Wiggins notes that race-based explanations of sports performance were harder to find in the early 20th century. How does Wiggins explain this phenomenon?

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Answer 1

Wiggins explains the fact of the lack of racialized explanations of athletic performance in the early 20th century, with respect to the dominant ideologies at the time.

During this time, segregation and discrimination were justified in many parts of society since it was widely believed that people of different races had inherent and unchangeable distinctions in their physical and mental skills. Sports, on the other hand, placed more emphasis on individual effort and training than on innate physical or mental qualities, hence there was less emphasis on race-based explanations of achievement. In other words, in the early 20th century, sports were seen as a meritocracy, where success was based on one's individual abilities and hard work, rather than one's race.

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Start a ball rolling down a bowling alley and you'll find that it moves slightly slower with time. Does this violate Newton's first law? Defend your answer.

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As it is a result of external forces acting upon it rather than a failure to maintain its state of motion.

The observation that a ball rolling down a bowling alley moves slightly slower with time does not violate Newton's first law of motion, also known as the law of inertia.

Newton's first law states that an object at rest will remain at rest, and an object in motion will remain in motion with a constant velocity (which includes moving at a constant speed in a straight line or moving with a constant speed in a curved path) unless acted upon by an external force. In other words, an object will maintain its state of motion (or lack thereof) unless an external force is applied to it.

In the case of a ball rolling down a bowling alley, the ball is subject to various external forces that act upon it and cause it to slow down. These forces include friction between the ball and the lane, air resistance, and deformation of the ball itself. These forces act in the opposite direction of the ball's motion and cause it to lose speed over time, as the ball's kinetic energy is dissipated into other forms of energy.

Therefore, the ball's decrease in speed over time is not a violation of Newton's first law, as it is a result of external forces acting upon it rather than a failure to maintain its state of motion.

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Rigel is more luminous than Sirius B. Rigel and Sirius B have the same temperature.Which star has the greater surface area?a.Rigelb. Sirius Bc. The samed. Not enough information

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Rigel has a larger surface area than Sirius B due to its higher luminosity. Option B is the correct answer.

The Stefan-Boltzmann law relates the luminosity, radius, temperature, and surface area of a star. If two stars have the same temperature but one is more luminous than the other, we can use this law to determine which star has the larger surface area.

The formula shows that luminosity is proportional to the surface area, so if one star is much more luminous than the other, it must have a larger surface area, L = 4πR²σ[tex]T^4[/tex]. In this case, Rigel is much more luminous than Sirius B, so we can conclude that Rigel has a greater surface area.

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The question is -

Rigel is much more luminous than Sirius B. Rigel and Sirius B has the same temperature.

Which star has the greater surface area?

a) Rigel

b) Sirius B

c) They have the same surface area.

d) There is insufficient information to answer this question

A substance is heated from 15°C to 35°C. What would the same incremental change be when registered in kelvins?

Answers

To convert Celsius to Kelvin, you simply add 273.15. Therefore, 15°C is equivalent to 288.15 K and 35°C is equivalent to 308.15 K. The incremental change in Kelvins would be 20 K (308.15 K - 288.15 K = 20 K).

To determine the incremental change in kelvins when a substance is heated from 15°C to 35°C, follow these steps:
1. Find the temperature difference in Celsius: 35°C - 15°C = 20°C
2. Convert the temperature difference to Kelvin: Since 1°C = 1K, the incremental change in kelvins is the same as in Celsius. The incremental change when registered in kelvins would be 20K.

Kelvin 0 degrees is the temperature or kinetic energy of zero. Because these scales don't start at zero, changes in Celsius or Fahrenheit don't directly relate to kinetic energy or volume. The worth of one degree on the Kelvin scale is indistinguishable from the worth of one degree on the Celsius scale that is the temperature differential or change is indistinguishable on the two scales.

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what is the total amount of m112 (in 1.25 lb. packages) needed to breach a 6-foot thick first class masonry wall utilizing a ground placed untamed charge?

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The amount of M112 required to breach a 6-foot thick first-class masonry wall will depend on various factors such as the dimensions and characteristics of the wall, the placement and configuration of the charge, and the specific properties and performance of the explosive material.

Therefore, it is difficult to give a definitive answer without additional information. However, it is important to note that the use of explosives is a highly regulated activity that requires specialized training and permits. It should only be performed by authorized and trained personnel following established safety protocols and regulations.

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A radioactive substance has a mean-life τ of 16 years. Assume we start with 166 kg of the substance. How many kg of the substance will be left after 27 years?Enter a number with one digit after the decimal point. Lowercase e^x is a button on the calculator.

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A radioactive substance has a mean-life τ of 16 years. 35.5 kg of the substance will be left after 27 years. So after 27 years, there will be approximately 30.6 kg of the radioactive substance left.


We can use the formula for radioactive decay:
N(t) = N0 * e^(-λt)
where N(t) is the amount of the substance remaining after time t, N0 is the initial amount, λ is the decay constant (related to the mean-life τ by λ = ln(2)/τ), and e is Euler's number (approximately 2.71828).
We know N0 = 166 kg, τ = 16 years, and t = 27 years. Therefore:
λ = ln(2)/τ = ln(2)/16 = 0.04355 (rounded to five decimal places)
N(27) = 166 * e^(-0.04355 * 27) ≈ 35.5 kg (rounded to one decimal place)
To find out how many kg of a radioactive substance with a mean-life τ of 16 years will be left after 27 years, given that we start with 166 kg, we can use the decay formula:
Remaining amount = Initial amount * e^(-t/τ)
where Remaining amount is the mass left after t years, Initial amount is the initial mass (166 kg), t is the time elapsed (27 years), and τ is the mean-life (16 years)

Step 1: Insert the values into the formula:
Remaining amount = 166 kg * e^(-27/16)
Step 2: Calculate the exponent:
Exponent = -27/16 ≈ -1.6875
Step 3: Calculate e^(exponent):
e^(-1.6875) ≈ 0.1847
Step 4: Multiply the initial amount by the calculated value:
Remaining amount = 166 kg * 0.1847 ≈ 30.6 kg
So after 27 years, there will be approximately 30.6 kg of the radioactive substance left.

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The Millenium Falcon is chased by the Imperial Forces. The ship is moving at a speed of 0. 587 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store for $20. 00 plus 6. 00% tax. The cannon emits protons at a speed of 0. 831 c with respect to the ship. What is the velocity of the protons in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction? (Use positive sign for the forward direction, and negative for the backward direction. )
Tries 0/20
What is the velocity of the protons in the resting frame when the cannon is shot in the backward direction? (Use positive sign for the forward direction, and negative for the backward direction. )

Answers

The Millenium Falcon is chased by the Imperial Forces. The ship is moving at a speed of 0. 587 c. Han Solo is shooting at the imperial fighters with his newly installed proton cannon purchased at the MSU Surplus Store for $20. 00 plus 6. 00% tax. The cannon emits protons at a speed of 0. 831 c with respect to the ship.

With the use of Relativistic velocity addition formula  we will find the velocity of proton in the resting frame of the movie audience in terms of the speed of the light when the cannon is shot in the forward direction
Formula is given as
v = (u+v')/(1+u*v'/[tex]c^{2}[/tex])
Where
v = velocity of the protons in the resting frame of the movie audience

u = velocity of the Millennium Falcon with respect to the audience

v' = velocity of the protons with respect to the Millennium Falcon

c = speed of light

By putting all the values we get
v = (0.587c + 0.831c) / (1 + 0.587c*0.831c/[tex]c^{2}[/tex])

v = (1.418c) / (1 + 0.486)

v = 0.942c

Hence, the velocity of the protons in the resting frame of the movie audience is 0.942 times the speed of light.

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ga 10-cm -long thin glass rod uniformly charged to 7.00 nc and a 10-cm -long thin plastic rod uniformly charged to -7.00 nc are placed side by side, 3.90 cm apart. what are the electric field strengths e1 to e3 at distances 1.0 cm , 2.0 cm , and 3.0 cm , from the glass rod along the line connecting the midpoints of the two rods?

Answers

The total electric field strength along the line connecting the midpoints of a charged glass and plastic rod decreases with distance and is directed towards the plastic rod at distances of 2.0 cm and 3.0 cm.

The negative sign in E1', E2', and E3' indicates that the electric field created by the plastic rod is in the opposite direction to that of the glass rod.

To find the total electric field at each distance, we can use the principle of superposition, which states that the total electric field at a point is the vector sum of the electric fields created by each charged object at that point.

At each distance, the direction of the electric field created by the glass rod is the same, while the direction of the electric field created by the plastic rod is opposite. Therefore, the total electric field E1 to E3 along the line connecting the midpoints of the two rods is given by:

E1 = E1' + E = 0

E2 = E2' + E = -4.86 x 10³ N/C

E3 = E3' + E = -1.61 x 10³ N/C

where E is the electric field created by the glass rod alone.

Thus, at a distance of 1.0 cm from the glass rod along the line connecting the midpoints of the two rods, the total electric field is zero. At distances of 2.0 cm and 3.0 cm, the total electric field is directed towards the plastic rod and decreases in magnitude as the distance increases.

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The question is -

A 10-cm-long thin glass rod uniformly charged to 7.00 nC and a 10-cm-long thin plastic rod uniformly charged to -7.00 nC are placed side by side, 4.20 cm apart. What are the electric field strengths of E1 to E3 at distances 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod along the line connecting the midpoints of the two rods?

T/F Assuming the same velocity at take-off, with the exception of a take-off angle of 45 degrees, there are two take-off angles that will give identical range.

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The given statement is true. Assuming the same velocity at take-off, with the exception of a take-off angle of 45 degrees, there are two take-off angles that will give identical range.

These two take off angles are complementary angles, which means their sum equals 90 degrees. If one angle is θ, the other angle will be (90 - θ). This is because the range of a projectile is determined by both its initial velocity and launch angle, and the range equation has a sine function, which exhibits symmetry for complementary angles.Hence, there are two take-off angles that will give identical range.

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STT 13 Three identical books are stacked vertically. The normal force of book 1 on book 2 A equal to the weight of one bookB less than the weight of one bookC greater than the weight of one book

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The weight of one book B must be less than the weight of one book (w), and the weight of book C must be greater than the weight of one book (w).

Let's assume that the weight of one book is w, then the weight of the three books stacked vertically is 3w.

According to Newton's Third Law, the force exerted by book1 on book2 is equal in magnitude and opposite in direction to the force exerted by book2 on book1.

So, we have:

Normal force of book1 on book2 = w + 2w = 3w

Since the books are identical. Therefore:

Normal force of book1 on book2 = w + 2w = 3w

This normal force is equal in magnitude to the weight of bookC.

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10.5 coulombs of positive charge flows from the +12 V positive terminal of a battery to the negative terminal at 0 V. What is the change in potential energy of the charge?

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To find the change in potential energy of the charge, we need to use the formula:

ΔU = qΔV

where ΔU is the change in potential energy,

q is the charge that flows, and

ΔV is the change in electric potential.

In this case, 10.5 coulombs of positive charge flow from a +12 V potential to a 0 V potential. So the change in electric potential is:

ΔV = Vf - Vi = 0 - 12 = -12 V

The negative sign indicates that the potential difference is in the opposite direction to the direction of the flow of charge.

Now we can use the formula to find the change in potential energy:

ΔU = qΔV = (10.5 C)(-12 V) = -126 J

Therefore, the change in potential energy of the charge is -126 J (joules). The negative sign indicates that the potential energy of the charge has decreased as it flowed from the higher potential to the lower potential.

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which one of the following types of waves is purely longitudinal? select answer from the options below light traveling through a vacuum. surface waves on a shallow pond. sound waves emitted from a speaker. waves on a plucked guitar string. radio waves traveling through air.

Answers

The type of wave that is purely longitudinal among the options provided is sound waves emitted from a speaker.

Longitudinal waves involve particles oscillating parallel to the direction of the wave's propagation, and this is the case for sound waves. Sound waves emitted from a speaker are an example of a purely longitudinal wave. In a longitudinal wave, the oscillations of the particles or medium are in the same direction as the direction of the wave propagation. Sound waves travel through a medium such as air, and as they move, they cause the air particles to vibrate in a parallel direction to the direction of the wave propagation. This results in the compressions and rarefactions of air particles, which we perceive as sound. Therefore, sound waves are classified as longitudinal waves. Other examples of longitudinal waves include seismic waves and ultrasonic waves.

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(T/F) The mechanical energy before and after an event are different.

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True. The mechanical energy before and after an event can be different, as mechanical energy can be converted to other forms of energy or vice versa during the event.

The mechanical energy before and after an event are generally different because mechanical energy is a measure of the potential and kinetic energy of an object or system. In most situations, energy is not conserved, and some energy is lost or gained due to various factors such as friction, air resistance, or heat transfer. For example, when an object falls from a height, its potential energy is converted into kinetic energy. However, as the object collides with the ground, some of the kinetic energy is lost as sound and heat energy, resulting in a decrease in the total mechanical energy of the system.

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A 1.5-kg object has a velocity of 5j m/s at t = 0. It is accelerated at a constant rate for five seconds after which it has a velocity of (6i + 12j) m/s. What is the magnitude of the resultant force acting on the object during this time interval?
1) 3.8 N
2) 3.2 N
3) 2.8 N
4) 4.3 N
5) 4.6 N

Answers

The magnitude of the resultant force acting on the object during this time interval is approximately 2.8 N. The correct option is 3.

To find the magnitude of the resultant force acting on the 1.5-kg object, we first need to determine the acceleration. The initial velocity (v0) is given as 5j m/s, and the final velocity (vf) is (6i + 12j) m/s after 5 seconds (t). We can find the acceleration (a) using the formula:

a = (vf - v0) / t

a = [(6i + 12j) - (0i + 5j)] / 5
a = (6i + 7j) / 5
a = 1.2i + 1.4j m/s²

Now that we have the acceleration, we can find the net force (F) using Newton's second law of motion, F = ma:

F = (1.5 kg) × (1.2i + 1.4j) m/s²
F = 1.8i + 2.1j N

To find the magnitude of the resultant force, we use the Pythagorean theorem:

|F| = √[[tex](1.8)^2 + (2.1)^2[/tex]]
|F| = √(3.24 + 4.41)
|F| = √(7.65)
|F| ≈ 2.8 N

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Stars like our Sun, and stars that may differ from our Sun are defined in temperature ranges. These temperature ranges of stars also describe these qualities
a. Spectral type and Color
b. Spectral type and Mass
c. Spectral type and Density

Answers

Answer:

a. Spectral type and Color

The fundamental frequency of a person's speech tends to be higher when they are excited or joyful.

T/F

Answers

Answer:

The fundamental frequency of a person's speech, also known as the pitch or F0, can vary depending on various factors such as age, gender, emotion, and cultural background. Studies have shown that the fundamental frequency tends to increase when a person is excited or joyful. This increase in pitch during intense emotions is thought to be due to changes in the tension of the vocal cords and increased respiratory activity.

Explanation:

Talk about the situation involves velocity of a wave on a string.

Answers

The velocity of a wave on a string is determined by the tension in the string, the mass of the string, and the linear density of the string.

The mass of the string per unit length is known as its linear density. Since the tension in the string is typically constant, the mass and linear density define the wave's velocity.

The velocity rises when the linear density drops, the string mass rises, or the tension in the string falls. A light, thin string, for instance, will move more quickly than a heavy, thick string.

The medium through which the wave is moving, such as air or a solid, has an impact on the wave's velocity as well.

Compared to a medium like air, a solid medium has a higher wave velocity.

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which of the following statements are true? the average speed of gas molecules decreases with decreasing temperature. the average kinetic energy of gas molecules increases with increasing temperature.

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Both of the following statements are true the average speed of gas molecules decreases with decreasing temperature. the average kinetic energy of gas molecules increases with increasing temperature.

Both statements are true because the average speed of gas molecules decreases with decreasing temperature because as the temperature decreases, the molecules/ gas have less energy, resulting in slower movement. molecules have less energy, resulting in slower movement. move slower due to reduced energy.

On the other hand, the average kinetic energy of gas molecules increases with increasing temperature because as the temperature increases, the molecules move faster and have more energy. When temperature increases, the gas molecules gain more energy and move faster, leading to an increase in their average kinetic energy. The motor energy of an article is the type of energy that it has because of its movement. It is defined as the effort required to propel a mass-bearing object from rest to its stated velocity.

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As a spinning star collapses into a neutron star of a smaller radius, retaining essentially all of its original mass, its angular...

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As a spinning star collapses into a neutron star of a smaller radius, retaining essentially all of its original mass, its angular velocity increases, following the conservation of angular momentum.

This is due to the conservation of angular momentum, which states that the total angular momentum of a system remains constant unless an external torque acts upon it. Since the star's radius decreases during the collapse, its moment of inertia also decreases, causing an increase in its angular velocity to conserve angular momentum.

This effect is known as the "spin-up" phenomenon and is observed in many astrophysical phenomena, including neutron star mergers and black hole formation.

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How can we find the absorbance/concentration for solutions of the same chemical species w/ different concentrations?

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We can use a spectrophotometer to measure the absorbance of each solution at a specific wavelength, then use Beer's Law to calculate the concentration of each solution based on their respective absorbance values and the molar absorptivity coefficient of the solute at that wavelength.

Spectrophotometry is a common analytical technique used to measure the amount of light absorbed by a sample at a specific wavelength. In the case of solutions containing a known chemical species, the amount of light absorbed is directly proportional to the concentration of the solute in the solution, according to Beer's Law. This law states that the absorbance (A) of a solution is equal to the molar absorptivity coefficient (ε) of the solute at a given wavelength, multiplied by the path length (l) of the sample cell, and the concentration (c) of the solute in the solution. Mathematically, this can be represented as:

A = εcl

By measuring the absorbance of solutions of known concentrations at a specific wavelength using a spectrophotometer, we can plot a calibration curve of absorbance versus concentration. This curve can then be used to determine the concentration of an unknown solution of the same chemical species by measuring its absorbance at the same wavelength and using the equation:

c = A / (εl)

Thus, by using a spectrophotometer and Beer's Law, we can determine the concentration of solutions of the same chemical species with different concentrations based on their respective absorbance values and the molar absorptivity coefficient of the solute at that wavelength.

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Capacitance of capacitors depends upon: Answer the space between the conductors. the material between the conductors. the geometry of the conductors. all of these answers. none of these answers.
Capacitance of capacitors depends upon

Answers

The capacitance of capacitors depends upon the space between the conductors, the material between the conductors, and the geometry of the conductors. Therefore, the correct answer is "all of these answers."

Capacitance is a measure of a capacitor's ability to store electrical energy. It is influenced by the following factors:
1. The space between the conductors: As the distance between the conductors increases, the capacitance decreases.
2. The material between the conductors: Different materials have different dielectric constants, which affect the capacitance. A higher dielectric constant results in a higher capacitance.
3. The geometry of the conductors: The surface area and shape of the conductors also influence capacitance. Larger surface areas and specific shapes can increase capacitance.

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a work of 15j is required to stretch a spring 10 cm beyond its natural length. how much work is done to stretch an additional 5 cm?

Answers

It requires 0.375j of work to stretch the spring an additional 5 cm beyond its natural length.

Who much spring required to stretch beyond its natural length?

To stretch the spring 10 cm beyond its natural length requires 15j of work. To stretch it an additional 5 cm requires additional work.

We can use the formula for work done on a spring:

Work = 0.5kx²

Where k is the spring constant and x is the distance the spring is stretched or compressed from its natural length.

Since we know that 15j of work is required to stretch the spring 10 cm, we can solve for k:

15j = 0.5k(0.1m)²

k = 300 N/m

Now we can use this value of k to find the work required to stretch the spring an additional 5 cm:

Work = 0.5(300 N/m)(0.05m)²

Work = 0.375j

It requires 0.375j of work to stretch the spring an additional 5 cm beyond its natural length.

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Your tube is a half meter long, with both ends closed. The speed of sound under current conditions (maybe different from the last experiment) is 344m/s. What is the lowest resonant frequency (largest wavelength)?
Please give units in Hz.

Answers

You have a tube that is half a meter long, with both ends closed, and the speed of sound under current conditions is 344 m/s. You'd like to know the lowest resonant frequency (largest wavelength) with units in Hz.

To find the lowest resonant frequency, we will use the formula for a closed-closed tube:

f = (2n - 1) * (v / 4L)

Here, f is the frequency, n is the harmonic number, v is the speed of sound, and L is the length of the tube. For the lowest resonant frequency, n = 1.

Step 1: Plug in the given values.
f = (2(1) - 1) * (344 m/s / 4(0.5 m))

Step 2: Simplify the equation.
f = (1) * (344 m/s / 2 m)

Step 3: Calculate the frequency.
f = 172 Hz

The lowest resonant frequency (largest wavelength) for your half-meter-long closed-closed tube under the given conditions is 172 Hz.

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Suppose the masses of two objects are the same and that the objects are moving toward each other at the same speed so that m1 = m2 and v1 = - v2 (same speed, opposite direction).
Predict the relative magnitudes of the forces between object 1 and object 2 during the collision.

Answers

When object 1 and object 2 collide, the forces being applied by object 1 to object 2 and by object 2 to object 1 are equal in strength but directed in different directions.

According to Newton's third law of motion, for every action, there is an equal and opposite reaction.

We can suppose that both objects feel equal and opposite forces during the collision because their masses are the same and they are traveling toward one another at the same speed. This is because the force the item experiences are equal to the rate at which its momentum changes, and since the two objects share the same mass and are traveling at the same speed toward one another, their momentum will change in an opposite manner during the collision.

Therefore, The force that objects 1 and object 2 applied to each other when they collided was of similar magnitude, as was the force that objects 2 applied to item 1.

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Horse to pull a cart. According to Newton's third law, if he pulls on the wagon it pulls back on him with an equal force, then the net force is zero, and the wagon will stay put. Explain

Answers

When a horse pulls a cart, it applies a force on the wagon in the forward direction. According to Newton's third law, the wagon also applies an equal and opposite force on the horse in the backward direction. These two forces cancel each other out, resulting in a net force of zero.

In other words, the horse is pulling on the cart, and the cart is pulling back on the horse with an equal force. These forces cancel each other out, resulting in a net force of zero. When there is no net force acting on an object, the object remains at rest or moves at a constant speed in a straight line, according to Newton's first law of motion. Therefore, if the horse pulls on the cart but the cart is stationary or immovable, the net force on the cart is zero, and the cart will not move. However, if there is an additional force acting on it, such as friction from the ground the cart will start to move.

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how can the motion of a charged particle be used to distinguish between a magnetic and an electric field?

Answers

We can distinguish between a magnetic and an electric field by observing the motion of the charged particle, analyzing the direction of motion, and considering the influence of the particle's charge.



1. Observe the motion of the charged particle: When placed in an electric field, a charged particle will experience a force that is either attracted to or repelled from the source of the field, depending on the charge. In a magnetic field, the charged particle will experience a force that is perpendicular to both its velocity and the magnetic field, causing it to move in a circular or helical path.

2. Analyze the direction of motion: In an electric field, the charged particle moves in a straight line along the field lines, either towards or away from the source, depending on its charge. In a magnetic field, the charged particle moves in a curved path, with its direction determined by the right-hand rule.

3. Consider the influence of the particle's charge: In an electric field, the force experienced by the particle is directly proportional to its charge, while in a magnetic field, the force depends on the charge, the velocity of the particle, and the magnetic field strength.

By observing these differences in motion, you can distinguish between the presence of an electric field or a magnetic field acting on a charged particle.

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At an instant when a 4.0-kg object has an acceleration equal to (5i + 3j) m/s2, one of the two forces acting on the object is known to be (12i + 22j) N. Determine the magnitude of the other force acting on the object.
1) 2.0 N
2) 13 N
3) 18 N
4) 1.7 N
5) 20 N

Answers

The magnitude of the other force acting on the object is approximately 13N. Therefore, option (2) is closest and correct.

To determine the magnitude of the other force acting on the object, we can use Newton's second law of motion, which states that the net force ([tex]F_{net}[/tex]) acting on an object is equal to the product of its mass (m) and acceleration (a):

[tex]F_{net}[/tex]= m * a

Given:

Mass of the object (m) = 4.0 kg

Acceleration (a) = (5i + 3j) m/s^2

Known force (F₁) = (12i + 22j) N

To find the unknown force (F₂), we can use the equation:

[tex]F_{net}[/tex] = F₁ + F₂

Substituting the given values, we have:

(12i + 22j) N + F₂ = (4.0 kg) * (5i + 3j) m/[tex]s^2[/tex]

Now, we can equate the corresponding components of the vectors:

12 + F₂ᵢ = 20

22 + F₂ⱼ = 12

Solving these equations, we find:

F₂ᵢ = 20 - 12 = 8

F₂ⱼ = 12 - 22 = -10

Thus, the magnitude of the other force (F₂) can be calculated using the Pythagorean theorem:

|F₂| = [tex]\sqrt{{(F_{2i})^2 + (F_{2j})^2}} = \sqrt{{8^2 + (-10)^2}} = \sqrt{{64 + 100}} \approx 12.81 , \text{N}[/tex]

Rounding to one decimal place, the magnitude of the other force acting on the object is approximately 12.8 N. Therefore, the closest option in the provided choices is 13 N (option 2).

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a mass m at the end of a spring vibrates with a frequency f. when an additional 2kg mass is added to m, the frequency is f/3. what is the value of m?

Answers

The value of m at the end of the spring is approximately 12.33 kg.

How to find the value of mass?

The frequency of a spring-mass system is given by:

f = 1 / (2π) * √(k / m)

where f is the frequency, k is the spring constant, and m is the mass.

Let's call the mass at the end of the spring m1, and the additional mass added to m₁ m₂. We can write two equations for the system, one for each scenario:

f₁ = 1 / (2π) * √(k / m₁) -- Equation 1

f₂ = 1 / (2π) * √(k / (m₁ + m₂)) -- Equation 2

We know that the frequency of the system is reduced to f/3 when m2 is added, so we can write:

f₂ = f/3 -- Equation 3

Now we can substitute Equation 3 into Equation 2:

f/3 = 1 / (2π) * √(k / (m₁ + m₂))

Multiplying both sides by 3 and squaring both sides, we get:

9f² = (k / π²) * (m₁ + m₂)

Similarly, we can substitute Equation 1 into the same equation and get:

f² = (k / π²) * m₁

Dividing the two equations, we get:

9 = (m₁ + m₂) / m₁

Simplifying and rearranging, we get:

m₁ = 9m₂

Therefore, the mass at the end of the spring, m₁, is 9 times the additional mass added, m₂.

Substituting this relationship into Equation 3, we get:

f/3 = 1 / (2π) * √(k / (10m₂))

Solving for m₂:

m₂ = k / (4π²f²) * (10/9)²

We do not have a value for k, so we cannot solve for m₂ directly. However, we do know that m₁ = 9m₂. If we assume that k is constant between the two scenarios, then we can write:

f₁ / f₂ = √(m₁+ m₂) / √m₁

Substituting the relationship m₁ = 9m₂ and f₁ / f₂= 3, we get:

3 = √(10m₂) / 3√m₂

Squaring both sides and simplifying, we get:

m₂ = 27m₂ / 100

Solving for m₂, we get:

m₂ = 100 / 73 kg

Finally, we can calculate m₁:

m₁ = 9m₂ = 900 / 73 kg ≈ 12.33 kg

Therefore, the value of m at the end of the spring is approximately 12.33 kg.

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(C) C = εA/d; if A à 2, C à 2 and if d à 2, C ÷ 2 so the net effect is C is unchanged

A parallel-plate capacitor has a capacitance Co. A second parallel-plate capacitor has plates with twice the area and twice the separation. The capacitance of the second capacitor is most nearly

(A) ¼Co
(B) ½Co
(C) Co
(D) 2Co
(E) 4Co

Answers

The capacitance of the second capacitor is most nearly Co. The correct option is C.

The capacitance of a parallel-plate capacitor is given by:

C = εA/d

where ε is the permittivity of the material between the plates, A is the area of each plate, and d is the separation between the plates.

For the second parallel-plate capacitor, the area of each plate and the separation between the plates are both doubled. Therefore, we have:

C' = ε(2A)/(2d) = εA/d = C

So the capacitance of the second capacitor is unchanged and is equal to the capacitance of the first capacitor, which is Co.

On the other hand other options:

(A) ¼Co - This is incorrect because doubling both the area and separation of the plates would decrease the capacitance of the capacitor, not increase it. So, the capacitance cannot be 1/4 Co.

(B) ½Co - This is also incorrect for the same reason as option A. Doubling both the area and separation of the plates would decrease the capacitance of the capacitor, not increase it. So, the capacitance cannot be 1/2 Co.

(D) 2Co - This is incorrect because doubling both the area and separation of the plates would decrease the capacitance of the capacitor, not double it. So, the capacitance cannot be 2 Co.

(E) 4Co - This is also incorrect for the same reason as options D. Doubling both the area and separation of the plates would decrease the capacitance of the capacitor, not quadruple it. So, the capacitance cannot be 4 Co.

Therefore, the answer is (C) Co.

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What is the acceleration of a projectile when it reaches its highest point? What is its acceleration just before and just after reaching this point?(ch.4)

Answers

The acceleration of a projectile at its highest point is zero. The  acceleration just before and just after reaching this point is due the vertical acceleration of the projectile  due to gravity, which is approximately 9.81 m/s² downward. This value remains constant throughout the projectile's motion.

When a projectile reaches its highest point, its acceleration is zero. This is because at the highest point, the projectile has momentarily come to a stop and is about to start falling back down due to gravity. Just before reaching this point, the acceleration of the projectile is negative, as it is slowing down due to the opposing force of air resistance. Just after reaching the highest point, the acceleration of the projectile becomes positive, as it starts accelerating due to the force of gravity pulling it back down.

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what is the normal force of an object on an inclined plane only being acted upon by gravity?

Answers

The normal force is the force exerted by the inclined plane perpendicular to the surface of the object. When an object is on an inclined plane and is only being acted upon by gravity, the normal force is equal to the component of the force of gravity that is perpendicular to the plane.
The normal force of an object on an inclined plane only being acted upon by gravity can be calculated using the following steps:

1. Identify the object's mass (m) and the angle of inclination (θ) of the plane.
2. Calculate the gravitational force (weight) acting on the object, which is equal to the mass times the acceleration due to gravity (g): F_gravity = m × g (where g ≈ 9.81 m/s²)
3. Determine the normal force (F_normal) acting perpendicular to the inclined plane using the formula: F_normal = F_gravity × cos(θ)

So, the normal force of an object on an inclined plane only being acted upon by gravity is F_normal = m × g × cos(θ).

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