Use the shel method to find the volume of the solid generated by revolving the regions bounded by the curves and lines about the x-axis. Y=^x, y=0, y= x-4/3. The volume is

The question is asking about which voting methods satisfy the top condition, where a candidate can never be among the winners unless ranked first by at least one voter. The voting methods mentioned are Borda, Coombs, Ranked Choice, and Plurality with Runoff.
The voting methods that satisfy the top condition are Coombs, Ranked Choice, and Plurality with Runoff.

1. Coombs: This method eliminates the candidate with the most last-place votes in each round until a candidate has a majority of first-place votes, thus satisfying the top condition.
2. Ranked Choice:

Also known as Instant Runoff Voting, this method eliminates the candidate with the fewest first-place votes in each round and redistributes their votes until a candidate has a majority, meeting the top condition.

3. Plurality with Runoff:

In this method, if no candidate has a majority of first-place votes, a runoff is held between the top two candidates. Since only first-place votes are considered, the top condition is satisfied.

However, Borda does not satisfy the top condition, as it assigns points based on rank, and a candidate can win without being ranked first by any voter.

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Answer: 30 black empty squares

Step-by-step explanation: Let’s solve this problem step by step:

There are 64 squares on a chessboard and 16 of them are covered by chess pieces, so there are 64 - 16 = 48 empty squares.

The ratio of white empty squares to black empty squares is 3:5. This means that for every 3 white empty squares, there are 5 black empty squares.

The total ratio of white to black empty squares is 3 + 5 = 8.

To find out how many of the 48 empty squares are black, we can divide the total number of empty squares by the total ratio and then multiply by the ratio for black empty squares: (48 / 8) * 5 = 30.

So, there are 30 black empty squares on the chessboard.

The series [infinity]Xk=1sin2(k)πk+ 1 either diverges (by the divergence test) or converges (by the alternating series test), depending on which test we choose to use.

To determine whether the series [infinity]Xk=1sin2(k)πk+ 1 is convergent or divergent, we can use the divergence test or the alternating series test.

Using the divergence test, we can see that lim(k→∞) sin2(k)πk+ 1 does not approach zero, since sin2(k) oscillates between 0 and 1 as k increases without bound. Therefore, the series diverges.

Alternatively, we can use the alternating series test by considering the sequence {an}, where an = sin2(k)πk+ 1. This sequence is alternating, since sin2(k) oscillates between 0 and 1, and it approaches zero as k increases without bound. Additionally, the sequence is decreasing, since sin2(k) decreases as k increases. Therefore, by the alternating series test, the series converges.

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The area and perimeter of the isosceles trapezoid are 83.04cm² and 20.76cm

An isosceles trapezoid is a convex quadrilateral with a line of symmetry bisecting one pair of opposite sides.

A trapezoid is a quadrilateral with two unequal parallel lines.

To find the base of one triangle;

Tan 60 = 6/x

1.732 = 6/x

x = 6/1.732

x = 3.46

sin60 = 6/hyp

hyp = 6/0.866

hyp = 6.93

the base = 2x = 2× 3.46 = 6.92cm

Therefore , the top parallel line = 6.92

and the base of the trapezoid = 3× 6.92 = 20.76cm

The perimeter = 6.93+6.93+6.92+20.76

= 41.54cm

Area = 1/2(a+b)h

= 1/2( 6.92+20.76)6

= 27.68×3

= 83.04cm²

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Another solution to the given differential equation x²y" + 3xy' - 8y = 0, with y = x as one solution, is y = x³.

We are given a homogeneous, linear, second-order differential equation: x²y" + 3xy' - 8y = 0. One solution is y = x. To find another solution, we will use the method of reduction of order. Assume the second solution is in the form y = vx, where v is a function of x.

1. Compute y' = v'x + v.
2. Compute y" = v''x² + 2v'x.
3. Substitute y, y', and y" into the differential equation: x²(v''x² + 2v'x) + 3x(v'x + v) - 8(vx) = 0.
4. Simplify the equation: x(v''x² + 2v'x) + 3(v'x + v²) - 8v = 0.
5. Factor out x: v''x² + 2v'x + 3v'x + 3v² - 8v = 0.
6. Solve for v: v''x² + 5v'x + 3v² - 8v = 0, v = x².
7. Calculate the second solution: y = vx = x(x²) = x³.

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Integral ≈ 904

Let's evaluate the integral of the given function:

∫[-5(-x³ - 10x² - 32x - 36)]dx from -2 to 2 First, we can distribute the -5 to each term inside the parentheses: ∫(5x³ + 50x² + 160x + 180)dx

Now, let's find the antiderivative of the function: Antiderivative: (5/4)x^4 + (50/3)x³ + 80x² + 180x + C

Now, we'll evaluate the antiderivative at the limits of integration, 2 and -2:

F(2) = (5/4)(2^4) + (50/3)(2^3) + 80(2^2) + 180(2) F(-2) = (5/4)(-2^4) + (50/3)(-2^3) + 80(-2^2) + 180(-2)

Now, subtract F(-2) from F(2) to get the integral value: Integral = F(2) - F(-2) Perform the arithmetic operations to get the final answer: Integral ≈ 904

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The critical value of t is approximately 1.895.

The critical value of t is approximately 2.626.

What is Confidence Interval?

In statistics, a confidence interval is a range of values calculated from a sample of data that is likely to contain the true value of an unknown population parameter with a certain level of confidence, usually expressed as a percentage. It is a measure of the precision and reliability of an estimate.

a) Using a t-distribution calculator or a t-table with 7 degrees of freedom and a 90% confidence level, the critical value of t is approximately 1.895.

b) Using a t-distribution calculator or a t-table with 103 degrees of freedom and a 99% confidence level, the critical value of t is approximately 2.626.

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The maximum value achieved by f(x) on the interval [0,6] is 21, which occurs at x=3. The minimum value is -12, which occurs at x=0 and x=6.

To find these values, we take the derivative of f(x), set it equal to zero, and solve for x. We then plug in the values of x and evaluate f(x) to find the corresponding maximum and minimum values.

Since the derivative is positive to the left of x=3 and negative to the right, we know that we have a maximum value at x=3.

Similarly, since the derivative is negative to the left of x=0 and positive to the right of x=6, we know that we have minimum values at x=0 and x=6. The graph of f(x) also confirms these results.

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The width of the triangle is 12 inches, and the height of the triangle is 44 inches.

Let w = the width of the triangle and h = the height.

The area of the triangle = 264 in²

Area of a triangle is given as A = (1/2) * base * height

Since the base of the triangle is the width "w," we can write the equation as:

264 = (1/2) * w * h

Therefore:

h = 4w - 4

Substitute the value of "h" in terms of "w" into the area equation:

264 = (1/2) * w * (4w - 4)

Now, we can solve for "w":

264 = 2w² - 2w

2w² - 2w - 264 = 0

Divide the entire equation by 2 to simplify:

w² - w - 132 = 0

factorize:

(w - 12)(w + 11) = 0

w = 12 or w = - 11

The width of the triangle cannot be negative, therefore:

Width "w" of the triangle = 12 inches.

Now, we can find the height "h" using the equation we derived earlier:

h = 4w - 4

h = 4(12) - 4

h = 44 in.

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The vector v, which begins at the origin and ends at the terminal point P2, can be expressed in standard form as (-5)i + (6)j.

A vector can be expressed in terms of its components along the x-axis (horizontal direction) and y-axis (vertical direction) using the notation ⟨x,y⟩. In other words, a vector can be represented as the sum of two component vectors, one along the x-axis and the other along the y-axis.

To find the components of the vector v that begins at the initial point P1 and ends at the terminal point P2, we can subtract the coordinates of P1 from the coordinates of P2. In other words, we can write:

v = ⟨(-2-3), (5-(-1))⟩ = ⟨-5, 6⟩

To express this vector in terms of i and j, we need to find the scalar multiples of i and j that add up to the vector v. We can do this by multiplying each component of v by the corresponding unit vector. In other words:

v = (-5)i + (6)j

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The American founding father and litterateur Thomas Paine referred to as King George III" the Royal Brute of high-quality Britain."

Paine was a main figure within the American Revolution and was a fierce advocate of american independence from British rule. He wrote a series of influential pamphlets, which includes" Common feel" and" The Rights of man," which helped to excite assist for the progressive reason.

In his thoughts, Paine often blamed the British monarchy and its leaders, including King George III, whom he saw as a dictator and an oppressor. His slicing phrases helped to rally reinforcement for the purpose of America self-reliance and performed a significant element in shaping the path of history.

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The minimum temperature is -26°F, and it occurs at the point

(x, y) = (3, 1).

We have,

To find the minimum temperature and its location, we need to minimize the given temperature function.

The temperature function is 2x² + 2y = 12x + 8y.

To minimize this function, we can take partial derivatives with respect to x and y and set them equal to zero.

∂T/∂x = 4x - 12 = 0

∂T/∂y = 2 - 8 = 0

Solving these equations, we get x = 3 and y = 1.

Substituting these values back into the temperature function, we can find the minimum temperature:

T_min = 2(3)² + 2(1) - 12(3) - 8(1)

= 18 - 36 - 8

= -26°F

Regarding the maximum temperature, since we found the minimum temperature to be -26°F, there is no maximum temperature as the temperature function does not have an upper bound.

Therefore,

The minimum temperature is -26°F, and it occurs at the point

(x, y) = (3, 1).

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Graduate student conducts survey about study habits, and scatter plot represents data point of one student and orange line represents linear relationship between 2 variables.

In this scenario, the graduate student is conducting a survey on undergraduate study habits by collecting data on students from different years in college. The data collected is a sample of four students, which may not represent the entire population of undergraduate students on campus.

The graduate student collects data by asking the students how many hours of course work they do for each class in a typical week. This data is then used to create a scatter plot, which shows the relationship between the year in college and hours of course work per class.

In the scatter plot, each blue circle represents one student's data point, and the orange line represents the linear relationship between the two variables. The equation for the orange line is Y = –2X + 9, where Y represents the hours of course work per class and X represents the year in college.

It is important to note that the accuracy of the survey results depends on the representativeness of the sample collected. A larger sample size and a more diverse sample may provide more accurate results in survey.

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The variables used in this multiple regression analysis are:
- Weekly sales of the brand (dependent variable)
- Media advertising (in thousands of dollars) (independent variable)
- Price (in dollars) (independent variable)
- Use of displays (in number of stores with the brand on an end-aisle display) (independent variable)

In the multiple regression analysis mentioned in the question, the product manager of the all-natural herbal shampoo brand used the following variables:

1. Weekly sales of the brand (in units) - This is the dependent variable, as it depends on the other factors mentioned below.

2. Level of media advertising (in thousands of dollars) - This is an independent variable, as it is one of the factors affecting the weekly sales.

3. Price (in dollars) - This is also an independent variable, as it influences the weekly sales of the brand.

4. Use of displays (in number of stores with the brand on an end-aisle display) - Lastly, this is another independent variable, as the presence of the product on end-aisle displays can impact the weekly sales.

So, the dependent variable is weekly sales, and the independent variables are the level of media advertising, price, and use of displays.

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The marginal PDF of X is:

fx(x) = 0 for all x

Now, For the marginal PDF of X, we need to integrate the joint PDF fxy (x,y) over all possible values of y.

This will leave us with a function in terms of x only, which is the marginal PDF of X.

So, the integral we need to evaluate is:

fx(x) = ∫ (- ∞, ∞) fxy(x,y) dy

Using the given joint PDF:

fxy(x,y) = [tex]ce^{x+ y}[/tex]

We can substitute it in the above integral:

fx(x) =  ∫ (- ∞, ∞) ce^(x+y) dy

Now, we can solve this integral:

fx(x) = c  eˣ  ∫ (- ∞, ∞) e^y dy

The integral from -inf to inf of e^y dy is just the constant 1, since this is the area under the curve of the exponential function, which is equal to 1.

fx(x) = c eˣ

Since the PDF must integrate to 1, we know that:

integral from -inf to inf of fx(x) dx = 1

Using the above equation, we can solve for the constant c:

∫ (- ∞, ∞) c  eˣ dx = 1

c  ∫ (- ∞, ∞) eˣ dx = 1

c  [eˣ]  (- ∞, ∞) = 1

c * (e^inf - e^-inf) = 1

c * (inf + inf) = 1

c * inf = 1

c = 1 / inf

c = 0

Therefore, the marginal PDF of X is:

fx(x) = 0 for all x

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The confidence interval (0.51, 0.68), determine, the value of E is 0.085, which is option (b).

The value of E, also known as the margin of error, can be determined using the formula:

E = (upper bound of CI - lower bound of CI) / 2

In this case, the upper bound of the confidence interval is 0.68 and the lower bound is 0.51, so:

E = (0.68 - 0.51) / 2 = 0.085

The margin of error is a measure of the precision of an estimate, and it indicates the amount by which the estimate may differ from the true population value. The smaller the margin of error, the more precise the estimate. The margin of error is affected by the sample size and the level of confidence. A larger sample size and a higher level of confidence will result in a smaller margin of error.

It's important to note that the margin of error only provides a range of plausible values for the true population parameter, and it doesn't guarantee that the true value falls within that range. Therefore, it's always important to interpret the results of a study or survey with caution and consider other factors that may impact the accuracy of the estimate.

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Mr. Robbin's commission rate is 15%.

A commission is a service charge assessed by a broker or investment advisor for providing investment advice or handling purchases and sales of securities for a client.

We know that:

commission = rate * sales

where "commission" is the amount earned in commission, "rate" is the commission rate, and "sales" is the total amount of sales.

In this case, we have:

commission = $31.29

sales = $208.60

Substituting these values into the formula, we get:

$31.29 = rate * $208.60

Solving for the rate, we get:

rate = $31.29 / $208.60

= 0.15 or 15%

Therefore, Mr. Robbin's commission rate is 15%.

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The vertex of the parabola y = -x² + 6x + 1 is (3, 10).

To find the vertex of the parabola y = -x² + 6x + 1, we first need to find the derivative of the function. The derivative of a function is another function that describes the rate of change of the original function at each point. In this case, we will find the derivative of y with respect to x, denoted by f'(x).

To find the derivative of y, we can use the power rule of differentiation, which states that the derivative of xⁿ with respect to x is nxⁿ⁻¹. Using this rule, we can find the derivative of y = -x² + 6x + 1 as follows:

f'(x) = -2x + 6

Now that we have the derivative, we can find the x-coordinate of the vertex by setting f'(x) = 0 and solving for x:

-2x + 6 = 0

2x = 6

x = 3

Therefore, the x-coordinate of the vertex is x = 3. To find the y-coordinate, we can substitute x = 3 into the original equation of the parabola:

y = -x² + 6x + 1

y = -(3)² + 6(3) + 1

y = -9 + 18 + 1

y = 10

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The probability that a randomly selected observation is between 23 and 85 is 31/35 or approximately 0.886.

To find the probability that a randomly selected observation is between 23 and 85, we need to calculate the area under the probability density function (PDF) between 23 and 85.

Since X is a uniform random variable, the PDF is a horizontal line with height 1/(90-20) = 1/70 over the interval [20, 90].

The area under the PDF between 23 and 85 is the area of a rectangle with width 85-23 = 62 and height 1/70, which is (62)(1/70) = 31/35.

Therefore, the probability that a randomly selected observation is between 23 and 85 is 31/35 or approximately 0.886.

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In light of the geometry puzzle, the tiles that correspond to the right boxes are mentioned below:

m∠COB = 114°

The measure of arc CE = 124°

m∠EOB = 122°

m∠DFA = 58°

A branch of mathematics known as geometry is concerned with the study of objects' forms, angles, dimensions, and sizes. A very significant area of mathematics that is covered in many levels of instruction is geometry. It enables us to relate to things and forms more efficiently, as well as their angles and measurements.

The calculation is attached in the file.

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The problem involves classifying 414 elephants into three groups: alpha, beta, and gamma. The equations and solutions for the three unknowns are x + y + 2 = 414 and x = 1/5(y + 2). The system is solved using matrices. It is explained why the group of 414 elephants must have 63 alpha, regardless of the distribution of the other two types.  the required number of the other two types is 250 gamma and 101 beta.

From the given information, we can set up two equations as follows

x + y + z = 414 (where x, y, and z represent the number of elephants in the alpha, gamma, and beta groups, respectively)

And, x = 1/5(y + 2)

To solve the system in terms of a parameter t, we can represent it in matrix form as follows

[tex]\left[\begin{array}{ccc}1&1&1\\1/5&-1&0\\\end{array}\right][/tex] [tex]\left[\begin{array}{cc}x\\y\end{array}\right][/tex] = [tex]\left[\begin{array}{cc}414\\0\\\end{array}\right][/tex]

Using matrix operations, we can solve for x and y in terms of z, which gives us

x = 83 - z/5

y = 331/5 + z/5

The total number of elephants in the alpha group is 69, regardless of the distribution of the other two types because we know that x + y + z = 414 and x = 1/5(y + 2). Substituting the second equation into the first, we get

(1/5)y + (1/5)2 + y + z = 414

Simplifying the equation, we get

6y + 5z = 2060

Since the total number of elephants is 414, we know that z = 414 - x - y. Substituting this into the equation above, we get

6y + 5(414 - x - y) = 2060

Simplifying this equation, we get

x + y = 69

Therefore, the number of alpha elephants is always 69, regardless of the distribution of the other two types.

If there are only 101 beta elephants available, we can set up a new equation as follows

x + y + z = 414

z = 101

Substituting z = 101 into the first equation, we get

x + y = 313

Using the equation x = 1/5(y + 2) from part a, we can solve for x and y, which gives us

x = 63

y = 250

Therefore, there are 63 alpha, 250 gamma, and 101 beta elephants.

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The minimum value of f(x, y) = 43x² + 11y² subject to the constraint x² + y² = 324 is 3564.

To find the minimum value, we use the method of Lagrange multipliers. Define a function L(x, y, λ) = 43x² + 11y² - λ(x² + y² - 324). Take partial derivatives with respect to x, y, and λ and set them to zero:

1. ∂L/∂x = 86x - 2λx = 0
2. ∂L/∂y = 22y - 2λy = 0
3. ∂L/∂λ = x² + y² - 324 = 0

From equations (1) and (2), we get x = y = 0 or λ = 43 for x and λ = 11 for y. Substituting λ = 43 into equation (3) gives x² + y² = 324. Solving for x and y, we get x = 18 and y = 6. Substituting these values into f(x, y), we obtain f(18, 6) = 3564, which is the minimum value.

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There is not sufficient evidence to support the claim that the mean score of students at XYZ is significantly different from 100.

The effect size is small, which means that the difference between the sample mean, and the population mean is not very large relative to the variability within the sample.

Test may not have sufficient statistical power to detect a meaningful difference in mean scores between the population and the sample.

We want to test the hypothesis that the mean score of students at XYZ is not significantly different from 100, at a significance level of 0.01.

Let's start by calculating the sample mean and sample standard deviation:

[tex]Sample mean (\bar x) = (80+60+120+140+200+70+30+180+70+150+20+50+170+90+130)/15 = 105.33[/tex]

Sample standard deviation (s) = 52.411

The test statistic for a two-tailed t-test with n-1 degrees of freedom is:

[tex]t = (\bar x - \mu ) / (s / \sqrt n)[/tex]

where μ is the hypothesized population mean.

Plugging in the values, we get:

[tex]t = (105.33 - 100) / (52.411 / \sqrt 15) = 1.208[/tex]

The critical t-value for a two-tailed test with 14 degrees of freedom and α =[tex]0.01 is \±2.977.[/tex]

Since our calculated t-value (1.208) falls within the acceptance region (between -2.977 and 2.977), we fail to reject the null hypothesis.

To compute the effect size, we can use Cohen's d:

[tex]d = (\bar x - \mu) / s[/tex]

where μ is the population mean and s is the sample standard deviation.

Plugging in the values, we get:

[tex]d = (105.33 - 100) / 52.411 = 0.104[/tex]

To estimate the power of the hypothesis test, we need to know the effect size, sample size, and significance level.

We have already calculated the effect size (d = 0.104), and the significance level is [tex]\alpha = 0.01.[/tex]

Assuming a sample size of n = 15, we can use the power curve chart to find the power of the test.

The chart shows that for a two-tailed t-test with n = 15 and α = 0.01, the power is approximately 0.26 when the effect size is 0.104.

Based on the power curve chart, the power of the test is relatively low (0.26), which means that there is a high probability of a Type II error (failing to reject the null hypothesis when it is actually false).

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Answer:

A, up I think

Step-by-step explanation:

The explorer is currently on a white circle with an X inside, and they must go through all the white circles exactly once. This means that their next move must be to either the white circle to the left or to the right of the X. However, the white circle to the right of the X is already connected to the black circle, which means that the explorer cannot use that path. Therefore, their next move must be to the white circle to the left of the X.Looking at the maze, the only way to get to the white circle to the left of the X is by going up. Therefore, the correct answer is (A) arrow pointing up.

(a) By giving each registered voter in the city a special number, and then choosing 200 numbers at random from the list, a straightforward random sample of registered voters in the City of Madison might have been obtained.

(b) Based on the available data, the true percentage of registered voters in the City of Madison who cast ballots in non-presidential elections has an 80% confidence interval of (0.533, 0.687).

(c) The interval means that approximately 80% of the calculated 80% confidence intervals for the proportion of voters who participate in non-presidential elections would contain the actual proportion of voters who participate in non-presidential elections if we were to take numerous random samples of 200 registered voters from the City of Madison.

(d) We cannot conclude that fewer than half of registered voters in the City of Madison vote in non-presidential elections, as the lower bound of the confidence interval is 0.533 which is greater than 0.5.

(a) A simple random sample of registered voters in the City of Madison could have been gathered by assigning each registered voter in the city a unique number, and then using a random number generator to select 200 numbers from the list.

(b) To construct an 80% confidence interval for the true proportion of registered voters in the City of Madison who vote in non-presidential elections, we can use the following formula:

[tex]CI = \hat{p} +/- z*(\sqrt{(\hat{p}(1-\hat{p})/n)} )[/tex]

where [tex]\hat{p}[/tex]  is the sample proportion (122/200 = 0.61),

z is the critical value from the standard normal distribution corresponding to an 80% confidence level (z = 1.28), and n is the sample size (200).

Plugging in the values, we get:

[tex]CI = 0.61 +/- 1.28* \sqrt{((0.61*(1-0.61)/200))}[/tex]

CI = 0.61 ± 0.077

Therefore, the 80% confidence interval for the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.533, 0.687).

(c) We can interpret this interval as follows: If we were to take many random samples of 200 registered voters from the City of Madison and calculate a 80% confidence interval for the proportion of voters who vote in non-presidential elections, about 80% of these intervals would contain the true proportion of voters who vote in non-presidential elections.

(d) Since the lower bound of the confidence interval is 0.533, which is greater than 0.5, we cannot conclude that fewer than half of registered voters in the City of Madison vote in non-presidential elections.

However, we can say with 80% confidence that the true proportion of voters who vote in non-presidential elections is somewhere between 0.533 and 0.687.

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Answer:

a. 61%

b. $1315.77

Step-by-step explanation:

a. find percent = part/whole = 732/1200 = 0.61 = 61%

b. 61% of $2157 = 2157 x 0.61 = $1315.77

Answer:

-x³ + 2x + 7

2x^5+x^4-x³+6x²+3x-3

Step-by-step explanation:

For #10:

(f-g)(x) = f(x) - g(x)

x³-2x+3 - (2x³ + 4x - 4)

-x³ + 2x + 7

For #11:

(f·g)(x) = f(x) * g(x)

(x³+3)(2x²+x-1) = 2x^5+x^4-x³+6x²+3x-3

The two events, selecting a queen and then selecting a king, are dependent events.

When the first card is drawn and not replaced, the number of cards in the deck decreases by one. This means that the probability of drawing a king on the second draw depends on whether or not a queen was drawn on the first draw.

If a queen was drawn on the first draw and not replaced, then there are fewer cards in the deck and the probability of drawing a king on the second draw decreases.

On the other hand, if a queen was not drawn on the first draw and not replaced, then there are more cards in the deck and the probability of drawing a king on the second draw increases.

Therefore, the probability of drawing a king on the second draw is dependent on whether or not a queen was drawn on the first draw. Hence, the two events, selecting a queen and then selecting a king, are dependent events.

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The probability that a randomly selected adult spends more than 2.5 hours on social media is approximately 45.82%.

According to the American Time Use Survey, adult Americans spend an average of 2.3 hours per day on social media, with a standard deviation of 1.9 hours. To find the probability that a randomly selected adult spends more than 2.5 hours on social media, we can use the z-score formula:

Z = (X - μ) / σ

Where X is the value we're interested in (2.5 hours), μ is the mean (2.3 hours), and σ is the standard deviation (1.9 hours).

Z = (2.5 - 2.3) / 1.9 = 0.2 / 1.9 ≈ 0.1053

Now, we can use a z-table to find the probability of a z-score greater than 0.1053. The corresponding probability is approximately 0.4582.

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Answer:

(x,y) become (-x,-y), so all you have to do is take those coordinates and make them negative unless they already are negative. For example: E (-1,3) would become E (1,-3) since two negatives cancel each other out. For the rest do this: F (1,4) becomes F (-1,-4). Do the same strategy for the rest of the points, then graph your answer.

Step-by-step explanation: