the distribution of raw scores on a chemistry final is approximately normal with mean of about 50 and standard deviation of about 10. what is the probability that a student will have a raw score that is more than 45?

X having a discrete uniform distribution on the integers 1 to 15 have  3V(X) = 168.

The discrete uniform distribution on the integers 1 to 15 means that each of the 15 integers is equally likely to be chosen as the value of X.

The mean or expected value of X is given by the formula:

E(X) = (1+15)/2 = 8

Therefore, the variance of X is given by the formula:

Var(X) = (15^2 - 1)/12 = 56

The standard deviation of X is the square root of the variance:

SD(X) = sqrt(Var(X)) = sqrt(56) = 2sqrt(14)

Finally, we can calculate 3V(X) as:

3V(X) = 3 x Var(X) = 3 x 56 = 168

Therefore, 3V(X) = 168.

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a)To Determine the z-score for the weight of 12.1 oz is  1.04.  b)The mean eight (in oz) is 12.6 oz.

a) To determine the z-score for the weight of 12.1 oz, we can use the formula:

z = (X - μ) / σ

where z is the z-score, X is the value (12.1 oz), μ is the mean weight, and σ is the standard deviation (-0.5 oz). We know that 15.9% of dinners weigh more than 12.1 oz, so we can look up the corresponding z-score in a z-table, which is approximately 1.04.

b) To find the mean weight (μ), we can rearrange the formula above:

μ = X - (z * σ)

Substituting the values we have:

μ = 12.1 - (1.04 * -0.5)
μ = 12.1 + 0.52
μ = 12.62

So, the mean weight is approximately 12.6 oz when rounded to one decimal place.

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Therefore, we can rewrite the integral as [tex]int(-2/(x-2) + 2/(x+2)) dx[/tex]

We can now integrate each term separately:

[tex]int(-2/(x-2)) dx = -2 ln|x-2| + C1[/tex]

[tex]int(2/(x+2)) dx = 2 ln|x+2| + C2[/tex]

where C1 and C2 are constants of integration.

We can start by factoring the denominator of the fraction, which is [tex]x^2-4[/tex]. This can be written as [tex](x-2)(x+2)[/tex]. Therefore, we can rewrite the integral as:

[tex]int(8/[(x-2)(x+2)]) dx[/tex]

We can then use partial fraction decomposition to simplify the integral. We want to find constants A and B such that:

[tex]8/[(x-2)(x+2)] = A/(x-2) + B/(x+2)[/tex]

Multiplying both sides by[tex](x-2)(x+2)[/tex], we get:

[tex]8 = A(x+2) + B(x-2)[/tex]

We can solve for A and B by setting x equal to -2 and 2, respectively. This gives us:

[tex]A = -2[/tex]

[tex]B = 2[/tex]

Therefore, we can rewrite the integral as:

[tex]int(-2/(x-2) + 2/(x+2)) dx[/tex]

We can now integrate each term separately:

[tex]int(-2/(x-2)) dx = -2 ln|x-2| + C1[/tex]

[tex]int(2/(x+2)) dx = 2 ln|x+2| + C2[/tex]

where C1 and C2 are constants of integration.

Putting it all together, the final solution is:

[tex]int(8/[(x-2)(x+2)]) dx = -2 ln|x-2| + 2 ln|x+2| + C[/tex]

where C = C1 + C2 is a constant of integration.

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The statement "one can set up a spreadsheet to compute the iterations of Euler's method for approximating solutions to second-order ODEs" is true because this method provides a numerical solution to differential equations by iteratively updating the variables based on the given differential equation.

A spreadsheet can be used to organize and calculate these iterations, making it easier to approximate the solutions to second-order ODEs.

To set up a spreadsheet for Euler's method to approximate solutions to a second-order ODE, one would need to follow these steps:

The spreadsheet would allow you to easily perform the iterative calculations required by Euler's method, and to visualize the behavior of the solution over time.

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Substituting the given probabilities, we get:
P(E1 and E2 and E3) = 0.33 * 0.19 * 0.43
P(E1 and E2 and E3) = 0.0279 or approximately 2.79%.

a. To calculate P(E1 and B), we can use the formula: P(E1 and B) = P(B) * P(E1 | B), where P(E1 | B) represents the probability of E1 occurring given that B has occurred. We are given that P(B) = 0.25 and P(E1, B) = 0.28, so we can solve for P(E1 | B) as follows:

P(E1, B) = P(B) * P(E1 | B)
0.28 = 0.25 * P(E1 | B)
P(E1 | B) = 0.28/0.25
P(E1 | B) = 1.12

Since probabilities must be between 0 and 1, we can see that there is an error in the problem statement, as P(E1 | B) cannot be greater than 1. Therefore, we cannot calculate P(E1 and B) using the given information.

b. To compute P(E1 or B), we can use the formula: P(E1 or B) = P(E1) + P(B) - P(E1 and B), where P(E1 and B) is the probability of both E1 and B occurring at the same time. We are given that P(E1) = 0.33, P(B) = 0.25, and we cannot calculate P(E1 and B) using the given information. Therefore, we cannot calculate P(E1 or B) with the information provided.

c. If E1, E2, and E3 are independent events, then the probability of all three occurring together can be calculated using the formula: P(E1 and E2 and E3) = P(E1) * P(E2) * P(E3).

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Answer:

answers are on picture

Step-by-step explanation:

please mark mine brainliest. answrs on picture

Answer:

25.4 x 17.78 x 12.7 cm

Step-by-step explanation:

The probability of a sample mean between 20 and 21 is approximately 0.4772 or 47.72%.

To solve this problem, we need to use the central limit theorem, which tells us that the distribution of sample means will be approximately normal, with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

In this case, the population mean is 20 inches and the population standard deviation is 4 inches. We plan to choose a sample of 64 bears at random, so the standard deviation of the sample mean will be:

standard deviation of the sample mean = 4 / √(64) = 0.5

To find the probability of a sample mean between 20 and 21, we need to calculate the z-scores for these values:

z-score for 20 = (20 - 20) / 0.5 = 0
z-score for 21 = (21 - 20) / 0.5 = 2

We can use a standard normal distribution table or calculator to find the area under the curve between these two z-scores. The area between z = 0 and z = 2 is approximately 0.4772.

Therefore, the probability of a sample mean between 20 and 21 is approximately 0.4772 or 47.72%.

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Let’s call the number we’re looking for “x”. If x is rounded to 400,000 when rounded to the nearest 100,000 and rounded to 350,000 when rounded to the nearest 10,000, then we know that x must be between 375,000 and 424,999.

This is because if we round x down to the nearest 100,000, we get 300,000 (since it rounds down to the nearest hundred thousand), and if we round x up to the nearest 100,000, we get 500,000 (since it rounds up to the nearest hundred thousand). Therefore, x must be between these two numbers.

Similarly, if we round x down to the nearest 10,000, we get 340,000 (since it rounds down to the nearest ten thousand), and if we round x up to the nearest 10,000, we get 359,999 (since it rounds up to the nearest ten thousand). Therefore, x must be between these two numbers as well.

Therefore, a possible number that satisfies these conditions is any number between 375,000 and 424,999 that rounds to 400,000 when rounded to the nearest hundred thousand and 350,000 when rounded to the nearest ten thousand.

I hope that helps!

There are 216 possible outcomes when you roll 3 dice in this game of chance.

In this game, players win if they roll triples, meaning all three dice display the same number. To find out how many possible outcomes there are when you roll 3 dice, follow these steps:
Step:1. Determine the number of sides on a die. A standard die has 6 sides, each with a different number (1-6).
Step:2. Calculate the total possible outcomes for each die. Since there are 6 sides on a die, there are 6 possible outcomes for each die.
Step:3. Multiply the possible outcomes of each die together. In this case, that would be 6 (for the first die) * 6 (for the second die) * 6 (for the third die). 6 * 6 * 6 = 216
So, there are 216 possible outcomes when you roll 3 dice in this game of chance.

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The perimeter of the shaded region is 39.71 units approximately to the nearest hundredth using the arc length of each sector

Arc length = (central angle / 360) x (2 x π x radius)

central angle = 120°

radius = 5/2 = 2.5

Arc length of a sector = (120°/360º) × 2 × 22/7 × 2.5

Arc length of a sector = 5.2381

Arc length of the three sector = 3 × 5.2381

Arc length of the three sector = 15.7143

perimeter of the shaded region = (3 ×5) + 15.7143

perimeter of the shaded region = 30.7143

Therefore, perimeter of the shaded region is 39.71 units approximately to the nearest hundredth using the arc length of each sector

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The volume of the rectangular prism is 8 in³.

What are the number of cubes in a rectangular prism?

Since the rectangular prism is filled with 16 cubes, we know that the total volume of the cubes is:

[tex]16 \: cubes × ( \frac{1}{2} inch) ^{3} /cube = 16 × ( \frac{1}{8} ) in ^{3} /cube = 2 in^{3} [/tex]

Since each cube has a volume of 1/2 inch cubed, the length, width, and height of the rectangular prism are all equal to 4 cubes or 2 inches, as 4 cubes × (1/2 inch)/cube = 2 inches. Therefore, the volume of the rectangular prism is:

[tex]Volume = Length × Width × Height = 2 \: inches × 2 \: inches × 2 \: inches = 8 \: cubic \: inches[/tex]

Therefore, the answer is (B) 8 in³.

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Answer:

B

Step-by-step explanation:

I took the test

The slope of a line perpendicular to the given line is -2.

The slope of a line parallel to the given line is 1/2.

To find the slopes of lines perpendicular and parallel to the given line, we first need to rewrite the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

Given equation: 4x - 8y = 5

Rearrange the equation to solve for y:

-8y = -4x + 5

y = (1/2)x - (5/8)

Now that the equation is in slope-intercept form, we can identify the slope of the given line:

m1 = 1/2

For a line to be parallel to the given line, it must have the same slope. So, the slope of a line parallel to this line is:

m_parallel = 1/2

For a line to be perpendicular to the given line, its slope must be the negative reciprocal of the slope of the given line. So, the slope of a line perpendicular to this line is:

m_perpendicular = -1/m1 = -1/(1/2) = -2

The given sequence is: lim (n→∞) (2n + 8) / n^7
To determine if this sequence is convergent or divergent, we can analyze its behavior as n approaches infinity. We can do this by dividing both the numerator and the denominator by the highest power of n in the denominator, in this case, n^7: lim (n→∞) [(2n/n^7) + (8/n^7)] / (n^7/n^7)

This simplifies to:
lim (n→∞) (2/n^6) + (8/n^7)
As n approaches infinity, both terms in the expression approach 0, since the denominator grows faster than the numerator:
lim (n→∞) (2/n^6) = 0
lim (n→∞) (8/n^7) = 0
So, the limit of the sequence is:
0 + 0 = 0
The sequence is convergent, and its limit is 0.

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There is actually a decrease in the mean for the second week compared to the first, and it is $7.58 less.

To find the mean for the first week, we add up all the lunch expenses and divide by the number of lunches:

(12.99 + 10.50 + 9.89 + 6.90 + 7.58) / 5 = 9.97

So the mean for the first week is $9.97.

In the second week, Devon spent $2 more in total for the 5 lunches than the first week, which means he spent:

9.97 + 2 = $11.97

To find the mean for the second week, we divide the total spent by the number of lunches:

11.97 / 5 = $2.39

The increase in the mean for the second week compared to the first is:

2.39 - 9.97 = -$7.58

So there is actually a decrease in the mean for the second week compared to the first, and it is $7.58 less.

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According to the information, the answer is (c) subtract 6 from 46, which is the inverse operation of adding 6 to the original number.

If we work backward to solve this problem, we need to undo the operations that Callie performed on the original number. The last operation Callie performed was to subtract 4 from the result of multiplying the original number by 2 and adding 6. So, the first step in working backward is to add 4 to 46:

Now, we need to undo the multiplication by 2 and the addition of 6. To undo multiplication by 2, we divide by 2:

To undo the addition of 6, we subtract 6:

Therefore, the number Callie started with was 19.

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Answer:

Perpendicular, 90 degrees

Step-by-step explanation:

Orthogonal means that the two vectors are Perpendicular. Meaning they form a [tex]90[/tex]° angle. The dot product of two Orthogonal vectors equals 0.

let there be 2 vectors u and v

If the two vectors are orthogonal, then the following must be true:

u·v=0

AND

the angle between the two vectors is a right angle, or 90°

We can conclude that for any natural number n,[tex]n^2[/tex]= 1 (mod 4) depending on the remainder of n when divided by 4.

The statement "For any natural number n, it is true that in=1,i,â1, depending on the remainder of n when divided by 4" is not true.

In fact, the statement is not well-defined because it is unclear what "in" refers to.

However, if the statement is intended to be "For any natural number n, it is true that [tex]n^2[/tex]=1 (mod 4) depending on the remainder of n when divided by 4," then this statement is true.

To see why, note that any natural number can be written as 4k, 4k+1, 4k+2, or 4k+3 for some integer k.

If n = 4k, then [tex]n^2 = (4k)^2 = 16k^2[/tex], which is divisible by 4 and hence is congruent to 0 (mod 4). Therefore, [tex]n^2[/tex] = 1 (mod 4).

If n = 4k + 1, then [tex]n^2 = (4k + 1)^2 = 16k^2 + 8k + 1 = 4(4k^2 + 2k) + 1[/tex], which is congruent to 1 (mod 4). Therefore, [tex]n^2[/tex] = 1 (mod 4).

If n = 4k + 2, then [tex]n^2 = (4k + 2)^2 = 16k^2 + 16k + 4 = 4(4k^2 + 4k + 1)[/tex], which is congruent to 0 (mod 4). Therefore, n^2 = 0 (mod 4), which is not equal to 1 (mod 4).

If n = 4k + 3, then[tex]n^2 = (4k + 3)^2 = 16k^2 + 24k + 9 = 4(4k^2 + 6k + 2)[/tex] + 1, which is congruent to 1 (mod 4). Therefore, [tex]n^2 = 1[/tex] (mod 4).

Therefore, we can conclude that for any natural number n,[tex]n^2 =[/tex]1 (mod 4) depending on the remainder of n when divided by 4.

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Based on the frequency distribution, the above question's response is 11. The answer is option (B).

The number of observations that fall into each category can be counted using a frequency distribution, which divides the data into intervals or categories. By displaying how frequently each category occurs, it summarises the data.

Using the [tex]2^k > n[/tex] rule, where n is the total number of data points, is as follows: [tex]2^k > 2000[/tex]

If we take the logarithm base 2 of both sides, we obtain:

k > log₂(2000)

k > 10.965784

Since k must be an integer, we can round up to the next integer to get:

k = 11

If we take the logarithm base 2 of both sides, we obtain:

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For a 90 degrees clockwise rotation,

A' = (y, -x) = (1, -2)

B' = (y, -x) = (3, -3)

C' = (y, -x) = (2, -5)

To plot a triangle onto a coordinate plane, these instructions must be followed:

Begin by drawing x and y axes to establish the necessary framework.

Choose three points upon which to place the vertices of the triangle on the graph.

Then connect the selected points through straight lines, thus resulting in the appearance of three sides; representing each point's distance from one another respectively.

Subsequently attach letter designations such as A, B, and C to each vertex.

Lastly, inspect the measurements of the sides and angles between them to confirm that they correspond with requisites specific to your chosen triangle type (such as an equilateral or Isosceles shape).

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The diameter of the circle is 2, which means the length and width of the rectangle can be at most 2. This means the length and width of the rectangle are each half the diameter, or 1. Therefore, the area of the largest rectangle that can be inscribed in the circle of radius 1 is 1 x 1 = 1.

The area of the largest rectangle can be inscribed in a circle of radius 1.

Step 1: Understand the problem
We are asked to find the area of the largest rectangle that can fit inside a circle with a radius of 1.

Step 2: Visualize the problem
The largest rectangle that can be inscribed in a circle is a square. This is because all corners of the square will touch the circle, and any other shape of the rectangle will have less area.

Step 3: Calculate the diagonal of the square
The diagonal of the square is equal to the diameter of the circle. Since the radius of the circle is 1, the diameter is 2 (radius * 2).

Step 4: Calculate the side length of the square
Since a square has all equal sides, we can use the Pythagorean theorem to find the side length (let's call it "s") of the square. In a square, the diagonal is equal to the square root of the sum of the squares of the sides.

Diagonal = √(s² + s²) = √(2 * s²)
2 = √(2 * s²)
Square both sides: 4 = 2 * s²
Divide by 2: s² = 2
Take the square root: s = √2

Step 5: Calculate the area of the rectangle (square)
Area = side * side
Area = (√2) * (√2)
Area = 2

The area of the largest rectangle that can be inscribed in a circle of radius 1 is 2 square units.

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The first step in finding the maximum likelihood estimator for this distribution is to write the likelihood function, which is the joint probability density function of the sample. For a random sample of size n, this is given by:

L(θ | y1, y2, ..., yn) = f(y1 | θ) × f(y2 | θ) × ... × f(yn | θ)

where θ is the parameter(s) of the distribution.

In this case, the parameter of interest is not explicitly stated, but based on the given probability density function f(y), we can identify that it is the probability of success p, where success is defined as the event that Y takes on a value between 0 and 1. This probability is given by:

p = P(0 ≤ Y ≤ 1) = ∫₀¹ f(y) dy

We can simplify this integral by using the Beta function, which is defined as:

B(a, b) = ∫₀¹ x^(a-1) (1-x)^(b-1) dx

Substituting in the values of a and b, we get:

B(5, 4) = ∫₀¹ y^4 (1-y)^3 dy

Therefore, we can express the probability of success as:

p = B(5, 4) = 280/429

Now we can write the likelihood function as:

L(p | y1, y2, ..., yn) = ∏ᵢ f(yᵢ | p) = ∏ᵢ (280yᵢ^4(1 - yᵢ)^3)

Taking the natural logarithm of the likelihood function, we get:

log L(p | y1, y2, ..., yn) = ∑ᵢ [log 280 + 4 log yᵢ + 3 log(1 - yᵢ)]

To find the maximum likelihood estimator for p, we need to differentiate the log likelihood function with respect to p and set the result equal to zero:

d/dp log L(p | y1, y2, ..., yn) = 0

Since p appears only in the expression B(5, 4), we can substitute in the value we previously derived:

log L(p | y1, y2, ..., yn) = ∑ᵢ [log(280/429) + 4 log yᵢ + 3 log(1 - yᵢ)]

d/dp log L(p | y1, y2, ..., yn) = 0

Simplifying this expression, we get:

∑ᵢ [(4/yᵢ) - (3/(1-yᵢ))] = 0

Multiplying both sides by p = 280/429, we get:

∑ᵢ [(4p/yᵢ) - (3p/(1-yᵢ))] = 0

This equation does not have a closed-form solution for p, so we need to use numerical methods to find an approximate solution. One common method is to use an iterative algorithm, such as Newton-Raphson, to update our estimate of p based on the derivative of the log likelihood function. We start with an initial guess for p, and then repeat the following steps until convergence:

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The coefficients of the quadratic equation are a = 9, b = 25.5, and c = 30. Therefore, the equation of the parabola is y = 9x² + 25.5x + 30.

A parabola is a U-shaped curve that is formed by the graph of a quadratic function. It is a type of conic section, along with the circle, ellipse, and hyperbola, that is formed by the intersection of a plane and a cone.

In algebraic terms, the general equation of a parabola is y = ax² + bx + c, where a, b, and c are constants that determine the shape, position, and orientation of the parabola. The sign of the coefficient a determines whether the parabola opens upwards (if a > 0) or downwards (if a < 0).

We are given three coordinates on the graph of the parabola, which we can use to form a system of three equations in three variables to solve for the coefficients a, b, and c.

Using the first coordinate (0,30), we have:

30 = a(0)² + b(0) + c

Simplifying, we get:

c = 30

Using the second coordinate (-2,0), we have:

0 = a(-2)² + b(-2) + 30

Simplifying, we get:

4a - 2b + 15 = 0

Using the third coordinate (-5,0), we have:

0 = a(-5)² + b(-5) + 30

Simplifying, we get:

25a - 5b + 30 = 0

Now we have a system of three equations in three variables:

c = 30

4a - 2b + 15 = 0

25a - 5b + 30 = 0

Using the first equation, we can substitute c = 30 into the other two equations to get:

4a - 2b = -15

25a - 5b = -30

Now we can solve for a and b using any method of solving systems of linear equations. One way is to multiply the first equation by 5 to get:

20a - 10b = -75

Subtracting the second equation from this, we get:

-5a = -45

Solving for a, we get:

a = 9

Substituting this back into one of the earlier equations, we can solve for b:

4(9) - 2b = -15

Simplifying, we get:

-2b = -51

Solving for b, we get:

b = 25.5

So the coefficients of the quadratic equation are a = 9, b = 25.5, and c = 30. Therefore, the equation of the parabola is:

y = 9x² + 25.5x + 30

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The complete question is:

The fourth derivative of f(x) over the interval [2π/4,2π/2] is -3/8.

The given function is f(x) = 6cos(x/2) over the interval [2π/4,2π/2]. To find the fourth derivative of this function, we need to apply the chain rule and the product rule repeatedly.

First, let's find the first derivative of f(x):

f'(x) = -3sin(x/2)

Next, let's find the second derivative of f(x):

f''(x) = -3/2cos(x/2)

Now, let's find the third derivative of f(x):

f'''(x) = 3/4sin(x/2)

Finally, let's find the fourth derivative of f(x):

f''''(x) = 3/8cos(x/2)

Now that we have the fourth derivative of the function, we can evaluate it over the interval [2π/4,2π/2] to get the value of L4. To do this, we simply substitute the upper limit of the interval (2π/2) and the lower limit of the interval (2π/4) into the fourth derivative expression and subtract the results. This gives us:

L4 = f''''(2π/2) - f''''(2π/4)

= (3/8)cos(π) - (3/8)cos(π/2)

= -(3/8)

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The x values of the inflection points of f(0) = 4x² + 8 are 'NONE'.

To find inflection points, we first need to find the second derivative of the function. The original function is f(x) = 4x² + 8. The first derivative, f'(x), is the derivative of 4x² + 8 with respect to x, which is 8x.

Now, find the second derivative, f''(x), by taking the derivative of 8x with respect to x, which is 8. Since the second derivative is a constant value (8) and does not change with x, there are no inflection points. Inflection points occur when the second derivative changes sign, but in this case, it remains constant.

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Answer:

There are 8 apples in basket

Answer:

Step-by-step explanation

the wander to this question is -1/2 , (3-4(

Answer:

B)  73°

Step-by-step explanation:

m∠NMP = 180 -168 = 12

Sum of interior angles of ΔNMP = 180

m∠P = 180 - 95 - 12 = 73

Answer:

D

Step-by-step explanation:

it should be D because the others seem too big or too small

After answering the presented question, we may conclude that  So, the expressions correct answer is option B: -2x + 1.

In mathematics, you can multiply, divide, add, or subtract. An expression is constructed as follows: Number, expression, and mathematical operator A mathematical expression (such as addition, subtraction, multiplication, or division) is made up of numbers, variables, and functions. It is possible to contrast expressions and phrases. An expression or algebraic expression is any mathematical statement that has variables, integers, and an arithmetic operation between them. For example, the phrase 4m + 5 has the terms 4m and 5, as well as the provided expression's variable m, all separated by the arithmetic sign +.

expression that is equivalent to 1/3 (9-6x+12),

9 - 6x + 12 = 21 - 6x

1/3 (21 - 6x) = (1/3) * 21 - (1/3) * 6x = 7 - 2x

Therefore, the expression that is equivalent to 1/3 (9-6x+12) is:

7 - 2x

So, the correct answer is option B: -2x + 1.

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(a) Probability is 0.755 (b) Probability is 0.0322 (c) Probability is 0.5871 (d) Percentile rank is 3.22%

(a) To find the probability that a randomly selected bag contains between 1100 and 1500 chocolate chips, inclusive, we need to find the area under the normal curve between the values of 1100 and 1500.

Using a z-score formula, we can standardize the values:

z1 = (1100 - 1252) / 123 = -1.24
z2 = (1500 - 1252) / 123 = 2.09

Then, we can use a standard normal distribution table or calculator to find the area under the curve between these z-scores:

P(-1.24 < Z < 2.09) = 0.755

Therefore, the probability that a randomly selected bag contains between 1100 and 1500 chocolate chips, inclusive, is 0.755.

(b) To find the probability that a randomly selected bag contains fewer than 1025 chocolate chips, we need to find the area under the normal curve to the left of 1025.

Again, we can standardize the value using a z-score formula:

z = (1025 - 1252) / 123 = -1.85

Then, we can use a standard normal distribution table or calculator to find the area under the curve to the left of this z-score:

P(Z < -1.85) = 0.0322

Therefore, the probability that a randomly selected bag contains fewer than 1025 chocolate chips is 0.0322.

(c) To find the proportion of bags that contains more than 1225 chocolate chips, we need to find the area under the normal curve to the right of 1225.

Again, we can standardize the value using a z-score formula:

z = (1225 - 1252) / 123 = -0.22

Then, we can use a standard normal distribution table or calculator to find the area under the curve to the right of this z-score:

P(Z > -0.22) = 0.5871

Therefore, the proportion of bags that contains more than 1225 chocolate chips is 0.5871.

(d) To find the percentile rank of a bag that contains 1025 chocolate chips, we need to find the percentage of bags that contain fewer chips than this bag.

We can use the same z-score formula to standardize the value:

z = (1025 - 1252) / 123 = -1.85

Then, we can use a standard normal distribution table or calculator to find the area under the curve to the left of this z-score:

P(Z < -1.85) = 0.0322

This means that approximately 3.22% of bags contain fewer than 1025 chocolate chips. Therefore, the percentile rank of a bag that contains 1025 chocolate chips is approximately 3.22%.

Learn more about probability here:

https://brainly.com/question/30034780

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