This question is about the application of linear programming (LP). Part(b) is a continuation of Part (a), and Part (c) is not related to Parts (a) and (b). (a) DToys is planning a new social media and TV advertising campaign to reach people. A total budget of $30k is allocated to the campaign and the campaign must run on or within the budget. Moreover, to meet the development needs of the company, at least$10k must be allocated to each medium. It is estimated that every $1k spent on social media ad will reach 15 people and every $1k spent on TV ad will reach 10 people. How should the budgeted amount be allocated between social media and TV? State verbally the objective, constraints and decision variables. Then formulate the problem as an LP model. After that, solve it using the graphical solution procedure. Please limit the answer to within two pages. (40 marks) (b) Show that the worth per additional $1k of budget is reaching 15 more people, which is the same as the number of people reached per $1k spent on social media ad. Interpret what this result means in terms of allocating additional budget. Please limit the answer to within one page. (10 marks) (C) Suppose your Residents' Committee (RC) invites you to give a speech introducing LP. The purpose of the speech is to attract senior citizens (over 65 years old, working in various industries before retirement, passionate about lifelong learning) to sign up for a basic LP course. The course teaches how to formulate a problem as an LP and how to solve it. Write down your complete speech, no more than 400 words. (50 marks)

The total area between the curves y = [tex]\sqrt{225-X^2}[/tex] and y=9x, is approximately 33.784 square units.

To find the total area between the curves, we need to set the two equations equal to each other and solve for x:

[tex]\sqrt{225-X^2}[/tex] = 9x

Squaring both sides:

225 - x^2 = 81x^2

Combining like terms:

82x^2 = 225

Dividing both sides by 82:

x^2 = 225/82

Taking the square root:

x = [tex]\pm[/tex] [tex]\sqrt{\frac{225}{82}}[/tex]

Since we are only interested in the interval 0 < x < 12, we take the positive square root:

x = [tex]\sqrt{\frac{225}{82}}[/tex]

Now we can integrate to find the area:

A = [tex]\int_{0}^{\sqrt{\frac{225}{82}}}[/tex] ([tex]\sqrt{225-X^2}[/tex] - 9x) dx

Using the power rule and the formula for the integral of the square root:

A = [tex]\frac{1}{2}[/tex] ([tex]\frac{\pi}{2}[/tex] [tex]\times[/tex] 15 - 9[tex]\times\sqrt{\frac{225}{82}}[/tex] [tex]\times[/tex] [tex]\sqrt{\frac{225}{82}}[/tex] - [tex]\frac{1}{2}[/tex] [tex]\times[/tex] 0)

Simplifying:

A = [tex]\frac{1}{2}[/tex] ([tex]\frac{15\pi}{2}[/tex] - [tex]\frac{2025}{82}[/tex])

A = [tex]\frac{15\pi}{4}[/tex] - [tex]\frac{10125}{328}[/tex]

Therefore, the total area between the curves y = [tex]\sqrt{225-X^2}[/tex] and y=9x, on the interval 0 < x < 12 is approximately 33.784 square units.

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Answer:

53

Step-by-step explanation:

180-127=53

(a) To construct a 93% confidence interval for the true proportion of all guests who arrive by bus, we can use the normal approximation to the binomial distribution.

Let p be the true proportion of guests who arrive by bus. Then, the sample proportion of guests who arrive by bus is:

P = 30/100 = 0.3

The standard error of the sample proportion is:

SE = sqrt[P(1-P)/n]

where n is the sample size.

Substituting the values, we get:

SE = sqrt[(0.3)(0.7)/100] ≈ 0.048

Using a 93% confidence level, we find the z-score from the standard normal distribution:

z = 1.81

The 93% confidence interval is then:

0.3 ± (1.81)(0.048)

0.3 ± 0.087

(0.213, 0.387)

Therefore, we can say with 93% confidence that the true proportion of all guests who arrive by bus is between 0.213 and 0.387.

(b) To estimate the required sample size n, we can use the formula:

n = (z^2 * P * (1-P)) / E^2

where E is the margin of error, which is 0.05 in this case.

Substituting the given values, we get:

n = (1.81^2 * 0.3 * 0.7) / 0.05^2

n ≈ 247.26

Rounding up to the nearest integer, we get the required sample size as 248. Therefore, if the restaurant wants to obtain a narrower estimate so that its error of estimate is within 0.05, with a 93% confidence, it should poll at least 248 guests.

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Therefore, the absolute minimum value of f(x) on the interval [-3, 3] is ln(2) ≈ 0.693, and the absolute maximum value is ln(32) ≈ 3.465.

To find the absolute minimum and maximum values of f(x) = ln(x² + 5x + 8) on the interval [-3, 3], we first need to find the critical points and endpoints of the interval.
Taking the derivative of f(x), we get:
f'(x) = (2x + 5)/(x² + 5x + 8)
Setting this equal to zero to find critical points, we get:
2x + 5 = 0
x = -5/2
Since -5/2 is not within the interval [-3, 3], we only need to consider the endpoints of the interval.
Evaluating f(-3) and f(3), we get:
f(-3) = ln(2) ≈ 0.693
f(3) = ln(32) ≈ 3.465
Since the function f(x) is continuous on the interval [-3, 3], the absolute minimum and maximum values must occur at either the critical points or the endpoints.

Since there are no critical points in the interval, the absolute minimum and maximum values must occur at the endpoints.

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The likelihood of it not raining both days day is 0.28, or 28%.

Who is the originator of probability?

An exchange if letters between two important mathematicians--Blaise Pascal or Pierre de Fermat--in the mid-17th century laid the groundwork for probability, transforming the way mathematicians and scientists regarded uncertainty and risk.

for Monday is 1 - 0.6 = 0.4 while the probability of rain for Thursday equals 1 - 0.3 = 0.7.

Because we assume that rain on Monday or rain on Thursday were independent events, the likelihood of no precipitation for both days is simply a function of the probabilities for zero rain on each day.

So the chances of it not raining on either day are:

P(no rain Monday and Thursday) = P(no rainfall Monday) x P(no rain Thursday) = 0.4 x 0.7 = 0.28

As a result, the likelihood of it not raining both days day is 0.28, or 28%.

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The critical value of $$\chi^2$$ for H1: σ > 26.1 with n = 9 and α = 0.01 is 18.475

To find the critical value or values of $$\chi^2$$, we need to use the chi-square distribution table or a calculator.

First, we need to determine the degrees of freedom (df) which is df = n - 1 = 9 - 1 = 8.

Next, we need to find the right-tailed critical value at a significance level of 0.01 and df = 8. From the chi-square distribution table or a calculator, we find that the critical value is 18.475.

Therefore, the critical value of $$\chi^2$$ for H1: σ > 26.1 with n = 9 and α = 0.01 is 18.475. If the calculated chi-square value is greater than this critical value, we can reject the null hypothesis in favor of the alternative hypothesis that the population standard deviation is greater than 26.1.

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Answer:

a 495

Step-by-step explanation:

count 180 then add 45 to ur answer

Answer:

677,890.77 dollars.

Step-by-step explanation:

To find the future value of the income stream, we can use the continuous compound interest formula:

FV = Pe^(rt)

Where FV is the future value, P is the present value, e is Euler's number (approximately 2.71828), r is the interest rate, and t is the time period.

In this case, the present value (P) is the revenue generated at a rate of R(t) = 150000 dollars/year for 4 years, so:

P = 150000 dollars/year * 4 years = 600000 dollars

The interest rate (r) is 2.8%/year, or 0.028/year as a decimal. The time period (t) is also 4 years.

Substituting these values into the formula, we get:

FV = 600000 * e^(0.028*4)

FV = 677,890.77 dollars

Therefore, the future value of this income stream after 4 years with continuous compounding at an interest rate of 2.8% per year is 677,890.77 dollars.

The solution of equation 4 cos²x-1=0 is x= 60 degree

We have,

4 cos²x-1=0

Now, simplifying the equation

4 cos²x = 1

cos²x= 1/4

cos x = √1/4

cos x= ± 1/2

x= [tex]cos^{-1[/tex](1/2)

as, by trigonometric ratios we know that cos 60 = 1/2.

So, x=  [tex]cos^{-1[/tex](cos 60)

x= 60 degree

Thus, the required solution is x= 60 degree.

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They are similar because it is possible to map one parallelogram to the other using a dilation and a reflection, which are both similarity transformations.

Examples of transformations are given as follows:

All these transformations are similarity transformations, as the figures continue having the same angle measures.

The transformations in this problem are given as follows:

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Probability is a branch of mathematics that deals with the study of random events or phenomena.

The probability of an event A is denoted by P(A) and is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. In other words:

P(A) = number of favorable outcomes / total number of possible outcomes

The probability of an event can be affected by various factors such as the sample space, the nature of the event, and the presence of other events. Probabilities can be combined using various rules such as the addition rule, the multiplication rule, and the conditional probability rule.

It is used to model and analyze various phenomena such as games of chance, genetics, weather forecasting, stock prices, and risk assessment, among others. The 1990s decade has 10 years, so there are 3650 days in total. The probability of guessing any particular day correctly is 1/3650. Therefore, the probability of guessing the exact birth date (including year) of a randomly selected mystery person born in the 1990s is 1/3650, which is approximately 2.738 x 10^-4.

So, the answer is option C. 2.738 x 10^-4.

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The antiderivative of Sv(v²+2)dv, which is Sv⁴/4 + Sv² + C.

To find the antiderivative of Sv(v²+2)dv, we can start by using the power rule of integration. The power rule states that the integral of xⁿ with respect to x is equal to xⁿ⁺¹/(n+1) + C, where C is the constant of integration.

Applying the power rule to the integrand Sv(v²+2)dv, we can first distribute the Sv term:

∫ Sv(v²+2)dv = ∫ Sv³ dv + ∫ 2Sv dv

Now, using the power rule, we can integrate each term separately:

∫ Sv³ dv = S(v³+1)/(3+1) + C1 = Sv⁴/4 + C1

∫ 2Sv dv = 2∫ Sv dv = 2(Sv²/2) + C2 = Sv² + C2

Putting these two antiderivatives together, we get the general indefinite integral of Sv(v²+2)dv:

∫ Sv(v²+2)dv = Sv⁴/4 + Sv² + C

Where C is the constant of integration.

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The equation that could be used to determine M, the unknown side length of the logo, is M = (5/36) x Maximum allowed area.

Let's assume that the length of the rectangular logo is 7 1/5 feet, which is equivalent to 36/5 feet.

Let's also assume that the width of the logo is M feet.

The area of the rectangular logo can be calculated using the formula:

Area = length x width

Since the area is exactly the maximum allowed by the building owner, we can write:

Area = Maximum allowed area

Substituting the given values, we get:

Area = 36/5 x M

Area = Maximum allowed area

Simplifying the equation, we get:

M = (5/36) x Maximum allowed area

Therefore, the equation that could be used to determine M, the unknown side length of the logo, is M = (5/36) x Maximum allowed area.

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The x-value corresponding to the absolute minimum value of f on the given interval (0,0) for f(x) = -5x¹⁴ / e²ˣ does not exist

To find the x-value corresponding to the absolute minimum value of f on the given interval, we need to take the derivative of f and set it equal to 0, then check the second derivative to confirm that it's a minimum.

So first, we take the derivative of f

f'(x) = (-5x¹⁴ e²ˣ - 10x¹³ e²ˣ) / e²ˣ

Next, we set f'(x) equal to 0:

(-5x¹⁴ e²ˣ - 10x¹³ e²ˣ) / e²ˣ = 0

Simplifying, we get:

-5x¹⁴ - 10x¹³ = 0

Dividing both sides by -5x¹³, we get:

x = -2/5

Now we need to check the second derivative to confirm that this is a minimum. We take the second derivative of f

f''(x) = (-5x¹⁴ e²ˣ - 10x¹³ e²ˣ)(4x-27) / e⁴ˣ

Plugging in x = -2/5, we get:

f''(-2/5) = (-5(-2/5)¹⁴ [tex]e^{-4/5}[/tex] - 10(-2/5)¹³  [tex]e^{-4/5}[/tex])(4(-2/5)-27) / [tex]e^{-8/5}[/tex]

f''(-2/5) = -3.295 × 10²⁷

Since the second derivative is negative, we know that x = -2/5 corresponds to a local maximum, not a minimum. Therefore, the absolute minimum value of f on the interval (0,0) does not exist

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The given question is incomplete, the complete question is:

Find the x-value corresponding to the absolute minimum value of f on the given interval. (If an answer does not exist, enter DNE.) f(x) = -5x¹⁴ /  e²ˣ on (0,0) X =

The angular momentum of the stuck-together particles with respect to the origin is (-3.09 î + 5.95 ĵ) kg*m²/s, in unit-vector notation.

To find the angular momentum of the stuck-together particles with respect to the origin after the collision, we need to first find the final velocity of the combined particles. Since the collision is completely inelastic, the two particles will stick together and move as one unit. We can use the conservation of momentum to find the final velocity:

(m₁v₁ + m₂v₂) / (m₁ + m₂) = v₀

where m₁ and v₁ are the mass and velocity of the first particle, m₂ and v are the mass and velocity of the second particle, and v₀ is the final velocity of the combined particles.

Plugging in the given values, we get:

(3.08 kg)(-1.43 m/s) + (3.16 kg)(8.93 m/s) / (3.08 kg + 3.16 kg) = 3.49 m/s

So the final velocity of the combined particles is 3.49 m/s.

Now, to find the angular momentum with respect to the origin, we need to use the cross product of the position vector and the linear momentum vector:

L = r x p

where r is the position vector from the origin to the center of mass of the combined particles, and p is the linear momentum vector of the combined particles.

The position vector can be found using the given xy coordinates:

r = (-0.291 m)î + (-0.152 m)ĵ

The linear momentum vector can be found using the combined mass and velocity:

p = (m1 + m2)vf = (3.08 kg + 3.16 kg)(3.49 m/s) = 21.42 kg*m/s

So the angular momentum can be calculated as:

L = (-0.152 m)(21.42 kgm/s)î - (-0.291 m)(21.42 kgm/s)ĵ

= -3.09 î + 5.95 ĵ kg*m²/s

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The gradient of the function at the point (3, 6, -3) is approximately 3.612.

To find the gradient of the function at the given point (3, 6, -3), we need to first find the partial derivatives of the function with respect to x, y, and z.

Using the product rule, we can find the partial derivative of w with respect to x:

∂w/∂x = tan(y + 2)

To find the partial derivative of w with respect to y, we use the chain rule:
∂w/∂y = x sec^2(y + 2)
And finally, the partial derivative of w with respect to z is simply 0:
∂w/∂z = 0
Now we can calculate the gradient vector:
grad(w) = (∂w/∂x, ∂w/∂y, ∂w/∂z)
= (tan(y + 2), x sec^2(y + 2), 0)
At the point (3, 6, -3), we have y = 6:
grad(w) = (tan(8), 3sec^2(8), 0)
To find the gradient at this point, we can take the magnitude of the gradient vector:
grad(w)| = sqrt[tan^2(8) + 9sec^4(8)]
= 3.612
Therefore, the gradient of the function at the point (3, 6, -3) is approximately 3.612.

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The series [tex](-1)^{(n+1)} \times Vn+3[/tex] is also divergent.

To apply the ratio test, we need to calculate the limit of the ratio of successive terms of the series:

lim n->∞ |(Vn+3)| / |Vn|

where Vn =[tex](-1)^n.[/tex]

Let's evaluate the limit:

lim n->∞ |(Vn+3)| / |Vn|

= lim n->∞[tex]|(-1)^{(n+3)}| / |(-1)^n|[/tex]

= lim n->∞ [tex]|-1|^{(n+3)} / |-1|^n[/tex]

= lim n->∞ [tex]|(-1)^3| / 1[/tex]

= 1

Since the limit is equal to 1, the ratio test is inconclusive. We cannot

determine the convergence or divergence of the series using this test.

However, we can observe that the series[tex](-1)^n[/tex] has alternating signs and

does not approach zero as n approaches infinity.

Therefore, it diverges by the divergence test.

Therefore, the series [tex](-1)^{(n+1)} \times Vn+3[/tex] is also divergent.

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By examining the relationships between different traits and methods, we can determine whether a measure is measuring what it is intended to measure, and identify any sources of error or bias in the measurement process.

Multitrait-Multimethod (MTMM) is a statistical technique that is commonly used in psychology and other social sciences to evaluate the validity of measures.

The MTMM correlation matrix is a square matrix that contains the correlations between each combination of traits and methods.

For example, suppose we want to evaluate the validity of a measure of social anxiety. We might use three different methods of measurement: self-report questionnaires, behavioral observation, and physiological measures such as heart rate. We might also measure social anxiety using multiple traits such as shyness, fear of social situations, and self-consciousness.

To arrange the MTMM correlation matrix for this example, we would first identify the traits and methods that we want to examine.

We would then collect data on each measure and calculate the correlations between each combination of traits and methods. We would then arrange these correlations in a square matrix, where the rows and columns represent the traits and methods, respectively.

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A 95% confidence interval means there is a 5% chance that the confidence interval will not include the actual population mean.

In your example, the 1.423 kg represents the researcher's estimate of the population mean. The values 0.112 kg and +8% represent the margin of error for the study. The phrase "19 times out of 20" or 95% refers to the confidence level, which shows how likely it is that the actual population mean is within the range given by the confidence interval. Factors affecting the margin of error include population size, standard deviation, and sample size. A 95% confidence interval means there is a 5% chance that the confidence interval will not include the actual population mean.

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Answer:

The answer is 12picm²

Step-by-step explanation:

Circumference of circle=2pir

C=2×6pi

C=12picm²

The probability that between 13 and 14.4 ounces are dispensed in a cup is approximately 0.3815 or 38.15%.

To find the probability that between 13 and 14.4 ounces are dispensed in a cup, we need to first standardize the values using the formula:

z = (x - μ) / σ Where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation.

For x = 13, we get: z = (13 - 13.5) / 3.5 = -0.14 For x = 14.4, we get: z = (14.4 - 13.5) / 3.5 = 0.26

We can then use a standard normal distribution table or a calculator to find the probability of the values falling between these two z-scores. Using a calculator, we can find: P(-0.14 < z < 0.26) = 0.3815

Therefore, the probability that between 13 and 14.4 ounces are dispensed in a cup is approximately 0.3815 or 38.15%.

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Standard deviation of 1.5 mile run time (X) = 2.11

The regression equation is: [tex]Y' = 65.03 - 2.478X[/tex], where Y' is the predicted VO2max and X is the 1.5 mile run time.

Sub. Y VO2max (ml·kg-1·min-1) X 1.5 mile run time (min) Yp Predicted VO2max.

To calculate the means and standard deviations:

Sub. Y VO2max (ml·kg-1·min-1) X 1.5 mile run time (min)

49.21 8.23

32.03 11.91

28.56 13.56

52.42 7.02

36.36 11.38

35.12 11.83

38.88 10.29

42.35 9.21

40.20 9.82

45.23 8.55

38.26 10.91

39.59 10.30

Mean of VO2max (Y) =[tex](49.21 + 32.03 + 28.56 + 52.42 + 36.36 + 35.12 + 38.88 + 42.35 + 40.20 + 45.23 + 38.26 + 39.59) / 12 = 39.21[/tex]

Standard deviation of VO2max (Y) = 6.45

Mean of 1.5 mile run time (X) =[tex](8.23 + 11.91 + 13.56 + 7.02 + 11.38 + 11.83 + 10.29 + 9.21 + 9.82 + 8.55 + 10.91 + 10.30) / 12 = 10.30[/tex]

Standard deviation of 1.5 mile run time (X) = 2.11

To calculate the slope and y-intercept for the regression equation:

We will use the formula for the slope and y-intercept of a linear regression equation:

[tex]b = r (Sy/Sx)[/tex]

[tex]a = Y - bX[/tex]

where r is the correlation coefficient, Sy is the standard deviation of Y, Sx is the standard deviation of X, Y is the mean of Y, and X is the mean of X.

First, we need to calculate the correlation coefficient:

[tex]r = \Sigma((Xi - X)(Yi - Y)) / \sqrt {(\Sigma(Xi - X)^2 \Sigma(Yi - Y)^2)}[/tex]

Using the means and standard deviations we calculated earlier, we get:

[tex]r = \Sigma((Xi - 10.30)(Yi - 39.21)) / \sqrt {(\Sigma( Xi - 10.30)^2 \Sigma(Yi - 39.21)^2)}[/tex]

r = -0.807

Now, we can calculate the slope and y-intercept:

[tex]b = r (Sy/Sx) = -0.807 (6.45/2.11) = -2.478[/tex]

[tex]a = Y - bX = 39.21 - (-2.478)(10.30) = 65.03[/tex]

The regression equation is: [tex]Y' = 65.03 - 2.478X[/tex], where Y' is the predicted VO2max and X is the 1.5 mile run time.

A 1.2- To calculate predicted VO2max for all participants in the data set:

Sub. Y VO2max (ml·kg-1·min-1) X 1.5 mile run time (min) Yp Predicted VO2max

49.21 8.23 55.36

32.03 11.91 47.10

28.56 13.56 44.22

52.42

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Answer:

575 square kilometer

Step-by-step explanation:

The  pilot is approximately 177.86 miles from the starting position.

To solve this problem, we can use trigonometry and the Pythagorean theorem.

First, let's find the distance traveled in the original straight path:

distance = speed x time
distance = 645 mph x 1.5 hours
distance = 967.5 miles

Next, let's find the distance traveled in the new direction:

distance = speed x time
distance = 645 mph x 2 hours
distance = 1290 miles

Now, let's use trigonometry to find the distance from the starting position to the final position. We can draw a right triangle with the original distance traveled as the adjacent side (because it is parallel to the ground) and the new distance traveled as the opposite side (because it is perpendicular to the ground due to the course correction). The hypotenuse of this triangle is the distance from the starting position to the final position.

To find the hypotenuse, we can use the tangent function:

tan(10 degrees) = opposite/adjacent
tan(10 degrees) = distance from starting position/967.5 miles

Solving for the distance from starting position:

distance from starting position = tan(10 degrees) x 967.5 miles
distance from starting position = 177.86 miles.

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The integration of the function ∫(1 + 2x²)[tex]e^{x} ^{2}[/tex] is -

[tex]$\frac{i\sqrt{\pi}\; erf(ix) }{2} +[/tex] [tex]$\frac{2i\sqrt{\pi}\;erf(ix) }{4} + \frac{xe^{x}^{2} }{2} +C[/tex].

Integration is the process of finding the area under the graph of the function f(x), between two specific values in the domain. We can write the integration as -

I = ∫f(x) dx

Given is to integrate the function -

∫(1 + 2x²)[tex]e^{x} ^{2}[/tex]

We have the function as -

I = ∫(1 + 2x²)[tex]e^{x} ^{2}[/tex]

I = ∫[tex]e^{x} ^{2}[/tex]  +  ∫2x²[tex]e^{x} ^{2}[/tex]

I =  [tex]$\frac{i\sqrt{\pi}\; erf(ix) }{2} +[/tex] [tex]$\frac{2i\sqrt{\pi}\;erf(ix) }{4} + \frac{xe^{x}^{2} }{2} +C[/tex]

Therefore, the integration of the function ∫(1 + 2x²)[tex]e^{x} ^{2}[/tex] is -

[tex]$\frac{i\sqrt{\pi}\; erf(ix) }{2} +[/tex] [tex]$\frac{2i\sqrt{\pi}\;erf(ix) }{4} + \frac{xe^{x}^{2} }{2} +C[/tex].

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The following parts can be answered by the concept of Standard deviation.

a. The percentage of drivers driving under the speed limit is approximately 36.34%.

b. The percentage of speeders who will be fined $5000 is approximately 1.39%.

c. The percentage of drivers who are unlikely to be pulled over by the police is approximately 48.98%.

d.  A driver must be traveling at least 121.91 km/h to be in the top 2% of all speeding drivers and subject to losing their license.

To answer these questions, we can use the concept of normal distribution and apply the Z-score formula to find the corresponding probabilities.

(a) The percentage of drivers driving under the speed limit can be calculated as the percentage of drivers whose speed is less than or equal to 100 km/h. Using the Z-score formula, we get:

Z = (100 - 103.4) / 9.8 = -0.3469

Looking up the Z-table or using a calculator, we find that the percentage of drivers driving under the speed limit is approximately 36.34%.

(b) The percentage of speeders who will be fined $5000 can be calculated as the percentage of drivers whose speed is at least 125 km/h (25 km/h over the limit). Using the Z-score formula, we get:

Z = (125 - 103.4) / 9.8 = 2.2051

Using the Z-table, we find that the percentage of speeders who will be fined $5000 is approximately 1.39%.

(c) The percentage of drivers who are unlikely to be pulled over by the police between 100 km/h and 110 km/h can be calculated as the percentage of drivers whose speed is between 100 km/h and 110 km/h. Using the Z-score formula, we get:

Z1 = (100 - 103.4) / 9.8 = -0.3469

Z2 = (110 - 103.4) / 9.8 = 0.6735

Using the Z-table, we find that the percentage of drivers who are unlikely to be pulled over by the police is approximately 48.98%.

(d) The speed at which a driver can lose their license if they are in the top 2% of all speeding drivers can be calculated using the Z-score formula:

Z = (X - 103.4) / 9.8

Using the Z-table, we find that the Z-score corresponding to the top 2% is approximately 2.05. Therefore:

2.05 = (X - 103.4) / 9.8

X = 121.91 km/h

Therefore, a driver must be traveling at least 121.91 km/h to be in the top 2% of all speeding drivers and subject to losing their license.

Therefore,

a. The percentage of drivers driving under the speed limit is approximately 36.34%.

b. The percentage of speeders who will be fined $5000 is approximately 1.39%.

c. The percentage of drivers who are unlikely to be pulled over by the police is approximately 48.98%.

d.  A driver must be traveling at least 121.91 km/h to be in the top 2% of all speeding drivers and subject to losing their license.

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We are given the polar coordinate (9). However, we also need to know the angle (theta) at which this point lies.

Convert polar coordinates to rectangular coordinates, we use the formulas:

x = r cos(theta)
y = r sin(theta)

In this case, we are given the polar coordinate (9). However, we also need to know the angle (theta) at which this point lies. Without this information, we cannot convert the polar coordinates to rectangular coordinates.

I cannot provide an exact answer to this question without additional information about the angle (theta).

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The given series can be represented in summation notation [tex]\sum(-1)^{(n+1)}1/n[/tex], where Σ represents the summation symbol and n is the index of the summation. This series is known as the alternating harmonic series. The series converges conditionally.

The alternating harmonic series satisfies the conditions of the Alternating Series Test, as the absolute values of its terms decrease and approach zero while the terms themselves alternate in sign. However, the series does not converge absolutely, as the harmonic series [tex]\sum1/n[/tex] diverges.

The Leibniz Convergence Test confirms conditional convergence, indicating that the alternating harmonic series converges to a specific value, which is the natural logarithm of 2.

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The series Σ (-1)^(n+1) / n from n = 1 to ∞ is an example of an alternating series which converged conditionally as per series test and absolute convergence test. However, the absolute values of the terms form a harmonic series which diverges.

This series can be represented in summation notation as Σ (-1)^(n+1) / n where the summation is from n = 1 to ∞. The general term (-1)^(n+1) / n alternates between positive and negative values as n increases. This is an example of an alternating series.

To determine if the series converges conditionally or absolutely, we apply two tests: the series test and the absolute convergence test.

The series test states that if the absolute value of successive terms in a series decrease to 0, the series converges. For the series in question, the absolute value of each term does indeed decrease to zero as n increases, so the series test shows that this series converges.

The absolute convergence test states that if the series of the absolute values of the terms converges, then the original series converges absolutely. In this case, the series of the absolute values of the terms is the harmonic series, which is known to diverge. Therefore, the original series converges conditionally, but not absolutely.

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Bayes’ Theorem is a way of finding a probability when we know certain other probabilities.

We can use Bayes' theorem to find P(A1|B1):

P(A1|B1) = P(B1|A1) * P(A1) / P(B1)

To find P(B1), we can use the law of total probability:

P(B1) = P(B1|A1) * P(A1) + P(B1|A2) * P(A2)

Since A1 and A2 are complements, P(A2) = 1 - P(A1) = 0.7.

Substituting the given values, we get:

P(B1) = 0.5 * 0.3 + 0.8 * 0.7 = 0.67

Now we can calculate P(A1|B1):

P(A1|B1) = 0.5 * 0.3 / 0.67 = 0.212

Therefore, P(A1IB1) = P(A1|B1) = 0.212 (rounded to three decimal places).

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The correct notation to denote the variance of a population is B) σ².

Variance is a measure of how much the values in a dataset deviate from the mean. It is calculated as the average of the squared differences between each data point and the mean. In statistics, the notation used to represent the variance of a population is σ², where σ represents the Greek letter sigma, and the superscript 2 indicates that the variance is squared.

The notation σ² is used specifically for population variance, which is calculated using the entire set of data points in a population. It is important to note that when working with a sample from a population, a slightly different notation is used for the sample variance, denoted as s². The sample variance takes into account the fact that the sample is only a subset of the entire population, and therefore requires a slightly different calculation.

Therefore, the correct notation to denote the variance of a population is B) σ².

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