)^2/2! + f'''(1)(x-1)^3/3! + f''''(1)(x-1)^4/4! + ...[/tex]

[tex]f(x) = cos(a) - a sin(a) (x-1) - (a^2/2) cos(a) (x-1)^2 + (a^3/6) sin(a) (x-1)^3 + (a^4/24) cos(a) (x-1)^4 - ...[/tex]

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Answer: B(0,-6); C(-2,0)

Step-by-step explanation:

A was translated 4 units to the right (x) and 5 units down (y)

Do the same for the other points

B(-4+4, -1-5)                        C(-6+4, 5-5)

B(0, -6)                                C(-2, 0)

Answer:

  $5420.35

Step-by-step explanation:

You want to find 6.2% of $87,425.

The wording "6.2% of $87,425" means ...

  0.062 × $87,425

That value is nicely computed using any calculator:

   0.062 × $87,425 = $5,420.35

The Social Security tax due is $5420.35.

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Additional comments

The percent sign (%) effectively moves the decimal point 2 places. It is fully equivalent to /100.

  6.2% = 6.2/100

Written as a decimal, this is ...

  6.2/100 = 62/1000 = 0.062 . . . . . "sixty-two thousandths"

Generally, in a verbal description of a math expression, "of" means "times".

The units of dollars, represented by a dollar sign ($), can be treated as though $ were a variable. It remains a part of the product the way "x" would if this were 0.062·87425x = 5420.35x.

The general indefinite integral of S(csc²t - 2[tex]e^t[/tex])dt is 1/sin(t) - 2[tex]e^t[/tex] + C

First, let's recall some basic rules of integration. The integral of a sum of functions is the sum of their integrals, and the integral of a constant times a function is the constant times the integral of the function. We also have some basic integration formulas, such as the integral of sin(t)dt = -cos(t) + C and the integral of [tex]e^t[/tex] dt = [tex]e^t[/tex] + C, where C is the constant of integration.

Now, let's consider the first term of the integrand, csc²t. This function can be rewritten using trigonometric identities as 1/sin²t. To integrate this function, we can use the substitution u = sin(t), du/dt = cos(t) dt, and rewrite the integral as ∫-1/u² du. Using the power rule of integration, we get ∫-1/u² du = 1/u + C = 1/sin(t) + C.

Next, let's consider the second term of the integrand, -2[tex]e^t[/tex]. This function is already in the form of the integral of [tex]e^t[/tex] dt, but with a constant factor of -2. Using the constant multiple rule of integration, we get -2 ∫[tex]e^t[/tex] dt = -2[tex]e^t[/tex] + C.

Putting these two results together using the sum rule of integration, we get the general indefinite integral of S(csc²t - 2e^t)dt:

∫S(csc²t - 2[tex]e^t[/tex])dt = ∫S(csc²t)dt - ∫2(S [tex]e^t[/tex])dt = 1/sin(t) - 2[tex]e^t[/tex] + C

where C is the constant of integration.

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The appropriate frequency distribution graph for scores measured on a nominal scale is only a bar graph.

A bar graph is the representation of numerical data by rectangles (or bars) of equal width and varying height. The gap between one bar and another should be uniform throughout. It can be either horizontal or vertical. The height or length of each bar relates directly to its value.

To answer your question, the appropriate frequency distribution graph for scores measured on a nominal scale is only a bar graph.

A nominal scale is a scale that uses categories instead of numbers.

A bar graph is ideal for displaying the frequencies of these categorical variables, as it separates each category by using individual bars.

Histograms and polygons are more suitable for continuous or interval data, which do not apply to nominal scales.

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