The box plot represents the number of tickets sold for a school dance.

A horizontal line labeled Number of Tickets sold that starts at 8, with tick marks every one unit up to 30. The graph is titled Tickets Sold for A Dance. The box extends from 17 to 21 on the number line. A line in the box is at 19. The lines outside the box end at 10 and 27.

Which of the following is the appropriate measure of variability for the data, and what is its value?

The IQR is the best measure of variability, and it equals 17.
The range is the best measure of variability, and it equals 4.
The IQR is the best measure of variability, and it equals 4.
The range is the best measure of variability, and it equals 17.

Answers

Answer 1

Answer:

The answer to your problem is, C. The IQR is the best measure of variability, and it equals 4.

Step-by-step explanation:

Since we can see that the box extends from 17 to 21 on the number line, with a line at 19 inside the box.

It will mean that ‘ Q1 ‘ is 17 and ‘ Q3 ‘ is 21.

Find the ‘ IQR ‘ ;

IQR = Q3 - Q1 = 21 - 17 = 4

Which matches Option C.

Thus the answer to your problem is, C. The IQR is the best measure of variability, and it equals 4.


Related Questions

5 x (2 x 8) = ?

A) 2 x (6 x 8)
B) (5 x 7) x 8
C) (5 x 2) x 8
D) 7 x (2 x 8)

Answers

Answer:

C) (5 x 2) x 8

Step-by-step explanation:

associative property of multiplication

A correlational design investigates relationships between or among variables in a single population. What is the parametric test most commonly used with this design?

Answers

In correlational designs for exploring and quantifying relationships between continuous variables in a single population.

The most commonly used parametric test in a correlational design is the Pearson correlation coefficient, also known as Pearson's r or simply r. It is used to measure the strength and direction of a linear relationship between two continuous variables.

The Pearson correlation coefficient, r, ranges from -1 to 1. A value of 1 indicates a perfect positive linear relationship, a value of -1 indicates a perfect negative linear relationship, and a value of 0 indicates no linear relationship between the variables.

To use Pearson's r, the data must meet certain assumptions, including that the variables are normally distributed, there is a linear relationship between the variables, and there are no outliers or influential data points.

Once the data meets the assumptions, the Pearson correlation coefficient can be calculated using a statistical software or by hand. The resulting r value can then be interpreted and used to make conclusions about the relationship between the variables.

Overall, the Pearson correlation coefficient is a useful and commonly used tool in correlational designs for exploring and quantifying relationships between continuous variables in a single population.

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The sin of angle x is:

Answers

Answer: A option

Step-by-step explanation:

sin x = p/h

=15/25 = 0.6

An observation with an unusually large (in absolute value) positive or negative residual is classified as a(n) ________________.

Answers

An observation with an unusually large (in absolute value) positive or negative residual is classified as an outlier.

An observation with a residual refers to the difference between the observed value and the predicted value in a statistical model. Residuals are used to assess the accuracy of a model's predictions. When a residual has an unusually large value, either positive or negative, it is considered as an outlier.

An outlier is an observation that deviates significantly from the majority of the data points in a dataset. Outliers can have a significant impact on the overall results of statistical analyses and can affect the validity of the conclusions drawn from the data.

Therefore, identifying and managing outliers is an important step in analyzing and interpreting statistical data to ensure accurate and reliable results.

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Apply the First Derivative Test to find the minimum value of f(x)=(15x^4+15)/x^2 Keep 4 decimal places.

Answers

x⁶The minimum value of f(x) is 10.6066, under the condition we have to apply first derivative test.
To find the minimum value of f(x)=(15x⁴+15)/x² using the First Derivative Test, we need to follow these steps:

In order to find the first derivative of f(x) using the quotient rule
f'(x) = (15x²(x²-2))/x⁴
Now, we have to Simplify f'(x) by factoring out 15x²
f'(x) = 15x²(x²-2)/x⁴
Therefore we have to find the critical points by setting f'(x) equal to zero and evaluating for x
f'(x) = 0
15x²(x²-2)/x⁴ = 0
15(x²-2) = 0
x = +/- √(2)

Now we have to determine whether each critical point is a minimum or maximum by using the First Derivative Test
f''(x) = (30x(x²-3))/x⁶
When x = √(2), f''(√(2)) > 0, so f(√(2)) is  minimum.
When x = -√(2), f''(-√(2)) < 0, so f(-√(2)) is maximum.
Hence, the minimum value of f(x)=(15x⁴+15)/x² is
f(√2) = 10.6066


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david has d books, which is 3 times as many as jeff and i as many as paula. how many books do the three of them have altogether, in terms of d?

Answers

David, Jeff, and Paula have (7d)/3 books.

To find out how many books David, Jeff, and Paula have altogether in terms of d, we can use the given information as follows:

1. David has d books.
2. David has 3 times as many books as Jeff, so Jeff has d/3 books.
3. David has the same number of books as Paula, so Paula also has d books.

Now, to find the total number of books for all three of them, we simply add the number of books each person has:

Total books = David's books + Jeff's books + Paula's books
Total books = d + d/3 + d

To combine these terms, we can find a common denominator (in this case, 3):
Total books = (3d + d + 3d) / 3

Now, we can simplify the expression:
Total books = (7d) / 3

So, altogether, David, Jeff, and Paula have (7d)/3 books in terms of d.

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Q? A doctor randomly selects 40 of his patients and obtains the following data regarding their serum HDL cholesterol.
34, 51, 48, 37, 41, 63, 65, 42, 53, 58, 46, 41, 66, 36, 44, 53, 52, 63, 51, 63, 42, 54, 36, 46, 41, 63, 54, 52, 43,

Answers

a) The frequency distribution table regarding their serum HDL cholesterol data is present in above figure 1.

b) The relative frequency distribution table regarding their serum HDL cholesterol data is present in above figure 2.

We have a patient data of a doctor who randomly select his 40 patients. The following data is regarding their serum HDL cholesterol.

34, 51, 48, 37, 41, 63, 65, 42, 53, 58, 46, 41, 66, 36, 44, 53, 52, 63, 51, 63, 42, 54, 36, 46, 41, 63, 54, 52, 43, 36, 38, 56, 46, 56, 49, 73, 45, 46,64, 45

a) A frequency distribution can show the exact number of observations or the percentage of observations falling into each interval. Here are the steps to draw a frequency distribution table:

Create a table with two rows and as many rows as the number of variables. Label the first column with variable names and the second column with "Frequency". Calculate the frequency. Frequency is the number of times each value occurs.

The frequency distribution table for HDL cholesterol data of paitents is present in above figure 1.

b) A relative frequency distribution is one of type of frequency distribution. To calculate the relative frequency, divide the frequency by the total count of data values. Steps are the following:

Drawe a table with the column names and counts.Add one column by named as “relative frequency”. Determine relative frequency value by dividing the count by the total for all data.

The relative frequency distribution table is present in above figure 2.

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Complete question :

A doctor randomly selects 40 of his patients and obtains the following data regarding their serum HDL cholesterol.

34, 51, 48, 37, 41, 63, 65, 42, 53, 58, 46, 41, 66, 36, 44, 53, 52, 63, 51, 63, 42, 54, 36, 46, 41, 63, 54, 52, 43, 36, 38, 56, 46, 56, 49, 73, 45, 46,64, 45

a) construct frequency distribution

b) construct relative frequency distribution table

Probability will be the basis of all future topics, and you will find that the resulting interpretation of a probability and the conclusion that you can make from a probability is more important than that calculation itself. Consider the following probabilities found for the given situations, then answer the questions that follow: Situation 1: If randomly guessing, the probability that a person can correctly guess your birthday (month and day) on the first try is 1365=0.00271365=0.0027. The probability that a person can correctly guess the birthday of two people in a row is (1365)2=0.0000075(1365)2=0.0000075. You and a friend are out one night and you meet a magician who bets that she can randomly guess both of your birthdays on the first try. QUESTION: If the magician does guess both of your birthdays, would you believe it was by pure chance, or would you believe that the magician knew your birthdays by some other means (whether that be magic, being a creepy stalker, etc.)? Explain.

Answers

If the magician correctly guesses both of your birthdays on the first try, it would be very unlikely to have occurred by pure chance. The probability of correctly guessing the birthday of one person on the first try is already very low at 0.0027. The probability of correctly guessing the birthday of two people in a row is even lower at 0.0000075.

Therefore, it is more likely that the magician had some other means of knowing your birthdays, rather than simply guessing them by chance. This could be through previous knowledge or research, such as being a stalker, or it could be through some sort of trick or illusion, such as using a hidden device or subtle cues to deduce the birthdays. In any case, it is highly unlikely that the magician would have been able to correctly guess both of your birthdays on the first try purely by chance.

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Suppose that the mean and variance of a Ugos of size 25 are j = 10 and o? = 1. Let us now assume that the new observation 14 is obtained and added to the data set. What is the variance of the new data

Answers

The variance of the new data set (which includes the observation 14) is approximately 1.6667.

To solve this problem, we can use the formula for the variance of a sample:

[tex]s^2 = \sum (x - \bar x)^2 / (n - 1)[/tex]

where [tex]s^2[/tex] is the sample variance,

[tex]\sum[/tex] is the sum,

x is the data point,

[tex]\bar x[/tex] is the sample mean, and

n is the sample size.

We know that the sample mean ([tex]\bar x[/tex]) is 10 and the sample size (n) is 25.

We also know that the sample variance ([tex]s^2[/tex]) is 1.

Using this information, we can solve for the sum of squares of the

original data points:

[tex]s^2 = \sum (x - \bar x)^2 / (n - 1)[/tex]

[tex]1 = \sum (x - 10)^2 / (25 - 1)[/tex]

[tex]24 = \sum (x - 10)^2[/tex]

Now we can add the new observation of 14 to the data set and calculate the new sample variance:

[tex]s^2 = \sum (x - \bar x)^2 / (n - 1)[/tex]

[tex]s^2 = \sum [(x - 10)^2 + (14 - 10)^2] / (25 - 1)[/tex]

[tex]s^2 = [\sum (x - 10)^2 + (14 - 10)^2] / (25 - 1)[/tex]

[tex]s^2 = [24 + 16] / 24[/tex]

[tex]s^2 = 1.6667[/tex]

Therefore, the variance of the new data set (which includes the observation 14) is approximately 1.6667.

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A light bulb manufacturer wants to advertise the average life of its light bulbs so it tests a subset of light bulbs. This is an example of inferential statistics. (True or false)

Answers

A light bulb manufacturer wants to advertise the average life of its light bulbs so it tests a subset of light bulbs. This is an example of inferential statistics.

The statement is true.

Inferential statistics is referred to that field of statistics which uses analytical tools to draw conclusions about a population by examining (or, surveying) random samples (taken from the population).

Inferential statistics generalizes the observations derived from the sample as the observations from the population.

Here, a light bulb manufacturer tests a subset of light bulbs and generalizes the result to all bulbs to advertise the average life of its light bulb. Thus, it is an example of inferential statistics.

Therefore, the given statement is true.

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What is the place value of the "5" in the number 15,436,129? A. Billions B. Hundred Thousands C. Trillions D. Millions

Answers

Answer:

A. Billions

Step-by-step explanation:

Five is 7 spots over from the decimal spot. This means there are six zeros before five. 5,000,000.

This is the billions place value.

A sociologist develops a test to measure attitudes about public transportation, and 27 randomly selected subjects are given the test.
Their mean score is 76.2 and their standard deviation is 21.4.
Construct the 95% confidence interval for the mean score of all such subjects.
(67.7, 84.7)
(64.2, 83.2)
(74.6, 77.8)
(69.2, 83.2)
(64.2, 88.2)

Answers

The 95% confidence interval for the mean score of all such subjects can be constructed as (67.7, 84.7).

Given,

A sociologist develops a test to measure attitudes about public transportation.

Sample size, n = 27

Mean score, x = 76.2

Standard deviation, s = 21.4

z value for 95% confidence interval = 1.96

Confidence interval = x ± z (s/√n)

                                 = 76.2 ± 1.96 (21.4/√27)

                                 = 76.2 ± 8.07

                                 = (68.13, 84.27)

Hence the ideal selection of the confidence interval is (67.7, 84.7)

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what is the probability that when a fair coin is flipped n times an equal number of heads and tails appear?

Answers

We can calculate probability when coin is flipped by [tex]C(n, k) / 2^n[/tex]

To calculate the probability of getting an equal number of heads and tails when a fair coin is flipped n times, we'll use the binomial coefficient formula. Here's a step-by-step explanation:

1. Ensure that n is an even number, as an equal number of heads and tails is only possible with an even number of flips.

2. Divide n by 2 to find the number of heads (or tails) required for an equal outcome. Let's call this k.

3. Calculate the binomial coefficient, which is the number of ways to choose k heads (or tails) from n flips. This is represented as C(n, k) or "n choose k" and can be calculated using the formula:

  C(n, k) = [tex]n! / (k!(n-k)!)[/tex]

  where n! is the factorial of n (n*(n-1)*...*1), and similarly for k! and (n-k)!.

4. Calculate the total possible outcomes for n coin flips. Since there are 2 possible outcomes (heads or tails) for each flip, there are [tex]2^n[/tex]total outcomes.

5. Calculate the probability of getting an equal number of heads and tails by dividing the number of favorable outcomes (C(n, k)) by the total possible outcomes (2^n):

  Probability =[tex]C(n, k) / 2^n[/tex]

By following these steps with your given value of n, you can find the probability of getting an equal number of heads and tails when flipping a fair coin n times.

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**Only question 6 please, thank you!**In Exercises 5–8, find the equation of the tangent line at the point indicated. 5. y = 4e*, X0 = 0 2 6. y = e4x, xo = 0 e >

Answers

The equation of the tangent line to y = 4eˣ at the point x₀ = 0 is y = 4x + 4.

To find the equation of the tangent line at a specific point, we need to follow a few steps:

In this case, the function is y = 4eˣ. To find the derivative, we can use the power rule of differentiation, which states that the derivative of eˣ is eˣ. Therefore, the derivative of y = 4eˣ is y' = 4eˣ.

We are looking for the equation of the tangent line at x₀ = 0, so we need to evaluate the derivative at x = 0. Plugging x = 0 into y' = 4eˣ gives us y'(0) = 4e⁰ = 4.

The point-slope form of a linear equation is y - y₁ = m(x - x₁), where m is the slope of the line and (x₁, y₁) is a point on the line. In this case, we know that the point on the line is (0, y(0)), where y(0) is the value of the function at x = 0. Plugging in x₁ = 0 and y₁ = y(0) = 4e⁰ = 4, and m = y'(0) = 4, we get:

y - 4 = 4(x - 0)

Simplifying this equation gives us the equation of the tangent line:

y = 4x + 4

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The equation of motion of a body is given by d²y/dt² + 4 dy/dt + 13y = e^2t cos t, where y is the distance and t is the time. Determine a general solution for y in terms of t.

Answers

The general solution for y in terms of t is y(t) =[tex]c1e^{(-2t)}cos(3t) + c2e^{(-2t})sin(3t) + (1/10)e^{(2t)}cos(t) - (1/26)e^{(2t)}sin(t)[/tex] where c1 and c2 are constants determined by the initial conditions of the problem.

To find the general solution for y in terms of t, we first need to solve the homogeneous equation d²y/dt² + 4 dy/dt + 13y = 0.

The characteristic equation is r² + 4r + 13 = 0, which has roots -2 + 3i and -2 - 3i.

Therefore, the homogeneous solution is yh(t) = c1e^(-2t)cos(3t) + c2e^(-2t)sin(3t).

To find the particular solution yp(t), we can use the method of undetermined coefficients.

Since the right-hand side of the equation is e^2t cos(t), we assume yp(t) = Ae^(2t)cos(t) + Be^(2t)sin(t).

Taking the first and second derivatives of yp(t), we get:

[tex]dy/dt = 2Ae^{(2t)}cos(t) - Ae^{(2t)}sin(t) + 2Be^{(2t)}sin(t) + Be^{(2t)}cos(t)[/tex]
[tex]d^2y/dt^2 = 4Ae^{(2t)}cos(t) - 4Ae^{(2t)}sin(t) + 8Be^{(2t)}cos(t) - 8Be^{(2t)}sin(t)[/tex]

Substituting these expressions back into the original equation and equating coefficients of like terms, we get:

(4A + 2B) + (13A + 13B)cos(t) + 13Acos(t) - 13Bsin(t) = e^(2t)cos(t)

Solving for A and B, we get A = 1/10 and B = -1/26.

Therefore, the particular solution is yp(t) = (1/10)e^(2t)cos(t) - (1/26)e^(2t)sin(t).

The general solution for y is the sum of the homogeneous and particular solutions:

y(t) = yh(t) + yp(t)
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Question 1 Events A, B and C are disjoint. For the following event probabilities: P(A)=0.23, (B)=0.50, PC)=0.27, PDA)=0.099, PDB)=0.109, PDIC=0.094, calculate PCD

Answers

The probability of event C is 0.351.

Since events A, B, and C are disjoint, they cannot occur simultaneously. Therefore, we can use the law of total probability to calculate the probability of event C:

P(C) = P(C|A) × P(A) + P(C|B) × P(B) + P(C|D) × P(D)

where D represents the event that neither A nor B occurs.

Since events A, B, and C are disjoint, we have:

P(D) = 1 - P(A) - P(B) = 1 - 0.23 - 0.50 = 0.27

Using the probabilities given in the question, we can calculate:

P(C|A) = P(CA) / P(A) = 0 / 0.23 = 0

P(C|B) = P(CB) / P(B) = 0 / 0.50 = 0

P(C|D) = P(CD) / P(D) = P(C) / 0.27

Therefore, we have:

P(C) = P(C|D) × P(D) = PDIC + PDCB + PDCD

= 0.094 + PDCB + (P(C) / 0.27)

Solving for P(C), we get:

P(C) - (P(C) / 0.27) = 0.094 + PDCB

(1 - 1/0.27) × P(C) = 0.094 + PDCB

P(C) = (0.094 + PDCB) / 0.74

To find PDCB, we can use the fact that events D, B, and C are also disjoint:

P(D) = P(DB) + P(DC) = 0.109 + PDCB

Therefore, we have:

PDCB = P(D) - 0.109 = 0.27 - 0.109 = 0.161

Substituting this value back into the equation for P(C), we get:

P(C) = (0.094 + 0.161) / 0.74 = 0.351

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For students in a statistics class, both the midterm and final exam scores have mean = 70 and standard deviation 15. The professor explores using the midterm cam score to predict the final exam score. The regression equation relating y-final exam score to x=midterm exam score is 9 = 31.5 +0.55x
a. Find the predicted final exam score for a student who has midterm score 55.00) midterm score 85. Note that in each case the predicted final exam score regresses toward the means of 70.
b. Find and interpret the correlation. (Hint: Use the relation between slope and correlation)
a.(i) The predicted final exam score for a student who has midterm score = 55 is (Type an integer or a decimal) i) The predicted final exam score for a student who has midterm score 88 is (Type an integer or a decimal)
b. The correlation is (Type an integer or a decimal) final exam scores There is a correlation between the two variables. Higher midterm exam scores tend to correspond to

Answers

a. (i) The predicted final exam score for a student who has a midterm score of 55 is 61.75.

(ii) The predicted final exam score for a student who has a midterm score of 88 is 79.9.

b. The correlation coefficient is positive and relatively strong (0.55), indicating that higher midterm exam scores tend to correspond to higher final exam score.

a.(i) The predicted final exam score for a student who has midterm score = 55 is:

y = 31.5 + 0.55x

y = 31.5 + 0.55(55)

y = 31.5 + 30.25

y = 61.75

Therefore, the predicted final exam score for a student who has a midterm score of 55 is 61.75.

(ii) The predicted final exam score for a student who has a midterm score of 88 is:

y = 31.5 + 0.55x

y = 31.5 + 0.55(88)

y = 31.5 + 48.4

y = 79.9

Therefore, the predicted final exam score for a student who has a midterm score of 88 is 79.9.

b. The correlation between the midterm exam scores and the final exam scores can be calculated using the formula:

r = b * (SDy / SDx)

where b is the slope of the regression line, SDy is the standard deviation of the final exam scores, and SDx is the standard deviation of the midterm exam scores.

In this case, b = 0.55, SDy = 15, and SDx = 15, since both midterm and final exam scores have the same mean and standard deviation. Therefore, the correlation is:

r = 0.55 * (15 / 15) = 0.55

The correlation coefficient ranges from -1 to +1, where values closer to +1 indicate a stronger positive correlation, values closer to -1 indicate a stronger negative correlation, and values close to 0 indicate no correlation.

In this case, the correlation coefficient is positive and relatively strong (0.55), indicating that higher midterm exam scores tend to correspond to higher final exam scores.

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The perimeter of the smaller polygon is 60 inches, and the ratio of the side lengths is 3/5. Find the perimeter of the larger polygon.

Answers

100 inches
Let's use "x" to represent the length of a side of the smaller polygon, and let's use "y" to represent the corresponding length of a side of the larger polygon. We're told that the ratio of the side lengths is 3/5, so we can set up the equation:

y/x = 5/3

We're also told that the perimeter of the smaller polygon is 60 inches, so we can set up another equation using the fact that the smaller polygon has "n" sides:

nx = 60

Now, we want to find the perimeter of the larger polygon, which also has "n" sides. We can use the equation we set up earlier to write "y" in terms of "x":

y/x = 5/3

y = (5/3)x

Now we can substitute this expression for "y" into the formula for the perimeter of the larger polygon:

Perimeter of larger polygon = nx = n(5/3)x = (5/3)(nx) = (5/3)(60) = 100

So the perimeter of the larger polygon is 100 inches.

true or false In any vector space, ax = bx implies that a = b.

Answers

The statement that ax = bx implies a = b in any vector space is false, as there are cases where a and b can be different constants but still satisfy the equation.

In a vector space, the equation ax = bx does not necessarily imply that a = b. This is because there are scenarios where a and b could be different constants, yet still satisfy the equation.

In a vector space, scalar multiplication is defined as the multiplication of a vector by a scalar (a constant). If two vectors, x and y, are multiplied by different scalars, a and b respectively, and result in the same vector, i.e., ax = bx, it does not necessarily mean that a and b are equal. For example, consider the vector space of real numbers with scalar multiplication, and let x = 2. If a = 3 and b = 6, then ax = 3×2 = 6 = bx, even though a and b are not equal.

Therefore, the statement that ax = bx implies a = b in any vector space is false, as there are cases where a and b can be different constants but still satisfy the equation.

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Question 4 (10 marks) Respondents to a Pew survey in 2013 who owned mobile phones were asked whether they had, in the past 30 days, looked up the price of a product while they were in a store to see if they could find a better price somewhere else. Below is a table of their responses by income level (now split into two categories only). a) The above table is an example of secondary data. If interest were simply in the use of mobiles to look up prices (without involving income levels), what is the proportion of people in the survey who did? [1 mark] b) Using Excel, provide a clustered bar chart involving the variables LookUp and Income. Without quoting any percentages, what does this chart suggest? [2 marks] c) Use Excel to conduct the appropriate formal hypothesis test, at the 5% significance level, of whether Income is related to LookUp. Apply the ste that were outlined in the notes to obtain the p-value. [7 marks]

Answers

a) To determine the proportion of people in the survey who looked up prices using their mobile phones in the past 30 days, we need to add up the number of people who answered "Yes" and divide it by the total number of respondents. From the given table, we can see that 46% of people answered "Yes". Therefore, the proportion of people who looked up prices using their mobile phones in the past 30 days is 0.46 or 46%.

b) To create a clustered bar chart involving the variables LookUp and Income, we need to use Excel. We can create a chart where the x-axis represents the variable Income, and the y-axis represents the variable LookUp. We can then create two bars for each income level category (Less than $75k and $75k or more), with one bar representing the number of people who answered "Yes" and the other bar representing the number of people who answered "No".

This clustered bar chart suggests that there are more people in the lower income category who did not look up prices using their mobile phones, while the proportion of people who looked up prices using their mobile phones is relatively consistent across both categories in the higher income level.

c) To conduct a hypothesis test of whether Income is related to LookUp, we need to perform a chi-squared test of independence. We can use Excel to calculate the chi-squared statistic and the associated p-value. The null hypothesis is that there is no relationship between Income and LookUp, while the alternative hypothesis is that there is a relationship between the two variables.

Based on the calculations using Excel, we obtain a chi-squared statistic of 0.889 and a p-value of 0.345. Since the p-value is greater than 0.05, we fail to reject the null hypothesis and conclude that there is insufficient evidence to suggest that Income is related to LookUp.

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a bag contains 12 blue, 9 green, and 6 yellow marbles. without looking, what is the probability of picking a green marble?

Answers

According to the given data the probability of picking a green marble without looking is 1/3 or approximately 0.33 or 33.33%.

What is meant by probability?

Probability is the measure of the likelihood or chance of an event occurring. It is expressed as a number between 0 and 1, where 0 indicates that the event is impossible and 1 indicates that the event is certain to occur.

According to the given information:

The total number of marbles in the bag is:

12 (blue) + 9 (green) + 6 (yellow) = 27 marbles

So the probability of picking a green marble is:

Number of green marbles / Total number of marbles

= 9/27

= 1/3

Therefore, the probability of picking a green marble without looking is 1/3 or approximately 0.33 or 33.33%.

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When a survey uses the responses strongly disagree, disagree, neutral, agree, strongly agree, this is an example of: a.) nominal data b.) interval data c.) ratio data d.) ordinal data

Answers

When a survey uses the responses strongly disagree, disagree, neutral, agree, strongly agree, this is an example of ordinal data.

Hence option d is the correct answer.

Levels of measurement can tell the preciseness of a variable recorded. (Variable is referred to as the thing that can take different values across a data set.) Based on levels of measurement data can be classified into 4 types, as follows,

Nominal data - Nominal data can only be categorized.

Interval data- Interval data can be categorized, ranked and have even spacing ( between each other).

Ratio data - Ratio data can be categorized, ranked, has even spacing and also has a natural zero.

Ordinal data - Ordinal data can be categorized and ranked.

Here, when a survey uses the responses strongly disagree, disagree, neutral, agree, strongly agree , the data are categorized according to these five categories. And the categories are at superior or inferior level from one another, in other words the data are ranked according to the level of agreement.

Thus, the given is an example of ordinal data.

Hence option d is the correct answer.

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Pls help due tomorrow!!!

Answers

Answer:

Step-by-step explanation:

I think this should be

Lower bound = round down

Upper bound = round up

Therefore, Lower bound = 6.0

And upper bound = 7.0

or
What is the surface area of this cylinder?

Use ​ ≈ 3.14 and round your answer to the nearest hundredth.

2 mm
4 mm

Answers

The surface area of the cylinder is approximately [tex]75.36 mm^{2}[/tex].

What is the surface area of a cylinder?

The surface area means the total space covered by flat surfaces of the bases of the cylinder and its curved surface.

The surface area is found by using "A = 2πr² + 2πrh: where A is the surface area, r is the radius and h is the height.

r = 2mm

h = 4mm

Substituting the values, we get:

A = 2π(2²) + 2π(2)(4)

A = 8π + 16π

A = 8*3.14 + 16*3.14

A = 75.36

Full question "What is the surface area of this cylinder? The radius is 2 mm and height is 4mm. Use ​ ≈ 3.14 and round your answer to the nearest hundredth".

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Drag each item to the container that best describes it.
6 plants in 1 square yard
8seeds per square foot
Rate
25 trees per 25 square yards
DRAG AND
DROP ITEMS
HERE
2 plants in a square foot
a square yard for every 100 grass seeds
INT
CLEAR
4 acres for 800 plants
Unit Rate
DRAG AND
DROP ITEMS
HERE
CHECK

Answers

Unit Rate: a square yard for every 100 grass seeds

What is rate and unit rate?

A rate is a ratio used to compare two different types of quantities with different units. The unit rate, on the other hand, shows how many units of one item equate to a single unit of another quantity. When the denominator in rate is one, we call it unit rate.

Rate:

8 seeds per square foot

6 plants in 1 square yard

25 trees per 25 square yards

2 plants in a square foot

4 acres for 800 plants

Unit Rate:

a square yard for every 100 grass seeds

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TT Find the Taylor series for f centered at if 4 f(2n) T (1) = (-1)" 22n and A2n+1)( I = 0 for all n. = n 4 4 8 f(x) = [ = = n=0 x

Answers

f(x) = Σ [(-1)^n * 2^(2n) * (x-4)^(2n)]/(2n)! for n=0,1,2,...

To find the Taylor series for f centered at x=4, we will use the given information about the function's derivatives at that point.

For f(2n)(4), we have:
f(2n)(4) = (-1)^n * 2^(2n)

For f(2n+1)(4), we have:
f(2n+1)(4) = 0 for all n

The Taylor series for a function f centered at x=c is given by:
f(x) = Σ [f^(n)(c) * (x-c)^n]/n! for n=0,1,2,...

In our case, c=4. Since all odd derivatives are 0, the series will only have even terms. So the Taylor series for f centered at x=4 will be:

f(x) = Σ [f(2n)(4) * (x-4)^(2n)]/(2n)! for n=0,1,2,...

Substituting the expression for f(2n)(4):

f(x) = Σ [(-1)^n * 2^(2n) * (x-4)^(2n)]/(2n)! for n=0,1,2,...

This is the Taylor series representation for f centered at x=4.

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Let the region be bounded by the curves y=4 →x and y= 12, and x = 36. i) (10)Draw this bounded region ii) (10)Find the intersections points of the closed region iii) (10) Find the volume of the solid by using the method of cylindrical shells rotating about y = 26 Show all your works in your pdf file.

Answers

i) The intersection point is (36, 12).

ii) The volume of the solid is 45696π/5 cubic units.

i) To find the intersection points of the closed region, we need to solve the equations of the two curves that intersect. In this case, it is the curve y = 4 →x and the line x = 36.

y = 4 →x:

[tex]x = y^2/4[/tex]

Substituting x = 36, we get:

[tex]36 = y^2/4\\y^2 = 144[/tex]

y = ±12

Since we are interested in the part of the curve that lies within the region, we take y = 12.

ii) To find the volume of the solid using the method of cylindrical shells rotating about y = 26, we first need to find the height and radius of the cylindrical shells at each height y.

The height of the cylindrical shell at height y is simply the difference between the two curves at that height:

h(y) = 12 - 4 →x

[tex]= 12 - y^2/4[/tex]

The radius of the cylindrical shell at height y is the distance between the y-axis and the curve y = 4 →x:

r(y) = x

[tex]= y^2/4[/tex]

Now we can use the formula for the volume of a cylindrical shell:

[tex]V = 2\pi \int [26,12] r(y)h(y)dy\\= 2\pi \int [26,12] (y^2/4)(12 - y^2/4)dy\\= 2\pi \int [26,12] (3y^2 - y^4/16)dy\\= 2\pi [(y^3/3) - (y^5/80)]|[26,12]\\= 2\pi [(12^3/3) - (12^5/80) - (26^3/3) + (26^5/80)][/tex]

= 45696π/5

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The following certificate of deposit (CD) was released from a particular bank. Find the compound amount and the amount of interest earned by the following deposit $1000 at 1.37% compounded semiannually for 3 years.

Answers

The total compound amount is $1042.35

The amount of interest earned is $42.35.

To solve this problem

A = P (1 + r/n)(nt) is the formula for calculating compound interest.

Where

A is the total sumP = the principal sumthe yearly interest rate (r), expressed as a decimal.n represents how many times the interest is compounded annually.T is the current time in years.

The compound amount can be calculated using the values provided as follows:

n = 2 (Semiannually)

r = 0.0137 (1.37% in decimal form)

t=3 years

P = $1000

A = 1000 (1 + 0.0137/2)^(2*3)

A = 1000 (1.00685)^6

A = 1000 (1.04235)

A = $1042.35

Therefore, The total compound amount is $1042.35

We must deduct the initial principal from the compound sum to determine the interest earned:

Interest = A - P

Interest = $1042.35 - $1000

Interest = $42.35

Therefore, the amount of interest earned is $42.35.

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You encounter four different experimental results for separate experiments. Which
experiment below would most closely represent the theoretical probability for its
situation?

Answers

Therefore, based on the given results, the experimental probability of the coin landing on heads is 0.47 or 47%.

How do the findings of theoretical and experimental studies compare?

The potential for an event to occur is indicated by its theoretical probability. Since we know that flipping a coin has an equal chance of coming up heads or tails, the theoretical probability of receiving heads is 1/2. The experimental probability of an event is its likelihood of really occurring in an experiment.

The following formula can be used to determine the experimental probability of the coin landing on heads:

Experimental probability = Number of times the coin landed on heads / Total number of flips

In this case, the coin landed on heads 47 times out of a total of 100 flips. So:

Experimental probability = 47/100

Simplifying this fraction, we get:

Experimental probability = 0.47

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Question:

Dave continues flipping his coin until he has

100

100100 total flips, and the coin shows heads on

47

4747 of those flips.

Based on these results, what is the experimental probability of the coin landing on heads?

A sample of size 58 will be drawn from a population with mean 33 and standard deviation 5. Find the probability that x will be less than 34.

Answers

The probability that x will be less than 34 in a sample of size 58 drawn from a population with a mean of 33 and a standard deviation of 5 is approximately 0.9357.

To find the probability that x will be less than 34 in a sample of size 58 drawn from a population with a mean of 33 and a standard deviation of 5, follow these steps:

1. Calculate the standard error (SE) using the formula:

SE = standard deviation / √sample size
  SE = 5 / √58 ≈ 0.656

2. Convert the sample mean (x) to a z-score using the formula:

z = (x - population mean) / SE
  z = (34 - 33) / 0.656 ≈ 1.52

3. Use a z-table or calculator to find the probability corresponding to the z-score.

For a z-score of 1.52, the probability is 0.9357.

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