Sensitivity analysis considers how changes in objective cell coefficients would effect the optimal solution. True
False

a) C(x) = 3954100

b) Average cost = 2325.94117

c) Marginal cost = 4000

d) Minimizing average cost = 210

e) Minimum average cost =  1020

What is the cost function?

A loss function, also known as a cost function, is a function used in mathematical optimization and decision theory that transfers an event or the values of one or more variables onto a real number that intuitively represents some "cost" connected to the occurrence. A loss function is the goal of an optimization problem.

Here, we have

Given: Given cost function C(x) = 44100 + 600x + x².

a) The average cost at the production level is 1700.

C(x) = 44100 + 600(1700) + (1700)²

C(x) = 44100 + 1020000 + 2890000

C(x) = 3954100

b) C(x) /x = Average cost

= C(1700) /1700 = 3954100/1700

= 2325.94117

c) dc/dx = 600 + 2x

x = 1700

dc/dx = 600 + 2(1700)

= 600 + 3400

= 4000

d) For minimizing average cost

[tex]\frac{d(C(x)}{dx}[/tex] = [tex]\frac{d}{dx}[44100/x + 600 + x] = 0[/tex]

= -44100/x² +1 = 0

x = √44100

x = 210

e) Minimum average cost

C(210)/210 = 214200/210

= 1020.

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There are 38,400 ways to seat the four couples in a row such that no person sits next to their significant other. This can be answered by the concept of Permutation and combination.

To solve this problem, we can use the concept of permutations and derangements. First, we need to find the total ways of seating the couples without restrictions and then subtract the ways where at least one couple is sitting together.

Total ways to seat the couples without restrictions: There are 8 people (4 couples), so there are 8! (8 factorial) ways to seat them.

Now, we'll find the number of ways where at least one couple sits together. For each of the 4 couples, consider them as a single unit. We have 5 units (4 couple-units and 4 single people), so there are 5! ways to arrange these units. However, within each couple-unit, there are 2! ways to arrange the individuals, so we need to multiply by 2!⁴.

Ways with at least one couple together: 5! × (2!)⁴

To find the number of ways where no person sits next to their significant other, we subtract the ways with at least one couple together from the total ways:

Desired seating arrangements: 8! - (5! × (2!)⁴)

Calculating the values: 40320 - (120 × 16) = 40320 - 1920 = 38,400

So, there are 38,400 ways to seat the four couples in a row such that no person sits next to their significant other.

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The value of f(5) for the given function is -6.

What is a sequence?

A sequence is an enumerated collection of objects in which repetitions are allowed. Like a set, it contains members (also called elements, or terms).

A heuristic, on the other hand, is an approach to problem-solving that seeks to come up with a workable answer quickly rather than promising an ideal or even accurate solution.

When an algorithmic solution is not viable, useful, or effective, heuristics are frequently applied.

Given that, f(1)=6 and  f(n)=f(n−1)−3 thus we have:

f(2) = f(1) - 3 = 6 - 3 = 3

f(3) = f(2) - 3 = 3 - 3 = 0

f(4) = f(3) - 3 = 0 - 3 = -3

f(5) = f(4) - 3 = -3 - 3 = -6

Hence, the value of f(5) for the given function is -6.

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The expected value of XY is 2.67.

We can start by using the definition of expected value:

E(XY) = Σxy × P(X=x, Y=y)

where Σ denotes the sum over all possible values of x and y, and P(X=x, Y=y) is the joint probability of X=x and Y=y.

Since X and Y are positive integers, the possible values for X and Y are {1, 2, 3}. We can calculate the joint probabilities as follows:

P(X=1, Y=1) = P(X=1) × P(Y=1) = (1/3) × (1/3) = 1/9

P(X=1, Y=2) = P(X=1) × P(Y=2) = (1/3) × (1/3) = 1/9

P(X=1, Y=3) = P(X=1) × P(Y=3) = (1/3) ×(1/3) = 1/9

P(X=2, Y=1) = P(X=2) × P(Y=1) = (1/3) × (1/3) = 1/9

P(X=2, Y=2) = P(X=2) × P(Y=2) = (1/3) × (1/3) = 1/9

P(X=2, Y=3) = P(X=2) × P(Y=3) = (1/3) × (1/3) = 1/9

P(X=3, Y=1) = P(X=3) × P(Y=1) = (1/3) × (1/3) = 1/9

P(X=3, Y=2) = P(X=3) × P(Y=2) = (1/3) × (1/3) = 1/9

P(X=3, Y=3) = P(X=3) × P(Y=3) = (1/3) × (1/3) = 1/9

Next, we need to find the values of X and Y that satisfy X^2 + Y < 13. These are:

(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2)

For each of these pairs, we can calculate the value of XY:

(1, 1): XY = 1

(1, 2): XY = 2

(1, 3): XY = 3

(2, 1): XY = 2

(2, 2): XY = 4

(2, 3): XY = 6

(3, 1): XY = 3

(3, 2): XY = 6

Finally, we can substitute these values into the definition of expected value:

E(XY) = Σxy × P(X=x, Y=y)

= (11/9) + (22/9) + (31/9) + (21/9) + (41/9) + (61/9) + (31/9) + (61/9)

= 2.67

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To approximate the change in volume, we can use the formula for the total differential of the volume:

dV = (∂V/∂r)dr + (∂V/∂h)dh

where (∂V/∂r) and (∂V/∂h) are the partial derivatives of V with respect to r and h, respectively.

Using the formula for the volume of a cone, we have:

∂V/∂r = 2πrh/3

∂V/∂h = πr^2/3

Plugging in the given values, we get:

∂V/∂r = 2π(6.7)(4.17)/3 ≈ 56.13

∂V/∂h = π(6.7)^2/3 ≈ 74.44

Now we can approximate the change in volume:

dV ≈ (∂V/∂r)Δr + (∂V/∂h)Δh

≈ (56.13)(6.7 - 5.9) + (74.44)(4.17 - 4.20)

≈ 60.03

Therefore, the approximate change in volume is dv = 60.03 (rounded to two decimal places).

Note: The units for dv would be cubic units, depending on the units used for r and h.

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The associated standard score for this hypothesis test is 3.16. There is is evidence that more than 1/2 of the entire voting population would vote for the green party candidate for governor.

To determine whether the random sample of 1000 registered voters showing 550 votes for the Green Party candidate is evidence that more than half of the entire voting population would vote for the Green Party candidate, we will conduct a hypothesis test with the null hypothesis H0: p ≤ 0.5 and the alternative hypothesis Ha: p > 0.5. We will assume a Type I error rate of 0.05.

1: Calculate the sample proportion (p):

p = 550/1000 = 0.55

2: Calculate the standard error (SE):

SE = sqrt[(p * (1 - p))/n] = sqrt[(0.55 * 0.45)/1000] ≈ 0.0158

3: Calculate the z-score (standard score) for the hypothesis test:

z = (p - p₀) / SE = (0.55 - 0.5) / 0.0158 ≈ 3.16

4. From the p-value table, the p-value is 0.00078885

The associated p-value for this z-score is extremely small (less than 0.001), which means we can reject the null hypothesis H0: p ≤ 0.5 and conclude that there is evidence to support the alternative hypothesis Ha: p > 0.5.

The associated standard score is approximately 3.16. Therefore, this is evidence that more than 1/2 of the entire voting population would vote for the green party candidate.

Note: The question is incomplete. The complete question probably is: a newspaper took a random sample of 1000 registered voters and found that 550 would vote for the green party candidate for governor. Is this evidence that more than 1/2 of the entire voting population would vote for the green party candidate? to answer this question, you will have to test the hypothesis H0: p ≤ 0.5 versus Ha: p > 0.5. assume a type i error rate of 0.05. What is the associated standard score for this hypothesis test?

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Answer:

Step-by-step explanation:

Answer is

(x+4) (2x+9)

(3x+13)

3/13

x =4.3

The inflection points of f(x) = sin (3x + 5) are x ≈ -3.363 and x ≈ -0.928.

To find the inflection points of f(x) = sin (3x + 5), we need to take the second derivative of the function and set it equal to zero.

f(x) = sin (3x + 5)

f'(x) = 3cos(3x + 5)

f''(x) = -9sin(3x + 5)

Setting f''(x) = 0 and solving for x:

-9sin(3x + 5) = 0

sin(3x + 5) = 0

3x + 5 = nπ, where n is an integer

x = (nπ - 5)/3

These are the potential inflection points. To determine if they are actual inflection points, we need to check the sign of f''(x) around each point.

Consider x = (nπ - 5)/3.

For x < (nπ - 5)/3, we have

3x + 5 < nπ

3x + 5 + 2π < (n+2)π

sin(3x + 5 + 2π) = sin(3x + 5)

cos(3x + 5 + 2π) = cos(3x + 5)

Therefore, f''(x) = -9sin(3x + 5) changes sign from positive to negative as x passes through (nπ - 5)/3, so this is an inflection point.

Checking with desmos, we see that there are two inflection points:

x ≈ -3.363, x ≈ -0.928

Therefore, the inflection points of f(x) = sin (3x + 5) are x ≈ -3.363 and x ≈ -0.928.

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The angles in degrees are

180 degrees

90 degrees

90 degrees

90 degrees

270 degrees

180 degrees

What is Rotation in Transformation?

In mathematical terminology, rotation is a special kind of transformation that implicates rotating an item about a designated point or an axis.

During the rotational process, each individual point of the item moves in a manner resembling a circular pattern around the constant point or axis. The space between these entities remains static; yet, the angle between them varies.  

Rotation can be either clockwise or counterclockwise, and is typically measured in degrees or radians.

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The value of the principal investment would be = $12,500.75

We know that,

A principal investment is defined as the capital amount of money that is being deposited into an account with the purpose of receiving interest for a particular period of time.

The years of investment (t) = 9 years

The annual interest rate (r) = 3.9% = 3.9/100= 0.039

The total worth of the investment (A) = $17,757.16

Then, solve the equation for P

P = A / ert

P = 17,757.16 / e(0.039*9)

P = $12,500.75

Therefore, the principal amount that is needed which can be compounded continuously to get the total amount given = $12,500.75

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complete question:

After 9 years in an account with a 3.9% annual interest rate compounded continuously, an investment is worth a total of $17,757.16. What is the value of the principal investment? Around the answer to the nearest penny.

According to Markov chain,

a) The limiting fraction of time that the chain spends at the state 1 is 3/7.

b) Pⁿ(1,1) converges as n tends to infinity, and the limiting value is the steady-state probability of being in state 1, which we have already calculated to be 3/7.

(i) To find the limiting fraction of time that the chain spends at the state 1, we need to find the steady-state probability of being in state 1. The steady-state probability of being in state i is the probability that the chain is in state i in the long run, i.e., as n tends to infinity, where n is the number of steps in the chain.

To find the steady-state probability, we need to solve the following system of equations:

π1 = π1(1+1) + π4(1)

π2 = π1(1+1)

π3 = π2(1+1)

π4 = π3(1+1)

where πi is the steady-state probability of being in state i. Solving these equations, we get π1 = 3/7, π2 = 2/7, π3 = 1/7, and π4 = 1/7.

(ii) To find whether Pⁿ(1,1) converges as n tends to infinity, we need to check if the chain is irreducible and aperiodic. A Markov chain is irreducible if it is possible to go from any state to any other state in a finite number of steps. A Markov chain is aperiodic if the chain does not have a regular pattern in the sequence of steps it takes to return to a state.

In this case, the Markov chain is irreducible and aperiodic since we can go from any state to any other state in a finite number of steps, and there is no regular pattern in the sequence of steps it takes to return to a state.

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The standard deviation for the random variable X will be 1.5811.

The number of twos that come up in 18 rolls of a die is a binomial random variable, denoted by X, with parameters n=18 and p=1/6 (since the probability of rolling a two on any one roll is 1/6).

The mean of a binomial distribution is given by μ = np, and the variance is given by σ^2 = np(1-p). Thus, in this case, we have:

μ = np = 18 × 1/6 = 3

σ^2 = np(1-p) = 18 × 1/6 × (1 - 1/6) = 2.5

The standard deviation is the square root of the variance, so:

σ = √(2.5) = 1.5811 (rounded to four decimal places)

Therefore, if this experiment is repeated many times, we would expect the number of twos to have a mean of 3 and a standard deviation of approximately 1.5811.

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A hypothesis is a tentative explanation that predicts the relationship between two or more variables to be tested, whereas a theory is a more general and established explanation that predicts future outcomes.

A hypothesis is a statement or proposition that is assumed to be true in order to prove or disprove a theorem or conjecture through logical reasoning and mathematical proof.

A theory is a systematic and coherent set of concepts, principles, and mathematical models that explain a wide range of related phenomena and make predictions that can be tested and verified through experimentation or observation.

According to the given information:

In scientific research, a hypothesis is a specific prediction or statement that proposes a possible relationship between two or more variables, which can be tested through experimentation or observation. It is a tentative explanation that seeks to explain an observed behavior or phenomenon, and it can be used to guide future research and experimentation.

On the other hand, a theory is a more general and comprehensive explanation of an observed behavior or phenomenon that has been tested and supported by numerous experiments and observations. A theory can be thought of as a well-established and widely accepted explanation that can be used to predict future outcomes and guide further research.

To summarize, a hypothesis is a specific prediction that can be tested through experimentation or observation, while a theory is a more general and established explanation that has been supported by numerous experiments and observations.

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We can conclude that the one-sided 95% lower confidence interval for the probability of a missile hitting its target is 0 to 1, which is not a very useful or informative result.

To find the confidence interval, we first need to calculate the sample proportion, which is the number of successes (missiles that hit the target) divided by the total number of trials (missiles fired). In this case, all four missiles hit the targets, so the sample proportion is 4/4 = 1.

Next, we use the formula for calculating a confidence interval for a proportion:

p ± zα/2 * √(p(1-p)/n)

where p is the sample proportion, zα/2 is the critical value from the standard normal distribution corresponding to the desired level of confidence (in this case, 95%), and n is the sample size.

Since we are looking for a lower confidence interval, we can use a one-sided normal distribution instead of a two-sided distribution. In this case, the critical value is -1.645, which we can find using a standard normal distribution table or a calculator.

Plugging in the values, we get:

1 - 1.645 * √((1*0)/4) ≤ p ≤ 1

Simplifying the expression, we get:

0 ≤ p ≤ 1

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Answer: The slope of the line is 7

Step-by-step explanation:

y=mx+b, in this m is always the slope

So in y=7x+16, 7 is the slope

The differentiation of the given function is [tex]\frac{dx}{dy} =\frac{ (sec^2(x+y) - x - 2y)}{  (y - sec^2(x+y))}[/tex]

Given the equation[tex]xy + y^2 = tan(x+y)[/tex], we want to find the derivative[tex]dx/dy.[/tex]

First, let's differentiate both sides of the equation with respect to y:

[tex]\frac{d(xy)}{dy} +\frac {d(y^2)}{dy} =\frac {d(tan(x+y))}{dy}[/tex]

Using the product rule for the first term and the chain rule for the last term, we get:

(x * dy/dy + y * dx/dy) + 2y = (sec^2(x+y)) * (dx/dy + 1)

Since dy/dy = 1, we can simplify the equation to:

[tex]x + y *\frac{ dx}{dy} + 2y = (sec^2(x+y)) * (\frac{dx}{dy} + 1)[/tex]

Now, we want to solve for dx/dy:

[tex]y * \frac{dx}{dy} - (sec^2(x+y)) * \frac{dx}{dy} = (sec^2(x+y)) - x - 2y[/tex]

Factor out dx/dy:

[tex]dx/dy * (y - sec^2(x+y)) = sec^2(x+y) - x - 2y[/tex]
Finally, divide both sides by[tex](y - sec^2(x+y))[/tex]to isolate dx/dy:

[tex]\frac{dx}{dy} =\frac{ (sec^2(x+y) - x - 2y)}{  (y - sec^2(x+y))}[/tex]

And that's your answer!

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If the perimeter of the smaller polygon is 48 centimeters and the ratio of the corresponding side lengths is 2:3, the perimeter of the larger polygon is 72 centimeters.

If two polygons are similar, it means that their corresponding angles are congruent and their corresponding sides are proportional. Let's denote the perimeter of the larger polygon as P.

Since the ratio of the corresponding side lengths is 2:3, we can set up the following proportion:

2/3 = perimeter of smaller polygon / perimeter of larger polygon

Solving for the perimeter of the larger polygon, we get:

perimeter of larger polygon = (3/2) x perimeter of smaller polygon

perimeter of larger polygon = (3/2) x 48

perimeter of larger polygon = 72

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Repeat the process for different combinations of n and p values to explore the performance of the normal approximation under various scenarios.

To evaluate how well a normal distribution can approximate a binomial distribution using simulation, you can follow these steps:

1. Choose a combination of n (number of trials) and p (probability of success) from the given sets: n ∈ {10, 50, 100, 200} and p ∈ {0.01, 0.1, 0.5}.

2. Generate 100 samples of binomial distributions using the chosen n and p values: X ~ Binomial(n, p).

3. Calculate T for each sample using the formula[tex]T = Vn(X/n - p),[/tex] where[tex]Vn= \sqrt{(n / p(1 -p))[/tex]. This will result in a transformation that should approximate N(0, p(1 – p)) if n is large.

4. Perform the Kolmogorov-Smirnov test (ks.test) to compare the empirical distribution of T with the theoretical normal distribution N(0, p(1 – p)). The null hypothesis is that the two distributions are the same, and the alternative hypothesis is that they are different.

5. Check the p-value obtained from the Kolmogorov-Smirnov test. If the p-value is less than the significance level (α = 0.05), you can reject the null hypothesis and conclude that the deviation of T from N(0, p(1 – p)) can be detected. If the p-value is greater than α, you cannot reject the null hypothesis, and the normal distribution approximation is considered valid.

6. Repeat the process for different combinations of n and p values to explore the performance of the normal approximation under various scenarios.

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At a significance level of 0.03, the critical value is 1.711 (found using a t-distribution table with degrees of freedom equal to 20 and a significance level of 0.015). Since the calculated test statistic (2.568) is greater than the critical value, we reject the null hypothesis at a significance level of 0.03.

The degrees of freedom for the unequal variance test can be calculated using the formula:

[tex]df = [(s1^2/n1 + s2^2/n2)^2] / [((s1^2/n1)^2)/(n1-1) + ((s2^2/n2)^2)/(n2-1)][/tex]

Substituting the given values, we get:

[tex]df = [(15^2/27 + 9^2/15)^2] / [((15^2/27)^2)/(27-1) + ((9^2/15)^2)/(15-1)][/tex]

= 20.37

≈ 20 (rounded down to nearest whole number)

The decision rule for the 0.025 significance level and a right-tailed test is to reject the null hypothesis if the test statistic exceeds the critical value. The critical value can be found using a t-distribution table with degrees of freedom equal to 20 and a significance level of 0.025. From the table, we find the critical value to be 1.734.

The test statistic for the two-sample t-test with unequal variances can be calculated using the formula:

[tex]t = (x1 - x2) / sqrt(s1^2/n1 + s2^2/n2)[/tex]

Substituting the given values, we get:

[tex]t = (114 - 106) / sqrt(15^2/27 + 9^2/15)[/tex]

= 2.568

Using a significance level of 0.025 and degrees of freedom equal to 20, the critical value is 1.734. Since the calculated test statistic (2.568) is greater than the critical value, we reject the null hypothesis.

At a significance level of 0.03, the critical value is 1.711 (found using a t-distribution table with degrees of freedom equal to 20 and a significance level of 0.015). Since the calculated test statistic (2.568) is greater than the critical value, we also reject the null hypothesis at a significance level of 0.03. Therefore, we can conclude that there is evidence to suggest that the population mean of the first population is greater than that of the second population.

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Sierra can select 1 of each item to accessorize her outfit in 384 ways.

The number of ways Sierra can  elect one belt from 8 belts is 8. The number of ways she can  elect one handbag from 4 handbags is 4. And the number of ways she can  elect one choker from 12 chokers is 12. thus, the total number of ways Sierra can  elect one of each item is   Total number of ways =  8 x 4 x 12 =  384  

This means that Sierra has 384 different options to choose from when  opting  accessories to  round  her outfit. This gives her a wide range of choices to  produce a unique and  swish look that suits her  particular taste and preferences.  

In conclusion, the  addition rule of counting is an essential principle in combinatorics and provides a simple way to calculate the total number of  issues in a given situation. In this case, we used the  addition rule to determine the total number of ways Sierra could  elect one belt, one handbag, and one choker to accessorize her outfit.

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Answer:  66% of 110 is 72.6

Step-by-step explanation:

Because i said so

Answer: did u find out the answer yet

Step-by-step explanation:

The given series [tex]\sum_{n=1}^{\infty} \frac{\ln(n+2)}{n^2}[/tex] diverges.

To determine if the given series converges or diverges, we can use the partial sums and the nth term test for series.

Partial Sums

The nth partial sum of the given series is denoted by S_n and is given by:

S_n = Σ k=1 to n ln(k+2)/k²

Nth Term Test for Series

The nth term of the given series is denoted by a_n and is given by:

a_n = ln(n+2)/n²

According to the nth term test for series, if the limit of the absolute value of a_n as n approaches infinity is zero, then the series converges. Mathematically, this can be expressed as:

lim (n->∞) |a_n| = 0

Applying the Nth Term Test

Let's calculate the limit of |a_n| as n approaches infinity:

[tex]\lim_{{n \to \infty}} \left| \frac{{\ln(n+2)}}{{n^2}} \right|[/tex]

Using L'Hospital's rule, we can find the limit of the ratio of the natural logarithm and the quadratic function:

[tex]\lim_{{n\to\infty}} \left| \frac{\ln(n+2)}{n^2} \right| = \lim_{{n\to\infty}} \frac{1}{\frac{n+2}{2n}}[/tex]

Now, we can simplify the expression:

[tex]\lim_{{n\to\infty}} \left(\frac{1}{\frac{n+2}{2n}}\right) = \lim_{{n\to\infty}} \left(\frac{2n}{n+2}\right)[/tex]

Applying L'Hospital's rule again, we get:

[tex]\lim_{{n \to \infty}} \left( \frac{2n}{n+2} \right) = \lim_{{n \to \infty}} \left( \frac{2}{1} \right) = 2[/tex]

Since the limit of |a_n| as n approaches infinity is not equal to zero, we can conclude that the series [tex]\sum_{n=1}^{\infty} \frac{\ln(n+2)}{n^2}[/tex]does not converge to a finite value.

Therefore, the given series [tex]\sum_{n=1}^{\infty} \frac{\ln(n+2)}{n^2}[/tex] diverges.

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Answer:

4 people per taxi

Step-by-step explanation:

60 divided by 15

Answer:4

Step-by-step explanation:

Your basically asking what 60 divided by 15 is or how many times can 15 be added to get 60.

15 can be added 4 times before reaching 60 So the anwser for your equation is 4.

The probability of obtaining 4 ones in a row when rolling a fair, six-sided die is 0.00077.

The probability of obtaining a one on any given roll of a fair, six-sided die is 1/6, since there is one outcome corresponding to rolling a one out of a total of six possible outcomes (rolling any one of the numbers 1 through 6).

By the multiplication rule for independent events, we can calculate this probability by multiplying the probabilities of each individual event:

P(rolling four ones in a row) = P(rolling a one on the first roll) × P(rolling a one on the second roll) × P(rolling a one on the third roll) × P(rolling a one on the fourth roll)

P(rolling four ones in a row) = (1/6) × (1/6) × (1/6) × (1/6)

P(rolling four ones in a row) = 1/6^4

P(rolling four ones in a row) = 1/1296

Therefore, the probability of obtaining four ones in a row when rolling a fair, six-sided die is approximately 0.00077, or about 0.077% (rounded to three decimal places).

This probability is very small, which means that it is unlikely to obtain four ones in a row when rolling a die. In fact, it would take an average of 1/0.00077 or about 1296 rolls to obtain four ones in a row.

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Answer: below!

Step-by-step explanation:

9: tan51 = 8/x

x = 8/(tan51) ≅ 6.478

10: sin24 = x/31

.: x = 31sin24 ≅ 12.609

11: You've done it correctly!

12: tanx = 25/78

.: x = [tex]tan^-^1(\frac{25}{78} )[/tex] ≅ 17.77°

15: Correct!

16: sin25 = 15/(XZ)

.: XZ = 15/sin25 ≅ 35.5

Since triangle WXZ is right, the pythagorean theorem tells us that WZ = [tex]\sqrt{22^2 + 35.5^2}[/tex] ≅ 41.76

Now, using the Law of Sines, we can say that sin90/WZ = sinW/XZ

this means 1/41.76 = sinW/35.5

W = [tex]sin^-^1(\frac{35.5}{41.76} )[/tex] ≅ 58.2°

17. Draw this image. You'll see a right triangle, with angles 90-75-15. Since the side adjacent to the 75 deg angle is 6, we can solve for the length of the ladder. in essence:

cos75 = 6/x, where x is the length of the ladder

.: x = 6/cos75 ≅ 23.18 feet

Answer:

The far right graph is correct.

Step-by-step explanation:

Answer:

1.73

Step-by-step explanation:

To find the cost for a 43.25-mile section of highway with a toll of $0.04 per mile, we can simply multiply the number of miles by the toll rate per mile.

Cost = Miles * Toll rate per mile

Given:

Miles = 43.25

Toll rate per mile = $0.04

Plugging in the values into the formula:

Cost = 43.25 * $0.04

Cost = $1.73

The rate at which the surface area is increasing when there are 288pi cubic inches of helium in the balloon is 4 * pi inches^2/second.

We are required to determine the rate at which the surface area of a spherical balloon is increasing when there are 288pi cubic inches of helium in the balloon.

1. First, we need to find the radius (r) of the balloon when the volume is 288pi cubic inches. The formula for the volume (V) of a sphere is:

V = (4/3) * pi * r^3

2. Plug in the given volume and solve for r:

288pi = (4/3) * pi * r^3

(3/4) * (288) = r^3

r = 6 inches

3. Next, we need to find the formula for the surface area (A) of a sphere:

A = 4 * pi * r^2

4. Now, let's differentiate the volume formula and the surface area formula with respect to time (t) to find dV/dt and dA/dt:

dV/dt = 4 * pi * r^2 * dr/dt

dA/dt = 8 * pi * r * dr/dt

5. We are given that the balloon is being filled at a rate of 2 cubic inches per second (dV/dt = 2). We can plug this into the dV/dt formula and solve for dr/dt:

2 = 4 * pi * (6)^2 * dr/dt

dr/dt = 1/36 inches per second

6. Finally, plug in the radius (r = 6) and dr/dt into the dA/dt formula:

dA/dt = 8 * pi * 6 * (1/36)

dA/dt = 4 * pi inches^2/second

So, the rate at which the surface area is increasing is 4 * pi inches^2/second.

Learn more about Surface area:

https://brainly.com/question/16519513

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