Use the graph to answer the following questions.

a. Describe and provide an explanation for the general period trend in boiling points.

b. Describe and provide an explanation for the general group trend in boiling points.

c. Describe and provide an explanation for exceptions to the general group trend in boiling points.

d. (i) Which of the substances shown are liquids at room temperature? (ii) Which of the substances shown are solids? (iii) Explain why these substances are found in this state at room temperature.

e. Predict an approximate boiling point for lead (IV) hydride. Justify your prediction.

Use The Graph To Answer The Following Questions.a. Describe And Provide An Explanation For The General

Answers

Answer 1

The general trend in boiling points across the period is that they increase from left to right. This is because as you move from left to right, the number of protons in the nucleus increases, causing the attraction between the electrons and the nucleus to increase.

What increases the boiling point?

In an open system, this is referred to as atmospheric pressure. Pressure rises as boiling points and the amount of energy needed to boil liquids rise.

Why does the boiling point increase when intermolecular interactions increase?

The standard boiling point should rise as intermolecular tensions grow. This is because it takes more energy to separate molecules during the transition from liquid to gas when intermolecular interactions are stronger.

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Related Questions

3 ml of urine will make how much of a 1:150 dilution

Answers

3 ml of urine will make a volume of 0.02 ml of a 1:150 dilution.

What is the volume made from the dilution?

To calculate the final volume of a dilution, we need to divide the initial volume by the dilution factor.

Here, we are diluting 3 ml of urine to make a 1:150 dilution. This means that we are diluting 1 part of urine in 150 parts of the diluent.

So, the total volume of the diluted solution will be:

3 ml / 150 = 0.02 ml

Thus, 3 ml of urine will make 0.02 ml of a 1:150 dilution based on the given dilution factor.

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ASAP PLEASEEEEE!!!!According to the diagram:
a. How many covalent bonds can form?
b. Explain why this is possible.

Answers

This is possible because the oxygen atom has two unpaired electrons that can form a covalent bond with the hydrogen atom's single unpaired electron.

What is hydrogen?

Hydrogen is the lightest and most abundant element in the universe, making up approximately 75% of all matter. It is odorless, colorless, and tasteless, and is the simplest element, consisting of a single proton and electron. Hydrogen is an energy carrier, meaning it can store and transport energy, and it is also used in many industrial processes. It can be used to produce electricity in fuel cells, or burned in internal combustion engines to produce heat and power. It is also a key component of many fuels, including gasoline, natural gas, and methanol. Hydrogen has a wide range of applications, from powering cars and homes to providing clean energy for entire communities.

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Hydrazine, N2H4, reacts with oxygen to form nitrogen gas and water.

N2H4(aq)+O2(g)⟶N2(g)+2H2O(l)

If 3.55 g of N2H4 reacts with excess oxygen and produces 0.850 L of N2, at 295 K
and 1.00 atm, what is the percent yield of the reaction?

Answers

The percentage yield of the reaction, given that the reaction produces 0.850 L of N₂, at 295 K and 1.00 atm is 3.16%

How do i determine the percentage yield of the reaction?

First, we shall determine the mole in 3.55 g of N₂H₄. This is shown below:

Mass of N₂H₄ = 3.55 gMolar mass of N₂H₄ = 32 g/mol Mole of N₂H₄ =?

Mole = mass / molar mass

Mole of N₂H₄ = 3.55 / 32

Mole of N₂H₄ = 0.1109 mole

Next,  we shall determine the theoretical yield. Details below:

N₂H₄(aq) + O₂(g) ⟶ N₂(g) + 2H₂O(l)

From the balanced equation above,

1 mole of N₂H₄ reacted to produce 1 mole of N₂

Therefore,

0.1109 mole of N₂H₄ will also react to produce 0.1109 mole of N₂

Thus, the theoretical yield is 0.1109 mole

Next, we shall determine the actual yield. Details below:

Volume (V) = 0.850 LTemperature (T) = 295 KPressure (P) = 1 atmGas constant (R) = 0.0821 atm.L/mol KNumber of mole (n) =?

PV = nRT

1 × 0.850 = n × 0.0821 × 295

Divide both sides by (0.0821 × 295)

n = 0.850 / (0.0821 × 295)

n = 0.0035 mole

Finally, we shall determine the percentage yield of N₂. This is illustrated below:

Actual yield of N₂ = 0.0035 moleTheoretical yield of N₂ = 35.5 gPercentage yield of N₂ =?

Percentage yield = (Actual /Theoretical) × 100

Percentage yield of N₂= (0.0035 / 0.1109) × 100

Percentage yield of N₂ = 3.16%

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1.) Lactated Ringer's solution (NaCl, KCl, CaCl2, and NaHCO3 in water) for intravenous fluid replacement contains 109mEq/L of Cl-. If the patient received 1250 mL of Ringers solution, how many moles of Cl- ion were given?

2.) How many milliliters of 10% (m/v) NaOH solution would contain 2.2g of NaOH?

3.) How many moles of BaCl2 are in 600 mL of a 2.5 M of BaCl2 solution?

4.) The molarity of a solution of 29.2g of NaCl in 134 mL of solution is ____mol/L.

5.) How many grams of Na2CO3 would be needed to prepare 400mL of 3.00M solution of Na2CO3?

6.) What is the molarity of NaNO3 solution made by diluting 33.0 ml of a 5.50 M solution to a final volume of 250. mL?

7.) A patient receives 100. mL of 20.0% (m/v) mannitol solution every hour. How many grams of mannitol are given in one hour?

8.) One needs a 25.00 mL of a 3.000 ppm Fe solution. How many microliters (mL) of a 4000.0 ppm Fe stock solution are needed to make a the desired solution?

Answers

Answer:

1. To calculate the number of moles of Cl- ion given, we need to first calculate the total number of Cl- ions in 1250 mL of Ringer's solution:

1250 mL x (109 mEq/L / 1000 mL/L) = 136.25 mEq of Cl-

Next, we can convert mEq to moles using the molecular weight of Cl-:

136.25 mEq x (1 mol / 1000 mEq) = 0.13625 mol of Cl-

Therefore, 0.13625 moles of Cl- ion were given.

2. To calculate the volume of 10% NaOH solution containing 2.2 g of NaOH, we need to use the definition of percent concentration:

10 g NaOH / 100 mL solution = 2.2 g NaOH / x mL solution

Solving for x, we get:

x = (2.2 g NaOH) / (10 g NaOH / 100 mL) = 22 mL

Therefore, 22 mL of 10% NaOH solution would contain 2.2 g of NaOH.

3. To calculate the number of moles of BaCl2 in 600 mL of a 2.5 M solution, we can use the definition of molarity:

2.5 mol/L = x mol / 0.6 L

Solving for x, we get:

x = 1.5 mol of BaCl2

Therefore, 1.5 moles of BaCl2 are in 600 mL of a 2.5 M solution.

4. To calculate the molarity of a solution of 29.2 g of NaCl in 134 mL of solution, we need to first convert the mass of NaCl to moles:

29.2 g NaCl x (1 mol / 58.44 g) = 0.499 mol NaCl

Next, we can calculate the volume of the solution in liters:

134 mL x (1 L / 1000 mL) = 0.134 L

Finally, we can calculate the molarity:

0.499 mol / 0.134 L = 3.72 M

Therefore, the molarity of the solution is 3.72 M.

5. To calculate the mass of Na2CO3 needed to prepare a 400 mL of 3.00 M solution of Na2CO3, we can use the molarity formula:

Molarity = moles of solute / liters of solution

Rearranging the formula to solve for moles of solute:

moles of solute = Molarity x liters of solution

moles of Na2CO3 = 3.00 M x 0.400 L = 1.20 moles of Na2CO3

Next, we can convert moles of Na2CO3 to grams using the molar mass of Na2CO3:

1.20 moles Na2CO3 x (105.99 g / 1 mole) = 127.2 g of Na2CO3

Therefore, 127.2 grams of Na2CO3 are needed to prepare a 400 mL of 3.00 M solution of Na2CO3.

6. To calculate the molarity of NaNO3 solution made by diluting 33.0 ml of a 5.50 M solution to a final volume of 250. mL, we can use the dilution formula:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Rearranging the formula to solve for M2:

M2 = M1V1 / V2

M2 = (5.50 M) x (33.0 mL) / (250. mL)

M2 = 0.726 M

Therefore, the molarity of NaNO3 solution made by diluting 33.0 ml of a 5.50 M solution to a final volume of 250. mL is 0.726 M.

7. To calculate the grams of mannitol given in one hour, we can use the definition of percent concentration:

20 g mannitol / 100 mL solution = x g mannitol / 100 mL solution

Simplifying the equation, we get:

x = 20 g mannitol

Therefore, 20 g of mannitol are given in 100 mL of solution. Since the patient receives 100 mL of solution every hour, the amount of mannitol given in one hour is also 20 g.

8. To calculate the microliters of a 4000.0 ppm Fe stock solution

Which statements about Earth's crust are true? Check all that apply
O The crust includes soil, rock, and water.
O There are three different kinds of crust.
O The crust is thickest under the ocean.
O The ocean crust is made of young rocks.
O The ocean crust is denser than continental crust.

Answers

The earth crust includes soil, water and rocks. Although it is denser than the shoreline crest, the marine crust is thinner than it is.

What is earth crest?

The soil, various kinds of rocks, and water make up the earth's crest.. The different types of rocks include, igneous rocks, sedimentary rocks and metamorphic rocks.

Is the Sun eastward rising and westward setting?

The majority of individuals are aware that the Sun "rises in the east and sets in the west". Most individuals, though, are unaware that is a generalisation. Actually, the spring and fall equinoxes are the only two days of the year when the Sun rises and sets directly east and west.

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The combustion of octane, C8H18, proceeds according to the reaction shown.

2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)

If 538 mol of octane combusts, what volume of carbon dioxide is produced at 31.0 ∘C
and 0.995 atm?

Answers

The volume of carbon dioxide is produced at 31.0 ∘C and 0.995 atm is 119,786 L

How do we calculate?

We must ensure that you have a balanced chemical equation

We can multiply 611 * 16 and divide by the 2. We have 4888 moles  CO2.

We determine the  volume by using ideal gas law

(PV=nRT).

P = 0.995 atm

V = x

n = 4888 mol CO2

T = 24.0C + 273 K = 297 K

R = 0.0821 (L*atm)/(mol*K)

PV =

nRT  

V  = (nRT)/P

V = ((4888 mol)(0.0821 L*atm/mol*K)(297K))/(0.995 atm)

V = 119,786 L

Therefore, the volume of carbon dioxide is produced at 31.0 ∘C and 0.995 atm is 119,786 L

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An aqueous magnesium chloride solution is made by dissolving 7.40 moles of MgCl2 in sufficient water so that the final volume of the solution is 4.80 L . Calculate the molarity of the MgCl2 solution.

Answers

An aqueous magnesium chloride solution is made by dissolving 7.40 moles of MgCl₂ in sufficient water so that the final volume of the solution is 4.80 L. the molarity of the MgCl₂ solution is equal to 1.54 M.

What is Molarity?

Molarity is a unit of concentration, which measures the number of moles of a solute per liter of a solution. To calculate molarity, one divides the amount of solute (in moles) by the total volume of the solution (in liters). In chemistry, molarity is often used to measure concentrations of acids, bases, and other solutes in solutions. This unit of concentration is important in lab work, as it allows scientists and researchers to accurately measure and predict the behavior of solutions.

Molarity (M) = /[tex]\frac{moles of solute}{liters of solution }[/tex]

Molarity (M) =  [tex]\frac{7.4mol}{4.8L}[/tex]

Molarity (M) = 1.54 M

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describe ways to seperate heterogeneous mixtures​

Answers

Sieving, handpicking, and filtration are some simple physical methods to separate heterogeneous mixtures

Sieving is typically used to separate particles by size through a mesh, like what you see near construction sites.

Filtration is a method used to separate insoluble solid from liquids using filter paper.

Handpicking is a method used to separate a mixture using hands.

There’s also distillation which is a process to separate components of a homogeneous mixture. It involves heat and a sophisticated apparatus, which is why it’s not considered a simple method.

How many moles of NaCl are in 115 kilograms of a 0.250 m sodium chloride solution?

Answers

Answer:

The molecular weight of sodium chloride is 58.44 which corresponds with 1 mole. The molar concentration is the number of moles in 1L of solvent. In our case - a solution of 0.25M has 0.25moles/1L of water.

Answer:

n(NaCl) = 20.9 mol

Explanation:

To determine the number of moles of NaCl in the solution, we need to use the definition of molality, which is defined as the number of moles of solute per kilogram of solvent.

We are given the mass of the solution (115 kg) and the molality of the sodium chloride solution (0.250 m), which means that there are 0.250 moles of NaCl for every kilogram of solvent.

We need to determine the mass of solvent in the solution, which is given by:

mass of solvent = total mass of solution - mass of solute

The mass of solute (NaCl) is not given explicitly, but we can calculate it using the molality and the mass of solvent. We have:

0.250 m = 0.250 moles of NaCl / 1 kg of solvent

Therefore, the number of moles of NaCl in 115 kg of solution is:

moles of NaCl = molality x mass of solvent

mass of solvent = total mass of solution - mass of solute
mass of solvent = 115 kg - (115 kg x 0.250 mol/kg x 58.44 g/mol)
mass of solvent = 83.5 kg

moles of NaCl = 0.250 mol/kg x 83.5 kg
moles of NaCl = 20.9 moles

Therefore, there are 20.9 moles of NaCl in 115 kilograms of a 0.250 m sodium chloride solution.

Is it possible to produce a real image using concave lens what about convex lens if so please explain how

Answers

Yes, a larger picture does develop. A concave lens cannot generate such an image since it always results in a decreased picture. Therefore, this lens is convex.

Can a convex mirror produce a true image of an object?

Convex and plane mirrors only create imaginary pictures. Real images can only be created by concave mirrors, and even then, only when the object is farther away from the mirror's surface than a focal length.

Real and virtual images can both be created by a convex lens. When an item is positioned outside of the focus, it creates a true, inverted picture, and when it is positioned between the focus and the optical centre, it creates a virtual, upright image.

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A sample of an ideal gas at 1.00 atm
and a volume of 1.38 L
was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 15.0 atm,
what was the volume of the sample? Assume that the temperature was held constant.

Answers

We can use Boyle's Law, which states that the pressure and volume of a fixed amount of gas at a constant temperature are inversely proportional, to solve this problem. Mathematically, Boyle's Law can be expressed as:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume of the gas, respectively, and P2 and V2 are the final pressure and volume of the gas, respectively.

In this problem, we are given that the initial pressure and volume of the gas are 1.00 atm and 1.38 L, respectively, and that the final pressure is 15.0 atm. We can rearrange Boyle's Law to solve for V2:

V2 = (P1V1) / P2

Substituting the given values, we get:

V2 = (1.00 atm x 1.38 L) / 15.0 atm

Simplifying, we get:

V2 = 0.092 L

Therefore, the volume of the gas sample when the pressure had increased to 15.0 atm is 0.092 L.

1. Calculate the temperature if 5 moles of a gas is compressed into a volume of 50L at a Pressure of 2000 mmHg. R= 0.08206 L•atm/ mole•K and (0°C+273)=K

Answers

Answer:

T = 362.2°C.

Explanation:

We can use the Ideal Gas Law to solve this problem, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the given pressure of 2000 mmHg to atm. We have:

P = 2000 mmHg = 2000/760 atm = 2.63 atm (rounded to two decimal places)

Next, we can plug in the values of the given pressure, volume, gas constant, and number of moles into the Ideal Gas Law and solve for T:

PV = nRT

T = PV / nR

T = (2.63 atm) x (50 L) / [(5 mol) x (0.08206 L•atm/mol•K)]

T = 635.2 K

Finally, we need to convert the temperature from Kelvin to Celsius:

T = 635.2 K - 273 = 362.2°C

Therefore, the temperature is 362.2°C.

If 5.00 L of water vapor at 50.2 °C and 0.121
atm reacts with excess iron, how many grams of iron(III) oxide will be produced?

2Fe(s)+3H2O(g)⟶Fe2O3(s)+3H2(g)

Answers

The mass of the iron III oxide produced from the stoichiometry of the reaction is  1.22 g.

What is the stoichiometry?

We have the reaction equation as;

[tex]2Fe(s)+3H_{2}O(g)--- > Fe_{2}O_{3} (s)+3H_{2} (g)[/tex]

The number of moles of the water vapor is obtained from;

PV = nRT

P = pressure of the gas

V = volume of the gas

n = Number of moles of the gas

R - gas constant

T = Temperature of the gas

n = PV/RT

n = 0.121 * 5/0.082 * 323.2

n = 0.605/26.5

n = 0.0228 moles

Then;

3 moles of water vapor produces 1 mole of iron III oxide

0.0228 moles of water vapor produces 0.0228 * 1/3

= 0.0076 moles

Mass of iron III oxide produced = 0.0076 moles * 160 g/mol

= 1.22 g

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9. Find the charge on the following and indicate if each will form a cation or an anion Na Se Ca Mg AI I P O

Answers

Na sodium has one valence electron and has the electron configuration [Ne] 3s1.

Describe the valence?

Atoms frequently form bonds with other atoms that enable them to add electrons to their valence shells. For instance, the chemical sodium chloride (NaCl) can be created by the bonding of an atom with a single valence electron, like sodium, and an atom with seven valence electrons, like as chlorine. Chlorine absorbs the one valence electron from sodium and then adds eight electrons to its valence shell.

Describe an electron?

A subatomic particle with an electrical charge that is negative is called an electron. complemented by protons and neutrons, it is one of the primary building blocks of atoms.

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Which atom or ion has the largest radius?
Fe3+ ion
Fe atom
Fe5+ ion
Fe2+ ion
Fe4+ ion
Fe6+ ion

Answers

Among the given options, Fe atom has the largest radius as neutral atoms have larger radii than ions.

Draw the two products of the following hydrolysis reaction

Answers

The products of the hydrolysis reaction is Carboxylic acid + Alcohol.

What are the products of the hydrolysis reaction?

A hydrolysis process occurs when a larger molecule splits into many smaller ones. An alcohol and a carboxylic acid are created when an ester is hydrolyzed by an acid. When an ester experiences basic hydrolysis, two products are created: an alcohol and a carboxylate salt (saponification).

What is the product of hydrolysis carboxylic acid?

The hydrolysis (a cleavage reaction with water) that all carboxylic acid derivatives go through to produce carboxylic acids unites them all. with the hydroxide ion to produce an alcohol and a carboxylate salt. When a powerful acid is then added to the reaction mixture, the carboxylic acid itself is created.

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exactly 149.6J will raise the temperature of 10.0g of a metal from 25.0C. what is the specific heat capacity of the metal

Answers

Exactly 149.6J will raise the temperature of 10.0g of a metal from 25.0C. The specific heat capacity of the metal is 5.984 J/g°C.

What is specific heat capacity?

The heat capacity of a sample of a substance divided by the mass of the sample yields the specific heat capacity (symbol c), also known as massic heat capacity. Informally, it is the quantity of heat that must be added to one unit of a substance's mass in order to raise its temperature by one unit. The specific heat capacity unit in the SI is the joule per kelvin per kilogram, or Jkg⁻¹K⁻¹. For instance, the specific heat capacity of water is 4184 J kg⁻¹K⁻¹, or the amount of energy needed to raise 1 kilogram of water by 1 K.

The specific heat capacity of the metal can be calculated using the equation Q = m × c ×ΔT.

Q = 149.6J

m = 10.0g

ΔT = (final Temperature - initial Temperature) = (25°C - 0°C) = 25°C

Plugging these values into the equation, we get:

149.6J = 10.0g × c ×25°C

Solving for c, we get:

c =  [tex]\frac{149.6J}{(10.0g *25C)}[/tex]

c = 5.984 J/g°C

Therefore, the specific heat capacity of the metal is 5.984 J/g°C.

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Complete and balance the molecular equation for the reaction of aqueous iron(III) nitrate, Fe(NO3)3 , and aqueous lithium hydroxide, LiOH. Include physical states. molecular equation: Fe(NO3)3(aq)+LiOH(aq)⟶
Enter the balanced net ionic equation for the reaction. Include physical states. net ionic equation:

Answers

The molecular equation for the reaction of aqueous iron(III) nitrate and aqueous lithium hydroxide is :

Fe(NO3)3(aq) + 3LiOH(aq) ⟶ Fe(OH)3(s) + 3LiNO3(aq)

By removing the spectator ions from the molecular equation—ions that appear on both sides of the equation but do not participate in the reaction—we can derive the balanced net ionic equation for the reaction. The spectator ions in this instance are Li+ and NO3-.

The net ionic equation is :

Fe3+(aq) + 3OH-(aq) ⟶ Fe(OH)3(s)

Be aware that solid Fe(OH)3 is created when the ions Fe3+ and OH- mix. Equations with (aq) for aqueous species and (s) for solid species denote the physical states.

Astronomy:


The sun rises in the east and sets in the west due to this phenomenon.



a) the earth is spinning clockwise

b) the earth is at the center of the solar system

c) the earth is spinning counter clockwise on its axis

d) the earth is revolving around the sun

Answers

The phenomena results from the sun appearing to rise in the east and set in the west due to the Earth's anticlockwise revolution on its axis.

Is the Sun eastward rising and westward setting?

The majority of individuals are aware that the Sun "rises in the east and sets in the west". Most individuals, though, are unaware that is a generalisation. Actually, the spring and fall equinoxes are the only two days of the year when the Sun rises and sets directly east and west.

What phenomenon is brought on by the Earth's axis rotating?

How weather patterns and ocean currents are impacted by the Earth's rotation. Because of the Coriolis effect, storms swirl in the Northern Hemisphere anticlockwise and in the Southern Hemisphere clockwise.

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The temperature of a sample of gas in a steel container at 25.0 kPa starts at -50 C and decreases by a factor of three. What is the final pressure inside the tank?

Answers

Answer: The final pressure inside the tank is 8.41 kPa.

Explanation: We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas:

(P1V1)/T1 = (P2V2)/T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We are given P1 = 25.0 kPa, T1 = -50 C = 223 K, and V1 is unknown. We also know that the temperature decreases by a factor of three, so T2 = T1/3 = 223/3 K.

To find V2, we need to assume that the steel container is rigid and its volume remains constant. Therefore, V1 = V2, and we can cancel out the volume from the equation:

P1/T1 = P2/T2

Substituting the values, we get:

P2 = P1 * T2 / T1 = 25.0 * (223/3) / 223 = 8.41 kPa

Therefore, the final pressure inside the tank is 8.41 kPa.

Answer:

So if pressure of a gas is increased by 25%, the volume of a gas is decreased by 25%.

Explanation:

Will mark Brainliest.

Answers

The statement that is true is that B will participate in reaction more than A. Option A

What is the relationship between kinetic energy and chemical reaction?

The energy that an object has as a result of its motion is referred to as kinetic energy. When a chemical reaction is involved, kinetic energy is a key factor in influencing the reaction's rate. In order to cross the activation energy barrier and undergo a chemical reaction, molecules or ions involved must collide with enough kinetic energy.

In general, particles with higher kinetic energies collide more frequently and with greater energy, which can speed up the process. However, there are a number of variables that can affect how kinetic energy is related to a particular chemical reaction, including the temperature and reactant concentration, the presence of a catalyst, and the reaction mechanism.

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The average birth weight of domestic cats is about 3 ounces. Assume that the distribution of birth weights is Normal with a standard deviation of 0 4 ounce.

a. Find the birtn weight of cats at the 90th percentile.
b. Find the birth weight of cats at the 10th percentile

Answers

The birth weight of cats at the 90th percentile would be approximately 3.7 ounces. b. The birth weight of cats at the 10th percentile would be approximately 2.3 ounces.

What are the methods of calculating weight?

There are three main methods of calculating weight:

1. Balance Beam Scale: A balance beam scale is an example of a mechanical weighing system. It uses a set of calibrated weights to measure the weight of an object.

2. Digital Scale: A digital scale uses an electronic or digital readout to display the weight of an object.

3. Calipers: Calipers are devices used to measure the distance between two points, such as thickness or diameter. They come in various sizes and shapes, depending on the type of measurement the user wants to take.

What is birth weight?

Birth weight is the weight of a baby at the time of birth. It is usually measured soon after delivery, with a special baby scale, though sometimes the baby's weight is estimated. The normal range of birth weight is anywhere between 5 lbs 8 oz and 10 lbs, though preterm or premature babies may be significantly lighter. A baby's birth weight is important because it can provide a clue to the baby's overall health. High birth weights may indicate an underlying medical condition, and low birth weights can be a sign of premature or difficult delivery and health risks associated with such a delivery.

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A laboratory high-vacuum system may
operate at 1.0 x 10 -5 mm Hg. What is this
pressure in pascals? Pls help before I cry

Answers

Answer:The pressure of 1.0 x 10^-5 mm Hg is equivalent to 1.33322 x 10^-3 Pa.

Explanation:

The pressure of 1.0 x 10^-5 mm Hg is equivalent to 1.33322 x 10^-3 Pa.

Mercury'II'oxide'decomposes'to'produce'mercury'and'oxygen

Answers

Answer:

The chemical equation for the decomposition of mercury(II) oxide is:

2HgO(s) → 2Hg(l) + O2(g)

This means that when solid mercury(II) oxide (HgO) is heated, it breaks down into liquid mercury (Hg) and gaseous oxygen (O2). The reaction is a decomposition reaction because one reactant (HgO) is broken down into two products (Hg and O2). This reaction is also exothermic, meaning that it releases heat.

Explanation:

After the reaction has reached equilibrium, what will happen to the equilibrium if extra amount of C2H5OH is added? And what will happen to the equilibrium if extra amount of HCl is added? Please explain your predictions.

Answers

On adding extra amount of C₂H₅OH to the system, the equilibrium will shift to the right, i.e., more C₂H₅Cl and H₂O will be produced and on  adding extra amount of HCl to the system, the equilibrium will shift to the left, i.e., more C₂H₅OH and HCl will be produced.

What is  Le Chatelier's principle?

Le Chatelier's principle states that if a system at equilibrium is subjected to a change in concentration, pressure, temperature, or volume, the system will adjust itself in such a way as to counteract the change and re-establish equilibrium. Specifically, if the concentration of one or more of the reactants or products in a chemical reaction is changed, the system will shift in the direction that counteracts the change in concentration.

To answer this question, we need to know the chemical reaction in question and its equilibrium expression. Let's assume that the reaction is:

C₂H₅OH + HCl ⇌ C₂H₅Cl  + H₂O

The equilibrium expression for this reaction is:

K = [C₂H₅Cl ][H₂O]/[C₂H₅OH][HCl]

where [ ] denotes the molar concentration of the species.

Now, if we add extra amount of C₂H₅OH to the system at equilibrium, the equilibrium will shift in the direction that consumes the added C₂H₅OH. In other words, the system will try to decrease the concentration of C₂H₅OH by converting it to C₂H₅Cl and H₂O, in accordance with Le Chatelier's principle. As a result, the equilibrium will shift to the right, i.e., more C₂H₅Cl  and H₂O  will be produced, until a new equilibrium is established. This will increase the concentration of C₂H₅Cl and H₂O , and decrease the concentration of C₂H₅OH and HCl, but the value of K will remain the same.

On the other hand, if we add extra amount of HCl to the system at equilibrium, the equilibrium will shift in the direction that consumes the added HCl. In other words, the system will try to decrease the concentration of HCl by converting it to C₂H₅Cl  and H₂O. As a result, the equilibrium will shift to the left, i.e., more C₂H₅OH and HCl will be produced, until a new equilibrium is established. This will increase the concentration of C₂H₅OH and HCl, and decrease the concentration of C₂H₅Cl  and H₂O , but the value of K will remain the same.

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ca: 80 - 4 − 2(2 + 1)²

Answers

Answer:

80 - 4 − 2(2 + 1)² =

80 - 4 - 2(3)² =

80 - 4 - 2(9) =

80 - 4 -18 = 58

Answer: 58

Explanation: 80-4-2(2+1)²

=80-4-2(3)²

=80-4-2(9)

=80-4-18

=58

Question 12 Consider the following unbalanced chemical equation for the reaction which is used to determine blood alcohol levels: H 1 + 1+ + Cr 2 2 ​ O 7 7 ​ 2 − 2− + C 2 2 ​ H 6 6 ​ O → → Cr 3 + 3+ + CO 2 2 ​ + H 2 2 ​ O Balance the equation using the smallest whole number coefficients. What is the coefficient in front of carbon dioxide in the balanced chemical equation? 1 point 2 1 3 4 none of the other answers is correct

Answers

3 is the coefficient in front of carbon dioxide in the balanced chemical equation

What does a balanced formula equation mean?

A balanced chemical equation is one in which the mass of the reactants and products are equal, and each element has an equal number of atoms on both sides of the equation.

Different numbers of atoms from various elements can be found in reactants and products in unbalanced chemical equations. When utilizing a constant, a balanced equation is crucial since the coefficients transform into the powers of the concentrations of the reactants and products. The constant must be accurate for the equation to be balanced.

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If 83.5 mol
of an ideal gas is at 5.81 atm
at 77.90 ∘C,
what is the volume of the gas?

Answers

Answer: 414 L

Explanation:

n=83.5mol

P=5.81atm

T=77.9C = 351.05K

R=0.08206

PV=nRT

V=nRT/P

V=(83.5 * 0.08206 * 351.05)/5.81

V= 414 L

How much heat is required to raise the temperature of 67.0g of water from 25.7°C to
66.0°C? The specific heat of H₂O is 4.184J/g°C)
a) 40.3 kJ
b) 11.3 kJ
c) 67.0 kJ
d) 280.3 kJ
e) 2.70 kJ

Answers

The amount of heat required to raise the temperature of 67 g of water from 25.7°C to 66°C is approximately equal to 40.3 kJ. Thus, the answer is option a) 40.3 kJ.

How do you calculate the amount of heat required to raise the temperature of the water to 66.0°C?

The amount of heat required to raise the temperature of a substance is given by the equation:

q = m * c * ΔT

Here, q is the amount of heat required to raise the temperature , m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature due to the heat supplied.

Substituting the given values in the equation, we get:

q = (67 g) * (4.184 J/g°C) * (66°C - 25.7°C)

q = 40,332 J

Converting this value to kilojoules we obtain:

q = 40.332 kJ = 40.3 kJ

Thus 40.3 kJ of heat energy is required to raise the temperature of  67g of water from 25.7 °C to 66° C.

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If 200. mL of water is added to 10.0 mL of 4.00 M NaCl solution,
is the concentration of the dilute solution?

Answers

Answer:

Therefore, the concentration of the resulting dilute solution is 0.190 M.

Explanation:

To determine the concentration of the resulting dilute solution, we can use the equation:

M1V1 = M2V2

where M1 and V1 are the initial concentration and volume of the solution, and M2 and V2 are the final concentration and volume of the solution.

In this case, the initial solution is 10.0 mL of 4.00 M NaCl, which can be expressed as:

M1 = 4.00 M

V1 = 10.0 mL = 0.0100 L

The final volume of the solution is the sum of the initial volume and the volume of water added:

V2 = V1 + V_water

V2 = 0.0100 L + 0.200 L

V2 = 0.2100 L

Since the amount of NaCl in the solution does not change upon dilution, we can set up the equation and solve for the final concentration:

M1V1 = M2V2

(4.00 M)(0.0100 L) = M2(0.2100 L)

M2 = (4.00 M)(0.0100 L)/(0.2100 L)

M2 = 0.190 M

Therefore, the concentration of the resulting dilute solution is 0.190 M.

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